paginate | A simple paginator for Jekyll sites | Static Site Generator library
kandi X-RAY | paginate Summary
kandi X-RAY | paginate Summary
Simple and flexible pagination for Jekyll sites featuring:.
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QUESTION
While trying to create show my students on Laravel 8, I met with some errors, first it wasn't creating the students, then I get errors on /students/ page
Attempt to read property "country_name" on null
index.blade.php
...ANSWER
Answered 2021-Jun-15 at 15:33Since foreignKey not laravel convention so you have to mention foreignKey in belongsTo.I believe foreignKey is country in Student Table
QUESTION
I am trying to contribute to a Github Page/Jekyll site and want to be able to visualise changes locally but when I run bundle exec jekyll serve but I get this output:
ANSWER
Answered 2021-Feb-02 at 16:29I had the same problem and I found a workaround here at https://github.com/jekyll/jekyll/issues/8523
Add gem "webrick" to the Gemfile in your website. Than run bundle install
At this point you can run bundle exec jekyll serve
For me it works!
QUESTION
I'm fetching data from an API that is paginated server-side. I have limited the number of results to 5 (rows=5). For the first set of data, a global variable pageNumber has been declared to 1, and eventListeners for the Previous/Next buttons have been added. Now I don't know how to get the next set of results. They can be fetched by changing the pageNumber to 2 but I don't know how to access the URL from const endpoint where I would change the pageNumber parameters to get previous and/or next results. Any idea how to do that?
...ANSWER
Answered 2021-Jun-14 at 13:51// First set of fetched data starts with page 1
let pageNumber = 1;
let term = '';
// 1. Define endpoint, fetch response and return data promise
const search = async () => {
const key = 'aroplosuitin';
const endpoint = `https://api.europeana.eu/record/v2/search.json`,
query = `?wskey=${key}&query=${term}&start=${pageNumber}&rows=5&profile=rich'`;
const response = await fetch(endpoint + query);
// Check response status:
if (response.status !== 200) {
throw new Error('Cannot fetch data. Response status is not 200.');
}
const data = await response.json();
return data;
};
// 2. Call search and return data promise
const searchEuropeana = async () => {
const data = await search();
return data;
};
// 3. Grab the input and invoke callback to update the UI
const searchForm = document.querySelector('#search-form');
searchForm.addEventListener('submit', (e) => {
e.preventDefault();
// grab user input
term = searchForm.search.value.trim();
// reset form on submit
searchForm.reset();
// For errors
const errorOutput = document.querySelector('.error');
// Invoke searchEuropeana
searchEuropeana()
.then((data) => {
updateUI(data);
console.log(data);
})
.catch((error) => {
console.log('An error occured:', error),
(errorOutput.innerText = 'Check your spelling or network.');
});
});
// 4. Update the UI with HTML template
const updateUI = (data) => {
console.log(data);
};
// 5. Previous / Next results
const previousBtn = document.querySelector('#previousBtn'),
nextBtn = document.querySelector('#nextBtn');
previousBtn.addEventListener('click', () => {
if (pageNumber > 1) {
pageNumber--;
} else {
return;
}
console.log(pageNumber);
searchEuropeana();
});
nextBtn.addEventListener('click', () => {
pageNumber++;
console.log(pageNumber);
searchEuropeana();
});
QUESTION
Good day, I'm creating a social media app using MEAN stack which will contain an option to list the users you are following however, as per Collections.Find() has been deprecated, I was using Colletions.estimatedDocumentCount() to list the users in JSON (as currently I'm testing it using postman).
It shows the number of users and how many you are following however, there is no more data in the JSON to display.
This is my function. Any help will be very appreciated
...ANSWER
Answered 2021-Jun-14 at 11:06You are using paginate() incorrectly.
Check this:
QUESTION
I want to query an eloquent method and later paginate. So I have written the code as
...ANSWER
Answered 2021-Jun-14 at 09:18First you have to pass one value to find() method as parameter.So that it will return one record based on given id .If you dont have id and want to fetch first record then you have to use first().
Also you are using paginate to return result ,i think you don't need find() method.
It should be
QUESTION
I'm trying to fetch data from my Strapi GraphQl api and paginate them. For that I need to pass down variables. I'm using react-query and fetch api.
Here I declare my variables and query.
...ANSWER
Answered 2021-Jun-13 at 14:43From a react-query specific perspective, it looks good:
- having all variables as part of the query key
- passing them correctly to the queryFn
I'm no graphQL expert, but looking at this example blog post on how to use graphql with fetch, you need to pass variables next to the query as the body of your fetch request.
Something like:
QUESTION
Currently the query that I am using is as follows:
...ANSWER
Answered 2021-Jun-13 at 09:45- you should apply
sumto each column separately:
search_columns = [db.func.sum(getattr(Model, i)) for i in col_headers]
- you can use
Query.add_columnsto add columns to the query results:
query = query.add_columns(*search_columns)
or you can pass them directly:
Model.query.with_entities(Model.m_t, *search_columns)
Putting it all together:
QUESTION
I am starting to learn JHipster with the "Full Stack Development with JHipster (Second Edition)" book which uses JHipster 6.5.0.
In Chapter 5 "Customization and Further Development" the default table view is replaced by a list. In order to bring back the sorting functionality, the authors include the following jhiSort directive (page 134):
jhiSort [(predicate)]="predicate" [(ascending)]="reverse" [callback]="transition.bind(this)"
as part of this code snippet:
...ANSWER
Answered 2021-Jun-13 at 09:28After all, the answer was quite easy as it has been part of the "product.component.html" page before the table view has been replaced by a list view.
The HTML tr tag featured the following jhiSort directive
QUESTION
So i'm trying to order some stuff. Like that:
...ANSWER
Answered 2021-Jun-13 at 06:48You can improve your query like this
QUESTION
I am using paginator in my list view. Every page listed 10 item. If I edit an item from page 5 then I want to redirect back to page 5. Right if I edit an team from page 5, it's redirecting me every time in page 1. here is my code:
...ANSWER
Answered 2021-Jun-09 at 19:12In your
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