Crimson | The Crimson Text typeface | User Interface library
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of Crimson
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Copy// 1. Create config object
Config config = new Config();
config.useClusterServers()
// use "rediss://" for SSL connection
.addNodeAddress("redis://127.0.0.1:7181");
// or read config from file
config = Config.fromYAML(new File("config-f Community Discussions
Trending Discussions on Crimson
QUESTION
I'm creating 2 pages (Summary and Cycles pages) using react.js.
On the Summary page, there is a column named CN that every item links to the Cycles page.
Summary page has a path /route/summary/location=abc and Cycles page has a path /route/cycle/location=abc/deviceId=4410
For example, if I click the value from CN column in the first row of the table inside the Summary page, I will be redirected to the Cycles page with the path /route/cycle/location=abc/deviceId=4410.
In the Summary page, I use https://github.com/react-bootstrap-table/react-bootstrap-table2 for the table component and I use a columnRenderer function inside columns.js to render a custom item inside the table like this one:
How can I put the pathname (example "abc") to a Link component inside cnColumnRenderer function in columns.js?
Summary page with the path: /route/summary/location=abc
Cycles page with the path: /route/cycle/location=abc/deviceId=4410
Error because of invalid hook call while rendering the Summary page
My Code:table code inside Summary page (inside Summary.js):
hint: focus on columns variable from './columns' and its implementation
ANSWER
Answered 2021-Jun-15 at 05:17React hooks are only valid in React functional components, not in any callbacks, loops, conditional blocks. If you need the location data in the callback it needs to be passed in.
From what I can tell it seems you need to move the columns.js code into the main component so the location values can be closed over in scope.
QUESTION
Problem:
A container that has three boxes is positioned in the center in desktop view. However, it is not in the center when viewed on a mobile.
Minimal Working Example (MWE):
HTML
...ANSWER
Answered 2021-Jun-14 at 18:19The solution is pretty simple.
When you change the direction to column the axis gets reversed too. So, adding align-items: center; will center the boxes.
This is what you need:
QUESTION
I have made this website as a practice portfolio website for myself and my website is pushed to the left whenever its smaller than particular size. it used to be around 600px but I removed the whole code and rewrote the website again but I checked it at early phases and still suffers from this problem which I cant find the reason for it. so I stopped coding and came straight here for help. please help me this is the third time I'm trying to build this website and still have this problem. something else i noticed is that althoug i have scroll x hidden i still have this tiny scroll to left when resizing the website.enter image description here
...ANSWER
Answered 2021-Jun-05 at 05:43Check your .info class, you are using 100px on padding. That's too large in smaller screen. You can reduce it using media query.
I'll also suggest changing .info class into:
QUESTION
This example simulation looks good but drag doesn't work!
...ANSWER
Answered 2021-Jun-04 at 20:05dragged1 and dragended1 should have event as the first argument.
QUESTION
I am a beginner. I am trying to use a jQuery plugin named "Daisy". I have implemented it successfully but I am facing a problem. The plugin is overlapping other contents of the div. Here below I am giving my full code.
Plugin: Daisy GitHub
...ANSWER
Answered 2021-Jun-04 at 05:48The plugin doesn't overlap the other content. You just need to change the dot and line color.
QUESTION
i took this code from here I want to change pop ups to open automatically when web pages are accessed
...ANSWER
Answered 2021-May-30 at 12:20Just add the following snippet to the object passed into the floatingWhatsApp function
QUESTION
I sincerely hope, that I followed all the rules and guidelines and that my question/problem is comprehensive enough to find an adequate answer. First, a small intro:
For a current project of mine I want to designate specific types to tree node objects. To keep matters simple here, I will use colours as an analogy.
Let's suppose I have the following enum, derived from the enum standard library:
ANSWER
Answered 2021-May-24 at 20:10To make sure I understand:
QUESTION
I compose a part of the code of my project here to report the problem I am facing. I need to keep the js function to work the links that I put in the top bar.
...ANSWER
Answered 2021-May-24 at 09:55$(document).on("click", function (e) {
e.preventDefault(); //<-- THIS HERE
QUESTION
My question relates to a JavaScript function I have written that seems to be behaving a bizarre way. In summary, the function execution seems to go on even after a return statement is encountered - it's as if the return statement inside a forEach loop is ignored. This is difficult to make sense of, and is not how it happens in any of the languages I have seen before.
Presenting a code snippet below - I have tried to make the code, logging and comments as focused and descriptive as possible so that the reader can easily identify the issue. However, I am sharing a detailed description of the problem as well if you'd prefer not to jump to the code directly.
In the code I have shared, the function substituteWithMainColor() takes a string value named color as argument. It matches it against each element of an array (called substitutionArray) of object literals, where each such object contains a member string called mainColor and member array called variations. If the function finds the color argument in any of the variations arrays, then it returns the corresponding mainColor of the object in which the match was found. If no match is found in any of the objects, then the function returns the original value passed as argument.
In my example, an argument "Cyan" is passed to the function substituteWithMainColor(). Since the array substitutionArray contains "Cyan" as one of the strings in the variations array of its third item, a match is found ( and the logs show it). However, at this point, instead of returning with the matched mainColor value "Blue" as expected, the function ignores the return statement inside the forEach() loop and keeps on executing further iterations of the forEach loop (the logs show this, too). Eventually it executes the final return statement which is after the forEach() loop, and returns the original color value, which is erroneous.
Can someone please help me understand what might be going on?
...ANSWER
Answered 2021-May-24 at 09:37A forEach is not the same an a normal for loop. You're essentially passing a function to be executed every loop, so your return acts in the scope of that function, not the loop.
It's a little like this:
QUESTION
from tkinter import *
from tkinter import ttk
from PIL import ImageTk ,Image
win=tkinter.Toplevel()
wrapper=Frame(win, bd=4, relief=RIDGE, bg="crimson")
wrapper.place(x=0, y=80, width=465, height=625)
wrapper3=Frame(win, bd=4, relief=RIDGE, bg="crimson")
wrapper3.place(x=950, y=80, width=465, height=625)
wrapper3_title=Label(wrapper3, text="Selected Data", bg="crimson", fg="white", font=("times new roman",30,"bold"))
wrapper3_title.grid(row=0,column=0,padx=20, pady=10)
wrapper2=Frame(win, bd=4, relief=RIDGE, bg="crimson")
wrapper2.place(x=465, y=80, width=485, height=625)
ent8=StringVar()
def code():
btn1.destroy()
add=StringVar()
sub=StringVar()
pro=StringVar()
img=ImageTk.PhotoImage(Image.open("Amritsar.jpg"))
Label2= Label(wrapper2, image=img)
Label2.grid(row=0, column=0, padx=10, pady=5, sticky='w')
def Find():
add.set(float(ent00.get())+float(ent01.get()))
sub.set(float(ent00.get())-float(ent01.get()))
pro.set(float(ent00.get())*float(ent01.get()))
ent00=Entry(wrapper, width=15)
ent00.grid(row=4, column=1, padx=10, pady=10, sticky='w')
ent01=Entry(wrapper, width=15)
ent01.grid(row=5, column=1, padx=10, pady=10, sticky='w')
lbl8=Label(wrapper, text="Add", bg="crimson", fg="white", font=("times new roman",15,"bold")).grid(row=6, column=0, padx=20, pady=10, sticky='w')
ent8=Entry(wrapper, textvariable=add, width=15, state='readonly')
ent8.grid(row=6, column=1, padx=10, pady=10, sticky='w')
lbl15=Label(wrapper, text="Subtract", bg="crimson", fg="white", font=("times new roman",15,"bold")).grid(row=7, column=0, padx=20, pady=10, sticky='w')
ent15=Entry(wrapper, textvariable=sub, width=15, state='readonly')
ent15.grid(row=7, column=1, padx=10, pady=10, sticky='w')
lbl9=Label(wrapper, text="Product", bg="crimson", fg="white", font=("times new roman",15,"bold")).grid(row=8, column=0, padx=20, pady=10, sticky='w')
ent9=Entry(wrapper, textvariable=pro, width=15, state='readonly')
ent9.grid(row=8, column=1, padx=10, pady=10, sticky='w')
btn = Button(wrapper, text = 'Calculate', command=Find, bd = '5', width=15, height=2)
btn.grid(row=11, column=1, padx=20, pady=10)
def img():
if ent8.get()=="4":
img=ImageTk.PhotoImage(Image.open("Amritsar.jpg"))
Label2= Label(wrapper3, image=img)
Label2.grid(row=0, column=2, padx=10, pady=5, sticky='w')
print("Move ahead")
else:
print("Try again")
btn2 = Button(wrapper, text = 'Image', command=img, bd = '5', width=15, height=2)
btn2.grid(row=12, column=1, padx=20, pady=10)
btn1 = Button(wrapper, text = 'OPEN CODE', command=code, bd = '5', width=20, height=2)
btn1.grid(row=11, column=1, padx=20, pady=10)
win.geometry("1400x700+250+250")
win.mainloop()
ANSWER
Answered 2021-May-19 at 13:15First of all, terrible names.
Both your function and your PhotoImage are named img. Rename the function to def add_img().
Second, looking at your code I have no idea what all the wrapper frames are for, why not name them according to what they are planned to hold? Same applies to all the widgets. Wouldn't calc_btn be a better name than btn? img_btn instead of btn2? Why do you need to read more than the name to know what something is?
Third, you have ent8 twice in your code. Once as Label and again as a StringVar.
Tkinter constantly refreshes your window so you need to save the image you are using.
Personally I would have done all of this in a class.
For right now, with your current code, just add
loaded_img = ImageTk.PhotoImage(Image.open("Amritsar.jpg")) before your functions and instead of using the variables you are using to open the image, just use Label(wrapper3, image=loaded_img)
As in:
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