baritone | Spotify controls that live in your menubar | Menu library
kandi X-RAY | baritone Summary
kandi X-RAY | baritone Summary
Spotify controls that live in your menubar. Download latest release.
Support
Quality
Security
License
Reuse
Top functions reviewed by kandi - BETA
Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of baritone
baritone Key Features
baritone Examples and Code Snippets
Community Discussions
Trending Discussions on baritone
QUESTION
I'm trying to make a minecraft plugin. I want it to create variable for every player. I'm using "for" for the loop. I'm trying to add the player's name to the variable's name. Can anyone help?
...ANSWER
Answered 2021-Feb-11 at 09:17It sounds like you want a Map with a key for every player. A Map creates an association between one variable (a key) and another (a value). Values are set using the put(key, value) method, and they retrieved using 'get(key)'
QUESTION
I am trying to convert a string with consecutive duplicate characters to it's 'dictionary' word. For example, 'aaawwesome' should be converted to 'awesome'.
Most answers I've come across have either removed all duplicates (so 'stations' would be converted to 'staion' for example), or have removed all consecutive duplicates using itertools.groupby()
, however this doesn't account for cases such as 'happy' which would be converted to 'hapy'.
I have also tried using string intersections with Counter()
, however this disregards the order of the letters so 'botaniser' and 'baritones' would match incorrectly.
In my specific case, I have a few lists of words:
...ANSWER
Answered 2020-Nov-16 at 19:28use the enchant module, you may need to install it using pip
See which letters duplicate, remove the letter from the word until the word is in the English dictionary.
QUESTION
I have discogs data about artists who perform on jazz albums and would like to create network maps of these individuals. Sample data are provided below. I need to compute all possible pairs of artists on a given album. To illustrate the desired result, the figure below shows the original data (left side) and how additional rows must be added to achieve a unique set of all possible pairs WITHIN an album. Additional information on role must be retained. In the example shown, there are originally 12 records for three albums. The restructured data will have 31 records and the same columns.
A post here seems similar but deals with data in a different structure.
...ANSWER
Answered 2020-Jan-30 at 18:25Here is at least one way.
QUESTION
I'm currently making a 1.12.2 Forge mod that involves pathfinding, so I decided to use Baritone. Can anyone help me with actually accessing the API? What I'm currently doing is manually accessing it with BaritoneAPI.getProvider()
, which crashes it.
According to the author of Baritone, "Baritone's forge jar is notch mapped, and relies on runtime remapping to searge. If you manually load the BaritoneAPI
class, or otherwise trick forge into thinking that it doesn't need to remap baritone, it will crash like this."
What's the proper way of accessing the Baritone API?
Update: I've resorted to using EntityPlayerSP#sendChatMessage(String)
and forcing the player to use a Baritone chat command for now.
ANSWER
Answered 2019-Dec-11 at 17:54I can't try it at the moment, so I don't know if this leads to the problem you mentioned, but it looks like it should be easy enough to use the API.
From here:
QUESTION
I want to create an app where I can rotate the camera to view a specific entity but my camera rotates instantaneously how can I make it a smooth transition
I tried attaching animation component to camera but due to look-controls component the rotation is overridden
(click here) to see the code
...ANSWER
Answered 2019-Oct-10 at 18:12Because look-controls overrides rotation component on the camera, you can't set or animate rotation directly.
One solution would be to disable look controls (or possibly remove it), and then perform the animation on rotation. Then when it finishes, enable (or add back in) the look-controls component.
Another solution is to use THREEjs camera control to set and animate the camera. Animation component only works on other component properties. So you need to make a custom component, and animate a schema property of that component. Then inside the component, in update(), you set the threejs rotation of the camera from the schema property.
QUESTION
I have an array of images. I would like to update the image in the CardMedia every time the user presses the image.
What I cant figure is how get the next image in the array (current index)?
...ANSWER
Answered 2019-Mar-14 at 17:07Start off with imageIndex = 0:
QUESTION
So I am trying to get the sing method to play one of the audioclips I created up top. I know I need an audioSource, I just have no clue how it fits in with the audioClips. I don't currently have an audiosoure assigned to the object that this script is assigned to, so that might impact things. Thanks for your help.
...ANSWER
Answered 2018-Jul-15 at 04:19If you attach an AudioSource
component to the GameObject
, then you could set an AudioSource
variable to that component and then call the setter function clip(AudioClip x)
to set the clip the source should play. At that point, you could just call Play()
and wait for the length of the audio clip.
Code shouldn't be too difficult to figure out but if you have any more questions, don't hesitate to ask. Good luck!
QUESTION
This is in SQLite.
I have two tables, X and Y. X has an 'id' field. Y has a 'tag' field and a foreign key 'xid' mapped to X.id.
Let's say we want to process a list of strings, for example ["abacus", "baritone", "custard"]. I want to select each record N in X where Y contains all of these records: {"abacus", N.id}, {"baritone", N.id}, {"custard", N.id}.
If possible it would also be nice to handle substrings so that we can get the same result from the list ["aba", "tone", "star"], but that might be asking too much.
I might not have explained very well so I am willing to clarify the question where required.
...ANSWER
Answered 2018-Jul-20 at 01:48You can use group by
and having
. For the first problem:
QUESTION
I have question, where I need to implement ladder problem with different logic.
In each step, the player must either add one letter to the word from the previous step, or take away one letter, and then rearrange the letters to make a new word.
croissant(-C) -> arsonist(-S) -> aroints(+E)->notaries(+B)->baritones(-S)->baritone
The new word should make sense from a wordList.txt which is dictionary of word.
My code look like this, where I have calculated first the number of character removed "remove_list" and added "add_list". Then I have stored that value in the list.
Then I read the file, and stored into the dictionary which the sorted pair.
Then I started removing and add into the start word and matched with dictionary.
But now challenge is, some word after deletion and addition doesn't match with the dictionary and it misses the goal.
In that case, it should backtrack to previous step and should add instead of subtracting.
I am looking for some sort of recursive function, which could help in this or complete new logic which I could help to achieve the output.
Sample of my code.
...ANSWER
Answered 2017-Dec-16 at 19:24Recursion-based backtracking isn't a good idea for search problem of this sort. It blindly goes downward in search tree, without exploiting the fact that words are almost never 10-12 distance away from each other, causing StackOverflow (or recursion limit exceeded in Python).
The solution here uses breadth-first search. It uses mate(s)
as helper, which given a word s
, finds all possible words we can travel to next. mate
in turn uses a global dictionary wdict
, pre-processed at the beginning of the program, which for a given word, finds all it's anagrams (i.e re-arrangement of letters).
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install baritone
Support
Reuse Trending Solutions
Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items
Find more librariesStay Updated
Subscribe to our newsletter for trending solutions and developer bootcamps
Share this Page