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I had the same problem, I leave you the steps

1. Click Files -> preferences -> Binary path
2. ProgresSQL Binary path: c:\Program Files\PosgresSQL\13\bin
3. Click right DataBase-> Restore...

NOTE: https://www.youtube.com/watch?v=7cBkXKCY4Ew

Assuming the format is always like this (e.g. it's always pgdump) you can iterate the text line by line and extract everything between CREATE TABLE and the closing paren:

You will probably need to make the table a few thousand times larger than the one at that link before you start to see meaningful differences.

For the index that starts with equality column, it can jump to the 'G' section within the index, it can then jump to 60 for the length, and read forward until it exceeds 70. All of those rows will then meet both qualifications.

But for the other index, it can't just jump to 60, and then jump to the G section, because there is no a single G section. There is one G section for each distinct value between 60 and 70. So what it ends up doing is scanning all rows from 60 to 70, individually filtering out ones which are not G.

It turns out the difference is not that big, because most of the time is spent visiting the table heap to fetch the data it needs from the table, and in this case the same set of rows need to visited for either index.

With PostgreSQL 11.8 it works if you have data in the table.

Note that your function returns void so you have no real result set: a function should return some data otherwise you could use a procedure.

The problem is the g in select * from g

it should be

Apparently, the developers "forgot" to enable authentication.

Right, it is quite possible that I didn't have auth on. I'll see whether I can give it a try on the weekend.

needless to say, two months later it is still not fixed

There are many resources around this, so to be short your expression says this in plain english:

Get all the records from the customer table Then for each of those records, get every payment record that has the same value in the customer_Id field. return a single row for each payment record that duplicates all the fields from the customer record for each row in the payment record. Finally, only return 3 columns:

• the customer_id column from the customer table
• the first_name column that is in one of the customer or payment table
• the last_name column that is in one of the customer or payment table

Note that we didn't bring back any columns from the payment table... (I assume first_name and last_name are fields in the customer table...)

Keep in mind, a CROSS JOIN (or a FULL OUTER JOIN) is a join that says take all fields from the left side and create a single row combination that is multiplied by the right side, so for every row on the left, return a combination of the left row with every row on the right. So the number of rows returned in a CROSS JOIN is the number of rows in the current table, multiplied by the number of rows in the joined table.

In your query, an INNER JOIN or LEFT INNER JOIN will produce a recordset that includes all the fields from the current table structure and will include fields from the joined table as well. the implicit LEFT component specifies that only records that match the existing table structure should be returned, so in this case only Payment records that match a customer_id in the currently not filtered customer table will be returned.

The number of resulting rows is the number of rows in the joined table that have a match in the current table.

If instead you want to query:

Select all the customers that have payments

then you can use a join, but you should also use a DISTINCT clause, to only return the unique records:

The explicit cast of the datatype «mpaa_rating» I added to my SQL prepared statement: