kandi X-RAY | Ruler Summary
kandi X-RAY | Ruler Summary
Provide a horizontal scrollable ruler widget, developer can get the value which user scrolled to. The widget is drawn by canvas. All elements is customizable. Provide a style by default.
Top functions reviewed by kandi - BETA
- Compute the scroll offset
- Stops the animation
- Returns true if the scroller has been finished
- Gets the interpolation
- Static function
- Reset the progress bar
- Returns the duration of the scroll event
- Sets the position of the scroller
- The vertical edge is reached
- The horizontal edge is reached
- Get the velocity of a spline
- Get the swipe distance
- Sets the activity to be saved
- Get the current velocity
- Ends the scroll animation
- Sets the amount of extrins applied to the scroll
- Returns the time elapsed for the current animation
- Check if the scroller is currently in direction
- Spring to spring a new coordinate range
- Set the final position of the scroll
Ruler Key Features
Ruler Examples and Code Snippets
Trending Discussions on Ruler
I am trying to see how word frequency correlates with phonotactic probability using R, but there are a few issues. First, and most generally, I don't know merge these two graphs together (i want them to appear on the same axis).
This leads to a second problem because the first graph's y values are in probabilities, and the second is a count, so the scales are not the same. Should I combine data frames first, or is there a simpler way to merge two graphs?
Here is the reproducible sample, and the code for my graphs:...
ANSWERAnswered 2022-Mar-09 at 20:44
One way could be to use a second y axis. Although this method is to be used critically, in this situation I think it is appropriate:
this is my first time using stack overflow as I am just starting to learn python so apologies if I don't phrase things as clearly as I should!
I am working on a problem which asks me to set up a stationery shop. There is a dictionary with prices:...
ANSWERAnswered 2022-Mar-04 at 04:25
Iterate over each element, unpacking the tuple:
For context Wordle is game where you have to decipher a 5 letter word in 6 or less guesses based on certain hints. The hints you get are as follows:
- If a character is coloured black there are no characters that match that character in the target word.
- If a character is coloured orange there is a character that matches that character in the target word but it is in a different position.
- If a character is coloured green the position and the character are a match.
I am making a wordle solver program that takes in an array of word attempts and eliminates them from a list of the possible words.
I feel that the best algorithm to solve this problem is a black list where a word that breaks one of the rules is eliminated from the array. But if there is a better alternative I am open to suggestion....
ANSWERAnswered 2022-Feb-04 at 18:13
You are building a list of candidates, what is a good start I think. It doesn't really matter whether you white- or blacklist the result is the list of candidates. The only concern is that you could get the solution faster or more reliably by guessing words that are not on the candidates list. Why? Because that way you can introduce more new letters at once to check if the word contains them. Maybe a mix between the two strategies is best, hard to tell without testing it first.
- "green" is OK.
- "black" needs to count the number of non-black appearances of the letter in the guess and all words that not contain that exact amount of that letter can be eliminated (and also those that have the letter at a black position).
- "orange" is OK but can be improved: you can count the number of non-black appearances of the letter in the guess and eliminate all words that contain the letter fewer times (checking for minimal appearance and not just at least once) and also what you already have applies: the letter cannot be at an orange position.
There are a lot of ideas for improvements. First I would create the filter before going through the words. Using similar logic as above you would get a collection of four different rule types: A letter has to be or cannot be at a specific position or a letter has to appear exactly (possibly 0) or at least a specific number of times. Then you go through the words and filter using those rules. Otherwise some work might be done multiple times. It is easiest to create such a filter by collecting the same letters in the guess first. If there is an exact number of appearence rule then you can obviously drop a minimal number of appearance rule for the same letter.
To guess the word fast I would create an evaluation function to find the most promising next guess among the candidates. Possible values to score:
- How many new letters are introduced (letters that were not guessed yet).
- Also the probabilites of the new letters could be taken into account. E.g. how likely is it that a word contains a specific letter. Or even look at correlations between letters: like if I have a Q then I probably also have a U or if the last letter is D then the likelyhood of the 2nd last being E is very high.
- You could even go through all the possible answers for every candidate and see which guess eliminates the most words on average or something similar. Although this probably takes too long unless somehow approximated.
I have been struggling for a long time to figure how to define a generator function of a ruler sequence in Python, that follows the rules that the first number of the sequence (starting with 1) shows up once, the next two numbers will show up twice, next three numbers will show up three times, etc.
So what I am trying to get is 1, 2, 2, 3, 3, 4, 4, 4, 5, 5, 5, 6, 6, 6, 7, 7, 7, 7 etc.
I understand that the way to do this is to have two separate count generators (itertools.count(1)) and then for every number in one generator yield number from the other generator:...
ANSWERAnswered 2022-Jan-28 at 18:43
I am trying to create a facet_grid that contains histograms for measurements for three different measuring methods for three different objects. However, my code returns a fourth "(all)" graph.
How can I remove the (all) graph and return a 3x3 facet_grid with the clavicle, phalanx, and sacrum as the columns, and calipers (cm), ruler (in), and your knuckle as the rows?
The following is a sample data frame and the ggplot2 code to create the histogram facet_grid....
ANSWERAnswered 2022-Jan-24 at 22:44
margins = FALSE in
I have some JSON that looks like this:...
ANSWERAnswered 2021-Dec-24 at 11:07
First create your array
I am trying to get the entity ruler patterns to use a combination of lemma & ent_type to generate a tag for the phrase "landed (or land) in Baltimore(location)". It seems to be working with the Matcher, but not the entity ruler I created. I set the override ents to True, so not really sure why this isn't working. It is most likely a user error, I am just not sure what it is. Below is the code example. From the output, you can see that the pattern rule was added after NER and I have set the override ents to true. Any input or suggestions would be appreciated!
The matcher tags the entire phrase (landed in Baltimore), but the entity rule does not.
ANSWERAnswered 2021-Dec-23 at 03:59
Here is a working version of your code:
I'm trying to use Loki new Recording Rules without alerting.
What is not clear to me is where would the result of the rule evaluation be available?
Can the ruler be scraped for the metrics values or they have to be pushed to something like Prometheus Pushgateway?...
ANSWERAnswered 2021-Sep-27 at 16:51
Accordingly, to the Loki documentation, metrics must be pushed to Prometheus, Cortex, or Thanos:
With recording rules, you can run these metric queries continually on an interval and have the resulting metrics written to a Prometheus-compatible remote-write endpoint. They produce Prometheus metrics from log entries.
At the time of writing, these are the compatible backends that support this:
- Prometheus (>=v2.25.0)
- Thanos (Receiver)
I have the following dataframe (a smaller sample):...
ANSWERAnswered 2021-Sep-16 at 17:01
We need to
replicate by the
lengths of the
list element for 'Date' and 'Signs'
We've got a frame div that acts as scrollbox for a "canvas" div of arbitrary size (not an actual canvas element, it may be anything, e.g. a div with an image inside). Inside that frame div, two rulers should be tacked to the left and bottom border, and those rulers should scroll with the canvas: the left ruler should scroll vertically with the canvas and the bottom ruler should scroll horizontally with the canvas, but both should stay tacked at their respective frame border.
Our approach until now works, IF the canvas and left ruler is higher than the frame:...
ANSWERAnswered 2021-Sep-02 at 08:30
When the bottom ruler is not at the bottom (i.e. not in its stuck position) it has the equivalent of position relative. The canvas has position absolute so does not influence this but the left ruler has position sticky. This means its height influences where the following element is positioned.
One way to get the bottom ruler properly positioned is to make it be in its stuck position from the start. When the canvas height is greater than the frame height this happens, as the first snippet in the question shows. When the canvas (and therefore the left ruler which has the same height) is shorter than the frame the bottom ruler is placed immediately below it.
If we make the left ruler have the same height as the frame then the bottom ruler will always be in its stuck position. We still need the left ruler to only show its 'markings' (the linear gradient in this example) for just the height of the canvas. This snippet does this by setting the size of the left ruler background accordingly. Click a button to alter canvas height.
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