APIJSON | 🏆 Zero-code , full-featured , strong security ORM library 🚀 | Object-Relational Mapping library
kandi X-RAY | APIJSON Summary
kandi X-RAY | APIJSON Summary
🏆 Zero-code, full-featured, strong security ORM library 🚀 Zero-code for back-end interface and document, and front-end (client) customizes the data and structure returned by JSON. 🏆 A JSON Transmission Protocol and an ORM Library 🚀 provides APIs and Docs without writing any code.
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Top functions reviewed by kandi - BETA
- new sql config
- perform execution
- On join request .
- Parses the given entry .
- verify use role
- Parse function .
- Put value .
- Format key .
- isIDCard boolean
- check if obj is a json object
APIJSON Key Features
APIJSON Examples and Code Snippets
Community Discussions
Trending Discussions on APIJSON
QUESTION
I have 2 view models TransferViewModel which has the respective TransferViewController for making Local Transactions from a model LocalTransactionRequest and i have BankTransferViewModel which has a model BankTransactionsRequest, the first one is working but the second one is not, both view controllers are supposed to perform segue to another view controller ConfirmViewController, but the second one (BankTransferViewController) is not working
[This one is TransferViewController][1]
...ANSWER
Answered 2022-Feb-03 at 08:49Make sure the following points are valid for your performSegue
to work in BankTransferViewController:
- The BankTransferViewController has a segue pointing to ConfirmViewController.
- The identifier in your
performSegue(withIdentifier: yourIdentifier, sender: yourModel)
is the exact same identifier as the segue in storyboard that is connecting the two view controllers. - Since you are using it inside the
viewModel.transferRequest.asObservable().subscribe(onNext:
code, make sure you are emmiting a value toviewModel.transferRequest
somewhere in the code. Otherwise,performSegue
will never get called. - Since you have this check
if let bank = bankRequest{
before usingperformSegue
, make sure the transferRequest value you emmit is not nil.
QUESTION
I have been using this below code which converts the data into Json format then post/add to API end points.
But its not working, there is no error occurs. But data is not sent to API. your help will be much appreciated.
I really do not know where the mistake is occurs it converts the data well into json but why it does not post to API. and API response comes empty when see.
...ANSWER
Answered 2021-Aug-03 at 16:58Based on the JSON sample, it seems that the API only accept 1 row of data at a time so you will have to build a JSON string and send to the API one row at a time.
- Since the sample JSON does not have a
[]
bracket at the start and end so you need to remove it. sku
,uniqueID
andepid
values are using a numeric value which are not enclosed with" "
so you will need to remove them as well.
I have modify your code (or mine?) to produce the required format. Running ConvertAndSend
will now build a JSON string for a row then send it to the API in a loop.
QUESTION
I have following JSON object which is dynamically created and can contain special characters in the names e.g. O'Brian in Last Name and special characters in Notes.
...ANSWER
Answered 2021-May-01 at 08:45Change
ConvertTo-Json
toConvertFrom-Json
- You want to convert the json to an object which can be converted into html tableAdd the
-Fragment
switch to theConvertTo-Html
in order to generate only the HTML table
_
QUESTION
I have a UITableView with the cells contain customized layers like shadows, drawing lines and corner radiuses. I have done the design through Storyboard using Autolayout in IPhone SE view size.
The problem is when first initialize of UITableView it show like this (which is not should be) :
However, when scrolling to bottom, it shows as what it should be, like this:
I have done so many things to make it updated such as:
...ANSWER
Answered 2020-Apr-03 at 01:23Bingo! I have spent hours to fix on this thing, I have been silly as I missed on this important thing, that I simply need to put on this code:
QUESTION
I already have a Json value got from calling an API, I want to add a new Json List to the exiting Property, So
...ANSWER
Answered 2020-Mar-26 at 16:00This is for when you are adding Strength
as a property to an existing single object (converted from JSON). When using Add-Member
, you need to force your new object to be a single array object.
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install APIJSON
You can use APIJSON like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the APIJSON component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .
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