EntityGraph | Example Spring Boot REST app | Object-Relational Mapping library
kandi X-RAY | EntityGraph Summary
kandi X-RAY | EntityGraph Summary
Example project for Spring Boot that uses JPA/Hibernate for querying data from database, exposed REST API that returns data querying for data structure:.
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Top functions reviewed by kandi - BETA
- Retrieves the company with the given company
- Returns the company with the given company
- Returns the company with the given ID
- Returns a company with the given ID
- Returns the Company with the given ID
- Returns the company with the given id
- Returns the company with the given company id
- Entry point for the application
- Retrieve a Company
- Get the details of a company
- Get information about a company
- Get the details of a company
EntityGraph Key Features
EntityGraph Examples and Code Snippets
Community Discussions
Trending Discussions on EntityGraph
QUESTION
Message Could not write JSON: failed to lazily initialize a collection of role: core.domain.Cat.catFoods, could not initialize proxy - no Session; nested exception is com.fasterxml.jackson.databind.JsonMappingException: failed to lazily initialize a collection of role: core.domain.Cat.catFoods, could not initialize proxy - no Session (through reference chain: web.dto.ToysDTO["toys"]->java.util.HashSet[0]->web.dto.ToyDTO["cat"]->core.domain.Cat["catFoods"])
Description The server encountered an unexpected condition that prevented it from fulfilling the request.
...ANSWER
Answered 2021-May-18 at 08:00In your Toy
class you are using @EqualsAndHashCode
which will be resolved in an hashCode()
implementation calculating the hashCode based on all properties of that class.
That means that the hashCode method in your Toy
class invokes the hasCode
method on Cat
. In cat there is a Set
of CatFoods
which is mapped by Cat
which means that to calculate the hashCode
of catFoods
the Cat
property is involved. To calculate the hashCode of Cat it begins again calculating the hashCode
of the Set
of CatFoods
(Sounds confusing but currently I am unable to describe it better)
As there is no session active the Lazy collection can not be fetched which is required to calculate the hashCod. Thats why you get this exception.
Takeaway: explicitly exclude LAZY
fetched properties from @EqualsAndHashCode
calculation. You can annotate these properties using @EqualsAndHashCode.Exclude
to exclude them from the hashCode calculation.
To see implementation of the hashCode calculation you can use the DeLombok functionality of IntelliJ.
QUESTION
I'm new to Spring Boot and I just started using graphql-spqr for Spring Boot since it allows for easy bootstrapping of Java projects.
However, as per my understanding, GraphQL basically allows the fetching of selected fields from the database. As per the examples, I've seen, this type of selection in the graphql-spqr library happens on the client side. Is there a way to do selection both client-side and server-side so as to speed up the queries?
I've looked into EntityGraph exmaples for GraphQL but they are mostly implemented for complex quieres that involve JOINs. However, nothing exists for simple queries like findAll(), findById() etc.
I would like to use findAll() with the server fetching only the fields as requested by the client. How can I do that?
...ANSWER
Answered 2021-Apr-19 at 08:49What was said in the comments is correct: GraphQL (and hence SPQR, as it's merely a tool to hook the schema up) does not know anything about SQL, databases, JOINs or anything else. It's a communication protocol, the rest is up to you. As for your situation, you'd have to inject the subselection into the resolver and pass it down to SQL. In the simplest case, it can look like this (in pseudo code):
QUESTION
I have a development project using Spring Data JPA and MapStruct to map between Entities and DTOs. Last week I decided it was time to address the FetchType.EAGER
vs LAZY
issue I have postponed for some time. I choose to use @NamedEntityGraph
and @EntityGraph
to load properties when needed. However I am stuck with this LazyInitializationExeption
problem when doing the mapping from entity to dto. I think I know where this happens but I do not know how to get passed it.
The code
...ANSWER
Answered 2021-Apr-12 at 13:07The problem is that when the code returns from findAll
the entities are not managed anymore. So you have a LazyInitializationException
because you are trying, outside of the scope of the session, to access a collection that hasn't been initialized already.
Adding eager make it works because it makes sure that the collection has been already initialized.
You have two alternatives:
- Using an
EAGER
fetch; - Make sure that the entities are still managed when you return from the
findAll
. Adding a@Transactional
to the method should work:
QUESTION
I'm trying to use EntityGraphs or JPQL to create 1 select instead of many small (sub) selects. However, there sub entities are loaded in extra selects. Example:
...ANSWER
Answered 2021-Mar-26 at 13:42EclipseLink you'll notice always does an extra query for any relationship mapping unless you specify a fetchJoin annotation (or query hint, or modify the mapping with customizers) that tells it what to do, and this is independent of the relationship being eager or lazily fetched. Hibernate on the other hand interprets all eager access to use join. No point debating which is better - they are situational and there are good reasons to go with either solution as a generic one.
This means that if you want a join with EclipseLink on the fly, you'll have to do more than just indicate the relationship needs to be eagerly fetched, and include in query hints. If you are going with fetch graphs to optimize things, it might be a helpful to look into the other fetch types, such as batch fetching. An extra query/statement isn't always a bad thing for performance, especially as object graphs grow. The database is going to be forced to return N*M duplicate rows of Foo data, one for each Bar and FooBar combination in the results. Depending on the data size, there will be a point where it is more efficient to get the children in separate queries.
QUESTION
I am trying to use the same query more than once, with different options set by annotations. Similar to:
...ANSWER
Answered 2021-Feb-01 at 08:54You can use EntityGraphJpaSpecificationExecutor
to pass different entitygraph
based on your method.
QUESTION
I have an entity, which has multiple(lets say more than 5) fields in it. I want to list only 2 of the fields in entity. I managed to do it with Entity Manager and JPA Query. In the code below, I added how I did it with entity manager, but it may not be optimal solution. What I want to ask is, can I do that with using the EntityGraph?
...ANSWER
Answered 2021-Mar-01 at 11:39as far as I know, entity graphs define which attributes to fetch from the database so you can fetch the 2 attributes eagerly and the other 3 lazily, "Thorben Janssen" has a good article on his website about graphs, another way to exclusively fetch selected attributes is to use DTO Projections, he also does have a good article touching the subject.
QUESTION
I have the following entities
RegisteredProgram
...ANSWER
Answered 2021-Jan-19 at 23:27The regular fix for solving MultipleBagFetchException
is change List
typed fields on Set
typed, like this:
QUESTION
I'm using hibernate 5.3.14 with hazelcast 3.11.5 as L2 cache provider and spring boot 2.1.11.
I have 3 entities defined with relations:
- one order has many order items
- one order has many custom fields L2 cache is enabled for entities, associations and queries.
ANSWER
Answered 2021-Jan-13 at 09:41That's a known issue and I think Hibernate 6.0 will fix it, but I don't remember if there ever was a ticket for this.
QUESTION
I have a Person entity with a @ManyToOne self-relationship named "manager". In most cases, I do not need to know the Person's manager, so I've marked the relationship with Fetch.LAZY. However, in every case where I retrieve an entity with a Person field, JPA (with Hibernate Provider) loads the referenced Person...and that person's manager...and that person's manager, and so on recursively, until the entire management chain is loaded. All those queries are executed before TypedQuery.getResultList() returns control to my code, so it's not a matter of me inadvertently referencing the manager somewhere in the session and triggering a true lazy load. It appears the JPA fetch plan has determined that the whole management chain is necessary for some reason and loads them all.
I'm using JPA persistence-api 2.2 and hibernate-core 5.4.20
Here's an abbreviation of the Person class:
...ANSWER
Answered 2020-Dec-03 at 10:03This could be an issue with the id class support or your use of @JoinFormula
. Try using embeddable ids instead:
QUESTION
I have two entities joined by a bidirectional OneToOne-association like this:
...ANSWER
Answered 2020-Dec-15 at 15:07This will be the case with @OneToOne mapping. I have been there, done that. To get past through that you would have to implement bytecode enhancement on Hibernate dirty checking mechanism and change parent side not to use proxy (annotation : @LazyToOne(LazyToOneOption.NO_PROXY)).
Please refer to Vlad Mihalcea's article describing exactly your case I think
In that article you will also find a link to anothere useful Vlad's article - an information how to implement the bytecode enhancement
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install EntityGraph
You can use EntityGraph like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the EntityGraph component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .
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