java-sdk | Binance Chain Java SDK works | Cryptocurrency library
kandi X-RAY | java-sdk Summary
kandi X-RAY | java-sdk Summary
The Binance Chain Java SDK works as a lightweight Java library for interacting with the Binance Chain. It provides a complete API coverage, and supports synchronous and asynchronous requests. It includes the following core components:.
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Top functions reviewed by kandi - BETA
- Decodes the payload
- Decodes an object into an object
- Decodes the given byte array
- Decodes an array of objects into a list of objects
- Get transaction
- Gets the index of the start index
- Fill tags and attributes
- Retrieves the proposal with the given ID
- Build WS request string
- Retrieve all fields
- Returns the account for the given address
- Gets the fee
- Get MiniTokenInfo by symbol
- Retrieves token info by symbol
- Retrieves a block by its height
- Decodes the cross - stake failed event
- Send a message to websocket
- Deserialize an order book entry
- Queries a proposal by its ID
- Overrides superclass method
- Search for transactions in the database
- Gets a proposal by ID
- Get a swap by ID
- Serializes the value of the integer
- Returns transaction by hash
- Convert a transaction to a transaction
java-sdk Key Features
java-sdk Examples and Code Snippets
Community Discussions
Trending Discussions on java-sdk
QUESTION
I am reading from a DynamoDB table in form of Map. The record looks something like this :-
...ANSWER
Answered 2022-Mar-24 at 07:33I used RecordMapper to serialise the value. https://github.com/awslabs/dynamodb-streams-kinesis-adapter/blob/master/src/main/java/com/amazonaws/services/dynamodbv2/streamsadapter/model/RecordObjectMapper.java
QUESTION
I'm using Apache Spark 3.1.0 with Python 3.9.6. I'm trying to read csv file from AWS S3 bucket something like this:
...ANSWER
Answered 2021-Aug-25 at 11:11You need to use hadoop-aws
version 3.2.0 for spark 3. In --packages
specifying hadoop-aws
library is enough to read files from S3.
QUESTION
I am using Gradle 7.3.3 to build a Spring Boot Application that uses jooq to generate Table, POJO, and Record Classes from a pre-existing database schema. When attempting to upgrade jooqVersion from 3.15.5 to 3.16.0, :generateJooq returns the following error:
...ANSWER
Answered 2022-Feb-02 at 15:35The third party gradle plugin to use for jOOQ code generation isn't ready for jOOQ 3.16 yet. A fix is being discussed here: https://github.com/etiennestuder/gradle-jooq-plugin/pull/208
QUESTION
I'm trying to run spring boot project, but i get this error.
any idea what error is this ?
...ANSWER
Answered 2022-Jan-31 at 14:56You need to add dependency for the jar required by your gradle version. Trying adding this dependency and refreshing your gradle.
implementation group: 'com.amazonaws', name: 'aws-java-sdk-core', version: '1.11.948'
or
QUESTION
We recently upgraded our project from Grails 3 to 5.1.1. Actually, it was not really an upgrade but rather a migration. We ended up creating a fresh project with 5.1.1 and migrated all of our code into it. Everything is currently working with an exception of one warning:
...ANSWER
Answered 2022-Jan-18 at 07:22I managed to get the error to go away. All I needed to do it all the dependency config for the related tasks (in build.gradle):
QUESTION
I have a multimodule Maven project where parent pom is as follows
...ANSWER
Answered 2022-Jan-12 at 10:04You have declared 'org.springframework.boot' as the parent module of both modules. So if some jars and artifacts like 'com.amazonaws' do not exist in 'org.springframework.boot', they won't be resolved in your project. These dependencies are not announced in 'Spring' module in your project and whatever you have declared in it, can be found in 'org.springframework.boot', then resolved. If you do not declare a 'version' tag in your pom, I guess the version of the parent (here 2.6.1) will be considered for your module version.
QUESTION
In my java application I need to write data to S3, which I don't know the size in advance and sizes are usually big so as recommend in the AWS S3 documentation I am using the Using the Java AWS SDKs (low-level-level API) to write data to the s3 bucket.
In my application I provide S3BufferedOutputStream
which is an implementation OutputStream
where other classes in the app can use this stream to write to the s3 bucket.
I store the data in a buffer and loop and once the data is bigger than bucket size I upload data in the buffer as a a single UploadPartRequest
Here is the implementation of the write method of S3BufferedOutputStream
ANSWER
Answered 2022-Jan-05 at 15:03You should look at using the AWS SDK for Java V2. You are referencing V1, not the newest Amazon S3 Java API. If you are not familiar with V2, start here:
Get started with the AWS SDK for Java 2.x
To perform Async operations via the Amazon S3 Java API, you use S3AsyncClient.
Now to learn how to upload an object using this client, see this code example:
QUESTION
Things worked fine in 2021.2 but when same project opened in 2021.3 then stated to got following error
...ANSWER
Answered 2021-Dec-06 at 11:192021.3 IDE version has updated the version of the bundled Maven to 3.8.1
. In this version, Maven blocks the access to http
repositories by default. Before that, Maven itself has moved from using the http repositories.
So now one needs to explicitly configure Maven to allow http
repositories if they are used in the project. E.g. in settings.xml
add a mirror to your http repository that allows HTTP:
QUESTION
I am trying to implement AWS SQS FIFO queue using spring boot(v2.2.6.RELEASE).
Created a queue, "Testing.fifo" in aws. Left all other fields to default while creating the queue.
My producer and consumer to the queue run on a single service.
code to put messages to queue
...ANSWER
Answered 2021-Dec-03 at 06:47This might help: The message group ID is used for ordering of SQS messages in groups.
So, if you have multiple group IDs like 1 and 2, then within those groups, the SQS messages will always be in order. The ordering will be preserved relative to the group and not the queue as a whole.
This can be used in cases like, if you are sending out events for different user details updates, you would want to group the data for a particular user in order, and at the same time you don't care about the ordering of the queue as a whole. You can then set the group ID as the unique user ID in this case.
If there is no use-case of creating groups, and there is only one group and you want the message order to be preserved as a whole, just use the same groupID for all messages.
more info here: https://docs.aws.amazon.com/AWSSimpleQueueService/latest/SQSDeveloperGuide/using-messagegroupid-property.html
QUESTION
ANSWER
Answered 2021-Nov-19 at 00:36Community Discussions, Code Snippets contain sources that include Stack Exchange Network
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