Rooster | Simple android xmpp chat client source code | Chat library

 by   blikoon Java Version: Current License: No License

kandi X-RAY | Rooster Summary

kandi X-RAY | Rooster Summary

Rooster is a Java library typically used in Messaging, Chat applications. Rooster has no vulnerabilities and it has low support. However Rooster has 2 bugs and it build file is not available. You can download it from GitHub.

Simple android smack xmpp chat client to show the usage of smack.
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            kandi-support Support

              Rooster has a low active ecosystem.
              It has 93 star(s) with 59 fork(s). There are 7 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 1 open issues and 4 have been closed. On average issues are closed in 15 days. There are 1 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of Rooster is current.

            kandi-Quality Quality

              Rooster has 2 bugs (0 blocker, 0 critical, 2 major, 0 minor) and 27 code smells.

            kandi-Security Security

              Rooster has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              Rooster code analysis shows 0 unresolved vulnerabilities.
              There are 2 security hotspots that need review.

            kandi-License License

              Rooster does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
              OutlinedDot
              Without a license, all rights are reserved, and you cannot use the library in your applications.

            kandi-Reuse Reuse

              Rooster releases are not available. You will need to build from source code and install.
              Rooster has no build file. You will be need to create the build yourself to build the component from source.
              Rooster saves you 410 person hours of effort in developing the same functionality from scratch.
              It has 974 lines of code, 56 functions and 20 files.
              It has medium code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed Rooster and discovered the below as its top functions. This is intended to give you an instant insight into Rooster implemented functionality, and help decide if they suit your requirements.
            • Initializes the UI
            • Attempts to register an account
            • Determines if the user has permission to read contacts
            • Saves the user s credentials
            • Initializes the model
            • Get contacts list
            • Get the ContactModel for this context
            • Registers the broadcast
            • Shows the login form and hides the login form
            • Unregister the broadcast receiver
            • Called when the connection is closed
            • Synchronized
            • Called when a connection is closed
            • OnCreateOptions menu
            • Populate with initial contacts
            • Reconnects in the background
            • On reconnection failed
            • Called when a reconnection is successful
            • On create
            • Checks if a service is running
            • Region Service Implementation
            • Stops the container
            • Handles the authenticated session
            • When an option is selected this method is called
            • Registers a receive message
            • Callback when a permissions result has been received
            Get all kandi verified functions for this library.

            Rooster Key Features

            No Key Features are available at this moment for Rooster.

            Rooster Examples and Code Snippets

            No Code Snippets are available at this moment for Rooster.

            Community Discussions

            QUESTION

            Code dosen't give output and keeps running
            Asked 2021-Jun-13 at 15:27

            I wanted to make a code that would give me all the answers to this question

            My code:

            ...

            ANSWER

            Answered 2021-Jun-13 at 15:27

            the loop will never because the ending condition is unreachable due to the list being set empty at the beginning of the loop. just cancel the line where the list is set empty inside the loop and it should work:

            Source https://stackoverflow.com/questions/67953778

            QUESTION

            Hide and show rows on every sheet
            Asked 2021-Feb-16 at 15:12

            I have a script that works fine for a while now for 1 sheet. I'm looking for a way to make it work for all of the sheets. So no restriction to "GetSheetByName". Is this posible?

            Script i'm using right now:

            ...

            ANSWER

            Answered 2021-Feb-16 at 15:12

            You can have it looped on all sheets in your spreadsheet.

            Code:

            Source https://stackoverflow.com/questions/66226789

            QUESTION

            for statement from dictionary, python
            Asked 2021-Jan-22 at 02:06

            Basically, I am new to programming and I sign up for a python course. I receive an exercise asking as follow:

            Build a function that returns, given an arbitrary birth year, the Chinese zodiac sign corresponding to that calendar year. You start from a dictionary of Chinese zodiac signs from 2001-2012 (covering the whole 12-sign cycle)

            So my idea is to create a dictionary,

            ...

            ANSWER

            Answered 2021-Jan-22 at 01:52

            You are on the right track. You can create a dictionary to store the Chinese Zodiac Signs. Since there are 12 of them and to make the math easier, let's get the modulus value of 12 for each year. That makes mod 0 = Monkey,... mod 11 = Goat.

            With that, you can do year % 12 will result with a number that we can use to extract the value from the dictionary d. The way to extract the value from the dictionary is dict[key]. In our case it will be d[0] will give Monkey.

            With that, we can write the program as follows:

            Source https://stackoverflow.com/questions/65838141

            QUESTION

            Is there other way of getting an input like date format?
            Asked 2021-Jan-21 at 17:11

            I was hoping and looking for some other ideas or ways to do this. As you can see, I asked the user for the input which is mmddyyyy (05022001 = May 2, 2001) and used substring in order for me to to take the certain input in the index then parse it. Now, What I want to accomplish is to find another way to do this for example is using the formal date formatter which in my case I didn't use. I think date formatter is alot better than this, but I don't get the idea out of it.

            Here's what I've got so far. Thanks in advance.

            ...

            ANSWER

            Answered 2021-Jan-21 at 17:11

            You should inform the user of what format you expect.

            Take the input string and make a parse attempt. Trap for exception in case of faulty input. No need for you to check the ranges of month and day. LocalDate.parse makes those data entry validation checks for you.

            Source https://stackoverflow.com/questions/65831738

            QUESTION

            Create parent child relation JSON tree
            Asked 2020-Dec-21 at 21:01

            This is my code I have three table posts table, comments table, and likes table. I have a left joined all three tables with postid common in all three tables. I'm getting all data perfectly but I'm getting repeating data of postdata (ex: Postid=1) I don't want that. My problem is getting repeating data of Postdata (ex: Postid=1) I want to make a parent of Postdata where postsdata=1 and I want to insert all data into parent

            ...

            ANSWER

            Answered 2020-Dec-21 at 21:01

            Hmm... At first I thought that your loops were the problem, and you misunderstood the behavior. But then I saw your "i want my output like below", and that didn't made sense, specifically you wanting duplicate likes/comments.

            First, the loops: a for loop and an inner foreach loop. The for loop iterates over the number of results. The inner foreach loop iterates over all the results. So if we have 6 results, instead of only iterating 6 times, we iterate 36 times (6 result count x 6 results).

            We actually need only 1 loop:

            Source https://stackoverflow.com/questions/65396714

            QUESTION

            Search for the shortest way to turn a string to another string one character at a time in a given list
            Asked 2020-Dec-12 at 02:49

            Given a list of strings with the SAME length, search for a way to transform a start string to an end string one character at a time such that every transformed string is still present in the list of strings.

            INPUTS!
            Input starts with T for the number of test cases. Then, in another line comes m asking for the number of strings to put in the list. m lines follow asking for the strings of the same length, and then, the last line consists start and end separated by a space.

            Example:

            ...

            ANSWER

            Answered 2020-Dec-11 at 14:01

            Here's a suggestion in case you haven't found a solution:

            Source https://stackoverflow.com/questions/65202729

            QUESTION

            Checks for a Path in a List of Strings Given a Starting and Ending Point
            Asked 2020-Dec-07 at 11:02

            We are tasked to create a program that will check if there is a possible way of going from a starting string to an end string, given a list of strings with the same length. There is a catch, we can only go from the current string to the adjacent string if both strings only have one character that is different. If there is no possible path from the starting string to the end string, just print not possible but if there is, output the number of steps from the start to end.

            ...

            ANSWER

            Answered 2020-Dec-04 at 08:24

            I hope that looks better:

            Source https://stackoverflow.com/questions/65121960

            QUESTION

            How to display an image from input text in HTML JavaScript?
            Asked 2020-Sep-11 at 19:59

            I need to display a picture of a duck on my webpage when the user types in "show duck image" in the text field and clicks a button "Execute command".

            The text field has numerous commands, hence the 'else if' statements. Here is what I have so far, when I trial the duck command, no image is displayed. Any help would be greatly appreciated!

            ...

            ANSWER

            Answered 2020-Sep-11 at 17:39

            You should use a element to display images.

            Source https://stackoverflow.com/questions/63851815

            QUESTION

            Simple HTML DOM returning underscores
            Asked 2020-Aug-26 at 15:32

            Alright, i am using Simple HTML DOM (https://simplehtmldom.sourceforge.io/) to get some data from a page.

            The data i would like to get are these selector options:

            ...

            ANSWER

            Answered 2020-Aug-26 at 15:32

            Your code is correct but data is not there.

            Please look at source of your page. Not in inspector but just raw source that is coming to your browser at first. In chrome you can do this with ctrl + u on windows (view source). This way you will see that page that you are requesting doesn't contain any values in html select item when it comes to the browser. This values are populated later with javascript functions but unfortunately Simple HTML DOM doesn't run javascript so scraping it is not possible with this library.

            You need to look for something that can run javascript. Probably some headless browser would be an option. If you need to stick with PHP you can start by looking here: https://github.com/symfony/panther or here: https://github.com/php-webdriver/php-webdriver

            Source https://stackoverflow.com/questions/63599826

            QUESTION

            How to read incoming MMS and SMS messages on Android
            Asked 2020-Jul-31 at 17:36

            I know this is a big topic, as seen here and here, so I just wanted to post how I solved both the issue of receiving incoming MMS and SMS messages and the issue of grabbing data from those MMS and SMS messages on Android 9.0 version 28+ using Xamarin.Forms. This code can easily be translated to Java. Here is the completed Android app so you can try it yourself. It also shows how to do some Azure machine learning if you're interested in that.

            For Broadcast Receivers: Classes, registering class instances , permissions needed.

            Note that the broadcast receivers were added dynamically, they can be added statically using Xamarin's intent-filter decorator , or (if you're not using Xamarin) the AndroidManifest.xml file.

            ...

            ANSWER

            Answered 2020-Jul-31 at 14:57

            Here is a code snippet to show how to parse incoming SMS data with a Broadcast Receiver:

            Source https://stackoverflow.com/questions/63194135

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install Rooster

            You can download it from GitHub.
            You can use Rooster like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the Rooster component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .

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