Cleaner | storage saving app | Database library
kandi X-RAY | Cleaner Summary
kandi X-RAY | Cleaner Summary
Android has existed for a long time. There have been good phones and bad phones, with good software and bad software. Eventually someone somewhere decided that it would be a good idea to make an app that helps your phone run faster by stopping all unnecessary processes and cleaning all unneeded cache files. Whether this was necessary at the time is debatable, but these types of apps gained a massive amount of popularity extremely quickly. If a user didn't like the performance of their Android phone, they could download this app and 'make it faster' again. Over time, a few large companies started to realize that this idea could be monetized. They essentially decided to profit off the failure of Android. Ignorant users wanting to make their phones run as fast as possible would download these apps and get bombarded with advertisments, questionable privacy policies, and possibly even harmful malware. Fast forward to today. With the release of recent versions of Android such as Marshmallow or Nougat, battery draining apps are now uncommon, low storage space is rare, and frame skips are almost unheard of. With software this optimized, deleted cache files will only need to be recreated. Stopped processes will only be started again a few minutes later. The only thing an app can do to improve performance is to shut itself down when the user leaves, and only start running again when absolutely necessary. However, people still download battery savers that don't save battery life. People keep using space savers that don't save them storage space.
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Top functions reviewed by kandi - BETA
- Renders the rectangle
- Convert a drawable to a bitmap
- Get a bitmap for a drawable resource
- Initializes the activity
- Start a touch event
Cleaner Key Features
Cleaner Examples and Code Snippets
Community Discussions
Trending Discussions on Cleaner
QUESTION
I wanted to insert my data to a specific sheet name based on form input value of "svdate":
...ANSWER
Answered 2021-Jun-16 at 02:12I thought that in your situation, it is required to retrieve 6/17
from 06/17/2021
. For this, how about the following modification?
In this case, please modify doPost
as follows.
QUESTION
I'm normally OK on the joining and appending front, but this one has got me stumped.
I've got one dataframe with only one row in it. I have another with multiple rows. I want to append the value from one of the columns of my first dataframe to every row of my second.
df1:
id Value 1 worddf2:
id data 1 a 2 b 3 cOutput I'm seeking:
df2
id data Value 1 a word 2 b word 3 c wordI figured that this was along the right lines, but it listed out NaN for all rows:
...ANSWER
Answered 2021-Jun-15 at 23:59Just get the first element in the value column of df1 and assign it to value column of df2
QUESTION
I have dataflow pipeline, it's in Python and this is what it is doing:
Read Message from PubSub. Messages are zipped protocol buffer. One Message receive on a PubSub contain multiple type of messages. See the protocol parent's message specification below:
...
ANSWER
Answered 2021-Apr-16 at 18:49How about using TaggedOutput.
QUESTION
I need a way to force the compaction of the __consumer_offsets topic. In a test environment I tried to delete the file cleaner-offset-checkpoint and then kafka deleted many segments as you can see below. Is it safe to delete this file in a production environment?
Before removing cleaner-offset-checkpoint:
...ANSWER
Answered 2021-Jun-15 at 13:24cleaner-offset-checkpoint
is in kafka logs directory. This file keeps the last cleaned offset
of the topic partitions in the broker like below.
QUESTION
I have the following problem and I am wondering if there is a faster and cleaner implementation of the removeLastChar()
function. Specifically, if one can already remove the last vowel without having to find the corresponding index first.
PROBLEM
Write a function that removes the last vowel in each word in a sentence.
Examples:
removeLastVowel("Those who dare to fail miserably can achieve greatly.")
"Thos wh dar t fal miserbly cn achiev gretly."
removeLastVowel("Love is a serious mental disease.")
"Lov s serios mentl diseas"
removeLastVowel("Get busy living or get busy dying.")
"Gt bsy livng r gt bsy dyng"
Notes: Vowels are: a, e, i, o, u (both upper and lowercase).
MY SOLUTION
A PSEUDOCODE
- Decompose the sentence
- For each word find the index of the last vowel
- Then remove it and make the new "word"
- Concatenate all the words
CODE
...ANSWER
Answered 2021-Jun-14 at 22:49This can be more easily achieved with a regex substitution that removes a vowel that's followed by zero or more consonants up to a word boundary:
QUESTION
I have a nested object as follows.
I am looking to remove the img property from it.
ANSWER
Answered 2021-Jun-14 at 17:17You're looking for the delete
operator.
delete myOriginalObject.props.data.img;
QUESTION
I notices that in __consumer_offsets topic there are many tombstone even if I have set log.cleaner.delete.retention.ms = 0
...ANSWER
Answered 2021-Jun-14 at 11:56To tomstone a message after compacted, current time - compacted time
should be grater than delete.retention.ms
. It is defaulted by broker config log.cleaner.delete.retention.ms
. So in your case it is zero. But this is applied for compacted logs.
But to compact kafka messages in logs, not compacted / compacted + not compacted
ratio it is called dirty ratio
should be greater than config min.cleanable.dirty.ratio
, defaul = is 0.5
. Active segment is not considered for this calculations.
So in your scenario, they are not still compacted. That is why they are remaining in the topic.
For more info about compaction and tombstone refer this
QUESTION
Recently I've been doing some CP stuff and grew bored of using cin
in C++.
So I thought I could at least create a cleaner input function.
So I'm stuck here.
...ANSWER
Answered 2021-Jun-13 at 21:06You need to take your arguments by reference.
QUESTION
I have a variable friendsList
that is passed to the FriendsFeed class. I reference the friendsList
in the FriendsFeed State with widget.friendsList
. Is using widget.[my_variable_name]
to reference StatefulWidget variables the professional way to do so? I can't help but feel like there's a cleaner way to do so.
ANSWER
Answered 2021-Jun-13 at 19:05Yeah, it is. But there are still ways you can make it cleaner.
One way is creating a final variable inside the build method or as a final field in your app, say "friendList" and you assign it a the value "widget.friendsList". You can now continue to use the var "friendList" anywhere in the build function or in your app (depending on where you declared it).
So, since from your code it seems you want to be able re-order/re-arrange the items in the list which means being able to modify the list, I will suggest you create a field in your state class like so:
QUESTION
So, I have a fun issue. I have some data that have a fun nested dictionary that I need to manipulate, but am having trouble. I can do it in pure python, but wanted to do the entire solution in Pandas so as to keep the code a little cleaner and not have to re-open the same files elsewhere.
Dataframe:
...ANSWER
Answered 2021-Jun-13 at 17:17One way:
- Create another
list of dict
viato_dict('records')
. zip
anditerate
over both thelist of dict
.Update
the 1st one with the other to get the desiredJSON
.
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No vulnerabilities reported
Install Cleaner
You can use Cleaner like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the Cleaner component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .
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