Look-Around | a Application name LookAround run in Android Platinum
kandi X-RAY | Look-Around Summary
kandi X-RAY | Look-Around Summary
a Application name LookAround run in Android Platinum. ##Preview ![github] "github") ![github] "github"). ##APK DOWNLOAD * [LookAround.apk] ###UI * [Glide] * [PhotoView] * [satellite-menu] * [SwitchButton] ###AOSP and so on. ##Run requirements Android OS 5.0 and up Tested with: Samsung, HTC, HuaWei Phone and so on….
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Top functions reviewed by kandi - BETA
- Copy a file
- Delete a directory
- OnClick method
- Cleans the disk cache
- Sends a response to the client
- Parses a JSON result
- Initialize theatelliteMenu
- Called when the button is clicked
- Handle message
- Shows a notification
- Handles a touch event
- Starts the animation
- Share a QZone to the QZone
- Share to the app
- Called when a detail item is entered
- Read zip file
- Share to the w friend
- Make a ShareItem to the Tenage
- HTTP POST request
- Handle a platform action
- Read an entity item
- Bind info item
- Bind view data
- Returns MD5 hash of string
- Send request to server
- Initialize the view
Look-Around Key Features
Look-Around Examples and Code Snippets
Community Discussions
Trending Discussions on Look-Around
QUESTION
I need a regex that replaces the pieces of a URI that would create a high cardinality situation.
Basically if the segment of a URI contains any non a-zA-Z
characters (other than /
), replace it with an *
Example:
...ANSWER
Answered 2022-Feb-07 at 21:38For the example data, you might use
QUESTION
I need to match a string that start end end with a specific string like [#start,
and ,#end]
. I use for that the regex /\[#start,(.*?),#end\]/g
:
ANSWER
Answered 2021-Jun-23 at 19:52You may use this regex:
QUESTION
Note:
The observed behavior is correct, but may at first be surprising; it was to me, and I think it may be to others as well - though probably not to those intimately familiar with regex engines.
The repeatedly suggested duplicate, Regex lookahead, lookbehind and atomic groups, contains general information about look-around assertions, but does not address the specific misconception at hand, as discussed in more detail in the comments below.
Using a greedy, by definition variable-width subexpression inside a positive look-behind assertion can exhibit surprising behavior.
The examples use PowerShell for convenience, but the behavior applies to the .NET regex engine in general:
This command works as I intuitively expect:
...ANSWER
Answered 2021-Mar-03 at 16:14tl;dr:
- Inside a look-behind assertion, a greedy subexpression in effect behaves non-greedily (in global matching in addition to acting greedily), due to considering every prefix string of the input string.
My problem was that I hadn't considered that, in a look-behind assertion, each and every character position in the input string must be checked for the preceding text up to that point to match the subexpression in the lookbehind assertion.
This, combined with the always-global replacement that PowerShell's -replace
operator performs (that is, all possible matches are performed), resulted in multiple insertions:
That is, the greedy, anchored subexpression ^.+_
legitimately matched twice, when considering the text to the left of the character position currently being considered:
- First, when
a_
was the text to the left. - And again when
a_b_
was the text to the left.
Therefore, two insertions of |
resulted.
By contrast, without a look-behind assertion, greedy expression ^.+_
by definition only matches once, through to the last _
, because it is only applied to the entire input string.
QUESTION
I have a look-ahead regex [^a-z0-9%*][a-z0-9%]{3,}(?=[^a-z0-9%*])
. In my test it extracts 4 substrings from @@||imasdk.googleapis.com/js/core/bridge*.html
:
|imasdk
.googleapis
.com
/core
I need to rewrite it with 2 good-old regexes as i can't use look-aheads (not supported by regex engine). I've split it into [^a-z0-9%*][a-z0-9%]{3,}
and [^a-z0-9%*]
and the latter is checked for each first regex match in the substring after the match.
For some reason it extracts /bridge
too as .
is not listed in [^a-z0-9%*]
and is found after /bridge
. So how does the look-ahead works: does it have to be a full match, a substr (find
result) or anything else? Does it mean every ending char is expected to be not from the set a-z0-9%*
in this case?
In Rust the code looks as follows:
...ANSWER
Answered 2021-Mar-30 at 14:28Your LOOKAHEAD_REGEX
looks for a character not in the range in any position after the match, but the original regex with lookahead only looks at the single character immediately after the match. This is why your code finds /bridge
and regex101 doesn't: your code sees the .
somewhere after the match whereas regex101 only looks at the *
.
You can fix your code by anchoring LOOKAHEAD_REGEX
so that it will only look at the first character: ^[^a-z0-9%*]
.
Aternatively, as suggested by @Sven Marnach, you can use a single regex matching the full expression: [^a-z0-9%*][a-z0-9%]{3,}[^a-z0-9%*]
, and strip the last character of the match.
QUESTION
I have a little problem with this regex crate in rust. I need match all ':word' strings, but not inside the quotes.
Unfortunately, some approaches like this (?!\B"[^"]*)(:[a-zA-Z0-9]{1,})(?![^"]*"\B)
, found here, doesn't work, returning the look-around, including look-ahead and look-behind, is not supported
error.
For now, i can match all ':word' strings using this regex: (:[a-zA-Z0-9]{1,})
ANSWER
Answered 2020-Oct-07 at 03:41I think your problem is beyond the capability of a regex. I think the simplest sound way to approach it is to write a tokenizer to examine all the tokens in the string in order, one at a time.
QUESTION
I am trying to make the following regular expressions to work in sed
command in bash.
ANSWER
Answered 2020-Jun-21 at 09:01If the input file is just a comment followed by a list of URLs, try:
QUESTION
I am trying to capture KEYWORD1 in .NET regex engine based on whether KeyWord2 is present in the string. So far the positive look-around solution I am using:
...ANSWER
Answered 2020-May-19 at 03:47You can use the regex below for your requirement:
QUESTION
I tried to implement this regular expression for checking if a string ("username"
) has a length between 3 and 30, contains only letters (a-z), numbers (0-9), and periods (.) (not consecutive):
ANSWER
Answered 2020-Apr-28 at 20:56The issue at hand is what is meant by "regular expression". Wikipedia has good information on this, but a simple summary is that a regular language is one defined with a few simple operations, including literal matches, alternation, and the Kleene star (match zero or more). Regex libraries have added features that don't extend this language, but make it easier to use (such as being able to say [a-z]
instead of (a|b|c|d|e|f...|z)
).
Then, along came Perl, which implemented support for regular expressions. However, instead of using the commonly used NFA/DFA implementation for regular expressions, it implemented them using backtracking. There are two consequences of this, one, it allowed things beyond regular languages to be added, such as backtracking, and two, it can be really, really slow.
Many languages used these backtracking implementations of regular expressions, but there has been a somewhat recent resurgence of removing the features from the expressions that make them difficult to implement efficiently, specifically backtracking. Go has done this, the Re2 library is a C/C++ implementation of this. And, as you've discovered the regex crate also works this way. The advantage is that it always matches in linear time.
For your particular example, what you are trying to match is indeed still a regular language, it just has to be expressed differently. Let's start with the easy part, matching the characters, but not allowing consecutive dots. Instead of thinking of it this way, think of it as matching possibly a dot between the characters, but the characters themselves aren't options. In other words, we can match with: [a-z0-9](\.?[a-z0-9])*
. We first match a single character. If you want to allow this to start with a dot, you could remove this part. Then we need zero or more occurrences of an optional dot followed by a single non-dot character. You could append a \.?
if you want to allow a dot at the end.
The second requirement, of 3-30 characters would make this regex rather complicated, because our repeated sequence is of 1 or 2 characters. I would suggest, instead, just checking the length programmatically in addition to checking the regex. You could also make a second regex that checks the length, and check that both match (Regular languages do not have an and operation).
You may also find, depending on how your are matching, you may have to anchor the match (putting a ^
at the start and a $
at the end).
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install Look-Around
You can use Look-Around like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the Look-Around component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .
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