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kandi has reviewed auto and discovered the below as its top functions. This is intended to give you an instant insight into auto implemented functionality, and help decide if they suit your requirements.
A collection of source code generators for Java.
License
Copyright 2013 Google LLC
Licensed under the Apache License, Version 2.0 (the "License");
you may not use this file except in compliance with the License.
You may obtain a copy of the License at
http://www.apache.org/licenses/LICENSE-2.0
Unless required by applicable law or agreed to in writing, software
distributed under the License is distributed on an "AS IS" BASIS,
WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
See the License for the specific language governing permissions and
limitations under the License.
Is if(A | B) always faster than if(A || B)?
if (b1[i]) // maybe this exists somewhere in the program
b2 = nullptr;
if(b1[i] || b2[i]) // OK
if(b1[i] | b2[i]) // NOT OK; indirection through null pointer
if(a || (a = b)) // OK
if(a | (a = b)) // NOT OK; undefined behaviour
if(ptr1 || ptr2) // OK
if(ptr1 | ptr2) // NOT OK; no bitwise or for pointers
-----------------------
if (b1[i]) // maybe this exists somewhere in the program
b2 = nullptr;
if(b1[i] || b2[i]) // OK
if(b1[i] | b2[i]) // NOT OK; indirection through null pointer
if(a || (a = b)) // OK
if(a | (a = b)) // NOT OK; undefined behaviour
if(ptr1 || ptr2) // OK
if(ptr1 | ptr2) // NOT OK; no bitwise or for pointers
-----------------------
if (b1[i]) // maybe this exists somewhere in the program
b2 = nullptr;
if(b1[i] || b2[i]) // OK
if(b1[i] | b2[i]) // NOT OK; indirection through null pointer
if(a || (a = b)) // OK
if(a | (a = b)) // NOT OK; undefined behaviour
if(ptr1 || ptr2) // OK
if(ptr1 | ptr2) // NOT OK; no bitwise or for pointers
-----------------------
if (p == NULL || test(*p)) { ... } // null pointer would crash on *p
if (should_skip() || try_update()) { ... } // active use of side effects
-----------------------
x = y+z;
flag1 = (x==0);
... code that uses flag1
x = y+z;
if (processor's Z flag was set)
{
... copy of that uses flag1, but where flag is replaced with constant 1
}
else
{
... copy of that uses flag1, but where flag is replaced with constant 0
}
-----------------------
x = y+z;
flag1 = (x==0);
... code that uses flag1
x = y+z;
if (processor's Z flag was set)
{
... copy of that uses flag1, but where flag is replaced with constant 1
}
else
{
... copy of that uses flag1, but where flag is replaced with constant 0
}
What is the proper evaluation order when assigning a value in a map?
auto size = valMap.size();
valMap[val] = size;
valMap.emplace(val, size);
-----------------------
auto size = valMap.size();
valMap[val] = size;
valMap.emplace(val, size);
Why does the thread sanitizer complain about acquire/release thread fences?
atomic_base.h:133:26: warning: 'atomic_thread_fence' is not supported with '-fsanitize=thread' [-Wtsan]
133 | { __atomic_thread_fence(int(__m)); }
| ~~~~~~~~~~~~~~~~~~~~~^~~~~~~~~~
while (a.load(std::memory_order_relaxed) != from) {}
__tsan_acquire(&a); // <--
std::atomic_thread_fence(std::memory_order_acquire);
-----------------------
atomic_base.h:133:26: warning: 'atomic_thread_fence' is not supported with '-fsanitize=thread' [-Wtsan]
133 | { __atomic_thread_fence(int(__m)); }
| ~~~~~~~~~~~~~~~~~~~~~^~~~~~~~~~
while (a.load(std::memory_order_relaxed) != from) {}
__tsan_acquire(&a); // <--
std::atomic_thread_fence(std::memory_order_acquire);
Why would one want to put a unary plus (+) operator in front of a C++ lambda?
#include <type_traits>
void foo(int);
template<class T>
struct is_foo : std::is_same<T, decltype(&foo)> {};
int main()
{
auto foo1 = +[](int)->void {};
auto foo2 = [](int)->void {};
static_assert(is_foo<decltype(foo1)>::value, "foo1 is not like foo");
static_assert(is_foo<decltype(+foo2)>::value, "+foo2 is not like foo");
static_assert(is_foo<decltype(foo2)>::value, "foo2 is not like foo");
}
-----------------------
template <typename F>
void f(F func) { func(); }
int main()
{
f([](){}); // f<lambda_1>
f([](){}); // f<lambda_2>
f(+[](){}); // f<void(*)()>
f(+[](){}); // f<void(*)()>
}
xcrun: error: SDK "iphoneos" cannot be located
sudo xcode-select --switch /Applications/Xcode.app
Why can't a const mutable lambda with an auto& parameter be invoked?
struct foo {
void operator()(){}
};
int main() {
const foo f;
f();
}
<source>:7:5: error: no matching function for call to object of type 'const foo'
f();
^
<source>:2:10: note: candidate function not viable: 'this' argument has type 'const foo', but method is not marked const
void operator()(){}
^
-----------------------
struct foo {
void operator()(){}
};
int main() {
const foo f;
f();
}
<source>:7:5: error: no matching function for call to object of type 'const foo'
f();
^
<source>:2:10: note: candidate function not viable: 'this' argument has type 'const foo', but method is not marked const
void operator()(){}
^
-----------------------
auto const f3 = [](auto&) mutable {};
static_assert(std::is_invocable_v<decltype(f3), int&>); // failed
auto const f4 = [](int&) mutable {}; // changed auto& to int&
static_assert(std::is_invocable_v<decltype(f4), int&>); // now ok
struct __unique_f4 {
auto operator()(int&) /* not const */ { }
};
struct __unique_f4 {
auto operator()(int&) /* not const */ { }
// conversion function to the appropriate function
// pointer type
operator void(*)(int&)() const { /* ... */ }
};
-----------------------
auto const f3 = [](auto&) mutable {};
static_assert(std::is_invocable_v<decltype(f3), int&>); // failed
auto const f4 = [](int&) mutable {}; // changed auto& to int&
static_assert(std::is_invocable_v<decltype(f4), int&>); // now ok
struct __unique_f4 {
auto operator()(int&) /* not const */ { }
};
struct __unique_f4 {
auto operator()(int&) /* not const */ { }
// conversion function to the appropriate function
// pointer type
operator void(*)(int&)() const { /* ... */ }
};
-----------------------
auto const f3 = [](auto&) mutable {};
static_assert(std::is_invocable_v<decltype(f3), int&>); // failed
auto const f4 = [](int&) mutable {}; // changed auto& to int&
static_assert(std::is_invocable_v<decltype(f4), int&>); // now ok
struct __unique_f4 {
auto operator()(int&) /* not const */ { }
};
struct __unique_f4 {
auto operator()(int&) /* not const */ { }
// conversion function to the appropriate function
// pointer type
operator void(*)(int&)() const { /* ... */ }
};
-----------------------
auto const f3 = [](auto&) mutable {};
static_assert(std::is_invocable_v<decltype(f3), int&>); // failed
auto const f4 = [](int&) mutable {}; // changed auto& to int&
static_assert(std::is_invocable_v<decltype(f4), int&>); // now ok
struct __unique_f4 {
auto operator()(int&) /* not const */ { }
};
struct __unique_f4 {
auto operator()(int&) /* not const */ { }
// conversion function to the appropriate function
// pointer type
operator void(*)(int&)() const { /* ... */ }
};
Passing a C-style array to `span<T>`
template<typename T>
size_t my_size(std::span<T> s)
{
return s.size();
}
prog.cc:18:25: error: no matching function for call to 'my_size(std::array<int, 5>&)'
18 | std::cout << my_size(arr) << my_size(vec) << my_size(il) << my_size(c_arr);
| ~~~~~~~^~~~~
prog.cc:7:8: note: candidate: 'template<class T> size_t my_size(std::span<_Type, 18446744073709551615>)'
7 | size_t my_size(std::span<T> s)
| ^~~~~~~
prog.cc:7:8: note: template argument deduction/substitution failed:
prog.cc:18:25: note: 'std::array<int, 5>' is not derived from 'std::span<_Type, 18446744073709551615>'
18 | std::cout << my_size(arr) << my_size(vec) << my_size(il) << my_size(c_arr);
| ~~~~~~~^~~~~
-----------------------
template<typename T>
size_t my_size(std::span<T> s)
{
return s.size();
}
prog.cc:18:25: error: no matching function for call to 'my_size(std::array<int, 5>&)'
18 | std::cout << my_size(arr) << my_size(vec) << my_size(il) << my_size(c_arr);
| ~~~~~~~^~~~~
prog.cc:7:8: note: candidate: 'template<class T> size_t my_size(std::span<_Type, 18446744073709551615>)'
7 | size_t my_size(std::span<T> s)
| ^~~~~~~
prog.cc:7:8: note: template argument deduction/substitution failed:
prog.cc:18:25: note: 'std::array<int, 5>' is not derived from 'std::span<_Type, 18446744073709551615>'
18 | std::cout << my_size(arr) << my_size(vec) << my_size(il) << my_size(c_arr);
| ~~~~~~~^~~~~
-----------------------
std::cout << getSize(std::span(arr));
std::cout << getSize(std::span(vec.begin(), vec.end()));
std::cout << getSize(std::span(il.begin(), il.end()));
std::cout << getSize(std::span(c_arr));
// For std containers
template<class T>
size_t getSize(T myContainer)
{
return std::span(myContainer.begin(), myContainer.end()).size();
}
// For c-style arrays
template<typename T, int n>
size_t getSize(T (&myArray)[n])
{
return std::span<T>(myArray).size();
}
-----------------------
std::cout << getSize(std::span(arr));
std::cout << getSize(std::span(vec.begin(), vec.end()));
std::cout << getSize(std::span(il.begin(), il.end()));
std::cout << getSize(std::span(c_arr));
// For std containers
template<class T>
size_t getSize(T myContainer)
{
return std::span(myContainer.begin(), myContainer.end()).size();
}
// For c-style arrays
template<typename T, int n>
size_t getSize(T (&myArray)[n])
{
return std::span<T>(myArray).size();
}
Doesn't constraining the "auto" in C++ defeat the purpose of it?
foo f = // ...
foo auto f = // ...
-----------------------
foo f = // ...
foo auto f = // ...
-----------------------
auto fn(auto x) {
return x++;
}
f(std::string("hello"));
error: cannot increment value of type 'std::basic_string<char>'
return x++;
auto fn(std::integral auto x) {
return x++;
}
-----------------------
auto fn(auto x) {
return x++;
}
f(std::string("hello"));
error: cannot increment value of type 'std::basic_string<char>'
return x++;
auto fn(std::integral auto x) {
return x++;
}
-----------------------
auto fn(auto x) {
return x++;
}
f(std::string("hello"));
error: cannot increment value of type 'std::basic_string<char>'
return x++;
auto fn(std::integral auto x) {
return x++;
}
-----------------------
auto fn(auto x) {
return x++;
}
f(std::string("hello"));
error: cannot increment value of type 'std::basic_string<char>'
return x++;
auto fn(std::integral auto x) {
return x++;
}
What is the purpose of `operator auto() = delete` in C++?
auto f() = delete;
A a = b; // error in Clang
auto f() = delete; // never expose a valid overload for f()
// elsewhere:
int f() { return 42; }
// error: functions that differ only in
// their return type cannot be overloaded
struct NoUserDefinedConversionFunctionsAllowed {
operator auto() = delete;
};
struct S : NoUserDefinedConversionFunctionsAllowed {
operator int() { return 1; } // can never be used
};
-----------------------
auto f() = delete;
A a = b; // error in Clang
auto f() = delete; // never expose a valid overload for f()
// elsewhere:
int f() { return 42; }
// error: functions that differ only in
// their return type cannot be overloaded
struct NoUserDefinedConversionFunctionsAllowed {
operator auto() = delete;
};
struct S : NoUserDefinedConversionFunctionsAllowed {
operator int() { return 1; } // can never be used
};
-----------------------
auto f() = delete;
A a = b; // error in Clang
auto f() = delete; // never expose a valid overload for f()
// elsewhere:
int f() { return 42; }
// error: functions that differ only in
// their return type cannot be overloaded
struct NoUserDefinedConversionFunctionsAllowed {
operator auto() = delete;
};
struct S : NoUserDefinedConversionFunctionsAllowed {
operator int() { return 1; } // can never be used
};
-----------------------
auto f() = delete;
A a = b; // error in Clang
auto f() = delete; // never expose a valid overload for f()
// elsewhere:
int f() { return 42; }
// error: functions that differ only in
// their return type cannot be overloaded
struct NoUserDefinedConversionFunctionsAllowed {
operator auto() = delete;
};
struct S : NoUserDefinedConversionFunctionsAllowed {
operator int() { return 1; } // can never be used
};
Why does std::initializer_list in ctor not behave as expected?
auto vTemp = std::vector<int>{};
auto v = std::vector<int>( vTemp );
auto v = std::vector{{std::vector<int>{}}};
auto v = std::vector<std::vector<int>>{ std::vector<int>{} };
-----------------------
auto vTemp = std::vector<int>{};
auto v = std::vector<int>( vTemp );
auto v = std::vector{{std::vector<int>{}}};
auto v = std::vector<std::vector<int>>{ std::vector<int>{} };
-----------------------
template<class T> void f(T x) {
std::vector v{x};
// …
}
QUESTION
How to open emulators in different windows at Android Studio (Bumblebee | 2021.1.1)?
Asked 2022-Feb-22 at 19:06I have two running emulators but they open together in different tabs and in one single window.
How to open them in two different window?
Android Studio Bumblebee | 2021.1.1
Build #AI-211.7628.21.2111.8092744, built on January 19, 2022
Runtime version: 11.0.11+0-b60-7590822 amd64
VM: OpenJDK 64-Bit Server VM by JetBrains s.r.o.
Linux 5.4.0-96-generic
GC: G1 Young Generation, G1 Old Generation
Memory: 3072M
Cores: 12
Registry: external.system.auto.import.disabled=true, debugger.watches.in.variables=false
Non-Bundled Plugins: JUnit4-Parallel-Runner (1.5), com.intellij.javafx (1.0.3), com.intellij.marketplace (211.7628.36), com.atlassian.bitbucket.references (2021.1.195), com.thoughtworks.gauge (211.6693.111), org.jetbrains.kotlin (211-1.6.10-release-923-AS7442.40), com.developerphil.adbidea (1.6.4)
Current Desktop: ubuntu:GNOME
ANSWER
Answered 2022-Feb-17 at 10:47File->Settings->Tools->Emulator, and uncheck Launch in a tool window Then they will open in their own stand alone windows again.
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