JsonView | a json string format view tool | JSON Processing library
kandi X-RAY | JsonView Summary
kandi X-RAY | JsonView Summary
a json string format view tool
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Top functions reviewed by kandi - BETA
- Performs the action
- Start a segment
- And expand the array
- Find tree child value
- Performs the selection
- Copy string key value to string
- Cast a string to string
- Copy node content
- Initialize components
- Format xml
- Translate map string to json string
- This method is used for XML conversion
- Handle tab removal
- Returns the JTree for the given tab data
- Performs an action on the file dialog
- Gets the syntax text area
- Called when the mouse released
- Start the application
- Performs a file dialog
JsonView Key Features
JsonView Examples and Code Snippets
Community Discussions
Trending Discussions on JsonView
QUESTION
I can't output the following json object in the jinja template engine
Abbreviated output:
...ANSWER
Answered 2021-Jun-08 at 08:35Something like this, using a recursive macro, might be closer to what you want, since your structure has both lists (children) and dicts (the objects within).
QUESTION
Good afternoon, I am working with a REST API in which I have a playlist that has many songs, for which I am using JPA and the benefits that allow me to make the relationships between the two. Now, if I want to delete a song already added to the PlayList, I can't do it, I show you my classes below
Class PlayList
...ANSWER
Answered 2021-May-14 at 16:40It is not a very good idea to remove a song using all the songs list in the PlayList.
There is not a join table for @OneToMany association. So we can delete a song much simpler, using SONG table (this is the main reason why a join table for @OneToMany is not convienent).
You need a song id for that and you need to use CrudRepository.deleteById() method.
You can use the full combination (title, artist, album, year) for that, but much simpler to add a song id to JSON.
Better to use this endpoint URL to delete a song
/{playListId}/songs/{songId}
You don't need delete part in the URL, you already use DELETE HTTP method.
Why your code doesn't work
- Incorrect using delete method from the list
QUESTION
I have 4 Tables: Table1, Table2, Table3, Table4.
- Table1 has a many to one relation to Table2
- Table2 has a many to one relation to Table3
- Table3 has a one to many relation to Table4
My intent is that Table1 will have a many-to-many member to Table4. That is, Table1 will have a List member of Table4's
...ANSWER
Answered 2021-Apr-30 at 09:06Why not just have a getter method that returns your list of Table4, like bellow? You already have all the mappings in place.
QUESTION
I am trying to find a way to put a calculated field within a JPQL query to map to an entity in Spring Boot.
The example I have just lists a static number, but I am intending it's use to also be used for aggregates as well in the future.
...ANSWER
Answered 2021-Apr-29 at 21:47I think you need to use a formula
QUESTION
I have an error when start my Spring Boot Application: java.lang.IllegalStateException: Expected to be able to resolve a type but got null! This usually stems from types implementing raw Map or Collection interfaces!
I created two tables via sql query:
...ANSWER
Answered 2021-Apr-26 at 06:24JSONB is not directly supported by Hibernate.
You have to use a converter.
There is a collection of converters in Hibernate Types project: https://github.com/vladmihalcea/hibernate-types
QUESTION
I am building a sample app for JSON tutorial. After posting JSON object (description and date), an ID should be auto generated in the database. How can I get this ID as the only field in the JSON response?
...ANSWER
Answered 2021-Apr-21 at 10:27if you are using Entity class then id column in you entity should have this line
@GeneratedValue(strategy = GenerationType.IDENTITY)
and when you save your Entity class in database .save will return the saved entity which contain the newly generated id
entity = repository.save(entity);
and then you can get the id of the data saved in database
entity.getId()
you can create another pojo class only with id vaiable with getter setter and return the instance of your pojo
QUESTION
I have a school assignment (intro to python so I am very much beginning my coding journey) I am looking for a more elegant way and not hardcoded way to solve the problem I was given.
The problem: I have a list of Nobel prizes winner and I need to count how many laureates there is in total for each category from a JSON file. So, I need to count nested JSON objects from nested arrays.
JSON link: http://api.nobelprize.org/v1/prize.json
JSON viewer: http://jsonviewer.stack.hu/
My code currently gives me the correct output, but it's hardcoded. Let's say that I have to re-do the assignment in X years and there's a new category of Nobel prizes, my program won't be able to catch it. I understand that I'll have to create a loop and that's where I am struggling... I am unsure how to create one from the set category_count since indexing is not possible in a set.
ANSWER
Answered 2021-Apr-08 at 18:41What you could do is use a collections.defaultdict and create a dictionary of all categories and keep adding up the total number of winners, if there were any.
For example:
QUESTION
I'm new to neo4j. From what I've read so far I understand that it's generally bad practise to use the default parameter externally of my app. I'd therefore like to be able to specify my own personId parameter separate of . To do this, I'd like to use neo4j-ogm, however I'm getting this exception:
ANSWER
Answered 2021-Mar-31 at 04:34It is possible that you are mixing the earlier neo4j-ogm with the latest Spring Data Neo4j
Check your dependencies and make sure your annotations are from the correct packages (for instance, org.springframework.data.neo4j.*)
If you follow the instructions in the link above, you should be able to resolve your errors.
QUESTION
ANSWER
Answered 2021-Jan-10 at 03:49The reason why you are getting objects is because the current procedure is creating nested t lists. You can see the output here: https://codesandbox.io/s/youthful-sunset-ru8ic?file=/src/Old.tsx
An alternative, working approach:
QUESTION
Exception handler is returning 200 response even though I have specified it to return 500 in the handler (HttpStatus.INTERNAL_SERVER_ERROR) when encountering this exception.
I am using Spring Boot v1.5.4.RELEASE.
I am calling a Spring Boot service returning a JSON object. I am using a custom exception handler.
When an EntityNotFoundException occurs during deserialization, instead of returning 500 response, it returns 200 response and embeds the error in the body output. This is caused by a data error where a ManyToOne relationship not being found in Database because the foreign key is invalid.
Note that I am using a native query to pull the entities.
...ANSWER
Answered 2020-Oct-22 at 05:35I wonder if your request is being handled by the same exception handler.
You have set the user message to the "Data issue" but whereas your output response is showing it as null.
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install JsonView
You can use JsonView like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the JsonView component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .
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