jpa | JPA全称Java Persistence API.JPA通过JDK | Object-Relational Mapping library

 by   je-ge Java Version: Current License: No License

kandi X-RAY | jpa Summary

kandi X-RAY | jpa Summary

jpa is a Java library typically used in Utilities, Object-Relational Mapping, Hibernate, JPA applications. jpa has no bugs, it has no vulnerabilities, it has build file available and it has high support. You can download it from GitHub.

我的博客 ##jpa-single-table 单表操作 ##jpa-one-way-many2one 单向多对一操作 ##jpa-one-way-one2many 单向一对多操作 ##jpa-two-way-one2many 双向一对多操作 ##jpa-one-way-many2many 单向多对多操作 ##jpa-two-way-many2many 双向多对多操作 ##jpa-one2one-primary-key 双向一对一共享主键操作 ##jpa-one2one-foreign-key 双向一对一唯一外键操作 ##jpa-one2one-join-table 双向一对一连接表操作 ##jpa-composite-id 复合主键-2个@Id操作 ##jpa-composite-id-class 复合主键-2个@Id+@IdClass操作 ##jpa-embedded-id 复合主键-@EmbeddedId+@Embeddable操作 ##jpa-embedded-id 自定义类型-@Embedded+@Embeddable操作 ##jpa-extents-single-table 继承-一个表-SINGLE_TABLE操作 ##jpa-extents-joined 继承-联合子类-JOINED操作 ##jpa-extents-table-per-class 继承-独立表-TABLE_PER_CLASS操作 ##jpa-first-last-name 自动把firstName+lastName合并为name字段操作 ##jpa-primary-jpa-uuid jpa-uuid主键生成策略操作 ##jpa2-element-collection-table JPA2.0-@CollectionTable操作.
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            kandi-support Support

              jpa has a highly active ecosystem.
              It has 61 star(s) with 33 fork(s). There are 3 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              jpa has no issues reported. There are no pull requests.
              It has a positive sentiment in the developer community.
              The latest version of jpa is current.

            kandi-Quality Quality

              jpa has 0 bugs and 0 code smells.

            kandi-Security Security

              jpa has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              jpa code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              jpa does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
              OutlinedDot
              Without a license, all rights are reserved, and you cannot use the library in your applications.

            kandi-Reuse Reuse

              jpa releases are not available. You will need to build from source code and install.
              Build file is available. You can build the component from source.
              jpa saves you 1870 person hours of effort in developing the same functionality from scratch.
              It has 4126 lines of code, 354 functions and 97 files.
              It has medium code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed jpa and discovered the below as its top functions. This is intended to give you an instant insight into jpa implemented functionality, and help decide if they suit your requirements.
            • Compares this AirlinePK with another object .
            • Saves the name .
            • Sets the primary key .
            • Gets the additional values for this request .
            • Returns the set of teacherachers .
            • Gets the name of the symbol .
            • Set a set of products .
            • Gets the type of the product .
            • Set the id .
            • Set the street name
            Get all kandi verified functions for this library.

            jpa Key Features

            No Key Features are available at this moment for jpa.

            jpa Examples and Code Snippets

            Creates jpa properties .
            javadot img1Lines of Code : 6dot img1License : Non-SPDX
            copy iconCopy
            private static Properties jpaProperties() {
                var properties = new Properties();
                properties.setProperty("hibernate.dialect", "org.hibernate.dialect.H2Dialect");
                properties.setProperty("hibernate.hbm2ddl.auto", "create-drop");
                return pro  

            Community Discussions

            QUESTION

            Spring JPA DTO projection and handling the nested projection with null values
            Asked 2021-Jun-15 at 17:31

            I am using class based projection with constructor expressions. here is a sample code form my work

            ...

            ANSWER

            Answered 2021-Jun-15 at 00:02

            QUESTION

            JPA delete method returns 200 but doesn't delete
            Asked 2021-Jun-15 at 17:21

            I'm using Postman to test my JPA delete method and when I test it, it returns a 200 response, but does not actually delete from my DB.

            Repo -

            ...

            ANSWER

            Answered 2021-Jun-15 at 17:21

            The userId must be null. That's why there is no delete.

            You need to bind the Path Parameters to the method parameters.

            So, in the Controller, change

            Source https://stackoverflow.com/questions/67989974

            QUESTION

            JOOQ Code Generation via JPADatabase problem with custom composite user type
            Asked 2021-Jun-15 at 13:38

            I am trying to use JOOQ code generation from JPA Entity. I have already created a dedicated maven module where the code will be generated which has dependency on a module containing all entities as well code generation plugin with of jooq.

            To add more clarify on project structure, here are the modules:(The names are made up but the structure reflects the current project i am working on)

            ...

            ANSWER

            Answered 2021-Jun-02 at 07:53
            Regarding the error

            I'm assuming you have missing dependencies on your code generation class path. Once you update your question, I'll update my answer.

            Regarding jOOQ code generation support for @TypeDef etc.

            jOOQ won't support your generated composite types in generated code out of the box, you'll still have to add forced type configurations for that, possibly embeddable type configurations:

            Note that the JPADatabase offers a quick win by integrating with simple JPA defined schemas very quickly. It has its caveats. For best results, I recommend going DDL first (and generate both jOOQ code and JPA model from that), because it will be much easier to put your schema change management under version control, e.g. via Flyway or Liquibase.

            Source https://stackoverflow.com/questions/67784647

            QUESTION

            How to convert Optional to Optional in Spring JPA?
            Asked 2021-Jun-15 at 06:52

            I am new in Spring and although I can convert domain entities as List, I cannot convert them properly for the the Optional. I have the following methods in repository and service:

            EmployeeRepository:

            ...

            ANSWER

            Answered 2021-Jun-15 at 06:52

            The mapping that happens between the output of employeeRepository#findByUuid that is Optional and the method output type Optional is 1:1, so no Stream (calling stream()) here is involved.

            All you need is to map properly the fields of Employee into EmployeeDTO. Handling the case the Optional returned from the employeeRepository#findByUuid is actually empty could be left on the subsequent chains of the optional. There is no need for orElse or findFirst calls.

            Assuming the following classes both with all-args constructor and getters:

            Source https://stackoverflow.com/questions/67981095

            QUESTION

            JPA throws java.lang.StackOverflowError with bidirectional @OneToMany
            Asked 2021-Jun-15 at 06:17

            I have two entity classes as follows. The Parachute is the parent object and it has multiple Component objects. I need to have bidirectional @OneToMany implemented here.

            Parent Parachute.java class.

            ...

            ANSWER

            Answered 2021-Jun-15 at 06:17

            You are violating the JPA spec by accessing the persistence context in a lifecycle listener.

            See the JPA Specification 4.2 Section 3.5.2

            In general, the lifecycle method of a portable application should not invoke EntityManager or query operations, access other entity instances, or modify relationships within the same persistence context. A lifecycle callback method may modify the non-relationship state of the entity on which it is invoked.

            "a portable application should not" is the specification way of saying: Don't do that, anything might happen. Maybe the world ends.

            The fix is not to do that. Maybe be preloading the currently logged in user and reference it so you may access it in your entity listener and do not set a reference to the user, but simple store its id or similar.

            Source https://stackoverflow.com/questions/67971795

            QUESTION

            Display a list of items of a specific user (by id) in One to many relationship Spring Boot
            Asked 2021-Jun-14 at 21:02

            in my example here i want to display a list of appointments of a specific patient in a one to many relationships .. the process is going well but the problem is how to display this list which is in patient as an attribute.

            Appointment Entity

            ...

            ANSWER

            Answered 2021-Jun-14 at 21:02

            As you have many to one mapping in Appointment entity. you could write the below query in AppointmentRep

            List findAllByPatientId(int id);

            https://docs.spring.io/spring-data/jpa/docs/current/reference/html/#repositories.query-methods.query-creation

            Source https://stackoverflow.com/questions/67976535

            QUESTION

            How to pass list of nested lists into JPA native query
            Asked 2021-Jun-14 at 15:14

            I need to create a JPA native query relevant to the example below:

            ...

            ANSWER

            Answered 2021-Jun-09 at 13:58

            Missing parentheses or commas have been known to throw this error.

            Source https://stackoverflow.com/questions/67904478

            QUESTION

            ContextLoader - Root WebApplicationContext initialized 3 times on ubuntu tomcat
            Asked 2021-Jun-14 at 12:43

            Dears, I have a jersey - spring api deployed on apache tomcat 9.0.46. (Jersey to handle restful services JAX-RS and Spring to handle all my beans{controllers, DAO, SessionFactory, JPA etc...}). Everything works fine on tomcat 9 on windows... When deploying the exact same war in ubuntu tomcat 9.0.46, the ContextLoader is getting triggered 3 times and I have all my singletons instantiated 3 times. I'm deploying the api on tomcat ports 80 and 443 (https - godady certificate). once I start tomcat the war is deployed and ports 80 and 443 get started (netstat -tulnp | grep java) and I see in log all singletons instantiated. (pool-2) Applicationcontext class my custom spring @Configuration class and it is getting triggered and DB is accessed without any issues

            ...

            ANSWER

            Answered 2021-Jun-14 at 12:43

            I have managed to figure out the problem. The issue was related to tomcat configuration in /conf/server.xml. Multiple Hosts will trigger the context loader to be triggered for each. I was keeping the default appBase to webapps for all host thus triggering the ContextLoader of each my war for each host. Another reason the ContextLoader will triggered multiple times as well is defining the option inside unless you need to load something external to your war. I recommend reading specs: https://tomcat.apache.org/tomcat-4.1-doc/config/host.html

            Source https://stackoverflow.com/questions/67907215

            QUESTION

            multiple models of the same length iterating simultaneously
            Asked 2021-Jun-14 at 06:58

            I have a very particular question related to thymeleaf in spring boot, using the Java Persitence API (JPA).

            I have three tables (A, B, C), hence models, they look like this:

            A:

            ...

            ANSWER

            Answered 2021-Jun-14 at 06:58

            Create a DTO that represents a row in your HTML:

            Source https://stackoverflow.com/questions/67963712

            QUESTION

            Spring Boot 2.5.0, Spring Cloud 2020.0.2 and Hibernate 5.4.31 - H2 Database Multi Row Insert Failing
            Asked 2021-Jun-13 at 22:47

            While Working on a Spring Boot Application with SB version 2.5.0, Spring Cloud (for Centralized Config 2020.0.2) The Hibernate version is 5.4.31 (I am not using a specific Hibernate version, it is as per Spring Boot compatibility). Using H2 database for in-memory data, as I need to create the sample application for demo.

            In the Resources folder, I do have my SQL file. When I name it data.sql the application does not start at all. When I renamed this file as import.sql, my application started but still facing issues for multi-row insertion.

            Data Insert SQL File

            ...

            ANSWER

            Answered 2021-Jun-09 at 10:11

            You need to add this to the app config:

            Source https://stackoverflow.com/questions/67650704

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install jpa

            You can download it from GitHub.
            You can use jpa like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the jpa component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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