wyatt | A Java crypto currency trading bot using the Binance API | Cryptocurrency library
kandi X-RAY | wyatt Summary
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- Displays the current status
- Returns the current balance list
- Get the current balance of the account
- Get up time in seconds
- Get price data
- Setter for btc
- Sets the doge value
- Set the ethernet value
- Main method
- Picks and returns a buy value
- Performs a sell operation
- Calculates average data for a list of candlesticks
- Shutdown the server
- Returns true if the provided password matches the provided key
- Gets the order history
- Gets the order history
- Get total balance
- Gets the total fit fit
wyatt Key Features
wyatt Examples and Code Snippets
Trending Discussions on wyatt
Trending Discussions on wyatt
QUESTION
I have a simple class Person:
class Person {
String firstName;
String lastName;
//getter, setter, constructor, toString
}
And an input list of Persons like:
List myList = List.of(
new Person("Helena", "Graves"),
new Person("Jasmine", "Knight"),
new Person("Phoebe", "Reyes"),
new Person("Aysha", "Graham"),
new Person("Madeleine", "Jenkins"),
new Person("Christina", "Johnson"),
new Person("Melissa", "Carpenter"),
new Person("Marie", "Daniel"),
new Person("Robin", "French"),
new Person("Tamara", "Wyatt"),
new Person("Freya", "Montgomery"),
new Person("Lacey", "Todd"),
new Person("Heather", "Parker"),
new Person("Lauren", "Wright"),
new Person("Annie", "Bradley")
);
Now I need to group the above list by the first character of the person's lastnames and again group the groups such that all last names which start between A-H fall in one group, the next group for those which start with I-N and lastly with O-Z.
I can already group the list by first character of last name:
myList.stream()
.collect(Collectors.groupingBy(p -> String.valueOf(p.getLastName().charAt(0))))
.entrySet()
.forEach(System.out::println);
Which gives me :
P=[Person{Heather, Parker}]
B=[Person{Annie, Bradley}]
R=[Person{Phoebe, Reyes}]
C=[Person{Melissa, Carpenter}]
T=[Person{Lacey, Todd}]
D=[Person{Marie, Daniel}]
F=[Person{Robin, French}]
W=[Person{Tamara, Wyatt}, Person{Lauren, Wright}]
G=[Person{Helena, Graves}, Person{Aysha, Graham}]
J=[Person{Madeleine, Jenkins}, Person{Christina, Johnson}]
K=[Person{Jasmine, Knight}]
M=[Person{Freya, Montgomery}]
Have difficulties how to proceed from here since I need to aggregate the above further to get a map with three entries/keys. Desired output:
Map> result = ...
A-H = [Person{Helena, Graves}, Person{Aysha, Graham}, Person{Melissa, Carpenter}, Person{Marie, Daniel}, Person{Robin, French}, Person{Annie, Bradley}]
I-N = [Person{Jasmine, Knight}, Person{Madeleine, Jenkins}, Person{Christina, Johnson}, Person{Freya, Montgomery}]
O-Z = [Person{Phoebe, Reyes}, Person{Tamara, Wyatt}, Person{Lacey, Todd}, Person{Heather, Parker}, Person{Lauren, Wright}]
ANSWER
Answered 2021-Oct-22 at 19:25Basically, all you need is grouping using Collectors.groupBy(Function) and a function that assigns each Person into a correct group:
/**
* This method is null-friendly
*/
String group(Person person) {
return Optional.ofNullable(person)
.map(Person::getFirstName)
.filter(name -> name.length() > 0)
.map(name -> name.charAt(0))
.map(ch -> {
if (ch >= 'A' && ch <= 'H') {
return "A-H";
} else if (ch > 'H' && ch <= 'N') {
return "I-N";
} else if (ch > 'N' && ch <= 'Z') {
return "O-Z";
}
return "*"; // In case the name starts with a character out of A-Z range
})
.orElse("none"); // In case there is empty/null firstName
}
Map> map = myList
.stream()
.collect(Collectors.groupingBy(this::group));
QUESTION
Good day.
I'm taking a JS course and right now we're covering Prototypes. My question has to do with the prototype object.
Here's the code sample:
class Pet {
constructor(name, age) {
this.name = name;
this.age = age;
}
eat() {
return `${this.name} is eating!`
}
}
class Dog extends Pet {
bark() {
return "Woof!"
}
eat() {
return `${this.name} scarfs his food!`
}
}
const wyatt = new Dog("Wyatt", 13);
If I type in the console: wyatt.eat()
(1) The console will look for the eat method on the Dog prototype. If it finds it, it'll run the method.
(2) If it doesn't find it there it will look at the Pet prototype for it, courtesy of the extends keyword.
(3) Now if it doesn't find it there, the console will look for it on the "Object Prototype" (the way the tutor formulated it).
I get all of the above and that a class instance has a prototype template it refers to, and possibly others. The confusing part for me is specifically at step (3), what is the prototype here? Is it looking on the global object? Would that be the window object? This part is still a bit shaky for me.
Many thanks.
ANSWER
Answered 2021-May-11 at 12:45While what you wrote is not wrong, the realty is simpler (IMO).
If you try to access a property on an object, the engine will first check whether the object itself (in your case wyatt) has that property. If not, it will look at the object's prototype (which is also an object) and repeat those steps until it finds the property or until an object doesn't have a prototype anymore. That's really all that is to it.
An object can only have one prototype. You can think of it as it being an "internal" property that is assigned a reference to another object.
I guess the next question is, how is a prototype assigned to an object? You already know one way: the extends keyword.
Maybe the point that you are missing is that the default prototype of an object is Object.prototype:
console.log(Object.prototype === Object.getPrototypeOf({}));Object.prototype however doesn't have a prototype:
console.log(Object.getPrototypeOf(Object.prototype));That's where the prototype chain ends.
So to summarize, the engine doesn't think "oh I have to look at Object.prototype now", it just knows to look at the object's prototype, whatever that may be. It's just the case that Object.prototype is the default prototype for "normal" objects.
QUESTION
Working on making a bot for a personal discord server, wanting it to simply join general voicechat when command "Blyat" is detected, play mp3 file, when its done to leave. Code:
var Discord = require('discord.js');
var client = new Discord.Client();
var isReady = true;
client.on('message', message => {
if (command === "Blyat") {
var VC = message.member.voiceChannel;
if (!VC) return message.reply("MESSAGE IF NOT IN A VOICE CHANNEL")
VC.join()
.then(connection => {
const dispatcher = connection.playFile('C:\Users\Wyatt\Music\soviet-anthem.mp3');
dispatcher.on("finish", end => { VC.leave() });
})
.catch(console.error);
};
});
client.login('token, not putting in code, is there in real code');
Error: "ReferenceError: command is not defined at Client. (C:\Users\jeffofBread\Desktop\Discord Bot\main.js:6:5)"
Any help or tips will be much appreciated, haven't coded in many years and have lost any knowledge I had once held.
ANSWER
Answered 2021-Mar-12 at 02:12Your problem comes from an unidentified variable. Fortunatly that is very easy to fix. All you have to do is define command before you call it.
For this we'll splice the message content into two parts. The command and any arguments that may be included like mentions or other words. We do that with:
const args = message.content.slice(prefix.length).split(/ +/);
const command = args.shift().toLowerCase();
Note: The args constant is an array.
Which would make your entire onMessage event look like this:
client.on('message', message => {
const prefix = "!";
const args = message.content.slice(prefix.length).split(/ +/);
const command = args.shift().toLowerCase();
if (command === "blyat") {
var VC = message.member.voice.channel;
if (!VC) return message.reply("MESSAGE IF NOT IN A VOICE CHANNEL")
VC.join()
.then(connection => {
const dispatcher = connection.play('C:\Users\Wyatt\Music\soviet-anthem.mp3');
dispatcher.on("finish", end => { VC.leave() });
})
.catch(console.error);
};
});
QUESTION
I am trying to take a random name from a list and then once it has been printed, I want to remove it from that list so that it isn't used ever again. I want to use the pop method but I'm not sure how to take a random name from the list since the pop method (to my knowledge) only accepts integers.
Here is my code:
Boy = ['David','John','Paul','Mark','James','Andrew','Scott','Steven','Robert','Stephen','William','Craig','Michael'
,'Stuart','Christopher','Alan','Colin','Kevin','Gary','Richard','Derek','Martin','Thomas','Neil','Barry',
'Ian','Jason','Iain','Gordon','Alexander','Graeme','Peter','Darren','Graham','George','Kenneth','Allan',
'Simon','Douglas','Keith','Lee','Anthony','Grant','Ross','Jonathan','Gavin','Nicholas','Joseph','Stewart',
'Daniel','Edward','Matthew','Donald','Fraser','Garry','Malcolm','Charles','Duncan','Alistair','Raymond',
'Philip','Ronald','Ewan','Ryan','Francis','Bruce','Patrick','Alastair','Bryan','Marc','Jamie','Hugh','Euan',
'Gerard','Sean','Wayne','Adam','Calum','Alasdair','Robin','Greig','Angus','Russell','Cameron','Roderick',
'Norman','Murray','Gareth','DeanEric','Adrian','Gregor','Samuel','Gerald','Henry','Benjamin','Shaun','Callum',
'Campbell','Frank','Roy','Timothy','Liam','Noah','Oliver','William','Elijah','James','Benjamin','Lucas',
'Mason','Ethan','Alexander','Henry','Jacob','Michael','Daniel','Logan','Jackson','Sebastian','Jack','Aiden',
'Owen','Samuel','Matthew','Joseph','Levi','Mateo','Wyatt','Carter','Julian','Luke','Grayson','Isaac','Jayden'
,'Theodore','Gabriel','Anthony','Dylan','Leo','Christopher','Josiah','Andrew','Thomas','Joshua','Ezra',
'Hudson','Charles','Caleb','Isaiah','Ryan','Nathan','Adrian','Christian']
Girl = ['Emma','Ava','Sophia','Isabella','Charlotte','Amelia','Mia','Harper','Evelyn','Abigail','Emily','Ella',
'Elizabeth','Camila','Luna','Sofia','Avery','Mila','Aria','Scarlett','Penelope','Layla','Chloe','Victoria',
'Madison','Eleanor','Grace','Nora','Riley','Zoey','Hannah','Hazel','Lily','Ellie','Violet','Lillian','Zoe',
'Stella','Aurora','Natalie','Emilia','Everly','Leah','Aubrey','Willow','Addison','Lucy','Audrey','Bella',
'Nova','Brooklyn','Paisley','Savannah','Claire','Skylar','Isla','Genesis','Naomi','Elena','Caroline','Eliana'
,'Anna','Maya','Valentina','Ruby','Kennedy','Ivy','Ariana','Aaliyah','Cora','Madelyn','Alice','Kinsley',
'Hailey','Gabriella','Allison','Gianna,Sarah','Autumn','Quinn','Eva','Piper','Sophie','Sadie','Delilah'
,'Josephine','Nevaeh','Adeline','Arya','Emery','Lydia','Clara','Vivian','Madeline','Peyton','Julia','Rylee',
'Brielle','Reagan','Natalia','Jade'',Athena','Maria','Leilani','Everleigh','Liliana','Melanie','Mackenzie',
'Hadley','Raelynn','Kaylee','Rose','Arianna','Isabelle','Melody','Eliza','Lyla','Katherine','Aubree',
'Adalynn','Kylie','Faith','Marly','Margaret','Ximena','Iris','Alexandra','Jasmine','Charlie','Amaya',
'Taylor','Isabel','Ashley','Khloe','Ryleigh','Alexa','Amara','Valeria','Andrea','Parker','Norah','Eden',
'Elliana','Brianna','Emersyn','Valerie','Anastasia','Eloise','Emerson','Cecilia','Remi','Josie','Reese',
'Bailey','Lucia','Adalyn','Molly','Ayla','Sara','Daisy','London','Jordyn','Esther','Genevieve','Harmony',
'Annabelle','Alyssa','Ariel','Aliyah','Londyn','Juliana','Morgan','Summer','Juliette','Trinity','Callie',
'Sienna','Blakely','Alaia','Kayla','Teagan','Alaina','Brynlee','Finley','Catalina','Sloane','Rachel','Lilly'
,'Ember']
def boyname():
result = Boy.pop(insert code for random name here)
print(result)
print(Boy)
boynames = boyname()
print(boynames)
ANSWER
Answered 2020-Dec-12 at 02:37Try this code
from random import choice
def boyname():
global Boy
result = choice(Boys)
print(result)
Boy.remove(result)
print(Boy)
boyname()
QUESTION
If I have one dictionary:
{'10103 - Baldwin, C': 'SFEN', '10115 - Wyatt, X': 'SFEN', '10172 - Forbes, I': 'SFEN'}
And another dictionary:
{'10103': ['CS 501', 'SSW 564', 'SSW 567', 'SSW 687'], '10115': ['CS 545', 'SSW 564', 'SSW 567', 'SSW 687'], '10172': ['SSW 555', 'SSW 567']}
What would be the best way to transfer the key from the first dictionary to the second dictionary so I get something like:
{'10103 - Baldwin, C': ['CS 501', 'SSW 564', 'SSW 567', 'SSW 687'], '10115 - Wyatt, X': ['CS 545', 'SSW 564', 'SSW 567', 'SSW 687'], '10172 - Forbes, I': ['SSW 555', 'SSW 567']}
I found this solution on another thread, but it requires a lookup of a value in the first dictionary to match the key in the second dictionary. If I just want to do a one-to-one transfer if I know that the order of the items in the dictionaries are the same, how could I do so?
lookup = {v: k for k, v in df2_dict.items()}
result = {lookup[k]: v for k, v in sorted_classes.items()}
ANSWER
Answered 2020-Nov-14 at 15:27Given dictionaries d1 and d2, you would need to parse out the number from the keys of d1 so that you can look it up in d2. From there, you can replace the values for each key
for k in d1.keys():
n, _ = k.split('-')
n = n.strip()
d1[k] = d2[n]
print(d1)
QUESTION
I have:
df1 = [['10103', 'Baldwin, C', 'SFEN'], ['10115', 'Wyatt, X', 'SFEN']]
What would be the best way to concatenate the items within so that I could get something like:
[['10103 - Baldwin, C', 'SFEN'], ['10115 - Wyatt, X', 'SFEN']]
If I try something like
for i in df1:
df1[0:1] = [' - '.join(df1[0:1])]
I get TypeError: sequence item 0: expected str instance, list found.
ANSWER
Answered 2020-Nov-14 at 03:46Do the same way as yours,
>>> df1 = [['10103', 'Baldwin, C', 'SFEN'], ['10115', 'Wyatt, X', 'SFEN']]
>>> for i, item in enumerate(df1):
... df1[i] = [' - '.join(item[:2]), item[2]]
...
>>> df1
[['10103 - Baldwin, C', 'SFEN'], ['10115 - Wyatt, X', 'SFEN']]
Another way to go,
>>> df1 = [['10103', 'Baldwin, C', 'SFEN'], ['10115', 'Wyatt, X', 'SFEN']]
>>> df1 = [[' - '.join([item1, item2]), item3] for item1, item2, item3 in df1]
>>> df1
[['10103 - Baldwin, C', 'SFEN'], ['10115 - Wyatt, X', 'SFEN']]
QUESTION
I use Backpack for Laravel 4.1.
Table: users
---------------------------
| id | name |
---------------------------
| 1 | Rory Choi |
---------------------------
| 2 | Freddie Farrington |
---------------------------
| 3 | Cristian Wyatt |
---------------------------
Table: documents
I want the value that stored in the table to be the value of name from users table, not the id.
I want this:
-------------------------------------------------------
| id | description | name |
-------------------------------------------------------
| 1 | Something | Cristian Wyatt |
-------------------------------------------------------
| 2 | Other thing | Freddie Farrington |
-------------------------------------------------------
| | | |
-------------------------------------------------------
Not this:
-------------------------------------------------------
| id | description | name |
-------------------------------------------------------
| 1 | Something | 3 |
-------------------------------------------------------
| 2 | Other thing | 2 |
-------------------------------------------------------
| | | |
-------------------------------------------------------
DocumentController.php:
It does show the list of names from users table, but it does not store the name value
protected function setupCreateOperation()
{
CRUD::addField([
'label' => 'Username',
'name' => 'username',
'type' => 'select2',
'entity' => 'users', // the method that defines the relationship in your Model
'attribute' => 'name', // foreign key attribute that is shown to user
]);
}
Document.php
The method that defines the relationship.
public function users()
{
return $this->hasOne('User','name','name');
}
What should I do? Thanks.
ANSWER
Answered 2020-Nov-09 at 08:42relationship not work for that you can use this method.
use that :
public function users()
{
return User::where('name',$this->name)->first();
}
instead of
public function users()
{
return $this->hasOne('User','name','name');
}
QUESTION
I have created a module for reservations like this, this is my vuex store:
import Vue from "vue";
import Vuex from "vuex";
Vue.use(Vuex);
const state = {
reservations: [],
stats: {
pending: 0,
confirmed: 0,
cancelled: 0
}
};
const actions = {
fetchReservations({commit}){
axios.get('/reservations').then(({data})=>{
commit('setReservations', data);
}).catch(error => {
throw new Error(error);
});
},
deleteReservation({commit}, reservationId){
axios.delete('/reservations/'+ reservationId).then(()=>{
commit('removerReservationInList', reservationId);
});
},
confirmReservation({commit}, reservationId){
axios.patch('/reservations/'+ reservationId +'/confirm').then(({data})=>{
commit('updateReservationInList', data);
});
},
cancelReservation({commit}, reservationId){
axios.patch('/reservations/'+ reservationId +'/cancel').then(({data})=>{
commit('updateReservationInList', data);
});
},
fetchReservationStats({commit}){
axios.get('/reservations/stats').then(({data})=>{
commit('setReservationsStats', data);
});
}
};
const mutations = {
setReservations(state, reservations) {
state.reservations = reservations;
},
removeReservationInList(state, reservationId){
state.reservations = state.reservations.filter((reservation)=>{
return reservation.id !== reservationId
});
},
updateReservationInList(state, data){
state.reservations = state.reservations.map(reservation => {
if (reservation.id !== data.id) {
return reservation;
}
reservation.state_id = data.state_id;
return reservation;
});
},
setReservationsStats(state, data) {
state.stats = data;
}
};
const getters = {
reservationsList(state){
return state.reservations
},
reservationsStats(state){
return state.stats;
}
};
export default new Vuex.Store({
state,
actions,
mutations,
getters
});
And those are the reservations:
[
{"id":1,"name":"Rollin Koss","email":"predovic.wyatt@example.net","state_id":2, "booking_date":"2020-12-12","number_of_guests":3},
{"id":2,"name":"Kellie Schroeder","email":"nicolette39@example.com","state_id":1,"booking_date":"2020-12-02","number_of_guests":14},
{"id":3,"name":"Autumn Goldner IV","email":"vkutch@example.org","state_id":3, "booking_date":"2020-12-15","number_of_guests":14}
.....
]
So, I get the stats in other request. I was thinking doing it in another way, for example, when I get the reservations, return the stats like this:
[
"reservations": [
{"id":1,"name":"Rollin Koss","email":"predovic.wyatt@example.net","state_id":2, "booking_date":"2020-12-12","number_of_guests":3},
{"id":2,"name":"Kellie Schroeder","email":"nicolette39@example.com","state_id":1,"booking_date":"2020-12-02","number_of_guests":14},
{"id":3,"name":"Autumn Goldner IV","email":"vkutch@example.org","state_id":3, "booking_date":"2020-12-15","number_of_guests":14},
....
....
],
"stats": {
"pending": 50,
"confirmed": 30
"cancelled": 10
}
]
state_id = 1 is for pending reservations, state_id = 2 is for confirmed reservations, state_id = 3 is for cancelled reservations
And then for example, when I update a pending reservation to confirmed, the pending should decrease and the confirmed should increase, and if a confirmed reservation is cancelled, the stats should reflects that, also, if some reservation is deleted for example a pending, then it should decrease, I am not sure how to do it. Thank you.
ANSWER
Answered 2020-Nov-07 at 02:18Instead of storing stats as a state object, you could use a getter which will be reactive to your reservation state.
getters: {
stats(state){
return {
pending: countState(1),
confirmed: countState(2),
cancelled: countState(3),
};
function countState(stateId){
return state.reservations.reduce((acc, cur) => (cur.state_id === stateId ? ++acc : acc), 0);
}
}
EDIT: If you'd like it to reflect your current paginated reservations you could move the stats code from vuex into the component itself using a computed function, like so:
computed: {
stats: function () {
// This should point to your current set of paginated reservations
const reservations = this.$store.getters.reservations;
return {
pending: countState(1),
confirmed: countState(2),
cancelled: countState(3),
};
function countState(stateId) {
return reservations.reduce((acc, cur) => (cur.state_id === stateId ? ++acc : acc), 0);
}
},
},
QUESTION
What is the best way to fix the issue where the form fields values cant be seen when selected when the table fits the screen. I want the table to scroll at least and have the form fields be actually visible to the eye. Specifically you can see this in the innings pitched.
Texas Oilers 11u - Hamblin/Hancock
Pitcher Name
Pitch Count
Innings Pitched
- Pitcher -Blair, Beau (0)Caves, Beckham (0)Flowers, Kade (0)Garrison, Gavin (0)Guerrero, Saul (0)Hernandez, Jovani (0)Lewis, Jhett (0)Pruitt, Colton (0)Ruggiano, Brooks (0)Smith, Greer (0)
99
100
9
10
1/3
2/3
- Pitcher -Blair, Beau (0)Caves, Beckham (0)Flowers, Kade (0)Garrison, Gavin (0)Guerrero, Saul (0)Hernandez, Jovani (0)Lewis, Jhett (0)Pruitt, Colton (0)Ruggiano, Brooks (0)Smith, Greer (0)
99
100
9
10
1/3
2/3
Pitcher
TCR Bobcats - Wise
Pitcher Name
Pitch Count
Innings Pitched
- Pitcher -Challender, Brodie (29)Dakin, Caleb (13)Fox, Brayden (11)Gardner, Trevor (12)Geraci, Brennen (2)Hull, Brody (99)Hunt, Wyatt (6)Jolley, Makay (34)Titsworth, Beau (4)Wise, Colton (9)
99
100
1
2
3
4
5
6
7
8
9
10
1/3
2/3
- Pitcher -Challender, Brodie (29)Dakin, Caleb (13)Fox, Brayden (11)Gardner, Trevor (12)Geraci, Brennen (2)Hull, Brody (99)Hunt, Wyatt (6)Jolley, Makay (34)Titsworth, Beau (4)Wise, Colton (9)
99
100
9
10
1/3
2/3
Pitcher
Save
ANSWER
Answered 2020-Oct-19 at 23:10Take out all .w-100 on the tables and the selects, and set those selects' width as fit-content. You can create a custom class for that:
.w-fit-content {
width: fit-content;
}
QUESTION
So in typical programming scenarios, if you mutate an object, it mutates the object everywhere. However, in React, since states are immutable and only mutable through each's set*, if states are nested in each other, like the scenario shown below, only the currentMember's name will change, and not the version of currentMember in currentTeam, or teams. I'd have to go through each and mutate them one by one, which is cumbersome.
What would be the best way to mutate multiple states at once, or achieve a similar effect? I've done so by indexing, but it's more cumbersome to work with, and i didnt know if there were a textbook hook that fixes this.
import React, { useState } from 'react'
interface Member {
name: string
}
interface Team {
name: string
members: Member[]
}
export default (props: {}) => {
const [teams, setTeams] = useState([
{
name: 'Team One',
members: [{ name: 'Wyatt' }, { name: 'Michael' }]
}
])
const [currentTeam, setCurrentTeam] = useState(teams[0])
const [currentMember, setCurrentMember] = useState(currentTeam.members[0])
return (
<>
${currentMember.name}
setCurrentMember(currentMember => { ...currentMember, name: 'Zach' })}>
Change current member name to Zach!
)
}
ANSWER
Answered 2020-Aug-10 at 06:32As mentioned, you are making things a bit complicated by using state this way. You should have one base state that contains all of the teams, then reference the bits that are important to you by index.
For example, your teams state is fine as is. Your currentTeam and currentMember states should be indexes or some other reference to the state within teams you want to map to.
So, in specific terms, I'd change the format of your code here like so (forgive me as I don't write TypeScript, so I'm going to straight vanilla javascript to avoid making typos):
import React, { useState } from 'react'
// interface Member {
// name: string
//}
// interface Team {
// name: string
// members: Member[]
//}
export default (props: {}) => {
const [teams, setTeams] = useState([
{
name: 'Team One',
members: [{ name: 'Wyatt' }, { name: 'Michael' }]
}
])
const [currentTeamIndex, setCurrentTeam] = useState(0)
const [currentMemberIndex, setCurrentMember] = useState(0)
return (
<>
${teams[currentTeamIndex].members[currentMemberIndex]}
setTeams(teams => ({
// Shallow copy the teams via mapping through them
...teams.map((team, teamIndex) => {
// If the current team index isn't the index we're on right now, then just
// return the existing team in its given place.
if (teamIndex !== currentTeamIndex) return team
// If we're at this point, it means the teamIndex matches the currentTeamIndex
// and we need to mutate this. We'll just do that by returning a new object
return {
...team, // Make sure we don't miss anything
...members.map((member, memberIndex) => {
// Same as the outer map, if the current member index isn't the same as the
// given memberIndex, then just return the member we're on, we're not mutating it
if (memberIndex !== currentMemberIndex) return member
return {
...member,
name: 'Zach'
}
})
}
}
})
>
Change current member name to Zach!
)
}As you can see, drilling that far down into an object isn't so simple, but it's possible to do without mutating the original data - you can accomplish what you are looking for by reconstructing the data on the fly with Array functions, spread syntax, and index references in state.
You might also want to consider confining this in a reducer, with a specific action containing the team id index, and member id index to make this quite a bit more composable.
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