NOA | 基于ssm的Web端OA系统 : boom : : boom : Spring | Object-Relational Mapping library
kandi X-RAY | NOA Summary
kandi X-RAY | NOA Summary
基于ssm的Web端OA系统 :boom::boom: , Spring,SpringMVC,Mybatis
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Top functions reviewed by kandi - BETA
- This method tries to find all the departments that can be accepted by the user
- Returns a list of subdeps for a given mainDep
- Display the mail page view
- This method checks if the subject is allowed to be able to be able to be able to post
- Upload pic to directory
- Delete a comment
- Send a mail
- Check username
- Offer an Employee
- Get a mission detail
- Posts a mission to the activity
- Display Home page
- Obtain the basic authorization info for a principal
- Log an Employee
- Show all the mission in the department
- Counts the number of month states
- Shows all announcements of a department
- Register an Employee
- Display a search page
- Displays a view of the active mission
- Method getAuthenticationInfo
NOA Key Features
NOA Examples and Code Snippets
Community Discussions
Trending Discussions on NOA
QUESTION
I ran a PDF through a series of processes to extra the text from it. I was successful in that regard. However, now I want to extract specific text from documents.
The document is set up as a multi lined string (I believe. when I paste it into Word the paragraph character is at the end of each line):
Send Unit: COMPLETE
NOA Selection: 20-0429.07
#for some reason, in this editor, despite the next line having > infront of it, the following line (Pni/Trk) keeps wrapping up to the line above. This doesn't exist in the actual doc.
Pni/Trk: 3 Panel / 3 Track
Panel Stack: STD
Width: 142.0000
The information is want to extract are the numbers following "NOA Selection:".
I know I can do a regex something to the effect of:
...ANSWER
Answered 2021-Apr-22 at 02:52Keeping it simple, you could use re.findall here:
QUESTION
Assuming this:
...ANSWER
Answered 2021-Apr-03 at 14:26A child has a mother and a father and would best be designed to have mother and father attributes contained within. I think the following class definitions make more sense for your case:
QUESTION
I'm trying to get some encryption/decryption going using AES/CBC/PKCS5Padding and am getting a strange result. Depending on the original value I use to encrypt I get an exception:
javax.crypto.BadPaddingException: Given final block not properly padded. Such issues can arise if a bad key is used during decryption.
To test this out, I wrote a little function that starts with a string and progressively makes it bigger, trying to encrypt the string and decrypt the encrypted result in each iteration.
- First iteration ==> string == "5"
Encrypt and decrypt - Next iteration ==> string == "55"
Encrypt and decrypt - Next iteration ==> string == "555"
Encrypt and decrypt - Next iteration ==> string == "5555"
Encrypt and decrypt - Next iteration ==> string == "55555"
Encrypt and decrypt
If consistently fails to decrypt the encrypted values in items 0 and 4 (first and last). It successfully decrypts the other values.
Any clues what may be causing this?
Here is the output of the program:
...ANSWER
Answered 2020-Dec-15 at 02:29
String encryptedRawValue
This cannot work. Strings are a sequence of characters. Encrypted data is a sequence of bytes. If we live in magic unicornland where unicode, and more generally western characters, can just be waved away as being non-existent, you can write really bad code and conflate the two. This was common in ye olden days. it's so bad, it's a major reason for why python 2 decided to up and ditch it all and move to python 3.
There is only one fix. Stop doing this. The correct type is byte[]. If you then need this byte[] rendered in string form for some reason, then the only sane reason is because it needs to be rendered in a highly limited venue, such as an email. In which case, you should base64 encode it. Search the web for 'java base64' on how to do this, if you must. Those APIs get it right: The 'encode' method takes a byte[] and returns a String, and the decode method takes a String and returns a byte[].
Fix this issue and the problem goes away.
String encryptedValue = new String(cipher.doFinal(value.getBytes(Charset.forName("UTF-8"))));
Do not wrap the result of doFinal into new String. Take the byte array. That's your data.
QUESTION
I want to compare the output of a scalar function with a scalar value in a CHECK statement when creating a table, but it doesn't seem to do the right comparisons. I want the check statement to be "checked" if the scalar function returns 1. Is there any way to do this? (The function is called in the last check statement)
The statement runs successfully, and if I run the function out of the CHECK function it returns the right values (0 or 1), but when I insert data that satisfies 1 in the function returned value, errors are returned. This is my code and what I've tried,
...ANSWER
Answered 2020-Dec-01 at 00:44Marx,
I see no error with the CHECK statement in your table. See the dbfiddle here; it is working as intended, because the value you are trying to INSERT violates the CHECK statement and will not work.
If you click the link and scroll down, you see that based on the data you provided, there is no way for the function to return 1 for some of these rows. Namely, here is one example that fails:
QUESTION
My aim to to explore GPU acceleration for tabular data with 10,000 to 10M+ records. I am most familiar with Pandas, so cuDF seems like a good place to start.
I'm finding mixed results re: whether cuDF will run on my system (Windows 7 Pro 64-bit, i7-6820HQ, 32GB RAM, NVidia Quadro M2000M 4GB). There is also an onboard graphics card.
per the gitHub page (https://github.com/rapidsai/cudf):
CUDA/GPU Requirements
- CUDA 10.0+ (YES - I have v10.1.120)
- NVIDIA driver 410.48+ (YES - I have 432.06)
- Pascal architecture or better (NO - Maxwell)
I have heard that Pascal architecture is preferred/optimal as opposed to a requirement, but maybe that was for older versions of cuDF? Just this morning I heard it will run on Win 64, though performance benefits may also be reduced. Nonetheless, I'm interested in giving it a shot.
When I install from the conda prompt (python 3.6 env) using the recommended command for my CUDA version:
conda install -c rapidsai -c nvidia -c numba -c conda-forge cudf=0.13 python=3.6 cudatoolkit=10.1
I get:
Collecting package metadata (repodata.json): done Solving environment: failed with initial frozen solve. Retrying with flexible solve.
PackagesNotFoundError: The following packages are not available from current channels:
- cudf=0.13
Current channels:
- https://conda.anaconda.org/rapidsai/win-64
- https://conda.anaconda.org/rapidsai/noarch
- https://conda.anaconda.org/nvidia/win-64
- https://conda.anaconda.org/nvidia/noarch
- https://conda.anaconda.org/numba/win-64
- https://conda.anaconda.org/numba/noarch
- https://conda.anaconda.org/conda-forge/win
- https://conda.anaconda.org/conda-forge/noa
- https://repo.anaconda.com/pkgs/main/win-64
- https://repo.anaconda.com/pkgs/main/noarch
- https://repo.anaconda.com/pkgs/r/win-64
- https://repo.anaconda.com/pkgs/r/noarch
- https://repo.anaconda.com/pkgs/msys2/win-6
- https://repo.anaconda.com/pkgs/msys2/noarc
To search for alternate channels that may provide the conda package you're looking for, navigate to
...
ANSWER
Answered 2020-Aug-27 at 17:03cuDF maintainer here.
Currently, cuDF nor any other RAPIDS libraries are supported in a native Windows environment. There's an issue tracking Windows support here: https://github.com/rapidsai/cudf/issues/28.
In general, native Windows support is not a priority for us, especially given the push towards GPU support in WSL2 that is currently in open beta.
QUESTION
I am just learning lex/bison/yacc etc and I am running it through a library called syntax
This is through a tutorial on UDemy.
I am just getting started and trying to get it to make it generate an AST for 2 + 2. Which seems like it should be trivial, but I can't figure out what is wrong with the code I am writing.
It is generating a AST for the number but not for the binary expression.
...ANSWER
Answered 2020-Nov-12 at 15:01You're missing commas in some of your object literals (specifically after both occurrences of type: BinaryExpression).
It looks like syntax simply ignores actions with syntax errors in --parse mode. If you actually compile the grammar to JavaScript using --output, you'll get an actual syntax error telling you where the mistake is when you try to run the generated file with node.
QUESTION
I know I can use the rest operator to remove a key from an Object, such as
...ANSWER
Answered 2020-Aug-22 at 02:19You'll need to specify a variable name to put the value into, but variable names can't be dynamic, so you'll have to use syntax very similar to computed properties, const { [prop]: propVal, ...noA } = myObject;:
QUESTION
I want to count the number of rows where a certain column has a substring in the column value.
This doesn't work
...ANSWER
Answered 2020-Jul-07 at 13:57Use a case expression:
QUESTION
I am trying to substract two rows in my dataset from each other:
...ANSWER
Answered 2020-Jun-26 at 08:53You could filter on the two periods and then join them together, thus facilitating the subtraction of columns.
QUESTION
I am attempting to get a accumulative sum and count within a groupby in pandas, but only if the but only on consecutive row values. If the value is not consecutive, I'd like to accumulative sum and count to reset.
The groups are by "ID" and "STATUS", and the "DAYS" are the values being summed.
My current data set looks like this:
...ANSWER
Answered 2020-Jun-17 at 01:06We need use shift with cumsum create the subgroup key , then we do cumsum and cumcount. Notice here I am using pd.Serise groupby
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Install NOA
You can use NOA like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the NOA component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .
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