kandi X-RAY | philadelphia Summary
kandi X-RAY | philadelphia Summary
Philadelphia is a low-latency Financial Information Exchange (FIX) engine for the JVM. You can use Philadelphia to connect to stock exchanges, brokerage firms, and other network endpoints that use the FIX protocol. You can also use it to provide your own services using the FIX protocol. Philadelphia is designed to exhibit low and predictable latency. To achieve this, it supports non-blocking, zero-copy networking and does not allocate any memory on message reception or transmission. It can achieve 7.7 µs round-trip time (RTT) over the loopback interface. Philadelphia requires Java Runtime Environment (JRE) 8 or newer.
Top functions reviewed by kandi - BETA
- Send FIXMessage
- Returns the first instance of a field with the specified tag
- Sends a Reject message
- Get the value as an integer
- Process a message
- Handle logon
- Handles a sequence reset flag
- Handle resend request
- Returns the value as a floating point number
- Get the value as a date
- Send a logon message
- Gets the value as a time only
- Display command
- Opens a socket connection
- Keep the connection alive
- Reads messages from the terminal
- Set the value to a date
- Set the value to a float
- Set the value to the given timestamp
- Set a fixed - time value to a fixed date
- Returns the value as a timestamp
- Set the value to a time only
- Returns a string representation of the message
- Send and receive a message
- Synchronously reads messages from the terminal
- Construct a FIXMessage from a string representation
philadelphia Key Features
philadelphia Examples and Code Snippets
Trending Discussions on philadelphia
I have two large-ish data frames I am trying to append...
In df1, I have state codes, county codes, state names (Alabama, Alaska, etc.), county names, and years from 2010:2020.
In df2, I have county names, state abbreviations (AL, AK), and data for the year 2010 (which I am trying to merge into df1. The issue lies in that without specifying the state name and simply merging df1 and df2, some of the data which I am trying to get into df1 is duplicated due to there being some counties with the same name...hence, I am trying to also join by state to prevent this, but I have state abbreviations, and state names.
Is there any way in which I can make either the state names in df1 abbreviations, or the state names in df2 full names? Please let me know! Thank you for the help.
ANSWERAnswered 2022-Apr-18 at 03:52
Here's one way you could turn state abbreviations into state names using R's built in state vectors:
Hi, I would like to display my social links after the typescript sentence has finished.
I am unsure how to achieve this, since I am kind of a beginner in React.
See my code below:
ANSWERAnswered 2022-Apr-04 at 22:28
I was not able to find anything on the Typewriter API that lets you know when it ended. However there is a simple way to achieve this, that is just calculating how long it takes to type everything out, and write a setTimeout for that time that changes a property that will show your links. Something like this
I'm trying to create my first map using ggrepel, but as you can see I've instead created a dumpster fire of overlapping labels. Most of the locations I'm mapping and labelling are clustered in the northeast, so the labels overlap. How do I get some of the labels to slide over beyond the map boundaries (in the ocean, so to speak)? Here's the code I used to create this monster:...
ANSWERAnswered 2022-Mar-31 at 15:59
With a little data manipulation, you could move the labels out to either side of the country an draw segments to connect the labels to the universities:
I have a function I was trying to build in PowerShell to explore an unknown JSON structure and am having trouble with the recursion failing after the second run.
Here is my code:...
ANSWERAnswered 2022-Mar-09 at 19:07
Regarding your code, I can see several issues, which I already highlighted in the 2 comments I left to your question.
Here is a simple function I made while looking at yours to produce the desired result.
I've looked at several SO posts but I'm at the "beating head against tree" stage. I appreciate your time.
I have a dataframe (about 300 cases) with a text string; I simply want to scan a separate list of cities (7000 of them), and if city in the string matches the list, I want a new data frame column to be written with the matching city name.
ANSWERAnswered 2022-Feb-23 at 17:10
Is this what you're looking for?
Trying to scrape odds from fanduel, goal is to get the player's name. In this case Jayson Tatum.
Even when I copy the xpath directly from chrome it doesnt seem to work. Though it works when I hardcode and look for an element through xpath containing the text Jayson Tatum. This is my code...
ANSWERAnswered 2021-Dec-20 at 22:10
To print the text
Jayson Tatum you can use the following Locator Strategy:
Using xpath and text attribute:
I have a column in one dataframe with city and state names in it:
ac <- c("san francisco ca", "pittsburgh pa", "philadelphia pa", "washington dc", "new york ny", "aliquippa pa", "gainesville fl", "manhattan ks")
ac <- as.data.frame(ac)
I would like to search for the values in
ac$ac in another data frame column,
d$description and return the value of column
id if there is a match.
ANSWERAnswered 2021-Dec-07 at 19:46
I'm trying to find the shortest distance between the places and the user's location and I have two table namely:
ANSWERAnswered 2021-Dec-04 at 00:18
This should out put the closest city to user:
I have following array of record which contains user as well as location information:...
ANSWERAnswered 2021-Dec-02 at 22:16
Try this code which print name and date only the first time:
I have a file I am reading from and putting it into a dictionary. How do I remove the new line from the key?...
ANSWERAnswered 2021-Nov-10 at 01:53
Just use the
replace function when defining your key. See below:
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