fuzzy | handy little library for writing expressive | Testing library
kandi X-RAY | fuzzy Summary
kandi X-RAY | fuzzy Summary
Fuzzy is a handy little library for writing expressive "fuzz tests" in Java. Fuzzy also comes with some built-in generators that ensure that your code is tested against common input edge cases. For example, a generator of Any.integer() will inject your inputs with negative values, positive values, and zero.
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Top functions reviewed by kandi - BETA
- Gets the subcases
- Translate a set of subcases to a set of subcases
- Initializes the context
- Factory method for creating an IllegalStateException for this test
- Registers a generator
- Reports a duplicate generator exception
- Returns the current context
- Creates an IllegalStateException from the current context
- Returns the subset of the subcases
- Returns a subset of all subcases
- Moves to the next test cases
- Returns a map of the keys generated by the current iteration
- Returns a new numeric value that is not excluded
- Returns all subcases contained in this delegate case
- Creates a todo task
fuzzy Key Features
fuzzy Examples and Code Snippets
@Test
public void myTest() {
// All of your generators must be declared before any of them are used, so
// that fuzzy understands the number of necessary test permutations.
// Declare test variables
Generator to = Generator.of(new EmailC
public void executeFuzzyTest() {
// Initialize the testing context. This applies to all generators
// created on this thread.
Context.init();
try {
do {
// Execute your test code here.
executeSingleTes
public class MyClassTest {
@Rule public FuzzyRule fuzzyRule = FuzzyRule.DEFAULT;
@Test
public void testSomething() {
// Declare your test variables
Generator myString = Generator.of(Any.string());
// Execute the
Community Discussions
Trending Discussions on fuzzy
QUESTION
After upgrading to Angular 13 the application no longer works during runtime. From what I've read NODE_DEBUG is Webpack specific and for some reason is not recognized when running the application with an 'ng serve'. I've also recently upgraded to macOS Monterey. I've very stuck at the moment....
package.json
...ANSWER
Answered 2021-Dec-20 at 05:04Try to delete your node_modules folder and run npm install again.
If still not working try to downgrade the node version to 12.20.x and check.
QUESTION
I wrote a simple code to search for circles in documents (since seals have a rounded shape).
But due to the poor image quality, the print outline is fuzzy, and opencv cannot always detect it. I edited the picture in photoshop and enhanced the dark colors. I saved the picture and sent it for processing. It helped me. Opencv has identified a circle representing a low-quality print (there are no such problems in high-quality documents). My code:
...ANSWER
Answered 2022-Mar-22 at 03:47Here's a simple approach:
Obtain binary image. Load image, convert to grayscale, Gaussian blur, then Otsu's threshold.
Merge small contours into a single large contour. We dilate using
cv2.dilate
to merge circles into a single contour.Find external contours. Finally we find external contours with the external
cv2.RETR_EXTERNAL
flag andcv2.drawContours()
Visualization of the image pipeline
Input image
Threshold for binary image
Dilate
Detected contours in green
Code
QUESTION
I'm implementing my own class, with custom __eq__
. And I'd like to return True
for things that are not "equal" in a mathematical sense, but "match" in a fuzzy way.
An issue with this is, however, that this leads to loss of transitivity in a mathematical sense, i.e. a == b && b ==c
, while a
may not be equal to c
.
Question: is Python dependent on __eq__
being transitive? Will what I'm trying to do break things, or is it possible to do this as long as I'm careful myself not to assume transitivity?
I want to match telephone numbers with one another, while those may be either formatted internationally, or just for domestic use (without a country code specified). If there's no country code specified, I'd like a number to be equal to a number with one, but if it is specified, it should only be equal to numbers with the same country-code, or without one.
So:
- Of course,
+31 6 12345678
should equal+31 6 12345678
, and06 12345678
should equal06 12345678
+31 6 12345678
should equal06 12345678
(and v.v.)+49 6 12345678
should equal06 12345678
(and v.v.)- But
+31 6 12345678
should not be equal to+49 6 12345678
Edit: I don't have a need for hashing (and so won't implement it), so that at least makes life easier.
...ANSWER
Answered 2022-Mar-14 at 18:06There is no MUST but a SHOULD relation for comparisons being consistent with the commonly understood relations. Python expressively does not enforce this and float
is an inbuilt type with different behaviour due to float("nan")
.
Expressions: Value comparisons[…]
User-defined classes that customize their comparison behavior should follow some consistency rules, if possible:
- […]
- Comparison should be symmetric. In other words, the following expressions should have the same result:
x == y
andy == x
x != y
andy != x
x < y
andy > x
x <= y
andy >= x
- Comparison should be transitive. The following (non-exhaustive) examples illustrate that:
- x > y and y > z implies x > z
- x < y and y <= z implies x < z
Python does not enforce these consistency rules. In fact, the not-a-number values are an example for not following these rules.
Still, keep in mind that exceptions are incredibly rare and subject to being ignored: most people would treat float
as having total order, for example. Using uncommon comparison relations can seriously increase maintenance effort.
Canonical ways to model "fuzzy matching" via operators are as subset, subsequence or containment using unsymmetric operators.
- The
set
andfrozenset
support>
,>=
and so on to indicate that one set encompases all values of another.
QUESTION
I am having trouble matching character strings. Most of the difficulty centers on abbreviation
I have two character vectors. I am trying to match words in vector A (typos) to the closes match in vector B.
...ANSWER
Answered 2022-Mar-07 at 17:10Maybe agrep
is what the question is asking for.
QUESTION
I have referred to this post but cannot get it to run for my particular case. I have two dataframes:
...ANSWER
Answered 2021-Dec-26 at 17:50You could try this:
QUESTION
I am trying to left-join df2
onto df1
.
df1
is my dataframe of interest, df2
contains additional information I need.
Example:
...ANSWER
Answered 2022-Feb-16 at 15:58The following works with the posted data examples but it uses two joins and is probably ineffective for larger data sets.
QUESTION
ANSWER
Answered 2021-Sep-03 at 12:11Not just XML preview, the Jetpack Compose preview is also very blurry on my Macbook. I tried the old trick Help > Edit custom properties and add:
hidpi=false
But this did not work (maybe it will work on Windows, you can try). Currently I have to revert back to Android Studio 4.2.2 .
QUESTION
I'm trying to connect my app with a firebase db, but I receive 4 error messages on app.module.ts:
...ANSWER
Answered 2021-Sep-10 at 12:47You need to add "compat" like this
QUESTION
Example
...ANSWER
Answered 2022-Feb-01 at 01:11Consider below approach
QUESTION
I am trying to apply a levenshtein function for each string in dfs
against each string in dfc
and write the resulting dataframe to csv. The issue is that I'm creating so many rows by using the cross join and then applying the function, that my machine is struggling to write anything (taking forever to execute).
Trying to improve write performance:
- I'm filtering out a few things on the result of the cross join i.e. rows where the
LevenshteinDistance
is less than 15% of the target word's. - Using bucketing on the first letter of each target word i.e. a, b, c, etc. still no luck (i.e. job runs for hours and doesn't generate any results).
ANSWER
Answered 2022-Jan-17 at 19:39There are a couple of things you can do to improve your computation:
Improve parallelism
As Nithish mentioned in the comments, you don't have enough partitions in your input data frames to make use of all your CPU cores. You're not using all your CPU capability and this will slow you down.
To increase your parallelism, repartition dfc
to at least your number of cores:
dfc = dfc.repartition(dfc.sql_ctx.sparkContext.defaultParallelism)
You need to do this because your crossJoin is run as a BroadcastNestedLoopJoin which doesn't reshuffle your large input dataframe.
Separate your computation stages
A Spark dataframe/RDD is conceptually just a directed action graph (DAG) of operations to run on your input data but it does not hold data. One consequence of this behavior is that, by default, you'll rerun your computations as many times as you reuse your dataframe.
In your fuzzy_match_approve
function, you run 2 separate filters on your df
, this means you rerun the whole cross-join operations twice. You really don't want this !
One easy way to avoid this is to use cache()
on your fuzzy_match result which should be fairly small given your inputs and matching criteria.
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