parsii | Super fast and simple evaluator | Machine Learning library

by scireum Java Version: Current License: MIT

X-Ray Key Features Code Snippets Community Discussions(1)Vulnerabilities Install Support

kandi X-RAY | parsii Summary

parsii is a Java library typically used in Artificial Intelligence, Machine Learning applications. parsii has no bugs, it has no vulnerabilities, it has build file available, it has a Permissive License and it has low support. You can download it from GitHub.

If you have questions or are just curious, please feel welcome to join the chat room: [Join the chat at Super fast and simple evaluator for mathematical expressions written in Java. More background information can be found in this blog post:

Support

Quality

Security

License

Reuse

Support

parsii has a low active ecosystem.

It has 173 star(s) with 62 fork(s). There are 37 watchers for this library.

It had no major release in the last 6 months.

There are 8 open issues and 14 have been closed. On average issues are closed in 17 days. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of parsii is current.

Quality

parsii has 0 bugs and 0 code smells.

Security

parsii has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

parsii code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

parsii is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

parsii releases are not available. You will need to build from source code and install.

Build file is available. You can build the component from source.

Installation instructions are not available. Examples and code snippets are available.

parsii saves you 905 person hours of effort in developing the same functionality from scratch.

It has 2060 lines of code, 227 functions and 23 files.

It has high code complexity. Code complexity directly impacts maintainability of the code.

Top functions reviewed by kandi - BETA

kandi has reviewed parsii and discovered the below as its top functions. This is intended to give you an instant insight into parsii implemented functionality, and help decide if they suit your requirements.

Subroutine to simplify the expression
Try to simplify the right - side expression
Returns the simplified version of this expression
Evaluates the operator
Simplifies this expression
Returns true if this expression is constant
Evaluates the function
Reads a single character
Creates a new ParseError for the given position
Sets the value of this variable
Adds a special id terminator
Determines whether the current token is more than the current token
Gets an EOI token
Removes all registered String delimiters
Removes a variable from this scope
Simplified expression
Returns a string representation of this Token
Returns a string representation of all errors
Determines if this token is a special identifier
Sets the parent scope
Returns a string representation of the item
Determines if this token is a keyword
Consumes the expected keyword with the expected content
Returns true if this token s content matches the given content
Consumes the given token as an expected symbol
Sets the problem collector

Get all kandi verified functions for this library.

parsii Key Features

No Key Features are available at this moment for parsii.

parsii Examples and Code Snippets

No Code Snippets are available at this moment for parsii.

Community Discussions

Trending Discussions on parsii

Bypassing the login page to send the user directly to the authorization URI

QUESTION

Bypassing the login page to send the user directly to the authorization URI

Asked 2018-Dec-07 at 20:32

I'm new to the Spring Framework and I'm trying to set up my application with Spring Security using Azure AD authentication. I have the basics set up and my application correctly authenticates to Azure AD.

The question I have involves bypassing the default "/login" page that gets generated. Instead of landing on the default "/login" page (or creating my own custom one) when authentication is required, I would like the application to automatically redirect to Microsoft's login page.

My dependencies:

...

ANSWER

Answered 2018-Dec-07 at 20:32

If you would like to bypass the default generated login page and automatically trigger authentication, you need to configure oauth2Login().loginPage(..)

For example:

Source https://stackoverflow.com/questions/53623746

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install parsii

You can download it from GitHub.
You can use parsii like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the parsii component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

Find more information at: