scouter | open source APM ( Application Performance Management | Performance Testing library
kandi X-RAY | scouter Summary
kandi X-RAY | scouter Summary
Scouter is an open source APM (Application Performance Management) tool.
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Top functions reviewed by kandi - BETA
- Creates the components .
- Get sample contents .
- Builds the profile .
- Build a thread profile .
- Signal end of http service .
- Builds the area charts
- Start tracing context
- Fills the context menu .
- Performs search with text matching .
- Setup the dialog layout .
scouter Key Features
scouter Examples and Code Snippets
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Trending Discussions on scouter
QUESTION
I am creating a program that involves pointers and arrays and I have stumbled upon a problem. Basically, I created three integers that would get its value from the user's input and later declared them all in an array in order to change all of their values in one single loop.
Then I declared a pointer which uses the array inside a loop in order to do that.
Expecting the pointer-array in the loop to print out the data in a normal order, rather, it had printed it backwards.
Mind you, I am a huge beginner to programming C++ and is still learning about pointers.
I have tried changing the index number in
...ANSWER
Answered 2021-Aug-17 at 14:45#include
using namespace std;
int main() {
int salary1, salary2, salary3;
cout << "Enter salary for John: ";
cin >> salary1;
cout << "Enter salary for Mark: ";
cin >> salary2;
cout << "Enter salary for Nathan: ";
cin >> salary3;
cout << "Name \t Age \t Position \t Salary" << endl;
cout << "John \t 16 \t Engineer \t " << salary1 << endl;
cout << "Mark \t 16 \t Scouter \t " << salary2 << endl;
cout << "Nathan \t 17 \t Manager \t " << salary3 << endl;
int salary[3] = {salary1, salary2, salary3};
for (int x = 0; x < 3; x++) {
cout << "Enter new salary: " << endl;
cin >> * (salary + x);
cout << "Salary " << x << ": " << * (salary + x) << endl;
}
cout << "Name \t Age \t Position \t Salary" << endl;
cout << "John \t 16 \t Engineer \t " << salary[0] << endl;
cout << "Mark \t 16 \t Scouter \t " << salary[1] << endl;
cout << "Nathan \t 17 \t Manager \t " << salary[2] << endl;
}
QUESTION
I am currently writing code for a scout system I have multiple classes and the hierarchy goes as follows iScoutMember -> Scout(implements iScoutMember) -> BeaverScout
(extends Scout). I also have a ScoutList
class that handles adding scouts to the ArrayList
of scouts and ScoutSystem
which makes a menu and uses the methods from the ScoutList
class.
The error I get is from the addScout method in the ScoutSystem
class when I try to add info for the ArrayList SpecialInterests
This is the error info
Error:(108, 103) java: incompatible types: SpecialInterest cannot be converted to java.util.ArrayList
Error:(112, 103) java: incompatible types: SpecialInterest cannot be converted to java.util.ArrayList
This is the code for the Scout class
...ANSWER
Answered 2020-Apr-06 at 17:34Your question isn't extremely clear, but from what I can tell, you're passing in a single SpecialInterest
object (sp1
) in the addScout method at:
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