Perm | Perm is a library that makes it simple to check and request | Android library
kandi X-RAY | Perm Summary
kandi X-RAY | Perm Summary
Perm is a library that makes it simple to check and request Android Permissions at runtime (like Camera or GPS) for Apps targetting Android 6 or more. Note that since version 1.1.1 of the library it is possible to request several Permissions at the same time. Permissions can now also be checked from an Androidx Fragment.
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Top functions reviewed by kandi - BETA
- Returns true if the specified permission is granted
- Checks if the given permission name is a valid Android permission
- Returns true if this permission has been denied
- Returns whether the given permission is denied or not
- Returns true if all the Permissions are granted
- Returns true if all the result has been denied
- Returns true if the result has been granted
- Requests android permissions
- Returns true if the given permission has been denied
- Returns true if the given permission has been granted
Perm Key Features
Perm Examples and Code Snippets
Community Discussions
Trending Discussions on Perm
QUESTION
I'm wanting to create a list of permutations or cartesian products (not sure which one applies here) where the sum of values in each permutation totals to a provided value.
There should be three parameters required for the function.
- Sample Size: The number of items in each permutation
- Desired Sum: The total that each permutation should add up to
- Set of Numbers: The set of numbers that can be included with repetition in the permutations
I have an implementation working below but it seems quite slow I would prefer to use an iterator to stream the results but I would also need a function that would be able to calculate the total number of items that the iterator would produce.
...ANSWER
Answered 2022-Apr-10 at 06:40Here is one way to break this down into two subproblems:
- Find all restricted integer partitions of
target_sum
intosample_size
summands s.t. all summands come fromset_of_number
. - Compute multiset permutations for each partition (takes up most of the time).
Problem 1 can be solved with dynamic programming. I used multiset_permutations
from sympy
for part 2, although you might be able to get better performance by writing your own numba code.
Here is the code:
QUESTION
Question in short
To have a proper input for pycosat, is there a way to speed up calculation from dnf to cnf, or to circumvent it altogether?
Question in detail
I have been watching this video from Raymond Hettinger about modern solvers. I downloaded the code, and implemented a solver for the game Towers in it. Below I share the code to do so.
Example Tower puzzle (solved):
...ANSWER
Answered 2022-Mar-19 at 22:23First, it's good to note the difference between equivalence and equisatisfiability. In general, converting an arbitrary boolean formula (say, something in DNF) to CNF can result in a exponential blow-up in size.
This blow-up is the issue with your from_dnf
approach: whenever you handle another product term, each of the literals in that product demands a new copy of the current cnf clause set (to which it will add itself in every clause). If you have n product terms of size k, the growth is O(k^n)
.
In your case n
is actually a function of k!
. What's kept as a product term is filtered to those satisfying the view constraint, but overall the runtime of your program is roughly in the region of O(k^f(k!))
. Even if f grows logarithmically, this is still O(k^(k lg k))
and not quite ideal!
Because you're asking "is this satisfiable?", you don't need an equivalent formula but merely an equisatisfiable one. This is some new formula that is satisfiable if and only if the original is, but which might not be satisfied by the same assignments.
For example, (a ∨ b)
and (a ∨ c) ∧ (¬b)
are each obviously satisfiable, so they are equisatisfiable. But setting b
true satisfies the first and falsifies the second, so they are not equivalent. Furthermore the first doesn't even have c
as a variable, again making it not equivalent to the second.
This relaxation is enough to replace this exponential blow-up with a linear-sized translation instead.
The critical idea is the use of extension variables. These are fresh variables (i.e., not already present in the formula) that allow us to abbreviate expressions, so we don't end up making multiple copies of them in the translation. Since the new variable is not present in the original, we'll no longer have an equivalent formula; but because the variable will be true if and only if the expression is, it will be equisatisfiable.
If we wanted to use x
as an abbreviation of y
, we'd state x ≡ y
. This is the same as x → y
and y → x
, which is the same as (¬x ∨ y) ∧ (¬y ∨ x)
, which is already in CNF.
Consider the abbreviation for a product term: x ≡ (a ∧ b)
. This is x → (a ∧ b)
and (a ∧ b) → x
, which works out to be three clauses: (¬x ∨ a) ∧ (¬x ∨ b) ∧ (¬a ∨ ¬b ∨ x)
. In general, abbreviating a product term of k literals with x
will produce k binary clauses expressing that x
implies each of them, and one (k+1)
-clause expressing that all together they imply x
. This is linear in k
.
To really see why this helps, try converting (a ∧ b ∧ c) ∨ (d ∧ e ∧ f) ∨ (g ∧ h ∧ i)
to an equivalent CNF with and without an extension variable for the first product term. Of course, we won't just stop with one term: if we abbreviate each term then the result is precisely a single CNF clause: (x ∨ y ∨ z)
where these each abbreviate a single product term. This is a lot smaller!
This approach can be used to turn any circuit into an equisatisfiable formula, linear in size and in CNF. This is called a Tseitin transformation. Your DNF formula is simply a circuit composed of a bunch of arbitrary fan-in AND gates, all feeding into a single arbitrary fan-in OR gate.
Best of all, although this formula is not equivalent due to additional variables, we can recover an assignment for the original formula by simply dropping the extension variables. It is sort of a 'best case' equisatisfiable formula, being a strict superset of the original.
To patch this into your code, I added:
QUESTION
So I have a list of dicts containing letters and their frequencies.
...ANSWER
Answered 2022-Mar-02 at 22:14itertools.product
is indeed what you want.
QUESTION
I have an object which looks like this :
...ANSWER
Answered 2022-Feb-23 at 18:06You could map new entries from the object and take the mapped new structure.
QUESTION
Some functions take a long time to execute. I want to make the user wait with a progress bar. Unfortunately, when I run this one, it runs but only at the end of my function and not when I would like. Let me explain, I launch my progress bar with the "sendloading()" method but during my tests this bar is only displayed after the processing of the other functions "copyAssets" or "createOnClicBtnInsert()". Can someone explain to me why?
Here is my code :
...ANSWER
Answered 2022-Feb-07 at 16:00Android is an event driven OS that runs on a single main thread. Drawing is an event. That means in order to draw the main thread needs to return to the event loop. Your code does not return to the event loop until after you do all your processing. Thus it won't draw until after the processing is done.
The way to solve this is to use either a Thread or a Kotlin coroutine to do the processing, and allow the main thread to return to the event loop. BTW, if you have long lasting processing you should not be doing it on the main thread anyway- it freezes your UI and makes your app appear non responsive, for the same reason. The main thread should do short quick calculations and respond to OS events only.
QUESTION
Implementing self attention in tensorflow Keras with a bit modification ( e.g., residual (add connection)).
I have the following input shape:
myinput: KerasTensor(type_spec=TensorSpec(shape=(None, 8, 6, 64), dtype=tf.float32, name=None), name='multiply/mul:0', description="created by layer 'multiply'")
My goal is to process TensorSpec(shape=(None, 8, 6, 64) (8 time stamps one by one (6 * 64)) through self attention and get self attention feature map for every time stamp and then concatenate it again into output tensor shape (None, 8, 6, 64).
Implemented Code:
...ANSWER
Answered 2022-Jan-31 at 10:03Make sure the number of channels are the same as the last dimension of your input data. Also adding a comma here: f = self.query(x),
creates a tuple, which you probably do not want: Here is a working example:
QUESTION
I am trying to create a command that lists the permissions that the user has in the current channel. I have tried using a function that adds permissions to a list and calling it in the command.
Unfortunately, this command sends all of the permissions that a member could possibly have, rather than the permissions that the member has currently. How could I edit my code into finding what permissions the member has currently?
...ANSWER
Answered 2022-Jan-12 at 08:45As described in the docs, a discord.Permissions object defines the __iter__
-method by returning a list of tuples (permission_name, permission_value)
, where permission_value
will be True
if the member has the permission and False
otherwise. You simply need to add a check if the value is true before appending the name to your list like so:
QUESTION
I have a procedure that returns a recordset using the cursor method:
...ANSWER
Answered 2022-Jan-09 at 08:53The procedure receives a name as its argument and returns a server-side cursor with that name. On the client side, after calling the procedure you must declare a named cursor with the same name and use it to access the query results. You must do this before committing the connection, otherwise the server-side cursor will be destroyed.
QUESTION
I want to program a ban
command for my Discord bot. I have this line where the bot should check if a user has the Administrator permission. If the user that should get banned has them, the bot doesn't ban the user and crashes. When I try to run this command I get this:
ANSWER
Answered 2022-Jan-08 at 17:56"TypeError: Cannot read properties of undefined (reading 'has')" means that mention.permissions
is undefined
. It's because your mention
variable is a User
and only GuildMember
s have permissions
.
Another error is that you try to check if the role.id
is equal to a number/integer but snowflakes (like 589850931785498624
) should always be strings as these are greater than the MAX_SAFE_INTEGER
.
QUESTION
I am trying to generate all permutations for an array using the Heap's algorithm that I found in wikipedia.
This is what I tried so far:
...ANSWER
Answered 2022-Jan-02 at 09:54To implement Heap's algorithm in R, here is a solution that outputs the result in a matrix for further processing:
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