MyLib | 现在网上有很多此种类型的 lib，但是别人的终究是别人的，只有自己认真总结，自己熟悉的 lib

lua_yield is a C function, and C does not have a mechanism to magically jump back into a function that has halted. lua_yield uses the C standard library longjmp function to arbitrarily jump out of the function that called it. But it can't come back.

So what happens is that your C function yields, exiting the function and returning control to the Lua code that called coroutine.resume. The resume was successful, so true is printed. You then resume the coroutine again, which begins execution at the site in Lua code that called the C function that yielded. That code then exits the coroutine normally. Since the resume was also successful, true is printed again.

But the coroutine is now exhausted and therefore cannot be resumed.

C functions don't have a clean way to be "resumed". Indeed, the Lua 5.1 documentation explicitly states:

This function should only be called as the return expression of a C function, as follows:

As Broots already mentioned the function signature for InserirEstatisticasEquipas requires that you return a single instance of EstatisticasEquipas, but the variable that you attempt to return is actually a List.

How you want to solve it depends on what you're trying to achieve, but the code in your main program indicates that you actually want a list, so you can simply change the return type of the function like so:

The actual problem was that linter was executed very very slowly (so slow that seemed to hang, unless you use debug), so in order for the issue to be fixed, in the inner .eslintrc.json of each project, under parserOptions, in the project array, I added tsconfig.json

There is no need to check this for static libraries. Static libraries are just archives with object files and they have no runtime dependencies. They are linked directly to your final binary file.

You should read more about how linker works:

• Stack overslow answer
• Wikipedia
• Youtube video

If you compile your final binary without libc++ and do not have any "undefined reference" error - everything is fine. Otherwise if the undefined symbols are functions from lib++, your static libraries were compiled with libc++ support.

The only way you can check symbole before linkage stage is checks symbols, which static libraries contain. See this answer about how to do this

Found it - in the .csproj file, in the "main" PropertyGroup element, add the element

ctypes doesn't understand C++ inheritance, even though you can declare the ctypes Structures similarly using Python inheritance.

You can solve the issue one of two ways. Below I've adjusted the C++ code to give some feedback that the structures are accessed properly:

test.cpp:

The short answer is "No, it is not"

In your case, your record may or may not be passed by reference. The size of the record is 1 of the factor I know of that affect that behavior. If your record is 4 bytes or less, I believe it will be passed by value, otherwise, it will be passed by reference. I don't believe this behavior is contractual (In other word, Embarcadero is free to change it at any time in the future). In other words, it's a bad idea to use const parameter to call an external function.

If you want to pass your record by reference, the proper way to do would be to declare it var

How? You need to follow "stubbed module can not be destructured." on the official guide How to stub a dependency of a module

For example I have file external-function.js, combo.js and test.js on the same directory. I choose to use console.log to show that stub works and fake function get called, because you are not expecting something returned on myMethod.

I managed to do this by running a script containing all the commands I need instead of running separate commands, since cd always fails to run on chroot (even though the directory is inside the jail). Here's the command: