sparrow | Desktop Bitcoin Wallet focused on security and privacy | Ecommerce library
kandi X-RAY | sparrow Summary
kandi X-RAY | sparrow Summary
Sparrow is a modern desktop Bitcoin wallet application supporting most hardware wallets and built on common standards such as PSBT, with an emphasis on transparency and usability. More information (and release binaries) can be found at Release binaries are also available directly from Github.
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Top functions reviewed by kandi - BETA
- Initialize the view
- Returns a change listener for the proxy server
- Returns a listener for the Bitcoin core core core
- SetEditable boolean
- Creates a transaction based on the given input address
- Create a transaction
- Sets the text for the item
- Creates a tooltip for a transaction
- Initialize view
- Sets the list of PayNym objects to the followers
- New wallet transactions
- Discover the keystores available in the wallet
- Create the pin entry
- Starts the Electrum connection
- Updates the item table
- Selecting a private part
- Sets the item to be displayed
- Main entry point
- Fetches the wallet and returns the transactions
- Increases the fee for a transaction
- Initialize view
- Exports a wallet to an output stream
- Broadcast a transaction
- Request payjoin
- Initializes the view
- Runs the loading wizard
sparrow Key Features
sparrow Examples and Code Snippets
Community Discussions
Trending Discussions on sparrow
QUESTION
#include
struct BirdHome{
char area[500];
char heightcm[100];
char feederquantity[10];
char hasNest[5];
};
struct Bird{
char isRinged[5];
char nameSpecies[50];
char birdAgeMonths[500];
struct BirdHome hom;
char gender[6];
};
struct Bird birds;
int main(void){
FILE *oput;
int max=100;
int count = 0;
char filename[100];
printf("file name? : ");
scanf("%s", &filename);
count = load(filename, &birds, max);
if (count == 0)
printf("No structures loaded\n");
else (
printf("Data loaded\n")
);
save(&birds, oput);
return 0;
}
int load(char *filename, struct Bird *birds, int max){
int count = 0;
FILE *fp = fopen(filename, "r");
char line[100 * 4];
if (fp == NULL)
return 1;
while (count < max && fgets(line, sizeof(line), fp) != NULL){
sscanf(line, "%s %s %s %s %s %s %s %s", birds[count].isRinged, birds[count].nameSpecies,
birds[count].birdAgeMonths, birds[count].hom.area,
birds[count].hom.heightcm, birds[count].hom.feederquantity,
birds[count].hom.hasNest,birds[count].gender);
count++;
}
fclose(fp);
return count;
}
int save (struct Bird *birds, FILE *oput){
int i;
oput=fopen("birdssave.txt","w");
for (i=0;i<3;i++){
fprintf(oput,"%s %s %s %s %s %s %s %s\n",birds[i].isRinged, birds[i].nameSpecies,
birds[i].birdAgeMonths, birds[i].hom.area,
birds[i].hom.heightcm, birds[i].hom.feederquantity,
birds[i].hom.hasNest,birds[i].gender);
}
fclose(oput);
}
ANSWER
Answered 2021-May-30 at 10:50The load function is made unproperly so it doesn't work. The normal functions does a lot more things to do. Here is the text of it with the needed commentaries
QUESTION
I need to mark documets as expired after some time and therefore I am trying to use @refresh feature to re-run subscription and to compute my 'expired' flag. I know there is 'Document expiration' feature but this one removes data which I don't want.
I have turned Refresh feature in settings and added @refresh UTC datetime in metadata for required documents. For example I added manually this document:
...ANSWER
Answered 2021-May-18 at 11:28The bug related to document that was added via cluster transaction, the workaround for now would be to not use cluster transaction.
I have opened an issue on bug tracker, https://issues.hibernatingrhinos.com/issue/RavenDB-16710
QUESTION
I am miserably stuck at Pandas Data Cleaning. I have made a very simple example to demonstrate my problem. For each row, I want to delete/alter the duplicate and keep the last one. Currently, my DataFrame is 'animals'. And I want it to be the DataFrame 'animals_clean'
Imagine this DataFrame. You can see duplicates along axis=0, e.g. 'cat' is repeated in row 0
...ANSWER
Answered 2021-May-17 at 23:52Try apply + mask + duplicated with keep='last':
QUESTION
I am running into issues getting my code to run through a list of words and list the location of the letters in the list. It works fine in listing location for the first two words, but when it encounters a word without the specified letter, the code skips. I will paste the problem and my current code as well as current output below.
words = ["dog", "sparrow", "cat", "frog"]
#You may modify the lines of code above, but don't move them! #When you Submit your code, we'll change these lines to #assign different values to the variables.
#This program is supposed to print the location of the 'o' #in each word in the list. However, line 22 causes an #error if 'o' is not in the word. Add try/except blocks #to print "Not found" when the word does not have an 'o'. #However, when the current word does not have an 'o', the #program should continue to behave as it does now.
#Hint: don't worry that you don't know how line 18 works. #All you need to know is that it may cause an error.
#You may not use any conditionals.
#Fix this code!
My Code
...ANSWER
Answered 2021-Apr-28 at 19:26You only need to add try-except block like this:
QUESTION
ANSWER
Answered 2021-Apr-28 at 11:35You need to pass the value of `{{widgets.Mortgage_info.Digits}}`` into the Twilio Function via the Run Function Widget Function Parameters.
You can see how this may work by looking at this code example.
QUESTION
I want to test my if else condition in the Twilio function.
The condition is if the user will text "Hi", Twilio will send him a quote.
The problem the condition always runs false even if I texted "Hi".
I'm not sure if the event.Body is the right code to get the value of the message body.
ANSWER
Answered 2021-Apr-28 at 10:56Step 1,
Use the split Based Widget and input to the "Variable to Test" trigger.message.Body
Then add a condition in the Split Based Widget that could be found in the Transitions tab, if the incoming messages is equal to "Hi" then it will proceed to the next widget
Step 2,
- Then add a message widget that tells the sender Fetching quote, the purpose of this is just to tell the sender that your processing the quoted message. This is just optional, you can remove this if you want.
Step 3
- Then create a function to parse the external API for the quoted message. Make sure to add the got module as Dependencies
Step 4
- And Lastly Parsed the Quote in the Body of the Send Message widget.
QUESTION
I'm having the following results from my sql query:
id sp_firstname sp_lastname member_firstname member_lastname 1 NULL NULL John Smith 2 Dejuan McLaughlin NULL NULL 2 NULL NULL Jack Sparrow 3 John Walker NULL NULL 3 NULL NULL Sherlock Holmes 4 Mellie Durgan NULL NULL 4 NULL NULL John Waston 5 Lucy Snider NULL NULLWhereas what I need to achieve is this:
id sp_firstname sp_lastname member_firstname member_lastname 1 NULL NULL John Smith 2 Dejuan McLaughlin Jack Sparrow 3 John Walker Sherlock Holmes 4 Mellie Durgan John Waston 5 Lucy Snider NULL NULLBasically, I need to somehow merge pairs of rows that sort of have nulls crosswise.
After looking through SO answers, I could only find variants of this problem when NULL values needed to be substituted by numbers, and in that case people used max function combined with group by.
However I have several joins in my table and my NULL values need to be substituted with strings, not numbers, so max wouldn't really work here (as I thought).
Here's my sql code:
...ANSWER
Answered 2021-Apr-21 at 18:46You can wrap your results with an outer query to aggregate the columns using max and group by the id
QUESTION
I have a dataframe that is structured like this:
...ANSWER
Answered 2021-Mar-06 at 18:43Use map here with fillna:
QUESTION
#include
#include
struct birdhome{
int area;
int heightcm;
int feederquantity;
char hasNest[6];
};
struct bird{
char isRinged[6];
char nameSpecies[50];
int birdAgeMonths;
struct BirdHome *hom;
char gender[7];
};
int save(char * filename, struct bird *st, int n);
int load(char * filename);
int main(void)
{
char * filename = "birds.dat";
struct bird birds[] = { "True","sparrow",3,10,20,2,"False","Male","False","crane",24,50,100,6,"True","Female","False","False","griffin",10,100,80,1,"False","Male" };
int n = sizeof(struct bird) / sizeof(birds[0]);
save(filename, birds, n);
load(filename);
return 0;
}
int save(char * filename, struct bird * st, int n)
{
FILE * fp;
char *c;
int size = n * sizeof(struct bird);
if ((fp = fopen(filename, "wb")) == NULL)
{
perror("Error occured while opening file");
return 1;
}
c = (char *)&n;
for (int i = 0; i0)
{
i = getc(fp);
if (i == EOF) break;
*c = i;
c++;
m--;
}
n = *pti;
struct bird * ptr = (struct bird *) malloc(n * sizeof(struct bird));
c = (char *)ptr;
while ((i= getc(fp))!=EOF)
{
*c = i;
c++;
}
printf("\n%d birds in the file stored\n\n", n);
for (int k = 0; kisRinged, (ptr + k)->nameSpecies,(ptr + k)->birdAgeMonths,(ptr + k)->hom.area,(ptr + k)->hom.heightcm,(ptr + k)->hom.feederquantity,(ptr + k)->hom.hasNest,(ptr + k)->gender);
}
ANSWER
Answered 2021-Feb-18 at 09:40The problem is that bird.hom is a pointer. Saving a pointer to a file is not a useful thing to do, because memory addresses change from one process to another. It's also not saving the contents of the BirdHome structure. And your initialization of birds doesn't work, because you can't initialize members of an indirect structure as part of the main structure.
You should declare it as an embedded structure rather than a pointer.
QUESTION
I'm trying to copy data over from one Panadas DataFrame into another and I'm getting some strange results. For example if I have:
...ANSWER
Answered 2021-Feb-15 at 17:15Using your code I get this (Jupiter Notebook). So your code seems to work right?
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install sparrow
You can use sparrow like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the sparrow component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .
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