JavaEE | ️框架学习笔记 | Object-Relational Mapping library

 by   sunnyandgood Java Version: Current License: No License

kandi X-RAY | JavaEE Summary

kandi X-RAY | JavaEE Summary

JavaEE is a Java library typically used in Utilities, Object-Relational Mapping, Spring Boot, Spring, Maven, Hibernate applications. JavaEE has no bugs, it has no vulnerabilities and it has low support. However JavaEE build file is not available. You can download it from GitHub.

️框架(SSM/SSH)学习笔记
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            kandi-support Support

              JavaEE has a low active ecosystem.
              It has 26 star(s) with 14 fork(s). There are no watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              JavaEE has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of JavaEE is current.

            kandi-Quality Quality

              JavaEE has 0 bugs and 0 code smells.

            kandi-Security Security

              JavaEE has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              JavaEE code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              JavaEE does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
              OutlinedDot
              Without a license, all rights are reserved, and you cannot use the library in your applications.

            kandi-Reuse Reuse

              JavaEE releases are not available. You will need to build from source code and install.
              JavaEE has no build file. You will be need to create the build yourself to build the component from source.
              JavaEE saves you 978 person hours of effort in developing the same functionality from scratch.
              It has 2225 lines of code, 253 functions and 33 files.
              It has medium code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed JavaEE and discovered the below as its top functions. This is intended to give you an instant insight into JavaEE implemented functionality, and help decide if they suit your requirements.
            • Runs the user .
            • String representation of this User object .
            • Creates the criteria object .
            • Clears this criteria .
            • Creates a new OR instance of this Criteria
            • Select all users .
            • Sets the email address .
            • Set the user name .
            • Get the user list .
            • Set the user list .
            Get all kandi verified functions for this library.

            JavaEE Key Features

            No Key Features are available at this moment for JavaEE.

            JavaEE Examples and Code Snippets

            No Code Snippets are available at this moment for JavaEE.

            Community Discussions

            QUESTION

            javax.naming.NoInitialContextException: Need to specify class name in environment or system property Heroku deploy
            Asked 2021-Jun-14 at 06:51

            Im trying to deploy a java web app to heroku, I did all their steps from https://devcenter.heroku.com/articles/deploying-java-applications-with-the-heroku-maven-plugin, but when I try to open a page where I have data from db I am getting:

            ...

            ANSWER

            Answered 2021-Jun-14 at 06:51

            changing pom.xml solved my problem:

            Source https://stackoverflow.com/questions/67911012

            QUESTION

            Printing Text before redirecting to another link
            Asked 2021-Jun-14 at 02:22

            I want to print some text before redirecting my response to google search link..but I am unable to print it.My code for redirecting servlet is as below:

            ...

            ANSWER

            Answered 2021-Jun-14 at 02:22

            sendRedirect is sending a response code like 302 or 304 (I assume 302 Temporary Redirect) to the browser and a Location header telling the client where to go instead. This is then handled transparently by the browser, without it ever having to display anything.

            To see the HTTP response for yourself use curl -v http://yourendpoint, or use Postman if you prefer a browser based tool. Or you can look at the request/response in your browser dev tools, under the network tab (you might have to find an option that doesn't clear the inpector history on page load).

            Alternatively you would pass the redirect url to the page and do the redirect later with javascript.

            You could respond with something like this, to display the page and redirect after 3 seconds:

            Source https://stackoverflow.com/questions/67961954

            QUESTION

            liberty:devc: not being honored
            Asked 2021-Jun-11 at 00:28

            I observe that the element, though it points to a valid Dockerfile is not honored by liberty:devc.

            Consider this output from mvn help:effective-pom:

            ...

            ANSWER

            Answered 2021-Jun-11 at 00:28
            SOLUTION: Use plugin-level configuration (not execution-level)

            You need to add your configuration at the plugin level rather than the execution level.

            So it should look more like:

            Source https://stackoverflow.com/questions/67929205

            QUESTION

            How to configure correctly an authentication using Tomcat 10?
            Asked 2021-Jun-10 at 13:44

            I'm using Tomcat 10 and eclipse to develop a J2E (or Jakarta EE) web application. I followed this tutorial (http://objis.com/tutoriel-securite-declarative-jee-avec-jaas/#partie2) which seems old (it's a french document, because i'm french, sorry if my english isn't perfect), but I also read the Tomcat 10 documentation.
            The dataSource works, I followed instructions on this page (https://tomcat.apache.org/tomcat-10.0-doc/jndi-datasource-examples-howto.html#Oracle_8i,_9i_&_10g) and tested it, but it seems that the realm doesn't work, because I can't login successfully. I always have an authentification error, even if I use the right login and password.
            I tried a lot of "solutions" to correct this, but no one works. And I still don't know if I have to put the realm tag inside context.xml, server.xml or both. I tried context.xml and both, but i don't see any difference.

            My web.xml :

            ...

            ANSWER

            Answered 2021-Jun-10 at 13:44

            As Piotr P. Karwasz said it, I misspelled dataSourceName in context.xml and server.xml file. I feel bad that I didn't notice it.

            But I still have one question : In which document should I put the realm tag ?

            Source https://stackoverflow.com/questions/67908137

            QUESTION

            Tomcat 10.0.4 doesn't load servlets (@WebServlet classes) with 404 error
            Asked 2021-Jun-09 at 10:19

            I'm having a problem with my first Web Application. I use IntelliJ as IDE and Tomcat as Webserver. Every servlet I've tried to acces, throws an 404 Error. Even if I copy some youtube tutorials, which seems to work like a charm.

            The button in the form sends me to: http://localhost:8080/IUBHQuiz/login

            Can you tell me whats wrong? I am going nuts.

            login.java

            ...

            ANSWER

            Answered 2021-Mar-25 at 22:17

            I had the same issue while reproducing the problem reported at IntelliJ IDEA forums.

            It didn't work with Tomcat 10 for the reasons described in the answer by Piotr P. Karwasz, but it works just fine with Tomcat 9.0.44 and earlier versions.

            Source https://stackoverflow.com/questions/66806582

            QUESTION

            How to store ResourceBundle object In session java?
            Asked 2021-Jun-07 at 22:01

            I have taglibrary for localization that contains 3 tags and one tag file:

            SetLocale - set selected Locale to session
            SetBundle - tag set's bundle to session by using Locale which Is aquired by session

            ...

            ANSWER

            Answered 2021-Jun-07 at 22:01

            It is theoretically possible to store all keys and values from a ResourceBundle in a serializable object, but you don’t need to. You can just store the Locale and the name of the ResourceBundle in your session.

            A web application has the same classpath for its entire lifetime, so the ResourceBundle will always be available by that name.

            Source https://stackoverflow.com/questions/67876017

            QUESTION

            Servlet mapping not found error while deploying JAX RS application to web sphere 8.5
            Asked 2021-May-31 at 16:53

            I am new to web services. have developed a simple rest web svc in java using Eclipse, Tomcat following this link. Application successfully runs on Tomcat but when i deploy it to IBM WebSphere 8.5.5. It deploys successfully but fails to start. I know its something with my Web.xml so i am adding it for rectification. Tried this but to no avail.

            ...

            ANSWER

            Answered 2021-May-31 at 13:56

            It's giving the error that "org.glassfish.jersey.servlet.ServletContainer" is missing in the Class path. Because of which the application is not starting.

            See the version of Jersey that is compatible with WAS 8.5.5? (I think it's Jersey 1.x). The corresponding library needs to be used.

            Source https://stackoverflow.com/questions/67740051

            QUESTION

            Why doesn`t url change when running servlet that presents in welcome-file-list
            Asked 2021-May-30 at 18:58

            I have simple servlet that prints something to response

            ...

            ANSWER

            Answered 2021-May-30 at 18:58

            That is the way welcome resources are supposed to work:

            The container may send the request to the welcome resource with a forward, a redirect, or a container specific mechanism that is indistinguishable from a direct request.

            (Servlet 5.0 Specification)

            Tomcat redirects the request internally. If you want to send a HTTP redirect, you need to do it yourself. You can check the original URI to see if the request was forwarded by the welcome files mechanism:

            Source https://stackoverflow.com/questions/67762678

            QUESTION

            Class not found even though it is clearly visible in Web App Libraries
            Asked 2021-May-26 at 17:16

            Similar question exists but none of the answers helped.

            Starting Tomcat Server 9 on my Eclipse Project gives the error

            ...

            ANSWER

            Answered 2021-May-26 at 17:16

            Remove the .class suffix

            Source https://stackoverflow.com/questions/67709436

            QUESTION

            Tomcat UserDatabase Unexpected error creating MBeans
            Asked 2021-May-23 at 14:37

            server.xml

            ...

            ANSWER

            Answered 2021-May-23 at 14:37

            The UserDatabaseRealm (cf. documentation) requires a resource of type org.apache.catalina.UserDatabase (not to be confused with a database connection pool, which is of type javax.sql.DataSource).

            In your configuration you provided the wrong object factory class name: you used org.apache.tomcat.jdbc.pool.DataSourceFactory, which creates Tomcat JDBC connection pools, instead of org.apache.catalina.users.MemoryUserDatabaseFactory.

            Just use:

            Source https://stackoverflow.com/questions/67660140

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install JavaEE

            You can download it from GitHub.
            You can use JavaEE like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the JavaEE component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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