DataMiningClassifier | text classifier based on Decision Trees ID3 | Machine Learning library
kandi X-RAY | DataMiningClassifier Summary
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- Main function for example
- Performs CRATE classification
- Returns the probability of CATE CATE words for the train file
- Get the CATE words
- Gets the cate words count
DataMiningClassifier Key Features
DataMiningClassifier Examples and Code Snippets
Trending Discussions on Machine Learning
Trending Discussions on Machine Learning
QUESTION
I have trained an RNN model with pytorch. I need to use the model for prediction in an environment where I'm unable to install pytorch because of some strange dependency issue with glibc. However, I can install numpy and scipy and other libraries. So, I want to use the trained model, with the network definition, without pytorch.
I have the weights of the model as I save the model with its state dict and weights in the standard way, but I can also save it using just json/pickle files or similar.
I also have the network definition, which depends on pytorch in a number of ways. This is my RNN network definition.
import torch
import torch.nn as nn
import torch.nn.functional as F
import torch.optim as optim
import random
torch.manual_seed(1)
random.seed(1)
device = torch.device('cpu')
class RNN(nn.Module):
def __init__(self, input_size, hidden_size, output_size,num_layers, matching_in_out=False, batch_size=1):
super(RNN, self).__init__()
self.input_size = input_size
self.hidden_size = hidden_size
self.output_size = output_size
self.num_layers = num_layers
self.batch_size = batch_size
self.matching_in_out = matching_in_out #length of input vector matches the length of output vector
self.lstm = nn.LSTM(input_size, hidden_size,num_layers)
self.hidden2out = nn.Linear(hidden_size, output_size)
self.hidden = self.init_hidden()
def forward(self, feature_list):
feature_list=torch.tensor(feature_list)
if self.matching_in_out:
lstm_out, _ = self.lstm( feature_list.view(len( feature_list), 1, -1))
output_space = self.hidden2out(lstm_out.view(len( feature_list), -1))
output_scores = torch.sigmoid(output_space) #we'll need to check if we need this sigmoid
return output_scores #output_scores
else:
for i in range(len(feature_list)):
cur_ft_tensor=feature_list[i]#.view([1,1,self.input_size])
cur_ft_tensor=cur_ft_tensor.view([1,1,self.input_size])
lstm_out, self.hidden = self.lstm(cur_ft_tensor, self.hidden)
outs=self.hidden2out(lstm_out)
return outs
def init_hidden(self):
#return torch.rand(self.num_layers, self.batch_size, self.hidden_size)
return (torch.rand(self.num_layers, self.batch_size, self.hidden_size).to(device),
torch.rand(self.num_layers, self.batch_size, self.hidden_size).to(device))
I am aware of this question, but I'm willing to go as low level as possible. I can work with numpy array instead of tensors, and reshape instead of view, and I don't need a device setting.
Based on the class definition above, what I can see here is that I only need the following components from torch to get an output from the forward function:
- nn.LSTM
- nn.Linear
- torch.sigmoid
I think I can easily implement the sigmoid function using numpy. However, can I have some implementation for the nn.LSTM and nn.Linear using something not involving pytorch? Also, how will I use the weights from the state dict into the new class?
So, the question is, how can I "translate" this RNN definition into a class that doesn't need pytorch, and how to use the state dict weights for it? Alternatively, is there a "light" version of pytorch, that I can use just to run the model and yield a result?
EDITI think it might be useful to include the numpy/scipy equivalent for both nn.LSTM and nn.linear. It would help us compare the numpy output to torch output for the same code, and give us some modular code/functions to use. Specifically, a numpy equivalent for the following would be great:
rnn = nn.LSTM(10, 20, 2)
input = torch.randn(5, 3, 10)
h0 = torch.randn(2, 3, 20)
c0 = torch.randn(2, 3, 20)
output, (hn, cn) = rnn(input, (h0, c0))
and also for linear:
m = nn.Linear(20, 30)
input = torch.randn(128, 20)
output = m(input)
ANSWER
Answered 2022-Feb-17 at 10:47You should try to export the model using torch.onnx. The page gives you an example that you can start with.
An alternative is to use TorchScript, but that requires torch libraries.
Both of these can be run without python. You can load torchscript in a C++ application https://pytorch.org/tutorials/advanced/cpp_export.html
ONNX is much more portable and you can use in languages such as C#, Java, or Javascript https://onnxruntime.ai/ (even on the browser)
A running exampleJust modifying a little your example to go over the errors I found
Notice that via tracing any if/elif/else, for, while will be unrolled
import torch
import torch.nn as nn
import torch.nn.functional as F
import torch.optim as optim
import random
torch.manual_seed(1)
random.seed(1)
device = torch.device('cpu')
class RNN(nn.Module):
def __init__(self, input_size, hidden_size, output_size,num_layers, matching_in_out=False, batch_size=1):
super(RNN, self).__init__()
self.input_size = input_size
self.hidden_size = hidden_size
self.output_size = output_size
self.num_layers = num_layers
self.batch_size = batch_size
self.matching_in_out = matching_in_out #length of input vector matches the length of output vector
self.lstm = nn.LSTM(input_size, hidden_size,num_layers)
self.hidden2out = nn.Linear(hidden_size, output_size)
def forward(self, x, h0, c0):
lstm_out, (hidden_a, hidden_b) = self.lstm(x, (h0, c0))
outs=self.hidden2out(lstm_out)
return outs, (hidden_a, hidden_b)
def init_hidden(self):
#return torch.rand(self.num_layers, self.batch_size, self.hidden_size)
return (torch.rand(self.num_layers, self.batch_size, self.hidden_size).to(device).detach(),
torch.rand(self.num_layers, self.batch_size, self.hidden_size).to(device).detach())
# convert the arguments passed during onnx.export call
class MWrapper(nn.Module):
def __init__(self, model):
super(MWrapper, self).__init__()
self.model = model;
def forward(self, kwargs):
return self.model(**kwargs)
Run an example
rnn = RNN(10, 10, 10, 3)
X = torch.randn(3,1,10)
h0,c0 = rnn.init_hidden()
print(rnn(X, h0, c0)[0])
Use the same input to trace the model and export an onnx file
torch.onnx.export(MWrapper(rnn), {'x':X,'h0':h0,'c0':c0}, 'rnn.onnx',
dynamic_axes={'x':{1:'N'},
'c0':{1: 'N'},
'h0':{1: 'N'}
},
input_names=['x', 'h0', 'c0'],
output_names=['y', 'hn', 'cn']
)
Notice that you can use symbolic values for the dimensions of some axes of some inputs. Unspecified dimensions will be fixed with the values from the traced inputs. By default LSTM uses dimension 1 as batch.
Next we load the ONNX model and pass the same inputs
import onnxruntime
ort_model = onnxruntime.InferenceSession('rnn.onnx')
print(ort_model.run(['y'], {'x':X.numpy(), 'c0':c0.numpy(), 'h0':h0.numpy()}))
QUESTION
I'm trying to implement a gradient-free optimizer function to train convolutional neural networks with Julia using Flux.jl. The reference paper is this: https://arxiv.org/abs/2005.05955. This paper proposes RSO, a gradient-free optimization algorithm updates single weight at a time on a sampling bases. The pseudocode of this algorithm is depicted in the picture below.
I'm using MNIST dataset.
function train(; kws...)
args = Args(; kws...) # collect options in a stuct for convinience
if CUDA.functional() && args.use_cuda
@info "Training on CUDA GPU"
CUDA.allwoscalar(false)
device = gpu
else
@info "Training on CPU"
device = cpu
end
# Prepare datasets
x_train, x_test, y_train, y_test = getdata(args, device)
# Create DataLoaders (mini-batch iterators)
train_loader = DataLoader((x_train, y_train), batchsize=args.batchsize, shuffle=true)
test_loader = DataLoader((x_test, y_test), batchsize=args.batchsize)
# Construct model
model = build_model() |> device
ps = Flux.params(model) # model's trainable parameters
best_param = ps
if args.optimiser == "SGD"
# Regular training step with SGD
elseif args.optimiser == "RSO"
# Run RSO function and update ps
best_param .= RSO(x_train, y_train, args.RSOupdate, model, args.batchsize, device)
end
And the corresponding RSO function:
function RSO(X,L,C,model, batch_size, device)
"""
model = convolutional model structure
X = Input data
L = labels
C = Number of rounds to update parameters
W = Weight set of layers
Wd = Weight tensors of layer d that generates an activation
wid = weight tensor that generates an activation aᵢ
wj = a weight in wid
"""
# Normalize input data to have zero mean and unit standard deviation
X .= (X .- sum(X))./std(X)
train_loader = DataLoader((X, L), batchsize=batch_size, shuffle=true)
#println("model = $(typeof(model))")
std_prep = []
σ_d = Float64[]
D = 1
for layer in model
D += 1
Wd = Flux.params(layer)
# Initialize the weights of the network with Gaussian distribution
for id in Wd
wj = convert(Array{Float32, 4}, rand(Normal(0, sqrt(2/length(id))), (3,3,4,4)))
id = wj
append!(std_prep, vec(wj))
end
# Compute std of all elements in the weight tensor Wd
push!(σ_d, std(std_prep))
end
W = Flux.params(model)
# Weight update
for _ in 1:C
d = D
while d > 0
for id in 1:length(W[d])
# Randomly sample change in weights from Gaussian distribution
for j in 1:length(w[d][id])
# Randomly sample mini-batch
(x, l) = train_loader[rand(1:length(train_loader))]
# Sample a weight from normal distribution
ΔWj[d][id][j] = rand(Normal(0, σ_d[d]), 1)
loss, acc = loss_and_accuracy(data_loader, model, device)
W = argmin(F(x,l, W+ΔWj), F(x,l,W), F(x,l, W-ΔWj))
end
end
d -= 1
end
end
return W
end
The problem here is the second block of the RSO function. I'm trying to evaluate the loss with the change of single weight in three scenarios, which are F(w, l, W+gW), F(w, l, W), F(w, l, W-gW)
, and choose the weight-set with minimum loss. But how do I do that using Flux.jl? The loss function I'm trying to use is logitcrossentropy(ŷ, y, agg=sum)
. In order to generate y_hat, we should use model(W), but changing single weight parameter in Zygote.Params() form was already challenging....
ANSWER
Answered 2022-Jan-14 at 23:47Based on the paper you shared, it looks like you need to change the weight arrays per each output neuron per each layer. Unfortunately, this means that the implementation of your optimization routine is going to depend on the layer type, since an "output neuron" for a convolution layer is quite different than a fully-connected layer. In other words, just looping over Flux.params(model)
is not going to be sufficient, since this is just a set of all the weight arrays in the model and each weight array is treated differently depending on which layer it comes from.
Fortunately, Julia's multiple dispatch does make this easier to write if you use separate functions instead of a giant loop. I'll summarize the algorithm using the pseudo-code below:
for layer in model
for output_neuron in layer
for weight_element in parameters(output_neuron)
weight_element = sample(N(0, sqrt(2 / num_outputs(layer))))
end
end
sigmas[layer] = stddev(parameters(layer))
end
for c in 1 to C
for layer in reverse(model)
for output_neuron in layer
for weight_element in parameters(output_neuron)
x, y = sample(batches)
dw = N(0, sigmas[layer])
# optimize weights
end
end
end
end
It's the for output_neuron ...
portions that we need to isolate into separate functions.
In the first block, we don't actually do anything different to every weight_element
, they are all sampled from the same normal distribution. So, we don't actually need to iterate the output neurons, but we do need to know how many there are.
using Statistics: std
# this function will set the weights according to the
# normal distribution and the number of output neurons
# it also returns the standard deviation of the weights
function sample_weight!(layer::Dense)
sample = randn(eltype(layer.weight), size(layer.weight))
num_outputs = size(layer.weight, 1)
# notice the "." notation which is used to mutate the array
layer.weight .= sample .* num_outputs
return std(layer.weight)
end
function sample_weight!(layer::Conv)
sample = randn(eltype(layer.weight), size(layer.weight))
num_outputs = size(layer.weight, 4)
# notice the "." notation which is used to mutate the array
layer.weight .= sample .* num_outputs
return std(layer.weight)
end
sigmas = map(sample_weights!, model)
Now, for the second block, we will do a similar trick by defining different functions for each layer.
function optimize_layer!(loss, layer::Dense, data, sigma)
for i in 1:size(layer.weight, 1)
for j in 1:size(layer.weight, 2)
wj = layer.weight[i, j]
x, y = data[rand(1:length(data))]
dw = randn() * sigma
ws = [wj + dw, wj, wj - dw]
losses = Float32[]
for (k, w) in enumerate(ws)
layer.weight[i, j] = w
losses[k] = loss(x, y)
end
layer.weight[i, j] = ws[argmin(losses)]
end
end
end
function optimize_layer!(loss, layer::Conv, data, sigma)
for i in 1:size(layer.weight, 4)
# we use a view to reference the full kernel
# for this output channel
wid = view(layer.weight, :, :, :, i)
# each index let's us treat wid like a vector
for j in eachindex(wid)
wj = wid[j]
x, y = data[rand(1:length(data))]
dw = randn() * sigma
ws = [wj + dw, wj, wj - dw]
losses = Float32[]
for (k, w) in enumerate(ws)
wid[j] = w
losses[k] = loss(x, y)
end
wid[j] = ws[argmin(losses)]
end
end
end
for c in 1:C
for (layer, sigma) in reverse(zip(model, sigmas))
optimize_layer!(layer, data, sigma) do x, y
logitcrossentropy(model(x), y; agg = sum)
end
end
end
Notice that nowhere did I use Flux.params
which does not help us here. Also, Flux.params
would include both the weight and bias, and the paper doesn't look like it bothers with the bias at all. If you had an optimization method that generically optimized any parameter regardless of layer type the same (i.e. like gradient descent), then you could use for p in Flux.params(model) ...
.
QUESTION
This question is the same with How can I check a confusion_matrix after fine-tuning with custom datasets?, on Data Science Stack Exchange.
BackgroundI would like to check a confusion_matrix, including precision, recall, and f1-score like below after fine-tuning with custom datasets.
Fine tuning process and the task are Sequence Classification with IMDb Reviews on the Fine-tuning with custom datasets tutorial on Hugging face.
After finishing the fine-tune with Trainer, how can I check a confusion_matrix in this case?
An image of confusion_matrix, including precision, recall, and f1-score original site: just for example output image
predictions = np.argmax(trainer.test(test_x), axis=1)
# Confusion matrix and classification report.
print(classification_report(test_y, predictions))
precision recall f1-score support
0 0.75 0.79 0.77 1000
1 0.81 0.87 0.84 1000
2 0.63 0.61 0.62 1000
3 0.55 0.47 0.50 1000
4 0.66 0.66 0.66 1000
5 0.62 0.64 0.63 1000
6 0.74 0.83 0.78 1000
7 0.80 0.74 0.77 1000
8 0.85 0.81 0.83 1000
9 0.79 0.80 0.80 1000
avg / total 0.72 0.72 0.72 10000
from transformers import DistilBertForSequenceClassification, Trainer, TrainingArguments
training_args = TrainingArguments(
output_dir='./results', # output directory
num_train_epochs=3, # total number of training epochs
per_device_train_batch_size=16, # batch size per device during training
per_device_eval_batch_size=64, # batch size for evaluation
warmup_steps=500, # number of warmup steps for learning rate scheduler
weight_decay=0.01, # strength of weight decay
logging_dir='./logs', # directory for storing logs
logging_steps=10,
)
model = DistilBertForSequenceClassification.from_pretrained("distilbert-base-uncased")
trainer = Trainer(
model=model, # the instantiated 🤗 Transformers model to be trained
args=training_args, # training arguments, defined above
train_dataset=train_dataset, # training dataset
eval_dataset=val_dataset # evaluation dataset
)
trainer.train()
Data set Preparation for Sequence Classification with IMDb Reviews, and I'm fine-tuning with Trainer.
from pathlib import Path
def read_imdb_split(split_dir):
split_dir = Path(split_dir)
texts = []
labels = []
for label_dir in ["pos", "neg"]:
for text_file in (split_dir/label_dir).iterdir():
texts.append(text_file.read_text())
labels.append(0 if label_dir is "neg" else 1)
return texts, labels
train_texts, train_labels = read_imdb_split('aclImdb/train')
test_texts, test_labels = read_imdb_split('aclImdb/test')
from sklearn.model_selection import train_test_split
train_texts, val_texts, train_labels, val_labels = train_test_split(train_texts, train_labels, test_size=.2)
from transformers import DistilBertTokenizerFast
tokenizer = DistilBertTokenizerFast.from_pretrained('distilbert-base-uncased')
train_encodings = tokenizer(train_texts, truncation=True, padding=True)
val_encodings = tokenizer(val_texts, truncation=True, padding=True)
test_encodings = tokenizer(test_texts, truncation=True, padding=True)
import torch
class IMDbDataset(torch.utils.data.Dataset):
def __init__(self, encodings, labels):
self.encodings = encodings
self.labels = labels
def __getitem__(self, idx):
item = {key: torch.tensor(val[idx]) for key, val in self.encodings.items()}
item['labels'] = torch.tensor(self.labels[idx])
return item
def __len__(self):
return len(self.labels)
train_dataset = IMDbDataset(train_encodings, train_labels)
val_dataset = IMDbDataset(val_encodings, val_labels)
test_dataset = IMDbDataset(test_encodings, test_labels)
ANSWER
Answered 2021-Nov-24 at 13:26What you could do in this situation is to iterate on the validation set(or on the test set for that matter) and manually create a list of y_true
and y_pred
.
import torch
import torch.nn.functional as F
from sklearn import metrics
y_preds = []
y_trues = []
for index,val_text in enumerate(val_texts):
tokenized_val_text = tokenizer([val_text],
truncation=True,
padding=True,
return_tensor='pt')
logits = model(tokenized_val_text)
prediction = F.softmax(logits, dim=1)
y_pred = torch.argmax(prediction).numpy()
y_true = val_labels[index]
y_preds.append(y_pred)
y_trues.append(y_true)
Finally,
confusion_matrix = metrics.confusion_matrix(y_trues, y_preds, labels=["neg", "pos"]))
print(confusion_matrix)
Observations:
- The output of the model are the
logits
, not the probabilities normalized. - As such, we apply
softmax
on dimension one to transform to actual probabilities (e.g.0.2% class 0
,0.8% class 1
). - We apply the
.argmax()
operation to get the index of the class.
QUESTION
I am trying to train a model using PyTorch. When beginning model training I get the following error message:
RuntimeError: CUDA out of memory. Tried to allocate 5.37 GiB (GPU 0; 7.79 GiB total capacity; 742.54 MiB already allocated; 5.13 GiB free; 792.00 MiB reserved in total by PyTorch)
I am wondering why this error is occurring. From the way I see it, I have 7.79 GiB total capacity. The numbers it is stating (742 MiB + 5.13 GiB + 792 MiB) do not add up to be greater than 7.79 GiB. When I check nvidia-smi
I see these processes running
| 0 N/A N/A 1047 G /usr/lib/xorg/Xorg 168MiB |
| 0 N/A N/A 5521 G /usr/lib/xorg/Xorg 363MiB |
| 0 N/A N/A 5637 G /usr/bin/gnome-shell 161MiB |
I realize that summing all of these numbers might cut it close (168 + 363 + 161 + 742 + 792 + 5130 = 7356 MiB) but this is still less than the stated capacity of my GPU.
ANSWER
Answered 2021-Nov-23 at 06:13This is more of a comment, but worth pointing out.
The reason in general is indeed what talonmies commented, but you are summing up the numbers incorrectly. Let's see what happens when tensors are moved to GPU (I tried this on my PC with RTX2060 with 5.8G usable GPU memory in total):
Let's run the following python commands interactively:
Python 3.8.10 (default, Sep 28 2021, 16:10:42)
[GCC 9.3.0] on linux
Type "help", "copyright", "credits" or "license" for more information.
>>> import torch
>>> a = torch.zeros(1).cuda()
>>> b = torch.zeros(500000000).cuda()
>>> c = torch.zeros(500000000).cuda()
>>> d = torch.zeros(500000000).cuda()
The following are the outputs of watch -n.1 nvidia-smi
:
Right after torch
import:
| 0 N/A N/A 1121 G /usr/lib/xorg/Xorg 4MiB |
Right after the creation of a
:
| 0 N/A N/A 1121 G /usr/lib/xorg/Xorg 4MiB |
| 0 N/A N/A 14701 C python 1251MiB |
As you can see, you need 1251MB
to get pytorch to start using CUDA, even if you only need a single float.
Right after the creation of b
:
| 0 N/A N/A 1121 G /usr/lib/xorg/Xorg 4MiB |
| 0 N/A N/A 14701 C python 3159MiB |
b
needs 500000000*4 bytes = 1907MB
, this is the same as the increment in memory used by the python process.
Right after the creation of c
:
| 0 N/A N/A 1121 G /usr/lib/xorg/Xorg 4MiB |
| 0 N/A N/A 14701 C python 5067MiB |
No surprise here.
Right after the creation of d
:
| 0 N/A N/A 1121 G /usr/lib/xorg/Xorg 4MiB |
| 0 N/A N/A 14701 C python 5067MiB |
No further memory allocation, and the OOM error is thrown:
Traceback (most recent call last):
File "", line 1, in
RuntimeError: CUDA out of memory. Tried to allocate 1.86 GiB (GPU 0; 5.80 GiB total capacity; 3.73 GiB already allocated; 858.81 MiB free; 3.73 GiB reserved in total by PyTorch)
Obviously:
- The "already allocated" part is included in the "reserved in total by PyTorch" part. You can't sum them up, otherwise the sum exceeds the total available memory.
- The minimum memory required to get pytorch running on GPU (
1251M
) is not included in the "reserved in total" part.
So in your case, the sum should consist of:
- 792MB (reserved in total)
- 1251MB (minimum to get pytorch running on GPU, assuming this is the same for both of us)
- 5.13GB (free)
- 168+363+161=692MB (other processes)
They sum up to approximately 7988MB=7.80GB, which is exactly you total GPU memory.
QUESTION
I am a bit confusing with comparing best GridSearchCV model and baseline.
For example, we have classification problem.
As a baseline, we'll fit a model with default settings (let it be logistic regression):
from sklearn.linear_model import LogisticRegression
from sklearn.metrics import accuracy_score
baseline = LogisticRegression()
baseline.fit(X_train, y_train)
pred = baseline.predict(X_train)
print(accuracy_score(y_train, pred))
So, the baseline gives us accuracy using the whole train sample.
Next, GridSearchCV:
from sklearn.model_selection import cross_val_score, GridSearchCV, StratifiedKFold
X_val, X_test_val,y_val,y_test_val = train_test_split(X_train, y_train, test_size=0.3, random_state=42)
cv = StratifiedKFold(n_splits=5, random_state=0, shuffle=True)
parameters = [ ... ]
best_model = GridSearchCV(LogisticRegression(parameters,scoring='accuracy' ,cv=cv))
best_model.fit(X_val, y_val)
print(best_model.best_score_)
Here, we have accuracy based on validation sample.
My questions are:
- Are those accuracy scores comparable? Generally, is it fair to compare GridSearchCV and model without any cross validation?
- For the baseline, isn't it better to use Validation sample too (instead of the whole Train sample)?
ANSWER
Answered 2021-Nov-04 at 21:17No, they aren't comparable.
Your baseline model used X_train
to fit the model. Then you're using the fitted model to score the X_train
sample. This is like cheating because the model is going to already perform the best since you're evaluating it based on data that it has already seen.
The grid searched model is at a disadvantage because:
- It's working with less data since you have split the
X_train
sample. - Compound that with the fact that it's getting trained with even less data due to the 5 folds (it's training with only 4/5 of
X_val
per fold).
So your score for the grid search is going to be worse than your baseline.
Now you might ask, "so what's the point of best_model.best_score_
? Well, that score is used to compare all the models used when searching for the optimal hyperparameters in your search space, but in no way should be used to compare against a model that was trained outside of the grid search context.
So how should one go about conducting a fair comparison?
- Split your training data for both models.
X_train, X_test, y_train, y_test = train_test_split(X, y, test_size=0.3, random_state=42)
- Fit your models using
X_train
.
# fit baseline
baseline.fit(X_train, y_train)
# fit using grid search
best_model.fit(X_train, y_train)
- Evaluate models against
X_test
.
# baseline
baseline_pred = baseline.predict(X_test)
print(accuracy_score(y_test, baseline_pred))
# grid search
grid_pred = best_model.predict(X_test)
print(accuracy_score(y_test, grid_pred))
QUESTION
I am not able to access jupyter lab created on google cloud
I created one notebook using Google AI platform. I was able to start it and work but suddenly it stopped and I am not able to start it now. I tried building and restarting the jupyterlab, but of no use. I have checked my disk usages as well, which is only 12%.
I tried the diagnostic tool, which gave the following result:
but didn't fix it.
Thanks in advance.
ANSWER
Answered 2021-Aug-20 at 14:00You should try this Google Notebook trouble shooting section about 524 errors : https://cloud.google.com/notebooks/docs/troubleshooting?hl=ja#opening_a_notebook_results_in_a_524_a_timeout_occurred_error
QUESTION
I am new to Machine Learning.
Having followed the steps in this simple Maching Learning using the Brain.js library, it beats my understanding why I keep getting the error message below:
I have double-checked my code multiple times. This is particularly frustrating as this is the very first exercise!
Kindly point out what I am missing here!
Find below my code:
const brain = require('brain.js');
var net = new brain.NeuralNetwork();
net.train([
{ input: [0, 0], output: [0] },
{ input: [0, 1], output: [1] },
{ input: [1, 0], output: [1] },
{ input: [1, 1], output: [0] },
]);
var output = net.run([1, 0]); // [0.987]
console.log(output);
I am running Nodejs version v14.17.4
ANSWER
Answered 2021-Sep-29 at 22:47Turns out its just documented incorrectly.
In reality the export from brain.js is this:
{
brain: { ...brain class },
default: { ...brain class again }
}
So in order to get it working properly, you should do
const brain = require('brain.js').brain // access to nested object
const net = new brain.NeuralNetwork()
QUESTION
IF we are not sure about the nature of categorical features like whether they are nominal or ordinal, which encoding should we use? Ordinal-Encoding or One-Hot-Encoding? Is there a clearly defined rule on this topic?
I see a lot of people using Ordinal-Encoding on Categorical Data that doesn't have a Direction. Suppose a frequency table:
some_data[some_col].value_counts()
[OUTPUT]
color_white 11413
color_green 4544
color_black 1419
color_orang 3
Name: shirt_colors, dtype: int64
There are a lots of guys who are preferring to do Ordinal-Encoding on this column. And I am hell-bent to go with One-Hot-Encoding. My view on this is that doing Ordinal Encoding will allot these colors' some ordered numbers which I'd imply a ranking. And there is no ranking in the first place. In other words, my model should not be thinking of color_white to be 4 and color_orang to be 0 or 1 or 2. Keep in mind that there is no hint of any ranking or order in the Data Description as well.
I have the following understanding of this topic:
Numbers that neither have a direction nor magnitude are Nominal Variables. For example, fruit_list =['apple', 'orange', banana']. Unless there is a specific context, this set would be called to be a nominal one. And for such variables, we should perform either get_dummies or one-hot-encoding
Whereas the Ordinal Variables have a direction. For example, shirt_sizes_list = [large, medium, small]. These variables are called Ordinal Variables. If the same fruit list has a context behind it, like price or nutritional value i-e, that could give the fruits in the fruit_list some ranking or order, we'd call it an Ordinal Variable. And for Ordinal Variables, we perform Ordinal-Encoding
Is my understanding correct? Kindly provide your feedback This topic has turned into a nightmare Thank you!
ANSWER
Answered 2021-Sep-04 at 06:43You're right. Just one thing to consider for choosing OrdinalEncoder
or OneHotEncoder
is that does the order of data matter?
Most ML algorithms will assume that two nearby values are more similar than two distant values. This may be fine in some cases e.g., for ordered categories such as:
quality = ["bad", "average", "good", "excellent"]
orshirt_size = ["large", "medium", "small"]
but it is obviously not the case for the:
color = ["white","orange","black","green"]
column (except for the cases you need to consider a spectrum, say from white to black. Note that in this case, white
category should be encoded as 0
and black
should be encoded as the highest number in your categories), or if you have some cases for example, say, categories 0 and 4 may be more similar than categories 0 and 1. To fix this issue, a common solution is to create one binary attribute per category (One-Hot encoding)
QUESTION
I am using sentence-transformers for semantic search but sometimes it does not understand the contextual meaning and returns wrong result eg. BERT problem with context/semantic search in italian language
by default the vector side of embedding of the sentence is 78 columns, so how do I increase that dimension so that it can understand the contextual meaning in deep.
code:
# Load the BERT Model
from sentence_transformers import SentenceTransformer
model = SentenceTransformer('bert-base-nli-mean-tokens')
# Setup a Corpus
# A corpus is a list with documents split by sentences.
sentences = ['Absence of sanity',
'Lack of saneness',
'A man is eating food.',
'A man is eating a piece of bread.',
'The girl is carrying a baby.',
'A man is riding a horse.',
'A woman is playing violin.',
'Two men pushed carts through the woods.',
'A man is riding a white horse on an enclosed ground.',
'A monkey is playing drums.',
'A cheetah is running behind its prey.']
# Each sentence is encoded as a 1-D vector with 78 columns
sentence_embeddings = model.encode(sentences) ### how to increase vector dimention
print('Sample BERT embedding vector - length', len(sentence_embeddings[0]))
print('Sample BERT embedding vector - note includes negative values', sentence_embeddings[0])
ANSWER
Answered 2021-Aug-10 at 07:39Increasing the dimension of a trained model is not possible (without many difficulties and re-training the model). The model you are using was pre-trained with dimension 768, i.e., all weight matrices of the model have a corresponding number of trained parameters. Increasing the dimensionality would mean adding parameters which however need to be learned.
Also, the dimension of the model does not reflect the amount of semantic or context information in the sentence representation. The choice of the model dimension reflects more a trade-off between model capacity, the amount of training data, and reasonable inference speed.
If the model that you are using does not provide representation that is semantically rich enough, you might want to search for better models, such as RoBERTa or T5.
QUESTION
I have a table with features that were used to build some model to predict whether user will buy a new insurance or not. In the same table I have probability of belonging to the class 1 (will buy) and class 0 (will not buy) predicted by this model. I don't know what kind of algorithm was used to build this model. I only have its predicted probabilities.
Question: how to identify what features affect these prediction results? Do I need to build correlation matrix or conduct any tests?
Table example:
+---------+-----+-----------+---------+--------+-----------+--------+---------+-------------+------------+
| user_id | age | car_price | car_age | income | education | gender | crashes | probability | true_labes |
+---------+-----+-----------+---------+--------+-----------+--------+---------+-------------+------------+
| 1 | 29 | 15600 | 3 | 20000 | 3 | 1 | 1 | 0.23 | 0 |
+---------+-----+-----------+---------+--------+-----------+--------+---------+-------------+------------+
| 2 | 41 | 43000 | 1 | 65000 | 2 | 0 | 1 | 0.1 | 0 |
+---------+-----+-----------+---------+--------+-----------+--------+---------+-------------+------------+
| 3 | 39 | 23500 | 5 | 43000 | 3 | 1 | 0 | 0.46 | 1 |
+---------+-----+-----------+---------+--------+-----------+--------+---------+-------------+------------+
| 4 | 19 | 12200 | 3 | 13000 | 1 | 1 | 0 | 0.34 | 1 |
+---------+-----+-----------+---------+--------+-----------+--------+---------+-------------+------------+
| 5 | 68 | 21900 | 2 | 31300 | 3 | 0 | 1 | 0.85 | 1 |
+---------+-----+-----------+---------+--------+-----------+--------+---------+-------------+------------+
ANSWER
Answered 2021-Aug-11 at 15:55You could build a model like this.
x = features you have. y = true_lable
from that you can extract features importance. also, if you want to go the extra mile,you can do Bootstrapping, so that the features importance would be more stable (statistical).
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