zfile | 在线云盘、网盘、OneDrive、云存储、私有云、对象存储、h5ai | Frontend Framework library

 by   zhaojun1998 Java Version: 3.2.2 License: MIT

kandi X-RAY | zfile Summary

kandi X-RAY | zfile Summary

zfile is a Java library typically used in User Interface, Frontend Framework, Vue applications. zfile has build file available, it has a Permissive License and it has medium support. However zfile has 13 bugs and it has 4 vulnerabilities. You can download it from GitHub.

基于 Java 的在线网盘程序,支持对接 S3、OneDrive、SharePoint、又拍云、本地存储、FTP 等存储源,支持在线浏览图片、播放音视频,文本文件等文件类型。.
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            kandi-support Support

              zfile has a medium active ecosystem.
              It has 4660 star(s) with 1081 fork(s). There are 75 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 43 open issues and 273 have been closed. On average issues are closed in 12 days. There are 3 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of zfile is 3.2.2

            kandi-Quality Quality

              zfile has 13 bugs (0 blocker, 0 critical, 2 major, 11 minor) and 190 code smells.

            kandi-Security Security

              zfile has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              OutlinedDot
              zfile code analysis shows 4 unresolved vulnerabilities (1 blocker, 0 critical, 0 major, 3 minor).
              There are 4 security hotspots that need review.

            kandi-License License

              zfile is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              zfile releases are available to install and integrate.
              Build file is available. You can build the component from source.
              Installation instructions are not available. Examples and code snippets are available.
              zfile saves you 2031 person hours of effort in developing the same functionality from scratch.
              It has 4462 lines of code, 331 functions and 109 files.
              It has low code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed zfile and discovered the below as its top functions. This is intended to give you an instant insight into zfile implemented functionality, and help decide if they suit your requirements.
            • Gets storage param list
            • Resolve placeholders
            • Get placeholder names
            • Resolve all placeholder properties
            • Get all sites
            • Get list of sites list
            • Renames a folder
            • Batch delete file
            • Gets the Spring bean
            • Handler for download
            • Get file item
            • Compare two file items
            • Url for googleDrive callback
            • Short link
            • List of gd drives
            • Get domain prefix
            • List short links
            • Retrieves a list of files within a folder
            • Retrieve items for a folder
            • Get site id
            • Wrap check password
            • Around route
            • Returns list of file items
            • OnoneDrive callback
            • Download file to stream
            • OneDrive callback
            Get all kandi verified functions for this library.

            zfile Key Features

            No Key Features are available at this moment for zfile.

            zfile Examples and Code Snippets

            No Code Snippets are available at this moment for zfile.

            Community Discussions

            QUESTION

            Load zip content (function executes 2 times)
            Asked 2021-May-23 at 19:44

            I want to get the contents of the zip file with func node with the following content, but I don't know why this node does it twice.

            Where did I go wrong? Please tell me!

            ...

            ANSWER

            Answered 2021-May-23 at 19:44

            You are calling both send(msg) and return msg

            This will mean that you send 2 messages from the function node and since NodeJS/JavaScript is pass by reference they will both end up with the same content.

            Best option is just to remove the return msg from the end of the function.

            Source https://stackoverflow.com/questions/67663460

            QUESTION

            Using requests module to download zip file from aspx site
            Asked 2021-Apr-04 at 06:16

            I'm trying to download a zip file using the requests module. If I run this code, it creates a zip file on my machine, but it is just HTML of an error page. If I enter the URL into a browser, it correctly downloads the zipped file.

            ...

            ANSWER

            Answered 2021-Apr-04 at 06:16

            TLDR: The zipurl you provided which works in the browser works because the browser is encoding and escaping some characters. The correct url is instead as follows:

            Source https://stackoverflow.com/questions/66857227

            QUESTION

            Extracting multiple zipped JSON files in-memory and saving them to Azure Blob Storage with Python
            Asked 2021-Mar-16 at 13:25

            I have a function that communicates with a SOAP API, receives binaries and ultimately extracts a small number of JSON files that I wish to save to an Azure Blob Storage Container using Python.

            The official Microsoft documentation and examples are useful for saving a single file, but when I try to do the same for multiple files I get an error code:

            TypeError: Blob data should be of type bytes.

            See below for the code cell and error code.

            ...

            ANSWER

            Answered 2021-Mar-16 at 13:25

            The reason you're getting this error is because you're passing a file object as data to the upload_blob method whereas the method expects the content.

            What you would do is read the contents of the file and then pass the file contents to the upload_blob method.

            Something like:

            Source https://stackoverflow.com/questions/66655703

            QUESTION

            Nested if statement returns no such item
            Asked 2021-Jan-18 at 05:30

            my scipt is working as in searching for zip files, unzip and do the things i want. But problem arise when i have nested zip files inside the zip file, so i thought maybe i copy the working if statement, make a few adjustments but i still cant get it to work.

            ...

            ANSWER

            Answered 2021-Jan-18 at 04:42

            QUESTION

            Zipfile: How to download a zipfile and save without extract?
            Asked 2021-Jan-11 at 14:34

            I would like to download a zipfile from url and save somewhere. I don't want to extract my file and that is my problem. I have a code which download zipfile and extract files, but I want to only download and save. What should I change?

            ...

            ANSWER

            Answered 2021-Jan-11 at 14:34

            Just don't use ZipFile at all. You have the file content, write it out:

            Source https://stackoverflow.com/questions/65667843

            QUESTION

            How to copy from zip file to a folder without unzipping it?
            Asked 2020-Nov-21 at 20:40

            How to make this code works? There is a zip file with folders and .png files in it. Folder ".\icons_by_year" is empty. I need to get every file one by one without unzipping it and copy to the root of the selected folder (so no extra folders made).

            ...

            ANSWER

            Answered 2020-Nov-19 at 21:05

            I'd take a look at the zipfile libraries' getinfo() and also ZipFile.Path() for construction since the constructor class can also use paths that way if you intend to do any creation.

            Specifically PathObjects. This is able to do is to construct an object with a path in it, and it appears to be based on pathlib. Assuming you don't need to create zipfiles, you can ignore this ZipFile.Path()

            However, that's not exactly what I wanted to point out. Rather consider the following:

            zipfile.getinfo()

            There is a person who I think is getting at this exact situation here:

            https://www.programcreek.com/python/example/104991/zipfile.getinfo

            This person seems to be getting a path using getinfo(). It's also clear that NOT every zipfile has the info.

            Source https://stackoverflow.com/questions/64919322

            QUESTION

            Can't open and read content of an uploaded zip file with FastAPI
            Asked 2020-Nov-12 at 06:52

            I am currently developing a little backend project for myself with the Python Framework FastAPI. I made an endpoint, where the user should be able to upload 2 files, while the first one is a zip-file (which contains X .xmls) and the latter a normal .xml file.

            The code is as follows:

            ...

            ANSWER

            Answered 2020-Nov-12 at 00:23

            This is a known Python bug:

            SpooledTemporaryFile does not fully satisfy the abstract for IOBase. Namely, seekable, readable, and writable are missing.

            This was discovered when seeking a SpooledTemporaryFile-backed lzma file.

            As @larsks suggested in his comment, I would try writing the contents of the spooled file to a new TemporaryFile, and then operate on that. As long as your files aren't too large, that should work just as well.

            Source https://stackoverflow.com/questions/64788026

            QUESTION

            Python : Download zip file without extraction from direct link
            Asked 2020-Sep-30 at 01:51

            i'm trying to make a script that download files from direct links (such as this one : "http://beatsaver.com/api/download/key/f55c" ) with a Python script. I've tried various code from here or / other website to either end up with a corrupted zip file or a "zipfile.BadZipFile: File is not a zip file".

            I tried with this : (zip corrupted)

            ...

            ANSWER

            Answered 2020-Sep-30 at 01:51

            First, the url is returning a 403 forbidden error when trying to get it with python. The site is refusing to send you the file because it knows you are a bot. I was able to get past this by setting the user-agent.

            Source https://stackoverflow.com/questions/64129584

            QUESTION

            Read MVS DataSet from java program
            Asked 2020-Sep-15 at 15:39

            I'm trying to access to a DataSet called X.Y.Z; my code is:

            ...

            ANSWER

            Answered 2020-Sep-15 at 15:39

            If the double slash notation is used to refer to a data set on z/OS, it assumes the data set's high level qualifier (HLQ) is the user id of the current user. For example, //X.Y.Z would resolve to MEAT.X.Y.Z assuming my username was my user id on z/OS. Quotes should be added if the data set specified is the fully-qualified data set name. In your case, //'X.Y.Z' would resolve to X.Y.Z.

            Source https://stackoverflow.com/questions/63880336

            QUESTION

            merge multiple zip files in python
            Asked 2020-Sep-03 at 12:19

            I know there are a couple of similar questions, from which i actually took bits of this code, but I cannot understand why I get the error i get.

            I have 3 urls which get me a zip file each, I would like to merge them into 1 using python without saving to disc.

            ...

            ANSWER

            Answered 2020-Sep-03 at 12:19

            Ok I spotted the error -

            I had no need of line

            Source https://stackoverflow.com/questions/63723452

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install zfile

            You can download it from GitHub.
            You can use zfile like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the zfile component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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            https://github.com/zhaojun1998/zfile.git

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            gh repo clone zhaojun1998/zfile

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            git@github.com:zhaojun1998/zfile.git

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