BM | A bookmarks manager made with React | Frontend Framework library
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kandi X-RAY | BM Summary
A bookmarks manager made with React.
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def gather_nd(params: ragged_tensor.RaggedOrDense,
indices: ragged_tensor.RaggedOrDense,
batch_dims=0,
name=None):
"""Gather slices from `params` using `n`-dimensional indices.
This operation is similar
Community Discussions
Trending Discussions on BM
QUESTION
Here is my problem, I build an archive with "xc32-ar.exe" with this command line.
...ANSWER
Answered 2021-Jun-13 at 18:02QUESTION
(new in javascript)
I am asked to remove a country (China) from the dropdown menu of the plugin intl-tel-input
the code below displays the dropdown menu and it looks that it calls the utils.js file to retain the countries
...ANSWER
Answered 2021-Jun-11 at 12:14If you take a look at the intl-tel-input
documentation regarding Initialisation Options. There is an option called excludeCountries
.
We can modify your initialisation code to include this option to exclude China:
QUESTION
So, I'm just figuring things out and can't wrap my head around the fact that the following code doesn't give me back an Identymatrix.
...ANSWER
Answered 2021-Jun-10 at 15:02A*A^(-1) = I and A^(-1)*A = I
should both be true.
I get somethin like this for the first multiplication:
QUESTION
I have some high dimensional repeated measures data, and i am interested in fitting random forest model to investigate the suitability and predictive utility of such models. Specifically i am trying to implement the methods in the LongituRF
package. The methods behind this package are detailed here :
Conveniently the authors provide some useful data generating functions for testing. So we have
...ANSWER
Answered 2021-Apr-09 at 14:46When the function DataLongGenerator()
creates Z
, it's a random uniform data in a matrix. The actual coding is
QUESTION
I am trying to create enable user to download this image that is stored in my AWS S3.
My Java server sends back a ResponseEntity object, which is received by the frontend in the form of the below JSON response:
...ANSWER
Answered 2021-Jun-08 at 02:11Have you tried a different approach from your Spring back-end? I would suggest returning your PNG image as a byte array, and annotate the REST Controller method to indicate the appropriate MediaType
that it produces:
QUESTION
#Start cleaning loop through all the pings
for P in Pings:
#All beams for current ping
print("Cleansing completed", round(P/len(Pings)*100,1),"%")
Slice_one = df[(df.P==P)&(df.Bm>0)&(df.Bm<257)].copy()
model = LinearRegression().fit(Slice_one.Bm.values.reshape((-1,1)), Slice_one.Z.values)
Slice_one["Z_1"] = model.predict(Slice_one.Bm.values.reshape((-1,1)))
Slice_one("dZ") = abs(Slice_one.Z_1 - Slice_one.Z)
Slice_one_Cor = Slice_one[(Slice_one.dZ < 0.4)]
Slice_one_Cor.drop(["Z_1", "dZ"], axis = 1, inplace = True)
df_Clean = pd.concat([df.Clean, Slice_one_cor], ignore_index = True)
...ANSWER
Answered 2021-Jun-04 at 13:04you have to use square brackets [ ], Slice_one["dZ"] = abs(Slice_one.Z_1 - Slice_one.Z)
QUESTION
I am trying to label x and y points based on their being in a specific section of a meshgrid in python. The points are stored in a pandas dataframe.
Here I have a scatter plot of the coordinates and above them I am plotting the grid. The entire grid is way bigger, from the bottom left point (500,1250) to upper right point (2750, 3250), which means the whole grid is 225x200 sections.
I want to iterate through the sections of the grid and check if a point is inside. If a point is inside the section I want to add a label to the point. The label should be the same of the section name. I want to add a column to the dataframe called 'section' that stores the section a point belongs to.
In the example (picture above) I would like to label all the points with 770 <= x <= 780 and 1795 <= y <= 1805 with the section name 'A3'.
my code currently looks like this:
...ANSWER
Answered 2021-Jun-03 at 15:07Since all your points are equally sized, there is no need to define all of your squares beforehand and then determine which squares have which points. I would use the coordinates of each point to directly determine which square it will land in.
Let's take the 1-dimensional case, for the sake of simplicity. You want to group points on the number line into "squares" (really 1-d line segments). If your first square starts at x=0, your second at x=10, your third at x=20, and so on, how do you find the square for an arbitrary point x? You know that your squares are spaced by 10 (and you know they start at 0, which makes things easier), so you can simply divide by 10 and round down to get the square index.
You can just as easily do the same thing in 3-dimensions (or n-dimensions).
QUESTION
I need to get the number of pages of a google document and have come across the following code
...ANSWER
Answered 2021-May-29 at 05:18For example, in your situation, how about counting the number of Contents
? I thought that when Google Document is converted to the PDF data by retrieving as the blob using Google Apps Script, this method can be used. When this is reflected to your script, it becomes as follows.
QUESTION
I have a table that looks something like this:
...ANSWER
Answered 2021-May-29 at 18:57I have used your static pivot part of the query as the source of dynamic pivot. Create two sets of dynamic pivot column list. One for pivoting and the another with Coalesce() to select pivoted columns (to convert null into 0). If there is no categcount for any category then that category has been replaced with null (case when). Two more aliases for Category and SumCatCount have been created since those were used in pivot condition.
Here goes your answer:
QUESTION
I have ~6 tables where I have to count or sum fields based on matching site_ids and date. I have the following query, with many subqueries which takes an extraordinary amount of time to run. I am certain there is an easier, more efficient way, however I am rather new to these more complex queries. I have read regarding optimizations, specifically using joins ON but struggling to understand and implement.
The goal is to speed this up and not bring my small server to it's knees when running. Any assistance or direction would be VERY much appreciated!
...ANSWER
Answered 2021-May-27 at 20:24It would be very difficult to analyze the query with out the data, Any ways!
try joining the tables and group it, that should improve the performance
here is a left join sample
SELECT column names FROM table1 LEFT JOIN table2 ON table1.common_column = table2.common_column;
check this for more detailed inform https://learnsql.com/blog/how-to-left-join-multiple-tables/
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