upload-img | 拖拽上传 | Application Framework library

by Andyliwr JavaScript Version: Current License: No License

X-Ray Key Features Code Snippets Community Discussions(10)Vulnerabilities Install Support

kandi X-RAY | upload-img Summary

upload-img is a JavaScript library typically used in Server, Application Framework applications. upload-img has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

upload-img

Support

Quality

Security

License

Reuse

Support

upload-img has a low active ecosystem.

It has 10 star(s) with 0 fork(s). There are 2 watchers for this library.

It had no major release in the last 6 months.

upload-img has no issues reported. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of upload-img is current.

Quality

upload-img has no bugs reported.

Security

upload-img has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

upload-img does not have a standard license declared.

Check the repository for any license declaration and review the terms closely.

Without a license, all rights are reserved, and you cannot use the library in your applications.

Reuse

upload-img releases are not available. You will need to build from source code and install.

Installation instructions are not available. Examples and code snippets are available.

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upload-img Key Features

No Key Features are available at this moment for upload-img.

upload-img Examples and Code Snippets

No Code Snippets are available at this moment for upload-img.

Community Discussions

Trending Discussions on upload-img

jQuery $(this) hide/show element correctly

Default value in input field lost after click

How to remove the image from the canvas?

Laravel, if I edit all the fields does not work. not saving what edited

timthumb.php and htaccess rules

How to make a div as input

Can't empty div with jquery

Fatal error: Switch statements may only contain one default clause (php7)

Add Form Fields Dynamically -- ReactJs

upload image file in laravel is not working

QUESTION

jQuery $(this) hide/show element correctly

Asked 2020-Jul-24 at 13:08

How can I properly use the $ (this) variable to hide an element?

The task is this: I have 2 or more inputs with a type file for upload img. On click I have to hide the input and show another div. Now, when I click, are show both divs.

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ANSWER

Answered 2020-Jul-24 at 13:08

Have a look at this

If you need a preview then Preview an image before it is uploaded is where to find it.

Source https://stackoverflow.com/questions/63072496

QUESTION

Default value in input field lost after click

Asked 2020-Jul-04 at 14:45

So, i'm making this social network app and it has user profile. if user wants to update profile, eg. name, by opening modal EditUser, the old value of users name should be there, in input filed, and user needs to have opportunity to change/update that. I used 'defaultValue', and there is it, in input field, but if i don't change anything in that field, just click 'update', it will be lost. updated value is empty string then, and not the value that is showing in that field. how can i fix this?

Also interested how to set as default user image. so, user has profile image, and on update if user changes only name, not the picture or something else, everything else should be the same, but photo is also like input text field lost.

here is what i tried: MyProfile.tsx

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ANSWER

Answered 2020-Jul-04 at 14:45

In UpdateProfile, you should initialise the states with the value you got in props and later they could change.

Source https://stackoverflow.com/questions/62730095

QUESTION

How to remove the image from the canvas?

Asked 2020-Jun-14 at 10:34

When I upload an image, it will display in the canvas. In this image, i can make changes. Now If I try to upload new image, I want to remove the previous image and display the new one. I have tried following lines for code. But it is not clearing the canvas. Instead new images are coming on top of the previous one.

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ANSWER

Answered 2020-Jun-11 at 12:55

You'd need to clear upon each change all canvas' already created before recreating any more

Source https://stackoverflow.com/questions/62324510

QUESTION

Laravel, if I edit all the fields does not work. not saving what edited

Asked 2020-Apr-19 at 20:42

My specialist setting adds and edits in one page. Everything is working But there is one problem. When I edit everything, it does not save what I edited. I don’t understand why. Specialist have one to one table (profile_settings).

Profile settings Migration

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ANSWER

Answered 2020-Apr-19 at 19:24

Using $request->validate() can be problematic. if validation fails, it attempts to return to the previous page, which isn't always what we want. Try to do it this way instead.

Source https://stackoverflow.com/questions/61310146

QUESTION

timthumb.php and htaccess rules

Asked 2019-Sep-02 at 18:40

My PHP site (not Wordpress) is using timthumb.php and I get img related errors because it can't access /team/assets/images/upload-img.jpg?h=50&w=50, but it works without query parameters: /team/assets/images/upload-img.jpg.

Which rewrite rules should I add in order to support those query parameters for image resizing? At the moment I only have a default htaccess:

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ANSWER

Answered 2019-Sep-01 at 21:33

It’s not a .htaccess problem. You’re using $ instead of &. The URL should be:

Source https://stackoverflow.com/questions/57742782

QUESTION

How to make a div as input

Asked 2019-Aug-23 at 08:59

In my angular app, I have a custom image grid when after last image I have custom made div with some fa-icon and text when user click on it want to display the image selection window in pc

I have tried to put inside my cutome made div and give it as input{display:none} in css but nothing happens.i will attach image with this post

...

ANSWER

Answered 2019-Aug-23 at 08:59

Simplest way

component.html

Source https://stackoverflow.com/questions/57621823

QUESTION

Can't empty div with jquery

Asked 2019-Jul-09 at 12:38

I'm trying to build a image preview for uploaded files but i want the images to update their previews when user re-uploades on the same input. The code that i wrote for multiple images works but the one with primary image doesn't.

...

ANSWER

Answered 2019-Jul-09 at 12:28

You can use files on the input to get the length:

Source https://stackoverflow.com/questions/56952383

QUESTION

Fatal error: Switch statements may only contain one default clause (php7)

Asked 2019-Mar-25 at 16:03

I use php ver. 7.1.0 and now I have problem

Fatal error: Switch statements may only contain one default clause in /icore.php on line 477

Here's the code:

...

ANSWER

Answered 2017-May-16 at 11:56

You can not use a case statement inside a case. Try this corrected code

Source https://stackoverflow.com/questions/44000568

QUESTION

Add Form Fields Dynamically -- ReactJs

Asked 2019-Jan-02 at 15:17

My requirement is to add form fields dynamically. I am able to add form group dynamically on click of button +Add Heading.

In that form group, I have a button +Add Content on click of which a new input element should be added to the group.

I am able to modify the JSON accordingly and logging the same and updating the state. but my view is not rendering as expected.

Any help will be highly appreciated.

Stackblitz: https://stackblitz.com/edit/react-utjwsu?embed=1&file=index.js

/Code for the same/

...

ANSWER

Answered 2018-Dec-30 at 12:25

The reason this isn't working properly is because you are directly modifying this.state. React won't automatically re-render, because you didn't tell it that the state had changed.

You need to be calling this.setState() to set the new state.

If you are adding to an object (such as this.state.content, you need to make sure that you take a copy of the object (using something like _.cloneDeep()) to make sure you are not modifying the existing object.

Hopefully that is enough explanation for you to be able to fix your problem.

UPDATE: You are indirectly modifying the state, with this code: const contents = this.state.content; contents[index].Content.push({value:''});

contents is a variable which isn't a copy of this.state.content, it'a a reference to it. So pushing a value into the object is actually modifying the state directly. My apologies for not making this clearer in the original answer

Source https://stackoverflow.com/questions/53976924

QUESTION

upload image file in laravel is not working

Asked 2018-Jun-14 at 17:49

i'm doing upload image file by laravel and that image is not to update to database. It's my controller

...

ANSWER

Answered 2018-Jun-14 at 17:49

You should use a MultiPart form

Source https://stackoverflow.com/questions/50862972

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install upload-img

You can download it from GitHub.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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