basin | A lightweight AST interpreter built in javascript | Parser library
kandi X-RAY | basin Summary
kandi X-RAY | basin Summary
A lightweight AST (abstract syntax tree) interpreter built in javascript. BASIN is an acronym for Basic Abstract Syntax Interpreter.
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QUESTION
I have a Landsat Image and an image collection (3 images: static in time but each partially overlapping the Landsat image) with one band and want to add this one band to the Landsat image.
In a traditional GIS/python df I would do an Inner Join based on geometry but I can't figure out how this might be carried out on GEE.
Neither the image or the collection share any bands for a simple join. From what I gather a spatial join is similar to a within buffer so not what I need here. I've also tried the Filter.contains() for the join but this hasn't worked. I tried addBands() despite expecting it not to work and it results in TypeError: 'ImageCollection' object is not callable:
...ANSWER
Answered 2021-May-20 at 08:35Not 100% sure this is what you're after, but you can simply mosaic()
the 3 images into one image, and then combine the two datasets into a new ImageCollection.
UPDATE: Use addBands() instead:
QUESTION
following are my files for html, .ts and json . As json data was very extensive therefore i have just added a few states and their cities. my 1st dropdown is showing all states. Now I want to match my 1st dropdown's selected value of state with a key "state" in "cities" object in my json file so i can populate 2nd dropdown with cities relevant to that state. and I want to do this in function "getCitiesForSelectedState". please help me find solution for this.
//.ts file
...ANSWER
Answered 2021-Apr-27 at 16:44You can do it with the $event
parameter.
Make sure to compare your values safely.
If your value is not in the right type or has spaces or unwanted chars, this c.state == val
might not work.
You can use the trim
function to compare your value safely:
c.state.trim() == val.trim()
HTML
QUESTION
I am writing a simulation script which involves 2-UUV and 1-USV. Both Underwater vehicle doing surveying in orthogonal lawnmower motion model. I would like to stay in the range of both vehicle, so they started at the same origin point. I want to know that How can define USV
motion model in such a way that it is always in the communication range of both UUV
's for most of the time.
- Basically How can I manually provide dynamic path planning/ motion model to
USV
so that I can communicate to bothUUV
most of the time ? Is it even possible ? Could someone provide a basic example of this or point me in the right direction ?
Here is my simulation script :
...ANSWER
Answered 2021-Apr-26 at 07:55The Unet simulator supports multiple levels of motion models depending on the required complexity in the simulation.
The NodeInfo agent in each simulated node implements a basic dynamics model. The model is turned on using the mobility
flag which can be set in a simulation script or directly on the NodeInfo
agent. When mobility
is enabled, the agent automatically updates location
based on motion parameters such as speed
and heading
using the simple dynamics model. This can be handy to simulate the motion of a node, for example, an AUV swimming away from an underwater modem.
We can easily do this by manually updating the parameters of one of the nodes in a simulation. Use the 2-node-network
example from Unet IDE. The "Map" view of the IDE is handy to visualize the motion of nodes. Connect to the WebShell of Node A and set the mobility
, heading
, and speed
parameters. As the simulation continues the location of Node A will continue to be updated based on the speed
and heading
.
QUESTION
In relation to this question
The answer does solve the problem, but the plot is very messy as seen below.
What I wanted was a single big window with all these points inside that window. But as you can see the plot shows each point with its own window because of 131 levels. I think this can be resolved by merging the levels such that n = 131
in window
. For reference the sf_object looks like this:
ANSWER
Answered 2021-Mar-03 at 07:16The generic split
operation divides the data into several sets of data. See help(split)
.
The method split.ppp
in the spatstat
package divides a point pattern into a list of point patterns. For example if you had a point pattern X
representing the locations of trees in a forest, with marks indicating the species of each tree, then split(X)
would produce a list of point patterns, each containing the locations of trees of one species.
It seems that you did not want to split your point pattern as you had asked in the previous three questions. Rather, it seems that you probably wanted to produce a single point pattern with factor-valued marks, where the mark value identifies the grouping/classification. You've already done this in the previous question, by doing marks(X) <- factor(.....)
, so just plot that point pattern X
.
QUESTION
In relation to this question I have a sptatstat ppp
object sf_owin
which has marks
as S3:data.frame
as seen below:
The sf_object looks like this:
...ANSWER
Answered 2021-Mar-03 at 00:12With spatstat loaded and the ppp
object saved as sf_owin
(very counterintuitive name for a ppp
object) you can simply overwrite the marks as:
QUESTION
I successfully converted an sf object to ppp using the code below:
sf_owin = maptools::as.ppp.SpatialPointsDataFrame(as_Spatial(sf_points__flat))
sf_points__flat looks like this:
...ANSWER
Answered 2021-Mar-02 at 06:49This question is about the spatstat
package.
The error message indicates that the split
command is dispatched to split.ppp
, so you could look up the help for split.ppp
to figure out the problem.
The help file would tell you that the argument which.marks
is ignored by split.ppp
. So you can remove that argument.
To split the point pattern, you need a factor
(a vector of categorical values which specify the grouping). The marks in the point pattern are not factors. (This is what the error message is saying.) According to your printed output, the column STATION_NA
is character valued. If you want to split the pattern according to these values, you need to convert them to factor values. For example
QUESTION
I am working with precipitation data for four river basins. The four rivers are Main, Danube, Isar and Inn. The precipitation data set is organised in an array (dimensions are 150 150 80
). The third dimension respresents the single time steps. For every river basin I have a matrix called "mask_rivername", so "mask_Main", "mask_Danube" etc. Each matrix is of dimensions 150 150
. The goal is to multiply the single matrices with every single time step of the precipitation data.
To achieve this, I created a list for every river called "Main.list", "Danube.list", "Isar.list" and "Inn.list".
Now I would like to fill the single lists, for example by using a loop. If I do that one by one it works well:
ANSWER
Answered 2021-Jan-28 at 18:32The question can be answered the R way with a double lapply
loop. As long as both arguments, the precipitation array and the masks are in list objects. That's what the preliminary code does, to create two lists.
QUESTION
So I'm programing a Basin Hoping from zero to find the potential minima of a system of interacting particles and I have obtained good results so far, but since since I increase the number of particles of the system, the code takes more time to run. I am using scipy conjugate gradient for finding local minima. I'm not getting any error messages and the program seems to work out fine, but I was wondering how I can optimize the code so the computing time is reduced.
I defined the Basin Hopping as a function, given:
...ANSWER
Answered 2021-Jan-27 at 02:25Two things I noticed after a quick look where you can definitely save some time. Both require some more thinking before, but afterwards you will be rewarded with an optimised and cleaner code.
1. Try to avoid using append
. append
is highly inefficient. You start with an empty array, and afterwards need to allocate more memory each time. This leads to inefficient memory handling, as you copy your array each time you append a number. The longer the array gets, the more inefficient append
becomes.
Alternative: Use np.zeros((m,n))
to initialise the array, with m
and n
being the size it will end up with. Then you need a counter that puts the new values in the corresponding places. If the size of the array is not defined before your calculation, you can initialise it as a big number, and afterwards cut it.
2. Try to avoid using for
loops. They are generally very slow, especially when iterating through large matrices, as you need to index each entry individually.
Alternative: Matrix operations are generally much faster. For example, instead of r = np.sqrt(sum((matposg[j,:]-matposg[k,:])**2))
inside two for
loops, you could first define two matrices A
and B
that correspond to matposg[j,:]
and matposg[k,:]
(should be possible without the use of loops!) and then simply use r = np.linalg.norm(A-B)
QUESTION
ANSWER
Answered 2021-Jan-17 at 15:39Alright, there are 2 problems that I spotted. Problem 1 is that in your draw_group()
ggproto method, you convert the radii from nautical miles to meters (I think), but you write this to the coords
variable. However, you use the data
variable to do the geosphere::destPoint
calculation.
Here is a version of that method that I think should work:
QUESTION
I'm working on a MERN app, pretty much done, all I have left to do is deploy it. The app works perfectly when I run it locally, but I deploy to Heroku, I get the following error in the browser console:
...ANSWER
Answered 2021-Jan-12 at 20:21The issue was the environment variables. The reason it worked on my local machine was because of the env file, but when I deploy to Heroku, the env file is gitignored. So I had to set up the environment variables again in Heroku by going to setting > config vars, and configuring the variables the same way they are on my local machine. This fixed the problem instantly.
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