franchise | π a notebook sql client what you get when have a lot of sequels | SQL Database library
kandi X-RAY | franchise Summary
kandi X-RAY | franchise Summary
Franchise is a lightweight but powerful SQL tool with a notebook interface. You can use it online at franchise.cloud.
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Top functions reviewed by kandi - BETA
- Creates a Swig widget .
- token base64 - > String
- Parse an input string
- prepare names from workspaces
- performs a view review
- extract edit columns from source
- open bridge socket .
- Create a new window
- Returns complete completions for a table .
- Constructs a new Schema instance .
franchise Key Features
franchise Examples and Code Snippets
Community Discussions
Trending Discussions on franchise
QUESTION
ANSWER
Answered 2022-Apr-11 at 10:48Please, try using the next code. It needs only a single dictionary, creating keys based on the first two company name characters. It will add new sheets based on the dictionary keys and clear the existing if they exist:
QUESTION
I am building backend app, when the order is placed I get console log but the screen doesn't get updated and also the back button(react navigation), response after few seconds.
...ANSWER
Answered 2022-Mar-07 at 11:05You have made an async function but you haven't used the await keyword. Also you'll have to create a state for loader and conditionally render a loader component till you have fetched all the data.
QUESTION
ANSWER
Answered 2022-Feb-27 at 10:35Your html
must use city_id
as a value and not the city name. Because you're trying to search using the id
not name
.
QUESTION
I have an array, I want to order that array by "is_available" key, (true first) I'm using laravel 8 and a livewire component
...ANSWER
Answered 2022-Feb-23 at 20:05Livewire will on each request serialize the public properties, so that it can be sent to the frontend and stored in JavaScript.
Now here's the kicker: JavaScript will do its own internal sorting on objects, which you can't prevent. So to work around that, you have to re-key your array after you sort it, so that the keys are now in ascending order of what you sorted it to.
Basically, all you need to do before you call ->toArray()
, is to call ->values()
on it, thereby grabbing the values in the order they were, and PHP will assign it new keys starting from 0.
QUESTION
I created this function to count the maximum number of consecutive characters in a word.
...ANSWER
Answered 2022-Feb-12 at 14:17This command rle(unlist(strsplit(word, split = "")))$lengths
is not vectorized and thus is operating on the entire list of words for each row thus the same result for each row.
You will need to use some type of loop (ie for
, apply
, purrr::map
) to solve it.
QUESTION
So I have a column that contains baseball team names, and I want to split it into the 2 new columns, that will contain separately city name and team name.
Team New York Giants Atlanta Braves Chicago Cubs Chicago White SoxI would like to get something like this:
Team City Franchise New York Giants New York Giants Atlanta Braves Atlanta Braves Chicago Cubs Chicago Cubs Chicago White Sox Chicago White SoxWhat I have tried so far?
- using
split
andrsplit
--> it gets the job done, but can't unify it. - did the count
df['cnt'] = df.asc.apply(lambda x: len(str(x).split(' ')))
to get number of strings, so I know what kind of cases I have
There are 3 different cases:
- Standard one (e.g. Atlanta Braves)
- City with 2 strings (e.g. New York Giants)
- Franchise name with 2 strings (e.g. Chicago White Sox )
What I would like to do?
- Split based on conditions (
if cnt=2 then split on 1st occurence
). Can't find syntax for this, how this would go? - Update based on names (e.g.
if ['Col_name'].str.contains("York" or "Angeles") then split on 2nd occurence
. Also, can't find working syntax, example for this?
What would be a good approach to solve this?
Thanks!
...ANSWER
Answered 2022-Jan-24 at 13:36Use:
QUESTION
I have location
index with following properties. Documents are related through entityId
and parentEntityId
, so there's hierarchical data. And also there's entityPath
field which contains path of current document all the way to root document.
Can someone guide how to get all children entityIds given an entityId?
...ANSWER
Answered 2022-Jan-12 at 09:15There's no way to do that in Elasticsearch with your current data structure.
There are two options:
- Use multi-level nested data structures and model them at indexing time
- Use recursive calls in your application
QUESTION
I have tried everything i know and can't get an alterate tablerow class to work , without having all the rows duplicated or having a bunch of dummy rows inserted
Here is what i have
...ANSWER
Answered 2021-Dec-20 at 03:42QUESTION
Hi I've been building this app and I came across a problem that I dont know how to solve. I want to have a Row of Card Widgets, that all display some info I provided beforehand. This is basically how I wanted to do it:
...ANSWER
Answered 2021-Nov-10 at 13:39You can do so by restricting the Card width by SizedBox or Container and then using the maxLines and overflow as you had used.
See the changes below in your MovieWidget
QUESTION
I'm creating a game for my manga comic franchise, Rebound Ready!, which combines basketball and PokΓ©mon. The idea of the game is that you play mini basketball matches, and points are awarded if you score a basket (1, 2, or 3 points can be awarded depending on a few factors).
If you play through the game, before the points are awarded, there is an accuracy meter that you have to complete, which determines how effective your shot is. Once you click the meter, the tracker (which is what indicates where you have landed) will stop - if you land on one of three colours on the accuracy meter (red, green and orange), you will get a certain amount of points - red being the least, green being the most.
I have drafted a way that the point-awarding system could work. I have tried two ways of attempting this:
...ANSWER
Answered 2021-Oct-28 at 14:10You're not actually changing the value of points
: use points = points + x
, or shorter, points += x
.
Also note, Method 1
uses the same conditions each time; to work, it would need to be
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Run a container with image:
After build check out dist folder.
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