Sherwood | com using a Ruby on Rails backend | Business library
kandi X-RAY | Sherwood Summary
kandi X-RAY | Sherwood Summary
Sherwood is a single page app clone of the popular stock trading site robinhood.com featuring over 8,000 publicly traded companies complete with company information, real-time stock data, and interactive charts of stock and portfolio performance.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of Sherwood
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Trending Discussions on Sherwood
QUESTION
So I have tried that:
...ANSWER
Answered 2021-Dec-28 at 15:03You are returning an array of arrays. You need to access them using an index
QUESTION
I am a beginner to learn about React. I tried to follow up on one Udemy lecture but my searchbox didn't work as well even though I rewrite the code three times... Could you check this code why my searchbox didn't work? If I type some words in searchbox, it should show matched cards(write down name on search box and it shows a matched card)
I will share my code bellow
This is index.js
...ANSWER
Answered 2021-Oct-18 at 17:11You've got a misspelling on line 31 in App.js
Your event is 'searchChange' not 'searchCange' and the line after fixing should look like this:
QUESTION
I have javascript to fetch json information. I will be storing this json file locally (I downloaded an example file and added birthdate object for my use example from https://jsonplaceholder.typicode.com/users)
I am trying to parse the returned JSON information and post the contents into 2 seperate div's. I have a json object named "birthdate". In my script, I have a var set to call today's date named "today". It prints the date as "05-12" in console, and that is how I have the "birthdate" formatted in JSON as well. I don't need the year or time.
What I would like is to have the script compare "today" with the json object "birthdate". If today = birthdate, then I would like to have that entry information displayed in the user-list-today div to appear under the Birthday Today section of the page.
If today does not equal birthdate, I would like to have all other entries displayed in the user-list-future div to appear under the Birthday Future section of the page.
Nothing should be posted in both areas, only one or the other.
Any help that anyone could provide would be greatly appreciated. I will include all of my code below. The snippet may give error because I have local path to JSON file instead of online version.
Here is my codepen of it codepen doesnt have the birthday JSON object https://codepen.io/abc-123-webguy/pen/poegaLq
...ANSWER
Answered 2021-May-12 at 21:47This is because you are appending the same node to two different divs. If you look at the documentation to appendChild
here, you can see this:
QUESTION
Given two dataframes as follow:
df1:
...ANSWER
Answered 2021-May-06 at 10:35k="|".join(df2['street'].to_list())
df1=df1.assign(temp=df1['address'].str.findall(k).str.join(', '), temp1=df1['address'].str.split(",").str[-1])
dfnew=pd.merge(df1,df2, how='left', left_on=['temp','temp1'], right_on=['street',"state"])
QUESTION
following are my files for html, .ts and json . As json data was very extensive therefore i have just added a few states and their cities. my 1st dropdown is showing all states. Now I want to match my 1st dropdown's selected value of state with a key "state" in "cities" object in my json file so i can populate 2nd dropdown with cities relevant to that state. and I want to do this in function "getCitiesForSelectedState". please help me find solution for this.
//.ts file
...ANSWER
Answered 2021-Apr-27 at 16:44You can do it with the $event
parameter.
Make sure to compare your values safely.
If your value is not in the right type or has spaces or unwanted chars, this c.state == val
might not work.
You can use the trim
function to compare your value safely:
c.state.trim() == val.trim()
HTML
QUESTION
I had a specific question about turning my data into two columns so I can make an edgelist. I've attached a screenshot of the data. There's up to V10, and each row represents artists that have worked on the same song. I wanted to create an edgelist with the artist names. For example, for rows that have person A, B, C, D, I wanted to create:
A B
A C
A D
B C
B D
C D
The code I used so far is:
reltest <- t(do.call(cbind, lapply(cleanartists[sapply(cleanartists, length) >= 2], combn, 2)))
But this gives me all possible combinations among the artist names, not just the ones that have existing relationships. This is what my data looks like:
...ANSWER
Answered 2020-Jun-11 at 19:36You can use apply
to apply your function to every row, and then only take the elements that are not NA
. And with the approach from here you can get rid of duplicates.
QUESTION
Any ideas on this one in Pyspark?
I have salaries like the below in the Salary column. I've tried to remove the $
...ANSWER
Answered 2020-Apr-12 at 15:06try the below regexp_replace code
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