do-notation | : arrow_left : Do notation for Fantasy Land monad | Functional Programming library
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kandi X-RAY | do-notation Summary
Do notation for Fantasy Land monad types.
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QUESTION
I wonder if it is possible to implement something similar to the do-notation of Haskell in Kotlin on Lists or List-Like structures with monadic properties.
Take following example:
...ANSWER
Answered 2021-Apr-14 at 08:18It's not possible at the moment to implement monad comprehension for List, Flow, and other non-deterministic data structures that emit more than one value. The current implementation of continuations in Kotlin is single shot only. This means a continuation can resume a program with a single emitted value. Resuming the program more than once requires hijacking the continuation stack labels with reflection in order to replay their state in the second resumption. Additionally replaying a block in which a multishot data type is binding would replay all effects previous to the bind since the block has to emit again.
QUESTION
Mind the following function:
...ANSWER
Answered 2021-Apr-07 at 17:25Sure, you can use ContT
, and as Carl pointed out in the comments, your Trampoline
is a specialisation of Free
, so we can reuse its Monad
instance, or you can write the instances for your Trampoline
yourself.
QUESTION
ANSWER
Answered 2021-Jan-02 at 17:58Each
sumArray
invocation returns a state monad holding the sum of givenInt
array values.
No, it doesn't return "a state monad", and it doesn't hold the sum of the array.
It returns a State Int Unit
value, which represents a "stateful computation of a Unit
" (using an Int
for the state). To get the sum, you actually have to run that computation:
QUESTION
What is the order in which Haskell guards are evaluated?
Say that I have a function which returns a Bool:
...ANSWER
Answered 2020-Dec-26 at 21:29Evaluating the tests within guards can’t have any side-effects — unlike in procedural languages. So the order of evaluating the comparisons or Boolean connectives doesn’t make any difference to the semantics of the program.
Prioritising the branches — that is, each of the lines starting |
— is from top to bottom. But really ‘evaluating’ is the wrong concept: it would be OK for the compiler to first evaluate your b1 == False
, providing it didn’t take the third branch until it had checked the first two. (GHC doesn’t actually do that; I’m just setting up a straw man.)
Note that in a call to someFunc
, the arguments for b1, b2
might be arbitrarily complex expressions. Haskell’s ‘Lazy semantics’ mean that neither of them are evaluated until needed.
Does this logic always hold?
Be careful: if an early guard turns out False, you can’t assume anything about the expressions in it. The compiler might have rearranged them for efficiency, evaluated one out of textual order, then moved on. In your example, if for the first branch it turned out b1 /= True
, the compiler might not evaluate b2
at all. So you can’t conclude anything about b2
. Indeed b2
might give bottom/infinite calculation, if evaluated.
It’s not just with Monads or Do-notation (which are the same thing) that expressions are not necessarily evaluated in textual order — that’s true across any expressions in any context. (The IO Monad has some dodgy semantics, to make it seem ‘statements’ are executed top-to-bottom.)
QUESTION
I'm trying to check my code using QuickCheck so I need to make Arbitrary
instances for my types. One type data Schedule
is complicated, and I don't know how to treat it properly. Three instances (for Date
, Activity
, TimeStart
) work fine. But the last instance (for Schedule
) is incorrect, and I seek for help with fixing it.
ANSWER
Answered 2020-Aug-23 at 07:44When you already have Arbitrary
instances for all the constituent types of a complex type (in this case Date
, Activity
, etc.), you don't have to do much.
Due to built-in Arbitrary
instances of lists, tuples, etc., you can simply define the composed Arbitrary
instance like this:
QUESTION
Background Context:
Mathematically, I can see the need for associativity to keep things simple without relying on order. All implementations of example monads that I've come across (blogs, books etc.,) seem to always work. It seems simply the act of having map, flatMap
(Scala) or fmap, >>=
(Haskell) makes things a working monad.
From what I gather this isn't entirely true, but can't come up with a counter example showing the "need" for the law via a failure case.
Wadler's paper mentions the possibility of an incorrect implementation:
The Haskell Wiki mentions the following:
The third law is a kind of associativity law for
>>=
. Obeying the three laws ensures that the semantics of the do-notation using the monad will be consistent.Any type constructor with return and bind operators that satisfy the three monad laws is a monad. In Haskell, the compiler does not check that the laws hold for every instance of the Monad class. It is up to the programmer to ensure that any Monad instance they create satisfies the monad laws.
Question(s):
- What is an example of an incorrect monad implementation, that looks correct but breaks associativity?
- How does this impact the
do
-notation? - How does one validate the correctness of a monad implementation? Do we need to write test cases for each new monad, or a generic one can be written to check that any monad implementation is correct?
ANSWER
Answered 2020-Mar-20 at 07:51Here's an example of non-monad which fails associativity:
QUESTION
Monadic computations quickly become confusing in JS:
...ANSWER
Answered 2020-Feb-15 at 04:28You can use the immutagen library to write monadic code using generators.
QUESTION
I recently discovered the guard
function associated with the Control.Monad
module (defined here) and it seemed to be a perfect function to solve a common programming challenge: the eight queens problem. I came up with this solution:
ANSWER
Answered 2020-Jan-12 at 11:22You can recurse while keeping around the list of already-placed queens:
QUESTION
ANSWER
Answered 2020-Jan-09 at 20:20There's a for comprehension construct in vavr that you could use for your use case. It helps you transform multiple Iterable
, Option
, Try
, Future
or List
instances to another Iterator
, Option
, Try
, Future
or List
instance respectively, by combining them (as rows of their cartesian product) into result values.
In your case, Either
being an Iterator
on the right value, you can use the For
construct for Iterable
s to construct a Tuple3
of the String
right values, and iterate over the resulting Iterator
by invoking your side-effecting code, or mapping/transforming them in whatever way you want. You will have a rich vavr Iterator
, so that's a lot more flexible than a simple JDK Iterator
.
QUESTION
To generate x86 assembly code, I have defined a custom type called X86
:
ANSWER
Answered 2018-Mar-31 at 04:45As you probably now underestand from the other answers, the problem with your approach was that even though you were using the counter, you were still generating your labels locally. In particular
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