mostly-adequate-guide | Mostly adequate guide to FP | Functional Programming library
kandi X-RAY | mostly-adequate-guide Summary
kandi X-RAY | mostly-adequate-guide Summary
This is a book on the functional paradigm in general. We'll use the world's most popular functional programming language: JavaScript. Some may feel this is a poor choice as it's against the grain of the current culture which, at the moment, feels predominately imperative. However, I believe it is the best way to learn FP for several reasons:. That said, typed functional languages will, without a doubt, be the best place to code in the style presented by this book. JavaScript will be our means of learning a paradigm, where you apply it is up to you. Luckily, the interfaces are mathematical and, as such, ubiquitous. You'll find yourself at home with Swiftz, Scalaz, Haskell, PureScript, and other mathematically inclined environments.
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Top functions reviewed by kandi - BETA
- Inspector function .
- Compose functions .
- Given a function returns a function that is invoked with arguments
- inspects a term
- Wrap a function on obj on the given function .
- named function .
- Pretty print function .
- Inspects args .
mostly-adequate-guide Key Features
mostly-adequate-guide Examples and Code Snippets
Lines of Code : 28License : Non-SPDX
Copyfunction inspect(x) {
if (x && typeof x.inspect === 'function') {
return x.inspect();
}
function inspectFn(f) {
return f.name ? f.name : f.toString();
}
function inspectTerm(t) {
switch (typeof t) {
case 'string' function compose(...fns) {
const n = fns.length;
return function $compose(...args) {
$compose.callees = [];
let $args = args;
for (let i = n - 1; i >= 0; i -= 1) {
const fn = fns[i];
assert(
typeof fn === 'f function curry(fn) {
assert(
typeof fn === 'function',
typeMismatch('function -> ?', [getType(fn), '?'].join(' -> '), 'curry'),
);
const arity = fn.length;
return namedAs(fn.name, function $curry(...args) {
$curry.partiall Community Discussions
Trending Discussions on mostly-adequate-guide
QUESTION
I'm reading a functional programming tutorial called Professor Frisby's Mostly Adequate Guide to Functional Programming, the author gives an introduction to Hindley-Milner and several examples about it, one of them being:
ANSWER
Answered 2021-Apr-14 at 08:27I went through this tutorial myself and I think generally functions are assumed to be curried so f being b -> a -> b is perhaps counter-intuitive but not necessarily wrong AFAIK. (Take everything I say with a pinch of salt; I'm not an expert ;)
However the parentheses around f itself in the reduce signature gives an important clue to the reader (at least to the JavaScript reader) that f is a function:
QUESTION
Still learning about FP but I feel that I finally started to get my head around monads, specifically on using them. So here is what I have:
...ANSWER
Answered 2020-Aug-09 at 20:40I think you're looking for
QUESTION
I'm very new to Functional Programming and I'm struggling a lot with running traverse on arrays.
When I read this book it seems that I should be able to simply traverse between Monads but I can't wrap my head around this concept with fp-ts.
Can someone explain the following using array.traverse/sequence or any other ways please?
- How can I go from
TaskEithertoTaskEither[]>; or is there a better way to go from a single error to nested errors while keeping the typings simple? - How can I go from
TaskEither>to something likeTaskEither>or something similar; or should we map the result of that function to turn back toEither?
Consider the following simplified code to have a better idea what we are doing with these arrays:
...ANSWER
Answered 2020-Apr-10 at 17:20Strictly spoken, Applicative is sufficient for traverse - you don't need a monad.
TaskEithertoTaskEither[]>?
QUESTION
Chapter 5 of Dr. Frisby's Guide asserts that identity of a unary function is the function itself. That is, the last line of the code below should return true.
However, I am getting 'false'. Why?
...ANSWER
Answered 2020-Mar-01 at 02:53I think it might depend on the language that you're using. Most languages are not equipped with a way to establish 'algebraic' equality between functions, and are likely to compare functions via their 'pointer' or 'reference', even if such is abstracted away. As a result, since your composed function would be a different function altogether (albeit with the same behaviour), it might not return as equal.
This being said, you can probably test it by having a set of input and running both functions on it, checking the equality of the output.
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