theory | Abstraction layer for cross platform JavaScript | Reactive Programming library

 by   amark JavaScript Version: Current License: No License

kandi X-RAY | theory Summary

kandi X-RAY | theory Summary

theory is a JavaScript library typically used in Programming Style, Reactive Programming applications. theory has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

Theory is an abstraction layer for server side and client side JavaScript.
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            kandi-support Support

              theory has a low active ecosystem.
              It has 142 star(s) with 6 fork(s). There are 7 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 1 open issues and 2 have been closed. On average issues are closed in 142 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of theory is current.

            kandi-Quality Quality

              theory has 0 bugs and 0 code smells.

            kandi-Security Security

              theory has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              theory code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              theory does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
              OutlinedDot
              Without a license, all rights are reserved, and you cannot use the library in your applications.

            kandi-Reuse Reuse

              theory releases are not available. You will need to build from source code and install.
              Installation instructions are not available. Examples and code snippets are available.
              theory saves you 80 person hours of effort in developing the same functionality from scratch.
              It has 206 lines of code, 0 functions and 37 files.
              It has low code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed theory and discovered the below as its top functions. This is intended to give you an instant insight into theory implemented functionality, and help decide if they suit your requirements.
            • Initiate the flow
            • Constructs a theory object .
            • Main test function
            • add fnns to functions
            • Create list .
            • Get an object
            • Get text .
            • set num to number
            • Creates a bi - number
            • Registers an event listener .
            Get all kandi verified functions for this library.

            theory Key Features

            No Key Features are available at this moment for theory.

            theory Examples and Code Snippets

            No Code Snippets are available at this moment for theory.

            Community Discussions

            QUESTION

            Change behaviour of AutoFixture with AutoMoq to return false for methods
            Asked 2022-Mar-31 at 09:22

            Say that I have the following interface:

            ...

            ANSWER

            Answered 2022-Mar-26 at 16:40

            First of all, you may want to use AutoMoqDataAttribute to create a mock of the ITeam interface:

            Source https://stackoverflow.com/questions/71626344

            QUESTION

            Why should I run multiple elasticsearch nodes on a single docker host?
            Asked 2022-Mar-09 at 18:17

            There are a lot of articles online about running an Elasticsearch multi-node cluster using docker-compose, including the official documentation for Elasticsearch 8.0. However, I cannot find a reason why you would set up multiple nodes on the same docker host. Is this the recommended setup for a production environment? Or is it an example of theory in practice?

            ...

            ANSWER

            Answered 2022-Mar-04 at 15:49

            You shouldn't consider this a production environment. The guides are examples, often for lab environments, and testing scenarios with the application. I would not consider them production ready, and compose is often not considered a production grade tool since everything it does is to a single docker node, where in production you typically want multiple nodes spread across multiple availability zones.

            Source https://stackoverflow.com/questions/71298259

            QUESTION

            Is Shannon-Fano coding ambiguous?
            Asked 2022-Mar-08 at 19:38
            In a nutshell:

            Is the Shannon-Fano coding as described in Fano's paper The Transmission of Information (1952) really ambiguous?

            In Detail:

            3 papers
            Claude E. Shannon published his famous paper A Mathematical Theory of Communication in July 1948. In this paper he invented the term bit as we know it today and he also defined what we call Shannon entropy today. And he also proposed an entropy based data compression algorithm in this paper. But Shannon's algorithm was so weak, that under certain circumstances the "compressed" messages could be even longer than in fix length coding. A few month later (March 1949) Robert M. Fano published an improved version of Shannons algorithm in the paper The Transmission of Information. 3 years after Fano (in September 1952) his student David A. Huffman published an even better version in his paper A Method for the Construction of Minimum-Redundancy Codes. Hoffman Coding is more efficient than its two predecessors and it is still used today. But my question is about the algorithm published by Fano which usually is called Shannon-Fano-Coding.

            The algorithm
            This description is based on the description from Wikipedia. Sorry, I did not fully read Fano's paper. I only browsed through it. It is 37 pages long and I really tried hard to find a passage where he talks about the topic of my question, but I could not find it. So, here is how Shannon-Fano encoding works:

            1. Count how often each character appears in the message.
            2. Sort all characters by frequency, characters with highest frequency on top of the list
            3. Divide the list into two parts, such that the sums of frequencies in both parts are as equal as possible. Add the bit 0 to one part and the bit 1 to the other part.
            4. Repeat step 3 on each part that contains 2 or more characters until all parts consist of only 1 character.
            5. Concatenate all bits from all rounds. This is the Shannon-Fano-code of that character.

            An example
            Let's execute this on a really tiny example (I think it's the smallest message where the problem appears). Here is the message to encode:

            ...

            ANSWER

            Answered 2022-Mar-08 at 19:00

            To directly answer your question, without further elaboration about how to break ties, two different implementations of Shannon-Fano could produce different codes of different lengths for the same inputs.

            As @MattTimmermans noted in the comments, Shannon-Fano does not always produce optimal prefix-free codings the way that, say, Huffman coding does. It might therefore be helpful to think of it less as an algorithm and more of a heuristic - something that likely will produce a good code but isn't guaranteed to give an optimal solution. Many heuristics suffer from similar issues, where minor tweaks in the input or how ties are broken could result in different results. A good example of this is the greedy coloring algorithm for finding vertex colorings of graphs. The linked Wikipedia article includes an example in which changing the order in which nodes are visited by the same basic algorithm yields wildly different results.

            Even algorithms that produce optimal results, however, can sometimes produce different optimal results based on tiebreaks. Take Huffman coding, for example, which works by repeatedly finding the two lowest-weight trees assembled so far and merging them together. In the event that there are three or more trees at some intermediary step that are all tied for the same weight, different implementations of Huffman coding could produce different prefix-free codes based on which two they join together. The resulting trees would all be equally "good," though, in that they'd all produce outputs of the same length. (That's largely because, unlike Shannon-Fano, Huffman coding is guaranteed to produce an optimal encoding.)

            That being said, it's easy to adjust Shannon-Fano so that it always produces a consistent result. For example, you could say "in the event of a tie, choose the partition that puts fewer items into the top group," at which point you would always consistently produce the same coding. It wouldn't necessarily be an optimal encoding, but, then again, since Shannon-Fano was never guaranteed to do so, this is probably not a major concern.

            If, on the other hand, you're interested in the question of "when Shannon-Fano has to break a tie, how do I decide how to break the tie to produce the optimal solution?," then I'm not sure of a way to do this other than recursively trying both options and seeing which one is better, which in the worst case leads to exponentially-slow runtimes. But perhaps someone else here can find a way to do that>

            Source https://stackoverflow.com/questions/71399572

            QUESTION

            Why PPI reported by Delphi is different from the calculated one?
            Asked 2022-Jan-21 at 08:08

            I use Delphi 10.3 Rio, and need to know the screen PixelsPerInch ratio to scale my application accordingly.

            Calculating with the formula, my screen has 142 ppi. (Real values are: 15.5" diagonal and 1920 x 1080 resolution). But when I read in Delphi the Screen.PixelsPerInch property, I get 134 ! And this value is reportend in PixelsPerInch property of every TForm I create, too. So, why this difference and which is the real ppi ?

            AIDA64 reports the real value of 142 ppi... So I think is something wrong with the pixels per inch ratio in Delphi...

            Edit:

            I managed to get the real PPI with this code... but I cannot change this in every Delphi component. So, if I use this value in my components, won't I mess everything up ?

            ...

            ANSWER

            Answered 2022-Jan-21 at 08:08
            Operating system PPI

            There is no bug and Delphi returns proper value in PixelsPerInch.

            PPI OS will return for the purpose of scaling your application is not the actual PPI value of the actual display device, but virtual pixel density.

            For developing applications the PPI value you need is the one that OS gives you, not the actual PPI value of the display device.

            Everything you need to know is baseline PPI for the OS and current PPI or the scale factor. Using those numbers you can then calculate number of scaled pixels from some baseline pixel value.

            For instance, if your control baseline width is 100 pixels and screen scale is 150% from the baseline PPI then your runtime control size will be 150 pixels.

            Different operating systems have different baseline PPI.

            OS Baseline PPI Windows 96 PPI macOS 72 PPI Android 160 PPI iOS 163 PPI

            Calculation:

            Source https://stackoverflow.com/questions/70788654

            QUESTION

            Problem with memory allocation in Julia code
            Asked 2022-Jan-19 at 09:34

            I used a function in Python/Numpy to solve a problem in combinatorial game theory.

            ...

            ANSWER

            Answered 2022-Jan-19 at 09:34

            The original code can be re-written in the following way:

            Source https://stackoverflow.com/questions/70766215

            QUESTION

            How to compare file paths from JsonConfigurationSources and Directory.GetFiles properly?
            Asked 2021-Dec-20 at 04:22

            I created an extension method to add all JSON configuration files to the IConfigurationBuilder

            ...

            ANSWER

            Answered 2021-Dec-19 at 09:24

            The logic of comparing files seems alright, I don't find any outstanding problem with it, it is ok to prepend the "/" to match what you need. Could be even better if you could use the System.IO.Path.DirectorySeparatorChar for the directory root path as well, so if you run on windows or Linux you will have no issues.

            But there may be a conceptual problem with what you are doing. To my understanding you aim to verify existence of specific configuration files required for your program to work right, if those files are missing than the program should fail. But that kind of failure due to missing configuration files, is an expected and valid result of your code. Yet, you unit-test this as if missing files should fail the test, as if missing files are an indication that something wrong with your code, this is wrong.

            Missing files are not indication of your code not working correct and Unit-test should not be used as a validator to make sure the files exist prior executing the program, you will likely agree that unit-test is not part of the actual process and it should only aim to test your code and not preconditions, the test should compare an expected result (mock result of your code) vs. actual result and certainly not meant to become part of the code. That unit test looks like a validator that should be in the code.

            So unless those files are produced by your specific code (and not the deployment) there is no sense testing that. In such case you need to create a configuration validator code - and your unit test could test that instead. So it will test that the validator expected result with a mock input you provide. But the thing here is that you would know that you only testing the validation logic and not the actual existence of the files.

            Source https://stackoverflow.com/questions/70378711

            QUESTION

            Why is a segmentation fault not recoverable?
            Asked 2021-Dec-13 at 08:36

            Following a previous question of mine, most comments say "just don't, you are in a limbo state, you have to kill everything and start over". There is also a "safeish" workaround.

            What I fail to understand is why a segmentation fault is inherently nonrecoverable.

            The moment in which writing to protected memory is caught - otherwise, the SIGSEGV would not be sent.

            If the moment of writing to protected memory can be caught, I don't see why - in theory - it can't be reverted, at some low level, and have the SIGSEGV converted to a standard software exception.

            Please explain why after a segmentation fault the program is in an undetermined state, as very obviously, the fault is thrown before memory was actually changed (I am probably wrong and don't see why). Had it been thrown after, one could create a program that changes protected memory, one byte at a time, getting segmentation faults, and eventually reprogramming the kernel - a security risk that is not present, as we can see the world still stands.

            1. When exactly does a segmentation fault happen (= when is SIGSEGV sent)?
            2. Why is the process in an undefined behavior state after that point?
            3. Why is it not recoverable?
            4. Why does this solution avoid that unrecoverable state? Does it even?
            ...

            ANSWER

            Answered 2021-Dec-10 at 15:05

            When exactly does segmentation fault happen (=when is SIGSEGV sent)?

            When you attempt to access memory you don’t have access to, such as accessing an array out of bounds or dereferencing an invalid pointer. The signal SIGSEGV is standardized but different OS might implement it differently. "Segmentation fault" is mainly a term used in *nix systems, Windows calls it "access violation".

            Why is the process in undefined behavior state after that point?

            Because one or several of the variables in the program didn’t behave as expected. Let’s say you have some array that is supposed to store a number of values, but you didn’t allocate enough room for all them. So only those you allocated room for get written correctly, and the rest written out of bounds of the array can hold any values. How exactly is the OS to know how critical those out of bounds values are for your application to function? It knows nothing of their purpose.

            Furthermore, writing outside allowed memory can often corrupt other unrelated variables, which is obviously dangerous and can cause any random behavior. Such bugs are often hard to track down. Stack overflows for example are such segmentation faults prone to overwrite adjacent variables, unless the error was caught by protection mechanisms.

            If we look at the behavior of "bare metal" microcontroller systems without any OS and no virtual memory features, just raw physical memory - they will just silently do exactly as told - for example, overwriting unrelated variables and keep on going. Which in turn could cause disastrous behavior in case the application is mission-critical.

            Why is it not recoverable?

            Because the OS doesn’t know what your program is supposed to be doing.

            Though in the "bare metal" scenario above, the system might be smart enough to place itself in a safe mode and keep going. Critical applications such as automotive and med-tech aren’t allowed to just stop or reset, as that in itself might be dangerous. They will rather try to "limp home" with limited functionality.

            Why does this solution avoid that unrecoverable state? Does it even?

            That solution is just ignoring the error and keeps on going. It doesn’t fix the problem that caused it. It’s a very dirty patch and setjmp/longjmp in general are very dangerous functions that should be avoided for any purpose.

            We have to realize that a segmentation fault is a symptom of a bug, not the cause.

            Source https://stackoverflow.com/questions/70258418

            QUESTION

            Compiler can't execute constexpr expression
            Asked 2021-Nov-24 at 04:11

            I have code something like this:

            ...

            ANSWER

            Answered 2021-Nov-24 at 04:11

            It's not about the reference problem. And constexpr variable and constexpr function are different things. Quoted from the answer https://stackoverflow.com/a/31720324:

            The reference does not have a preceding initialization from the point of view of i, though: It's a parameter. It's initialized once ByReference is called.

            This is fine, since f does have preceding initialization. The initializer of f is a constant expression as well, since the implicitly declared default constructor is constexpr in this case (§12.1/5). Hence i is initialized by a constant expression and the invocation is a constant expression itself.

            And about "preceding initialization", quoted from this:

            It does mean "be initialized", but it's more importantly about the visibility of a preceding initialization within the context of the expression being evaluated. In your example, in the context of evaluating func(0) the compiler has the context to see the initialization of rf with 0. However, in the context of evaluating just the expression rf within func, it doesn't see an initialization of rf. The analysis is local, as in it doesn't analyze every call-site. This leads to expression rf itself within func not being a constant expression while func(0) is a constant expression.

            Corresponding to your case, the line:

            Source https://stackoverflow.com/questions/70018502

            QUESTION

            Parsing binary files in Raku
            Asked 2021-Nov-09 at 11:34

            I would like to parse binary files in Raku using its regex / grammar engine, but I didn't found how to do it because the input is coerce to string.

            Is there a way to avoid this string coercion and use objects of type Buf or Blob ?

            I was thinking maybe it is possible to change something in the Metamodel ?

            I know that I can use unpack but I would really like to use the grammar engine insted to have more flexibility and readability.

            Am I hitting an inherent limit to Raku capabilities here ?

            And before someone tells me that regexes are for string and that I shouldn't do it, it should point out that perl's regex engine can match bytes as far as I know, and I could probably use it with Regexp::Grammars, but I prefer not to and use Raku instead.

            Also, I don't see any fundamental reason why regex should be reserved only to string, a NFA of automata theory isn't intriscally made for characters instead of bytes.

            ...

            ANSWER

            Answered 2021-Nov-09 at 11:34

            Is there a way to avoid this string coercion and use objects of type Buf or Blob ?

            Unfortunately not at present. However, one can use the Latin-1 encoding, which gives a meaning to every byte, so any byte sequence will decode to it, and could then be matched using a grammar.

            Also, I don't see any fundamental reason why regex should be reserved only to string, a NFA of automata theory isn't intriscally made for characters instead of bytes.

            There isn't one; it's widely expected that the regex/grammar engine will be rebuilt at some point in the future (primarily to deal with performance limitations), and that would be a good point to also consider handling bytes and also codepoint level strings (Uni).

            Source https://stackoverflow.com/questions/69892053

            QUESTION

            Is the const overload of begin/end of the range adapters underconstrained?
            Asked 2021-Oct-09 at 03:58

            In C++20, some ranges have both const and non-const begin()/end(), while others only have non-const begin()/end().

            In order to enable the range adapters that wraps the former to be able to use begin()/end() when it is const qualified, some range adapters such as elements_view, reverse_view and common_view all provide constrained const-qualified begin()/end() functions, for example:

            ...

            ANSWER

            Answered 2021-Oct-09 at 03:58

            Recent SG9 discussion on LWG3564 concluded that the intended design is that x and as_const(x) should be required to be substitutable with equal results in equality-preserving expressions for which both are valid. In other words, they should be "equal" in the [concepts.equality] "same platonic value" sense. Thus, for instance, it is not valid for x and as_const(x) to have entirely different elements.

            The exact wording and scope of the rule will have to await a paper, and we'll have to take care to avoid banning reasonable code. But certainly things like "x is a range of pairs but as_const(x) is a range of ints" are not within any reasonable definition of "reasonable".

            Source https://stackoverflow.com/questions/69268516

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install theory

            You can download it from GitHub.

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