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QUESTION
I have a very specific Tomcat configuration that I don't want to change and I am looking for a solution for this specific configuration.
I have declared multiple contexts () for deployment inside the conf/server.xml file in Tomcat, something I know is not recommended. My problem is that if one of those deployments fail, the whole Tomcat process stops which terminates the rest of the applications that have successfully started. Is this behavior expected? Is there an attribute or a way to prevent this and emulate the behavior of distinct context declarations akin to the usage of
context.xml
file?
The error I'm getting is the following:
ConfigServletWebServerApplicationContext : Exception encountered during context initialization
with this stacktrace (for Tomcat version 8.5.24):
...ANSWER
Answered 2021-May-28 at 17:27Basically:
- an exception during the
start
phase (cf. LifeCycle) of any component configured inserver.xml
causes the server to exit. However some exceptions (like a failedServletContextListener
) don't propagate. - an error of a component added during runtime, does not cause the server to exit.
If you don't want the whole server to stop, when a context fails to start up, use auto-deployment: for each context defined in server.xml
create a file $CATALINA_BASE/conf///.xml
with content:
QUESTION
I'm running Panda Resort CMS locally on XAMP, PHP 8.0.3, Mariadb/Phpmyadmin 5.1.0 so the "article" module is returning a SQLSTATE error:
1064 You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near ') AND checked = 1 AND lang = 1 ORDER BY rank'
Exactly at line 28
...ANSWER
Answered 2021-May-10 at 14:29Be careful to check if your variables are empty before you interpolate them into an SQL query. If $article['tags']
is empty, you could end up with a query like this:
QUESTION
I have currently a problem with the Tomcat configuration of a web application (I use Tomcat 8.5.57).
This web application is packaged in a war file containing, among others, html files and css files.
This application works well.
Now, I have a request from a customer asking to be able to modify the look and feel of the application from outside of the war via a custom css file managed by the client (used to set the logo of the client or stuff like that).
So I tried to create a custom context file, called custom.xml
, that I placed in tomcat\conf\Catalina\localhost
directory.
This file looks like :
ANSWER
Answered 2021-Mar-19 at 15:08The path
attribute of element is ignored outside of
server.xml
:
This attribute must only be used when statically defining a Context in server.xml. In all other circumstances, the path will be inferred from the filenames used for either the .xml context file or the docBase. [from Tomcat documentation]
Therefore you have two choices:
- You can define a new context (new web application) with context path
/app/css
by creating a file namedconf\Catalina\localhost\app#css.xml
and content:
QUESTION
I'm forwarding requests from Apache to Tomcat.
...ANSWER
Answered 2021-Mar-11 at 19:13What you are looking for is the ProxyPreserveHost
directive, which uses the Host
header of the original request in the requests to proxied servers:
QUESTION
I am new to this Dev Ops work so please forgive anything simple which I may have overlooked. I am in the middle of upgrading from Tomcat 7 to 8.5. There is not much in terms of migration manuals other then the apache website and using the 7 to 8 then the 8 to 8.5. All seems ok, expect for when I start up the application and the code tries to load information using the following
...ANSWER
Answered 2021-Mar-03 at 17:47The method ClassLoader#getResourceAsStream
only finds resources, which are on the web application classpath, i.e.:
- in the folder
WEB-INF/classes
or in a JAR file inside theWEB-INF/lib
folder, - in the classpath of Tomcat's
Shared
,Common
,System
orBootstrap
classloaders (cf. Tomcat documentation). As you noticed, by default theCommon
classloader has the directories$CATALINA_HOME/lib
and$CATALINA_BASE/lib
in its classpath.
The method you are looking for is ServletContext#getResourceAsStream
, which searches in the application directory and META-INF/resources
entries of all JARs in WEB-INF/lib
. So you should call:
QUESTION
We are deploying a IIS site including several folders, a few virtual directories, and a Tomcat host.
When running Tomcat 8 (8.0.46) on Java 8, everything is fine.
After upgrading to JDK 9 (OpenJDK 64-Bit Server VM (build 9.0.4+11, mixed mode)), we notice that each servlet is initialized several times (i.e. the method init(ServletConfig) is executed several times), the first time on the host context (as expected), and alter once for each folder in the site.
The undesired side-effect is that temporary files/logs created by the servlets are duplicated inside each folder in the site.
Tomcat server.xml contains the Host definition:
...ANSWER
Answered 2021-Mar-03 at 07:32The issue is solved, according to indication by @PiotrP.Karwasz, by setting both autoDeploy="false" deployOnStartup="false"
in Host configuration in server.xml.
QUESTION
I am trying to configure a tomee-embedded
in an application. All classes and html files are in the same gradle
project so the tomee-embedded
serves the classpath
as a webApp
.
I can verify that EJB and Servlets are working and so are webservices.
However it seems that the html
static resources that are found in /src/webapp are not served.
I cannot access for instance the index.html that is in /src/webapp/index.html
, nor any of the other files and folders.
I have tried some approaches, like the ones shown below.
Adding the
webapp
folder asCustomWebResources
in theConfiguration
.Adding the
webapp
folder asdocBase
when deployingclasspath
aswebApp
.public final class Main {
...
ANSWER
Answered 2021-Feb-15 at 17:28I was finally able to figure this out. The following will work when running with the "run" task of the gradle application plugin.
QUESTION
I have two CentOS 7. On one I have Open JDK 11 & Tomcat 9.0.43. The AJP connection setting is like below
...ANSWER
Answered 2021-Feb-13 at 09:14Found the solution. Change the address to 0.0.0.0. That will do the trick.
address="0.0.0.0"
QUESTION
Our project is not currently using a spring framework.
Therefore, it is being tested based on the standalone tomcat runner.
However, since integration-enabled tests such as @SpringBootTest
are not possible, Tomcat is operated in advance and the HTTP API test is carried out using Spock.
Is there a way to turn this like @SpringBootTest
?
- TomcatRunner
ANSWER
Answered 2020-Dec-20 at 15:33I would suggest to create a Spock extension to encapsulate everything you need. See writing custom extensions of the Spock docs as well as the built-in extensions for inspiration.
QUESTION
I have Tomcat 9. I am trying to get the URL lik this: http://default.local:8080/default_war/
but my site is still available only by http://default.local:8080
.
The address I am going to set is also generated by Intellij in Run/Configuration so it shoud be possible to set it. Of course I could edit it in Intellij but I wonder how to achieve URL subderictories in Tomcat 9.
What should I change in my code? Here there are my setting files:
...ANSWER
Answered 2020-Dec-06 at 19:14This is happening because you are using a context file called ROOT.xml
.
The ROOT
application is the one which is served from the base URL - in your case, http://default.local:8080
.
Depending on exactly how you deployed your WAR, you will need to take the following steps:
1 - Stop Tomcat and change the name of the ROOT.xml
file to default_war.xml
.
The above step means you are no longer using a ROOT
-based webapp (see final note below for more on that).
2 - Because you have specified appBase="default"
in your server.xml
, you may also need to go to that default
folder and remove any sub-folders in there, before restating Tomcat.
I would expect there to be a ROOT
folder in there, because you have already used a ROOT.xml
context file. You don't want that folder, because that will continue to serve your webapp from the base URL.
When you restart Tomcat, you should see a new folder called default_war
in the default
folder - and that is where your application will be served from - and it should be available only at http://default.local:8080/default_war/
.
Background note: In Tomcat, ROOT
is something of a special case. When you download and install a fresh installation of Tomcat, you will see a folder called ROOT
in the webapps
directory. This is where the main Tomcat welcome/congratulations page is served from - and like your ROOT.xml
content, it is served from the base URL. You can see some of the possible configurations in the "naming" table shown in this Tomcat documentation page.
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