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predictionary | learning JavaScript dictionary-based word | Natural Language Processing library

 by   asterics JavaScript Version: Current License: AGPL-3.0

 by   asterics JavaScript Version: Current License: AGPL-3.0

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kandi X-RAY | predictionary Summary

predictionary is a JavaScript library typically used in Artificial Intelligence, Natural Language Processing applications. predictionary has no bugs, it has no vulnerabilities, it has a Strong Copyleft License and it has low support. You can install using 'npm i predictionary' or download it from GitHub, npm.
JavaScript dictionary-based word prediction library with self-learning abilities.
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Quality
Quality
Security
Security
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kandi-support Support

  • predictionary has a low active ecosystem.
  • It has 19 star(s) with 4 fork(s). There are 7 watchers for this library.
  • It had no major release in the last 12 months.
  • predictionary has no issues reported. There are 13 open pull requests and 0 closed requests.
  • It has a neutral sentiment in the developer community.
  • The latest version of predictionary is current.
predictionary Support
Best in #Natural Language Processing
Average in #Natural Language Processing
predictionary Support
Best in #Natural Language Processing
Average in #Natural Language Processing

quality kandi Quality

  • predictionary has 0 bugs and 0 code smells.
predictionary Quality
Best in #Natural Language Processing
Average in #Natural Language Processing
predictionary Quality
Best in #Natural Language Processing
Average in #Natural Language Processing

securitySecurity

  • predictionary has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
  • predictionary code analysis shows 0 unresolved vulnerabilities.
  • There are 0 security hotspots that need review.
predictionary Security
Best in #Natural Language Processing
Average in #Natural Language Processing
predictionary Security
Best in #Natural Language Processing
Average in #Natural Language Processing

license License

  • predictionary is licensed under the AGPL-3.0 License. This license is Strong Copyleft.
  • Strong Copyleft licenses enforce sharing, and you can use them when creating open source projects.
predictionary License
Best in #Natural Language Processing
Average in #Natural Language Processing
predictionary License
Best in #Natural Language Processing
Average in #Natural Language Processing

buildReuse

  • predictionary releases are not available. You will need to build from source code and install.
  • Deployable package is available in npm.
  • Installation instructions, examples and code snippets are available.
predictionary Reuse
Best in #Natural Language Processing
Average in #Natural Language Processing
predictionary Reuse
Best in #Natural Language Processing
Average in #Natural Language Processing
Top functions reviewed by kandi - BETA

kandi has reviewed predictionary and discovered the below as its top functions. This is intended to give you an instant insight into predictionary implemented functionality, and help decide if they suit your requirements.

  • Translates a single string literal .
    • Creates an array of characters .
      • DOM callback function
        • This method is pretty printing all children of an HTML element
          • shortcut for h
            • Cross - browser implementation
              • matches a matcher
                • Evaluates an element .
                  • HTML METHODS
                    • Extracts the y - y - axis

                      Get all kandi verified functions for this library.

                      Get all kandi verified functions for this library.

                      predictionary Key Features

                      A learning JavaScript dictionary-based word prediction / autocomplete / suggestion library.

                      Installation

                      copy iconCopydownload iconDownload
                      <script src="https://unpkg.com/predictionary/dist/predictionary.min.js"></script>
                      

                      Basic usage

                      copy iconCopydownload iconDownload
                      import Predictionary from 'predictionary' //only if installed via npm
                      
                      let predictionary = Predictionary.instance();
                      predictionary.addWords(['apple', 'apricot', 'banana']);
                      let suggestions = predictionary.predict('ap'); // == ['apple', 'apricot'];
                      

                      How do I choose multiple minimum values in a dictionary?

                      copy iconCopydownload iconDownload
                      d = {'candidate1': 35.71, 'candidate2': 28.57, 'candidate4': 14.29, 'candidate3': 7.14}
                      min_value = min(d.values())
                      
                      d_without_min_value = {k: v for k, v in d.items() if v != min_value}
                      
                      # output
                      # {'candidate1': 35.71, 'candidate2': 28.57, 'candidate4': 14.29}
                      
                      d = {k: float(v) for k, v in d.items()}
                      
                      d = {'candidate1': 35.71, 'candidate2': 28.57, 'candidate4': 14.29, 'candidate3': 7.14}
                      min_value = min(d.values())
                      
                      d_without_min_value = {k: v for k, v in d.items() if v != min_value}
                      
                      # output
                      # {'candidate1': 35.71, 'candidate2': 28.57, 'candidate4': 14.29}
                      
                      d = {k: float(v) for k, v in d.items()}
                      

                      Community Discussions

                      Trending Discussions on predictionary
                      • How do I choose multiple minimum values in a dictionary?
                      Trending Discussions on predictionary

                      QUESTION

                      How do I choose multiple minimum values in a dictionary?

                      Asked 2022-Mar-20 at 20:07

                      I'm trying to inspect and choose values in a dictionary if they're the same minimum values from the whole dictionary.

                      As you can see, my code is choosing duplicate values although they're not the minimum values. How do i correct this error? For example, my code shouldn't't delete values (including duplicates) unless there are multiple '7.14'

                           def tieBreaker (preDictionary):
                              while True:
                                  minValues = min(preDictionary.values())
                                  minKeys = [k for k in preDictionary if preDictionary[k] == minValues]
                                  print(minKeys)
                      
                                  for i in range(0, len(minKeys)):
                                      for j in range(0, len(minKeys)):
                      
                                          if minKeys[i] > minKeys[j]:
                                              del preDictionary[minKeys[i]]
                                              i += 1
                                              j += 1
                      
                                  if len(minKeys) < 2:
                      
                                      return preDictionary
                                      break
                      

                      Current output is {'candidate1': '35.71', 'candidate2': '28.57', 'candidate4': '14.29', 'candidate3': '7.14'}

                      While the input is {'candidate1': '35.71', 'candidate2': '28.57', 'candidate5': '14.29', 'candidate4': '14.29', 'candidate3': '7.14'}

                      candidate 5 should not be deleted as although it's a duplicate value, not a minimum..

                      Also, minKeys currently is ['candidate5', 'candidate4'] where it should be ['candidate3']

                      ANSWER

                      Answered 2022-Mar-20 at 20:07

                      You do not need a while loop. You can run through each key value pair and construct a new dict without the keys with minimum value.

                      d = {'candidate1': 35.71, 'candidate2': 28.57, 'candidate4': 14.29, 'candidate3': 7.14}
                      min_value = min(d.values())
                      
                      d_without_min_value = {k: v for k, v in d.items() if v != min_value}
                      
                      # output
                      # {'candidate1': 35.71, 'candidate2': 28.57, 'candidate4': 14.29}
                      

                      EDIT

                      Seems like you are passing values as string instead of float. Calling min() on a list of str will result in minimum value in lexicographical order. Remove the quotes around the values or convert the values into float before you process the dict

                      d = {k: float(v) for k, v in d.items()}
                      

                      Source https://stackoverflow.com/questions/71550037

                      Community Discussions, Code Snippets contain sources that include Stack Exchange Network

                      Vulnerabilities

                      No vulnerabilities reported

                      Install predictionary

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                      Support

                      see full API documentation: to API documentation.

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