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AsTeRICS | Assistive Technology Rapid Integration & Construction Set | Emulator library

 by   asterics Java Version: v4.1.0 License: Non-SPDX

 by   asterics Java Version: v4.1.0 License: Non-SPDX

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kandi X-RAY | AsTeRICS Summary

AsTeRICS is a Java library typically used in Utilities, Emulator applications. AsTeRICS has no bugs, it has no vulnerabilities and it has low support. However AsTeRICS build file is not available and it has a Non-SPDX License. You can download it from GitHub.
The Assistive Technology Rapid Integration & Construction Set
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kandi-support Support

  • AsTeRICS has a low active ecosystem.
  • It has 36 star(s) with 24 fork(s). There are 17 watchers for this library.
  • It had no major release in the last 12 months.
  • There are 80 open issues and 156 have been closed. On average issues are closed in 287 days. There are 2 open pull requests and 0 closed requests.
  • It has a neutral sentiment in the developer community.
  • The latest version of AsTeRICS is v4.1.0
AsTeRICS Support
Best in #Emulator
Average in #Emulator
AsTeRICS Support
Best in #Emulator
Average in #Emulator

quality kandi Quality

  • AsTeRICS has no bugs reported.
AsTeRICS Quality
Best in #Emulator
Average in #Emulator
AsTeRICS Quality
Best in #Emulator
Average in #Emulator

securitySecurity

  • AsTeRICS has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
AsTeRICS Security
Best in #Emulator
Average in #Emulator
AsTeRICS Security
Best in #Emulator
Average in #Emulator

license License

  • AsTeRICS has a Non-SPDX License.
  • Non-SPDX licenses can be open source with a non SPDX compliant license, or non open source licenses, and you need to review them closely before use.
AsTeRICS License
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AsTeRICS License
Best in #Emulator
Average in #Emulator

buildReuse

  • AsTeRICS releases are available to install and integrate.
  • AsTeRICS has no build file. You will be need to create the build yourself to build the component from source.
AsTeRICS Reuse
Best in #Emulator
Average in #Emulator
AsTeRICS Reuse
Best in #Emulator
Average in #Emulator
Top functions reviewed by kandi - BETA

kandi has reviewed AsTeRICS and discovered the below as its top functions. This is intended to give you an instant insight into AsTeRICS implemented functionality, and help decide if they suit your requirements.

  • Register all available ports .
    • Start a server .
      • Make control panel .
        • Open a connection to ENOIDE .
          • add new eye data
            • Calculates the coordinates of the coordinates of a point .
              • Gets a resource .
                • Translate the keyCodeString to the keyCodeMap
                  • Buffers data for the specified port .
                    • Returns the conversion between two data types .

                      Get all kandi verified functions for this library.

                      Get all kandi verified functions for this library.

                      AsTeRICS Key Features

                      The Assistive Technology Rapid Integration & Construction Set

                      Get rid of just the numers inside asterics "*" using regex in Python

                      copy iconCopydownload iconDownload
                      result = re.sub('\*.+\*',
                                      lambda x: ''.join(c for c in x.group(0) if not c.isdigit()),
                                      msg)
                      
                      print(result)
                          1 x * Build your pizza * ($ 99MXN)
                          1 x * Baitz Cinnamon  pieces * ($ 44.50 MXN)
                          1 x * Potatoes  g * ($ 44.50 MXN) 
                      
                      result = re.sub('\*.+\*',
                                      lambda x: re.sub('\s*\d+\s*','',x.group(0)),
                                      msg)
                      print(result)
                          1 x * Build your pizza * ($ 99MXN)
                          1 x * Baitz Cinnamonpieces * ($ 44.50 MXN)
                          1 x * Potatoesg * ($ 44.50 MXN) 
                      
                      result = re.sub('\*.+\*',
                                      lambda x: ''.join(c for c in x.group(0) if not c.isdigit()),
                                      msg)
                      
                      print(result)
                          1 x * Build your pizza * ($ 99MXN)
                          1 x * Baitz Cinnamon  pieces * ($ 44.50 MXN)
                          1 x * Potatoes  g * ($ 44.50 MXN) 
                      
                      result = re.sub('\*.+\*',
                                      lambda x: re.sub('\s*\d+\s*','',x.group(0)),
                                      msg)
                      print(result)
                          1 x * Build your pizza * ($ 99MXN)
                          1 x * Baitz Cinnamonpieces * ($ 44.50 MXN)
                          1 x * Potatoesg * ($ 44.50 MXN) 
                      
                      result = re.sub('\*.+\*',
                                      lambda x: ''.join(c for c in x.group(0) if not c.isdigit()),
                                      msg)
                      
                      print(result)
                          1 x * Build your pizza * ($ 99MXN)
                          1 x * Baitz Cinnamon  pieces * ($ 44.50 MXN)
                          1 x * Potatoes  g * ($ 44.50 MXN) 
                      
                      result = re.sub('\*.+\*',
                                      lambda x: re.sub('\s*\d+\s*','',x.group(0)),
                                      msg)
                      print(result)
                          1 x * Build your pizza * ($ 99MXN)
                          1 x * Baitz Cinnamonpieces * ($ 44.50 MXN)
                          1 x * Potatoesg * ($ 44.50 MXN) 
                      

                      How to implement the function into the main

                      copy iconCopydownload iconDownload
                      public static int askPositiveInteger(String question, String messageIfError, Scanner scan) {
                          int num = -1;
                          while(num <= 0){
                              System.out.print(question);
                              num = scan.nextInt();
                              if(num <= 0){
                                  System.out.println(messageIfError);
                              }
                              scan.nextLine();
                          }
                          return num;
                      }
                      
                      public static void main(String[] args) {
                      
                          int height, width;
                          Scanner scan = new Scanner(System.in);
                      
                          height = askPositiveInteger("Enter the height of the rectangle: ","I need an int, please try again.", scan);
                          System.out.println("h = " + height);
                          width = askPositiveInteger("Enter the width of the rectangle: ","I need an int, please try again.", scan);
                          scan.close();
                      
                          for(int i = 1; i <= height; i++){
                              for(int j = 1; j <= width;j++){
                                  System.out.print("*");
                              }
                              System.out.print("\n");
                          }
                      }
                      
                      public static int askPositiveInteger(String question, String messageIfError, Scanner scan) {
                          int num = -1;
                          while(num <= 0){
                              System.out.print(question);
                              num = scan.nextInt();
                              if(num <= 0){
                                  System.out.println(messageIfError);
                              }
                              scan.nextLine();
                          }
                          return num;
                      }
                      
                      public static void main(String[] args) {
                      
                          int height, width;
                          Scanner scan = new Scanner(System.in);
                      
                          height = askPositiveInteger("Enter the height of the rectangle: ","I need an int, please try again.", scan);
                          System.out.println("h = " + height);
                          width = askPositiveInteger("Enter the width of the rectangle: ","I need an int, please try again.", scan);
                          scan.close();
                      
                          for(int i = 1; i <= height; i++){
                              for(int j = 1; j <= width;j++){
                                  System.out.print("*");
                              }
                              System.out.print("\n");
                          }
                      }
                      

                      How do I apply formatting to the parts of word.range?

                      copy iconCopydownload iconDownload
                      Sub test()
                      
                          Dim wordApp As Object
                          Dim testDoc As Object
                          Dim testString
                          
                          testString = "this is something **important** and **this** is not"
                          
                          'the code that initialized Word
                          On Error Resume Next
                          Set wordApp = GetObject(, "Word.Application")
                          If wordApp Is Nothing Then
                              Set wordApp = CreateObject("Word.Application")
                          End If
                          wordApp.Visible = True
                          
                          Set testDoc = wordApp.Documents.add
                          
                          'parsing the range
                          testDoc.Range.text = testString
                          FindReplaceWithWildcards testDoc, "(\*{2})(*)(\*{2})"
                      
                      End Sub
                      
                      Sub FindReplaceWithWildcards(docTarget As Document, findText As String)
                         Dim findRange As Word.Range
                      
                         Set findRange = docTarget.Range
                      
                         With findRange.Find
                            .ClearFormatting
                            .text = findText
                            .Forward = True
                            .Wrap = wdFindStop
                            .Format = True
                            .MatchWildcards = True
                            With .Replacement
                               .ClearFormatting
                               .text = "\2"
                               .Font.Bold = True
                            End With
                            .Execute Replace:=wdReplaceAll
                         End With
                      End Sub
                      

                      How do I define a new word.range through existing word.range without affecting the original?

                      copy iconCopydownload iconDownload
                      Set workRange = parseRange.Duplicate
                      Set workRange2 = parseRange.Duplicate
                      Set workRange3 = parseRange.Duplicate
                      

                      Why we don't need to de-reference pointer value in case of malloc array?

                      copy iconCopydownload iconDownload
                      #include <stdlib.h>
                      #include <stdio.h>
                      
                      int main() {
                          int *p = (int *)malloc(sizeof(int)*5);
                          int *q = (int *)malloc(sizeof(int)*5);
                          int i = 0;
                          int test_val = 100;
                      
                          for(i = 0; i < 5; i++) {
                              *(p + i) = test_val;
                              q[i] = test_val;
                              test_val = test_val + 10;
                          }
                      
                          for(i = 0; i < 5; i++)
                              printf("p[%d] = %d\n", i, p[i]);
                      
                          printf("p[i] gives the value in array p at index i \n\n");
                      
                          for(i = 0; i < 5; i++)
                              printf("q[%d] = %d\n", i, q[i]);
                          
                          printf("Note that the values in p and q are equal which means that *(x + 1) and x[i] are 2 ways to access the same values \n\n");
                      
                          for(i = 0; i < 5; i++)
                              printf("*p + %d = %d\n", i, *p + i);
                      
                          printf("*p + i gets value pointed by p and adds i to it in each iteration \n\n");
                      
                          for(i = 0; i < 5; i++)
                              printf("*(p + %d) = %d\n", i, *(p + i));
                      
                          printf("*(p + i) gets value pointed by p + i \n\n");
                      
                          int *j = (int *)malloc(sizeof(int)*5);
                          int *k = (int *)malloc(sizeof(int)*5);
                          int *l = (int *)malloc(sizeof(int)*5);
                      
                          for(i = 0; i < 5; i++) {
                               j[i] = test_val;
                               k[i] = test_val;
                               l[i] = test_val;
                          }
                          printf("(*j)++ = %d\n\n", (*j)++);
                          printf("*(k++) = %d\n\n", *(k++));
                          printf("*l++ = %d\n\n", *l++);
                          
                          for(i = 0; i < 5; i++) {
                               j[i] = test_val;
                               k[i] = test_val;
                               l[i] = test_val;
                          }
                          printf("test_val = %d\n\n", test_val);
                          printf("++(*j) = %d\n\n", ++(*j));
                          printf("*(++k) = %d\n\n", *(++k));
                          printf("*++l = %d\n\n", *++l);
                          return 0;
                      }
                      
                      p[0] = 100
                      p[1] = 110
                      p[2] = 120
                      p[3] = 130
                      p[4] = 140
                      p[i] gives the value in array p at index i 
                      
                      q[0] = 100
                      q[1] = 110
                      q[2] = 120
                      q[3] = 130
                      q[4] = 140
                      Note that the values in p and q are equal which means that *(x + 1) and x[i] are 2 ways to access the same values 
                      
                      *p + 0 = 100
                      *p + 1 = 101
                      *p + 2 = 102
                      *p + 3 = 103
                      *p + 4 = 104
                      *p + i gets value pointed by p and adds i to it in each iteration 
                      
                      *(p + 0) = 100
                      *(p + 1) = 110
                      *(p + 2) = 120
                      *(p + 3) = 130
                      *(p + 4) = 140
                      *(p + i) gets value pointed by p + i 
                      
                      test_val = 150
                      
                      (*j)++ = 150
                      
                      *(k++) = 150
                      
                      *l++ = 150
                      
                      test_val = 150
                      
                      ++(*j) = 151
                      
                      *(++k) = 150
                      
                      *++l = 150
                      
                      #include <stdlib.h>
                      #include <stdio.h>
                      
                      int main() {
                          int *p = (int *)malloc(sizeof(int)*5);
                          int *q = (int *)malloc(sizeof(int)*5);
                          int i = 0;
                          int test_val = 100;
                      
                          for(i = 0; i < 5; i++) {
                              *(p + i) = test_val;
                              q[i] = test_val;
                              test_val = test_val + 10;
                          }
                      
                          for(i = 0; i < 5; i++)
                              printf("p[%d] = %d\n", i, p[i]);
                      
                          printf("p[i] gives the value in array p at index i \n\n");
                      
                          for(i = 0; i < 5; i++)
                              printf("q[%d] = %d\n", i, q[i]);
                          
                          printf("Note that the values in p and q are equal which means that *(x + 1) and x[i] are 2 ways to access the same values \n\n");
                      
                          for(i = 0; i < 5; i++)
                              printf("*p + %d = %d\n", i, *p + i);
                      
                          printf("*p + i gets value pointed by p and adds i to it in each iteration \n\n");
                      
                          for(i = 0; i < 5; i++)
                              printf("*(p + %d) = %d\n", i, *(p + i));
                      
                          printf("*(p + i) gets value pointed by p + i \n\n");
                      
                          int *j = (int *)malloc(sizeof(int)*5);
                          int *k = (int *)malloc(sizeof(int)*5);
                          int *l = (int *)malloc(sizeof(int)*5);
                      
                          for(i = 0; i < 5; i++) {
                               j[i] = test_val;
                               k[i] = test_val;
                               l[i] = test_val;
                          }
                          printf("(*j)++ = %d\n\n", (*j)++);
                          printf("*(k++) = %d\n\n", *(k++));
                          printf("*l++ = %d\n\n", *l++);
                          
                          for(i = 0; i < 5; i++) {
                               j[i] = test_val;
                               k[i] = test_val;
                               l[i] = test_val;
                          }
                          printf("test_val = %d\n\n", test_val);
                          printf("++(*j) = %d\n\n", ++(*j));
                          printf("*(++k) = %d\n\n", *(++k));
                          printf("*++l = %d\n\n", *++l);
                          return 0;
                      }
                      
                      p[0] = 100
                      p[1] = 110
                      p[2] = 120
                      p[3] = 130
                      p[4] = 140
                      p[i] gives the value in array p at index i 
                      
                      q[0] = 100
                      q[1] = 110
                      q[2] = 120
                      q[3] = 130
                      q[4] = 140
                      Note that the values in p and q are equal which means that *(x + 1) and x[i] are 2 ways to access the same values 
                      
                      *p + 0 = 100
                      *p + 1 = 101
                      *p + 2 = 102
                      *p + 3 = 103
                      *p + 4 = 104
                      *p + i gets value pointed by p and adds i to it in each iteration 
                      
                      *(p + 0) = 100
                      *(p + 1) = 110
                      *(p + 2) = 120
                      *(p + 3) = 130
                      *(p + 4) = 140
                      *(p + i) gets value pointed by p + i 
                      
                      test_val = 150
                      
                      (*j)++ = 150
                      
                      *(k++) = 150
                      
                      *l++ = 150
                      
                      test_val = 150
                      
                      ++(*j) = 151
                      
                      *(++k) = 150
                      
                      *++l = 150
                      
                      int *p = ....
                      
                      p ______
                             |
                            \|/
                           --------------------------
                           | 55 | 66 | 77 | 88 | 99 |
                           --------------------------
                      
                      printf("%d", *p+i); // De-referencing the values in location p by using asterics, + the value of iteration,i //
                      
                      (*p) + 0  ->  55 + 0  ->  55
                      
                      (*p) + 1  ->  55 + 1  ->  56
                      
                      (*p) + 1  ->  55 + 4  ->  59
                      
                      printf("%d", p[i]); // No asterics used. How does the compiler know I want the value and not the address? as p only should hold the addresses, and *p should give us the values in those addresses //
                      
                      p[i] -> *((p) + (i)) -> *(p + i)
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `0`th index
                             -> *(0th location address) -> 55
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `1`st index
                             -> *(1st location address) -> 66
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `4`th index
                             -> *(4th location address) -> 99
                      
                      p[i] -> *((p) + (i)) -> *(p + i)
                      
                      scanf("%d", &p[i]);
                      
                      &p[i] -> &(p[i]) -> &(*((p) + (i)) -> ((p) + (i)) -> p + i
                                |                |
                        Precedence of operator   |
                        [] is higher than        |
                        & operator               |
                                                 |
                            The operator & is used to get the address and the operator * is used for dereferencing.
                            These operators cancel the effect of each other when used one after another. 
                      
                      scanf("%d", &p[i]);
                      
                      scanf("%d", p + i);
                      
                      int *p = ....
                      
                      p ______
                             |
                            \|/
                           --------------------------
                           | 55 | 66 | 77 | 88 | 99 |
                           --------------------------
                      
                      printf("%d", *p+i); // De-referencing the values in location p by using asterics, + the value of iteration,i //
                      
                      (*p) + 0  ->  55 + 0  ->  55
                      
                      (*p) + 1  ->  55 + 1  ->  56
                      
                      (*p) + 1  ->  55 + 4  ->  59
                      
                      printf("%d", p[i]); // No asterics used. How does the compiler know I want the value and not the address? as p only should hold the addresses, and *p should give us the values in those addresses //
                      
                      p[i] -> *((p) + (i)) -> *(p + i)
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `0`th index
                             -> *(0th location address) -> 55
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `1`st index
                             -> *(1st location address) -> 66
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `4`th index
                             -> *(4th location address) -> 99
                      
                      p[i] -> *((p) + (i)) -> *(p + i)
                      
                      scanf("%d", &p[i]);
                      
                      &p[i] -> &(p[i]) -> &(*((p) + (i)) -> ((p) + (i)) -> p + i
                                |                |
                        Precedence of operator   |
                        [] is higher than        |
                        & operator               |
                                                 |
                            The operator & is used to get the address and the operator * is used for dereferencing.
                            These operators cancel the effect of each other when used one after another. 
                      
                      scanf("%d", &p[i]);
                      
                      scanf("%d", p + i);
                      
                      int *p = ....
                      
                      p ______
                             |
                            \|/
                           --------------------------
                           | 55 | 66 | 77 | 88 | 99 |
                           --------------------------
                      
                      printf("%d", *p+i); // De-referencing the values in location p by using asterics, + the value of iteration,i //
                      
                      (*p) + 0  ->  55 + 0  ->  55
                      
                      (*p) + 1  ->  55 + 1  ->  56
                      
                      (*p) + 1  ->  55 + 4  ->  59
                      
                      printf("%d", p[i]); // No asterics used. How does the compiler know I want the value and not the address? as p only should hold the addresses, and *p should give us the values in those addresses //
                      
                      p[i] -> *((p) + (i)) -> *(p + i)
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `0`th index
                             -> *(0th location address) -> 55
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `1`st index
                             -> *(1st location address) -> 66
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `4`th index
                             -> *(4th location address) -> 99
                      
                      p[i] -> *((p) + (i)) -> *(p + i)
                      
                      scanf("%d", &p[i]);
                      
                      &p[i] -> &(p[i]) -> &(*((p) + (i)) -> ((p) + (i)) -> p + i
                                |                |
                        Precedence of operator   |
                        [] is higher than        |
                        & operator               |
                                                 |
                            The operator & is used to get the address and the operator * is used for dereferencing.
                            These operators cancel the effect of each other when used one after another. 
                      
                      scanf("%d", &p[i]);
                      
                      scanf("%d", p + i);
                      
                      int *p = ....
                      
                      p ______
                             |
                            \|/
                           --------------------------
                           | 55 | 66 | 77 | 88 | 99 |
                           --------------------------
                      
                      printf("%d", *p+i); // De-referencing the values in location p by using asterics, + the value of iteration,i //
                      
                      (*p) + 0  ->  55 + 0  ->  55
                      
                      (*p) + 1  ->  55 + 1  ->  56
                      
                      (*p) + 1  ->  55 + 4  ->  59
                      
                      printf("%d", p[i]); // No asterics used. How does the compiler know I want the value and not the address? as p only should hold the addresses, and *p should give us the values in those addresses //
                      
                      p[i] -> *((p) + (i)) -> *(p + i)
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `0`th index
                             -> *(0th location address) -> 55
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `1`st index
                             -> *(1st location address) -> 66
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `4`th index
                             -> *(4th location address) -> 99
                      
                      p[i] -> *((p) + (i)) -> *(p + i)
                      
                      scanf("%d", &p[i]);
                      
                      &p[i] -> &(p[i]) -> &(*((p) + (i)) -> ((p) + (i)) -> p + i
                                |                |
                        Precedence of operator   |
                        [] is higher than        |
                        & operator               |
                                                 |
                            The operator & is used to get the address and the operator * is used for dereferencing.
                            These operators cancel the effect of each other when used one after another. 
                      
                      scanf("%d", &p[i]);
                      
                      scanf("%d", p + i);
                      
                      int *p = ....
                      
                      p ______
                             |
                            \|/
                           --------------------------
                           | 55 | 66 | 77 | 88 | 99 |
                           --------------------------
                      
                      printf("%d", *p+i); // De-referencing the values in location p by using asterics, + the value of iteration,i //
                      
                      (*p) + 0  ->  55 + 0  ->  55
                      
                      (*p) + 1  ->  55 + 1  ->  56
                      
                      (*p) + 1  ->  55 + 4  ->  59
                      
                      printf("%d", p[i]); // No asterics used. How does the compiler know I want the value and not the address? as p only should hold the addresses, and *p should give us the values in those addresses //
                      
                      p[i] -> *((p) + (i)) -> *(p + i)
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `0`th index
                             -> *(0th location address) -> 55
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `1`st index
                             -> *(1st location address) -> 66
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `4`th index
                             -> *(4th location address) -> 99
                      
                      p[i] -> *((p) + (i)) -> *(p + i)
                      
                      scanf("%d", &p[i]);
                      
                      &p[i] -> &(p[i]) -> &(*((p) + (i)) -> ((p) + (i)) -> p + i
                                |                |
                        Precedence of operator   |
                        [] is higher than        |
                        & operator               |
                                                 |
                            The operator & is used to get the address and the operator * is used for dereferencing.
                            These operators cancel the effect of each other when used one after another. 
                      
                      scanf("%d", &p[i]);
                      
                      scanf("%d", p + i);
                      
                      int *p = ....
                      
                      p ______
                             |
                            \|/
                           --------------------------
                           | 55 | 66 | 77 | 88 | 99 |
                           --------------------------
                      
                      printf("%d", *p+i); // De-referencing the values in location p by using asterics, + the value of iteration,i //
                      
                      (*p) + 0  ->  55 + 0  ->  55
                      
                      (*p) + 1  ->  55 + 1  ->  56
                      
                      (*p) + 1  ->  55 + 4  ->  59
                      
                      printf("%d", p[i]); // No asterics used. How does the compiler know I want the value and not the address? as p only should hold the addresses, and *p should give us the values in those addresses //
                      
                      p[i] -> *((p) + (i)) -> *(p + i)
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `0`th index
                             -> *(0th location address) -> 55
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `1`st index
                             -> *(1st location address) -> 66
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `4`th index
                             -> *(4th location address) -> 99
                      
                      p[i] -> *((p) + (i)) -> *(p + i)
                      
                      scanf("%d", &p[i]);
                      
                      &p[i] -> &(p[i]) -> &(*((p) + (i)) -> ((p) + (i)) -> p + i
                                |                |
                        Precedence of operator   |
                        [] is higher than        |
                        & operator               |
                                                 |
                            The operator & is used to get the address and the operator * is used for dereferencing.
                            These operators cancel the effect of each other when used one after another. 
                      
                      scanf("%d", &p[i]);
                      
                      scanf("%d", p + i);
                      
                      int *p = ....
                      
                      p ______
                             |
                            \|/
                           --------------------------
                           | 55 | 66 | 77 | 88 | 99 |
                           --------------------------
                      
                      printf("%d", *p+i); // De-referencing the values in location p by using asterics, + the value of iteration,i //
                      
                      (*p) + 0  ->  55 + 0  ->  55
                      
                      (*p) + 1  ->  55 + 1  ->  56
                      
                      (*p) + 1  ->  55 + 4  ->  59
                      
                      printf("%d", p[i]); // No asterics used. How does the compiler know I want the value and not the address? as p only should hold the addresses, and *p should give us the values in those addresses //
                      
                      p[i] -> *((p) + (i)) -> *(p + i)
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `0`th index
                             -> *(0th location address) -> 55
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `1`st index
                             -> *(1st location address) -> 66
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `4`th index
                             -> *(4th location address) -> 99
                      
                      p[i] -> *((p) + (i)) -> *(p + i)
                      
                      scanf("%d", &p[i]);
                      
                      &p[i] -> &(p[i]) -> &(*((p) + (i)) -> ((p) + (i)) -> p + i
                                |                |
                        Precedence of operator   |
                        [] is higher than        |
                        & operator               |
                                                 |
                            The operator & is used to get the address and the operator * is used for dereferencing.
                            These operators cancel the effect of each other when used one after another. 
                      
                      scanf("%d", &p[i]);
                      
                      scanf("%d", p + i);
                      
                      int *p = ....
                      
                      p ______
                             |
                            \|/
                           --------------------------
                           | 55 | 66 | 77 | 88 | 99 |
                           --------------------------
                      
                      printf("%d", *p+i); // De-referencing the values in location p by using asterics, + the value of iteration,i //
                      
                      (*p) + 0  ->  55 + 0  ->  55
                      
                      (*p) + 1  ->  55 + 1  ->  56
                      
                      (*p) + 1  ->  55 + 4  ->  59
                      
                      printf("%d", p[i]); // No asterics used. How does the compiler know I want the value and not the address? as p only should hold the addresses, and *p should give us the values in those addresses //
                      
                      p[i] -> *((p) + (i)) -> *(p + i)
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `0`th index
                             -> *(0th location address) -> 55
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `1`st index
                             -> *(1st location address) -> 66
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `4`th index
                             -> *(4th location address) -> 99
                      
                      p[i] -> *((p) + (i)) -> *(p + i)
                      
                      scanf("%d", &p[i]);
                      
                      &p[i] -> &(p[i]) -> &(*((p) + (i)) -> ((p) + (i)) -> p + i
                                |                |
                        Precedence of operator   |
                        [] is higher than        |
                        & operator               |
                                                 |
                            The operator & is used to get the address and the operator * is used for dereferencing.
                            These operators cancel the effect of each other when used one after another. 
                      
                      scanf("%d", &p[i]);
                      
                      scanf("%d", p + i);
                      
                      int *p = ....
                      
                      p ______
                             |
                            \|/
                           --------------------------
                           | 55 | 66 | 77 | 88 | 99 |
                           --------------------------
                      
                      printf("%d", *p+i); // De-referencing the values in location p by using asterics, + the value of iteration,i //
                      
                      (*p) + 0  ->  55 + 0  ->  55
                      
                      (*p) + 1  ->  55 + 1  ->  56
                      
                      (*p) + 1  ->  55 + 4  ->  59
                      
                      printf("%d", p[i]); // No asterics used. How does the compiler know I want the value and not the address? as p only should hold the addresses, and *p should give us the values in those addresses //
                      
                      p[i] -> *((p) + (i)) -> *(p + i)
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `0`th index
                             -> *(0th location address) -> 55
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `1`st index
                             -> *(1st location address) -> 66
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `4`th index
                             -> *(4th location address) -> 99
                      
                      p[i] -> *((p) + (i)) -> *(p + i)
                      
                      scanf("%d", &p[i]);
                      
                      &p[i] -> &(p[i]) -> &(*((p) + (i)) -> ((p) + (i)) -> p + i
                                |                |
                        Precedence of operator   |
                        [] is higher than        |
                        & operator               |
                                                 |
                            The operator & is used to get the address and the operator * is used for dereferencing.
                            These operators cancel the effect of each other when used one after another. 
                      
                      scanf("%d", &p[i]);
                      
                      scanf("%d", p + i);
                      
                      int *p = ....
                      
                      p ______
                             |
                            \|/
                           --------------------------
                           | 55 | 66 | 77 | 88 | 99 |
                           --------------------------
                      
                      printf("%d", *p+i); // De-referencing the values in location p by using asterics, + the value of iteration,i //
                      
                      (*p) + 0  ->  55 + 0  ->  55
                      
                      (*p) + 1  ->  55 + 1  ->  56
                      
                      (*p) + 1  ->  55 + 4  ->  59
                      
                      printf("%d", p[i]); // No asterics used. How does the compiler know I want the value and not the address? as p only should hold the addresses, and *p should give us the values in those addresses //
                      
                      p[i] -> *((p) + (i)) -> *(p + i)
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `0`th index
                             -> *(0th location address) -> 55
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `1`st index
                             -> *(1st location address) -> 66
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `4`th index
                             -> *(4th location address) -> 99
                      
                      p[i] -> *((p) + (i)) -> *(p + i)
                      
                      scanf("%d", &p[i]);
                      
                      &p[i] -> &(p[i]) -> &(*((p) + (i)) -> ((p) + (i)) -> p + i
                                |                |
                        Precedence of operator   |
                        [] is higher than        |
                        & operator               |
                                                 |
                            The operator & is used to get the address and the operator * is used for dereferencing.
                            These operators cancel the effect of each other when used one after another. 
                      
                      scanf("%d", &p[i]);
                      
                      scanf("%d", p + i);
                      
                      int *p = ....
                      
                      p ______
                             |
                            \|/
                           --------------------------
                           | 55 | 66 | 77 | 88 | 99 |
                           --------------------------
                      
                      printf("%d", *p+i); // De-referencing the values in location p by using asterics, + the value of iteration,i //
                      
                      (*p) + 0  ->  55 + 0  ->  55
                      
                      (*p) + 1  ->  55 + 1  ->  56
                      
                      (*p) + 1  ->  55 + 4  ->  59
                      
                      printf("%d", p[i]); // No asterics used. How does the compiler know I want the value and not the address? as p only should hold the addresses, and *p should give us the values in those addresses //
                      
                      p[i] -> *((p) + (i)) -> *(p + i)
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `0`th index
                             -> *(0th location address) -> 55
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `1`st index
                             -> *(1st location address) -> 66
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `4`th index
                             -> *(4th location address) -> 99
                      
                      p[i] -> *((p) + (i)) -> *(p + i)
                      
                      scanf("%d", &p[i]);
                      
                      &p[i] -> &(p[i]) -> &(*((p) + (i)) -> ((p) + (i)) -> p + i
                                |                |
                        Precedence of operator   |
                        [] is higher than        |
                        & operator               |
                                                 |
                            The operator & is used to get the address and the operator * is used for dereferencing.
                            These operators cancel the effect of each other when used one after another. 
                      
                      scanf("%d", &p[i]);
                      
                      scanf("%d", p + i);
                      
                      int *p = ....
                      
                      p ______
                             |
                            \|/
                           --------------------------
                           | 55 | 66 | 77 | 88 | 99 |
                           --------------------------
                      
                      printf("%d", *p+i); // De-referencing the values in location p by using asterics, + the value of iteration,i //
                      
                      (*p) + 0  ->  55 + 0  ->  55
                      
                      (*p) + 1  ->  55 + 1  ->  56
                      
                      (*p) + 1  ->  55 + 4  ->  59
                      
                      printf("%d", p[i]); // No asterics used. How does the compiler know I want the value and not the address? as p only should hold the addresses, and *p should give us the values in those addresses //
                      
                      p[i] -> *((p) + (i)) -> *(p + i)
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `0`th index
                             -> *(0th location address) -> 55
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `1`st index
                             -> *(1st location address) -> 66
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `4`th index
                             -> *(4th location address) -> 99
                      
                      p[i] -> *((p) + (i)) -> *(p + i)
                      
                      scanf("%d", &p[i]);
                      
                      &p[i] -> &(p[i]) -> &(*((p) + (i)) -> ((p) + (i)) -> p + i
                                |                |
                        Precedence of operator   |
                        [] is higher than        |
                        & operator               |
                                                 |
                            The operator & is used to get the address and the operator * is used for dereferencing.
                            These operators cancel the effect of each other when used one after another. 
                      
                      scanf("%d", &p[i]);
                      
                      scanf("%d", p + i);
                      
                      int *p = ....
                      
                      p ______
                             |
                            \|/
                           --------------------------
                           | 55 | 66 | 77 | 88 | 99 |
                           --------------------------
                      
                      printf("%d", *p+i); // De-referencing the values in location p by using asterics, + the value of iteration,i //
                      
                      (*p) + 0  ->  55 + 0  ->  55
                      
                      (*p) + 1  ->  55 + 1  ->  56
                      
                      (*p) + 1  ->  55 + 4  ->  59
                      
                      printf("%d", p[i]); // No asterics used. How does the compiler know I want the value and not the address? as p only should hold the addresses, and *p should give us the values in those addresses //
                      
                      p[i] -> *((p) + (i)) -> *(p + i)
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `0`th index
                             -> *(0th location address) -> 55
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `1`st index
                             -> *(1st location address) -> 66
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `4`th index
                             -> *(4th location address) -> 99
                      
                      p[i] -> *((p) + (i)) -> *(p + i)
                      
                      scanf("%d", &p[i]);
                      
                      &p[i] -> &(p[i]) -> &(*((p) + (i)) -> ((p) + (i)) -> p + i
                                |                |
                        Precedence of operator   |
                        [] is higher than        |
                        & operator               |
                                                 |
                            The operator & is used to get the address and the operator * is used for dereferencing.
                            These operators cancel the effect of each other when used one after another. 
                      
                      scanf("%d", &p[i]);
                      
                      scanf("%d", p + i);
                      
                      int *p = ....
                      
                      p ______
                             |
                            \|/
                           --------------------------
                           | 55 | 66 | 77 | 88 | 99 |
                           --------------------------
                      
                      printf("%d", *p+i); // De-referencing the values in location p by using asterics, + the value of iteration,i //
                      
                      (*p) + 0  ->  55 + 0  ->  55
                      
                      (*p) + 1  ->  55 + 1  ->  56
                      
                      (*p) + 1  ->  55 + 4  ->  59
                      
                      printf("%d", p[i]); // No asterics used. How does the compiler know I want the value and not the address? as p only should hold the addresses, and *p should give us the values in those addresses //
                      
                      p[i] -> *((p) + (i)) -> *(p + i)
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `0`th index
                             -> *(0th location address) -> 55
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `1`st index
                             -> *(1st location address) -> 66
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `4`th index
                             -> *(4th location address) -> 99
                      
                      p[i] -> *((p) + (i)) -> *(p + i)
                      
                      scanf("%d", &p[i]);
                      
                      &p[i] -> &(p[i]) -> &(*((p) + (i)) -> ((p) + (i)) -> p + i
                                |                |
                        Precedence of operator   |
                        [] is higher than        |
                        & operator               |
                                                 |
                            The operator & is used to get the address and the operator * is used for dereferencing.
                            These operators cancel the effect of each other when used one after another. 
                      
                      scanf("%d", &p[i]);
                      
                      scanf("%d", p + i);
                      
                      int *p = ....
                      
                      p ______
                             |
                            \|/
                           --------------------------
                           | 55 | 66 | 77 | 88 | 99 |
                           --------------------------
                      
                      printf("%d", *p+i); // De-referencing the values in location p by using asterics, + the value of iteration,i //
                      
                      (*p) + 0  ->  55 + 0  ->  55
                      
                      (*p) + 1  ->  55 + 1  ->  56
                      
                      (*p) + 1  ->  55 + 4  ->  59
                      
                      printf("%d", p[i]); // No asterics used. How does the compiler know I want the value and not the address? as p only should hold the addresses, and *p should give us the values in those addresses //
                      
                      p[i] -> *((p) + (i)) -> *(p + i)
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `0`th index
                             -> *(0th location address) -> 55
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `1`st index
                             -> *(1st location address) -> 66
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `4`th index
                             -> *(4th location address) -> 99
                      
                      p[i] -> *((p) + (i)) -> *(p + i)
                      
                      scanf("%d", &p[i]);
                      
                      &p[i] -> &(p[i]) -> &(*((p) + (i)) -> ((p) + (i)) -> p + i
                                |                |
                        Precedence of operator   |
                        [] is higher than        |
                        & operator               |
                                                 |
                            The operator & is used to get the address and the operator * is used for dereferencing.
                            These operators cancel the effect of each other when used one after another. 
                      
                      scanf("%d", &p[i]);
                      
                      scanf("%d", p + i);
                      
                      int *p = ....
                      
                      p ______
                             |
                            \|/
                           --------------------------
                           | 55 | 66 | 77 | 88 | 99 |
                           --------------------------
                      
                      printf("%d", *p+i); // De-referencing the values in location p by using asterics, + the value of iteration,i //
                      
                      (*p) + 0  ->  55 + 0  ->  55
                      
                      (*p) + 1  ->  55 + 1  ->  56
                      
                      (*p) + 1  ->  55 + 4  ->  59
                      
                      printf("%d", p[i]); // No asterics used. How does the compiler know I want the value and not the address? as p only should hold the addresses, and *p should give us the values in those addresses //
                      
                      p[i] -> *((p) + (i)) -> *(p + i)
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `0`th index
                             -> *(0th location address) -> 55
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `1`st index
                             -> *(1st location address) -> 66
                      
                      *(p++) -> p will be incremented but the value of p in the expression will be its value prior to the increment operation which is location of element at `4`th index
                             -> *(4th location address) -> 99
                      
                      p[i] -> *((p) + (i)) -> *(p + i)
                      
                      scanf("%d", &p[i]);
                      
                      &p[i] -> &(p[i]) -> &(*((p) + (i)) -> ((p) + (i)) -> p + i
                                |                |
                        Precedence of operator   |
                        [] is higher than        |
                        & operator               |
                                                 |
                            The operator & is used to get the address and the operator * is used for dereferencing.
                            These operators cancel the effect of each other when used one after another. 
                      
                      scanf("%d", &p[i]);
                      
                      scanf("%d", p + i);
                      

                      Batch writes to Cosmos DB from Databricks

                      copy iconCopydownload iconDownload
                      flights.write.format("com.microsoft.azure.cosmosdb.spark")\
                                   .option("Endpoint", "https://doctorwho.documents.azure.com:443/")\
                                   .option("Upsert", "true")\
                                   .option("Masterkey", "YOUR-KEY-HERE")\
                                   ...etc 
                      
                      flights.write.format("com.microsoft.azure.cosmosdb.spark").options(
                          **yourdict).save()
                      
                      flights.write.format("com.microsoft.azure.cosmosdb.spark")\
                                   .option("Endpoint", "https://doctorwho.documents.azure.com:443/")\
                                   .option("Upsert", "true")\
                                   .option("Masterkey", "YOUR-KEY-HERE")\
                                   ...etc 
                      
                      flights.write.format("com.microsoft.azure.cosmosdb.spark").options(
                          **yourdict).save()
                      

                      Community Discussions

                      Trending Discussions on AsTeRICS
                      • Get rid of just the numers inside asterics &quot;*&quot; using regex in Python
                      • How to implement the function into the main
                      • Looping over list of lists, but if statement does not seem to work correctly
                      • How do I apply formatting to the parts of word.range?
                      • How do I define a new word.range through existing word.range without affecting the original?
                      • Why we don't need to de-reference pointer value in case of malloc array?
                      • Batch writes to Cosmos DB from Databricks
                      Trending Discussions on AsTeRICS

                      QUESTION

                      Get rid of just the numers inside asterics &quot;*&quot; using regex in Python

                      Asked 2021-Nov-09 at 04:10

                      What I am trying to do is to get rid of the numbers that are between asterics and keep the other numbers around. I run my regex but it erases everything between asterics.

                      import re
                      msg = """
                          1 x * Build your pizza * ($ 99MXN)
                          1 x * Baitz Cinnamon 16 pieces * ($ 44.50 MXN)
                          1 x * Potatoes 220 g * ($ 44.50 MXN) """
                      re.sub(r'\*.*\*', "", msg)
                      

                      The expected result I am looking for is:

                        """
                           1 x * Build your pizza * ($ 99MXN)
                           1 x * Baitz Cinnamon pieces * ($ 44.50 MXN)
                           1 x * Potatoes g * ($ 44.50 MXN)
                          """
                      

                      ANSWER

                      Answered 2021-Nov-09 at 04:10

                      You can pass a lambda to re.sub for repl and filter out the digits for the substring enclosed inside asterisk:

                      result = re.sub('\*.+\*',
                                      lambda x: ''.join(c for c in x.group(0) if not c.isdigit()),
                                      msg)
                      
                      print(result)
                          1 x * Build your pizza * ($ 99MXN)
                          1 x * Baitz Cinnamon  pieces * ($ 44.50 MXN)
                          1 x * Potatoes  g * ($ 44.50 MXN) 
                      

                      You can use nested re.sub if you don't want to use above method (which doesn't remove preceding/following white space characters):

                      result = re.sub('\*.+\*',
                                      lambda x: re.sub('\s*\d+\s*','',x.group(0)),
                                      msg)
                      print(result)
                          1 x * Build your pizza * ($ 99MXN)
                          1 x * Baitz Cinnamonpieces * ($ 44.50 MXN)
                          1 x * Potatoesg * ($ 44.50 MXN) 
                      

                      Source https://stackoverflow.com/questions/69892662

                      Community Discussions, Code Snippets contain sources that include Stack Exchange Network

                      Vulnerabilities

                      No vulnerabilities reported

                      Install AsTeRICS

                      You can download it from GitHub.
                      You can use AsTeRICS like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the AsTeRICS component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .

                      Support

                      For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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