pyscript | A python to javascript compiler | Parser library
kandi X-RAY | pyscript Summary
kandi X-RAY | pyscript Summary
A python to javascript compiler.
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Trending Discussions on pyscript
QUESTION
def turn_clockwise(point):
all_point = ["N", "E", "S", "W"]
for loop in range[4]:
if all_point[loop] == point:
if loop == 3:
return "N"
else:
return all_point[loop + 1]
...ANSWER
Answered 2021-Apr-26 at 10:23for loop in range(4) instead of range[4]
QUESTION
I have a standard Maven project and I want to run the meTypeset script. This script takes 3 args where the second one is a file and the third one is a folder created as output.
This is how the script runs in a cmd:
...ANSWER
Answered 2021-Feb-08 at 09:30Unlike python Java may need some help. Do I guess correctly you are running on Windows?
You invoke the Runtime.exec() method. The method returns a Process instance, and in it's documentation you can read
By default, the created process does not have its own terminal or console. All its standard I/O (i.e. stdin, stdout, stderr) operations will be redirected to the parent process, where they can be accessed via the streams obtained using the methods getOutputStream(), getInputStream(), and getErrorStream(). The parent process uses these streams to feed input to and get output from the process. Because some native platforms only provide limited buffer size for standard input and output streams, failure to promptly write the input stream or read the output stream of the process may cause the process to block, or even deadlock.
So it is likely your process is started by the OS but gets blocked due to I/O restrictions. Get around that by reading the STDOUT and STDERR streams until your process finishes. One good programming model is visible at https://www.baeldung.com/run-shell-command-in-java
QUESTION
I am new in Python and I get these errors when running this Python class:
I am using PyScripter and I am running Python 3.9 (64-bit)
I created the class Heater, initialized a variable temperature
, and some functions that modifies this variable.
Then I created an object and used the functions then it gave me an Error!
...ANSWER
Answered 2020-Nov-25 at 21:49After looking at your code, I noticed that you are trying to access self.temperature
using just temperature
.
The first argument each method receives (self
) is a reference of the object itself, and is used to access object attributes and methods.
QUESTION
From PyScripter (3.6.4.0) REPL console:
...ANSWER
Answered 2020-Oct-18 at 07:01In pyscripter REPL I get the correct result when I don't rely on the REPL to provide the answer but use a print
statement:
QUESTION
I have a python file in: '/home/username/scripts/pyscript' and I want set a word for execute directly this script.
I want do this "python3 /home/username/scripts/pyscript/main.py arg1 arg2" but looks like this "myscript arg1 arg2"
Is this posible? Thank you anyway.
...ANSWER
Answered 2020-Aug-15 at 15:58QUESTION
I've been trying to build a speech-recognition
application with gtts
. What I want to do now is to use a variable from another python script so I can update a tk Label. I tried to put my code in a structure of a class to access the variable. I've added a smaller program to showcase my problem.
(These programs are ment to be running at the same time)
I'am a beginner in Python so I hope you guys can teach me how to do it better. :)
Thank you in advance!!
Error:
...ANSWER
Answered 2020-Aug-05 at 12:04SuperAssistent
does not have a class attribute named audio
. For this you would have to set it somewhere in your class. For example, you could do something like SuperAssistent.audio = audio
in talkToMe
.
Is it on purpose that you use class methods only and do not instantiate SuperAudio
? If that is not the case you should add a constructor and add self
as first arguments of all methods that are not class methods.
I suggest to go through an introduction for Python classes/objects like this one on w3schools if that is the case.
Here is an example for setting and accessing class and instance attributes with split up files for script and class definition:
example.py
:
QUESTION
I created a Dockerfile and then built it for my team to use. Currently I am pulling from the CentOS:latest image, then building the latest version of Python and saving the image to a .tar file. The idea is for my colleagues to use this image to add their Python projects to the /pyscripts folder. Is this the recommended way of building a base image or is there a better way I can go about doing it?
...ANSWER
Answered 2020-Jun-16 at 16:55Yes this is the standard and recommended way of building a base image from a parent image (CentOS in this example) if that is what you need Python 3.8.3
(latest
version) on CentOS system.
Alternatively you can pull a generic Python image with latest Python version (which is now 3.8.3
) but based on other Linux distribution (Debian) from Docker HUB repository by running:
QUESTION
Essence of this code is to depict Rock, Paper and Scissors game using Python language basically with for
loop and if
...else
statements. I used PyScripter to run the code on Python 3.7.2 as engine. The def main()
and if __name__ == '__main__'
are PyScripter codes for running the machine
ANSWER
Answered 2020-Jul-12 at 22:16The reason for that is the first three lines in the for loop. You are increasing the sum of computer, human and tie while checking the condition and when you the loop iterates again, it sums up again. Here's the modified code:
QUESTION
I am trying to run a simple mitmscript script by issuing ./mitmproxy --mode transparent -s pyscript.py
.The proxy works fine and there's no error info in mitmproxy console,but it seems the script didn't even run,log.txt
file is empty even though proxy successfully proxied client requests:
ANSWER
Answered 2020-Jul-08 at 09:29You have created an add-on class, but you forgot to create a new instance of the class and register it in mitmproxy.
To do so you have to add the following entry at the end of your script:
QUESTION
Attempt to call python function from scala fails with below error. But works fine when the same command is invoked directly from command line.
Please find below simplified code snippets :-
greeting.py
...ANSWER
Answered 2020-May-18 at 21:14It works from the command line because the shell is parsing and interpreting the string before invoking the python
command. In the Scala code the ProcessBuilder
is trying to parse and interpret the string without the shell's help.
We can help the interpreting. This should work.
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