beef | The Browser Exploitation Framework Project | Security Testing library

by beefproject JavaScript Version: v0.5.4.0 License: No License

X-Ray Key Features Code Snippets Community Discussions(10)Vulnerabilities Install Support

kandi X-RAY | beef Summary

beef is a JavaScript library typically used in Testing, Security Testing, Framework applications. beef has no bugs, it has no vulnerabilities and it has medium support. You can download it from GitHub.

BeEF is short for The Browser Exploitation Framework. It is a penetration testing tool that focuses on the web browser. Amid growing concerns about web-borne attacks against clients, including mobile clients, BeEF allows the professional penetration tester to assess the actual security posture of a target environment by using client-side attack vectors. Unlike other security frameworks, BeEF looks past the hardened network perimeter and client system, and examines exploitability within the context of the one open door: the web browser. BeEF will hook one or more web browsers and use them as beachheads for launching directed command modules and further attacks against the system from within the browser context.

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Security

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beef has a medium active ecosystem.

It has 8466 star(s) with 1959 fork(s). There are 428 watchers for this library.

It had no major release in the last 12 months.

There are 74 open issues and 1976 have been closed. On average issues are closed in 6 days. There are 7 open pull requests and 0 closed requests.

It has a neutral sentiment in the developer community.

The latest version of beef is v0.5.4.0

Quality

beef has 0 bugs and 0 code smells.

Security

beef has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

beef code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

beef does not have a standard license declared.

Check the repository for any license declaration and review the terms closely.

Without a license, all rights are reserved, and you cannot use the library in your applications.

Reuse

beef releases are available to install and integrate.

Installation instructions, examples and code snippets are available.

beef saves you 18187 person hours of effort in developing the same functionality from scratch.

It has 59433 lines of code, 1727 functions and 1081 files.

It has medium code complexity. Code complexity directly impacts maintainability of the code.

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beef Key Features

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beef Examples and Code Snippets

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Community Discussions

Trending Discussions on beef

Function that removes duplicates in a list of values assigned to each key in a dictionary?

Obtaining NAN value for successfully solved optimization problem using GEKKO on Python

how to make multiple counter buttons not interfere with each other

Python data validation not working as intended

Replace pandas dataframe substrings using regex based on condition at row level

Dataframe column looping and string concatenation based on conditional in R (pref dplyr)

Use VBA to copy unique rows to another spreadsheet if condition is met

How to inherit from an abstract class properly in C++?

Check if any word from a string is in an array (Case insensitive)

Save dictionary to file Python Tkinter

QUESTION

Function that removes duplicates in a list of values assigned to each key in a dictionary?

Asked 2022-Apr-11 at 09:52

I want to make a function that first merges the duplicate entries by key in a dictionary, then removes the duplicate values in each key. However, I want the removed duplicates to be relative to the other values in the value list they’re in, not the value lists of the entire dictionary. If possible, could this be done using only for-loops without list comprehension?

An example input would look like

...

ANSWER

Answered 2022-Apr-10 at 19:49

The perfect data structure for your Dictionary values would be sets and not lists, as you don't want duplicates. So if that isn't a constraint now or in the future, I'd suggest you make that change.

But if it is a constraint, following could be your code:

Source https://stackoverflow.com/questions/71819898

QUESTION

Obtaining NAN value for successfully solved optimization problem using GEKKO on Python

Asked 2022-Apr-04 at 02:19

I am trying to solve an optimization problem using the GEKKO solver on Python, but keep obtaining an NAN objective value, even though the problem is successfully solved. There seems to be something I am missing, but I have not been able to identify what it is. I tried to make sure that nothing is being divided by zero, but as far as I can tell, that is not the case. The code I have is:

...

ANSWER

Answered 2022-Apr-04 at 02:19

The optimizer tries to maximize the objective function by making (foodvars[i][0]+foodvars[i][1]-foodvars[i][2]) approach zero. This gives an infinity objective function that results in the NaN result. Two suggestions:

Multiply both sides of equation 2 by (10**6*(1-fooditems_params[i][1])*(1-fooditems_params[i][2])) to remove the potential divide-by-zero.
Set bounds on foodvars to prevent divide-by-zero in the objective.

Source https://stackoverflow.com/questions/71683912

QUESTION

how to make multiple counter buttons not interfere with each other

Asked 2022-Mar-11 at 18:47

So basically I am making an online restaurant website where you can order food. I am going to make cards for each food item listed. Right now, I am making buttons that add and subtract the number of each item the customer wants to purchase.

...

ANSWER

Answered 2022-Mar-11 at 18:42

The main issue is that currentNumber is shared between both counters, making it impossible to differentiate one from the other.

Additionally, keeping state in the HTML (the current price per burger) and using onclick makes it difficult to manage scoping.

I suggest removing all of the state from the HTML, then writing a loop over the .food-item elements to add click handlers to their buttons and be able to manipulate each of their outputs. You can use a data structure like burgers to keep track of prices for each burger instead of separate variables, which aren't amenable to looping over.

Here's one approach:

Source https://stackoverflow.com/questions/71442700

QUESTION

Python data validation not working as intended

Asked 2022-Feb-28 at 01:04

Python 3.8.12

The intended goal of this code is to allow the user to select a "beef", "chicken", "tofu", or "none" sandwich. If the user does not enter one of those options, it will prompt them again to select a sandwich. If they do enter one of these options, then it will continue on with the code.

It is not working properly. It will not accept any input, valid or not. All input causes the program to prompt the user again, rather then moving on with the program if it is valid.

...

ANSWER

Answered 2022-Feb-28 at 00:34

A better way would be:

Source https://stackoverflow.com/questions/71289524

QUESTION

Replace pandas dataframe substrings using regex based on condition at row level

Asked 2022-Feb-26 at 23:03

I need to find a way of replacing a substring in a pandas dataframe at row level based on condition. (df = pd.DataFrame({'Name':['Meat 1.7 Kg','Chicken 1.9 Kg','Ground Beef 1.0 Kg','Turkey 1.2 kg','Wagyu 400 g'],'Weight':[10,8,2,6,4],'Mult':[4.0,5.2,5.6,5.9,4.9]}))

...

ANSWER

Answered 2022-Feb-26 at 23:03

You can use

Source https://stackoverflow.com/questions/71280891

QUESTION

Dataframe column looping and string concatenation based on conditional in R (pref dplyr)

Asked 2022-Feb-24 at 20:55

I have a 2-column dataframe. First column contains a single entry of a class of items (in this case, vegetables). The second column is the incoming new_item, which are grocery items of different categories (meat, fruit, veg, etc).

...

ANSWER

Answered 2022-Feb-24 at 19:43

current <- tibble::tribble(
  ~prev_veg, ~new_item,
  "cabbage", "lettuce",
  NA, "apple",
  NA, "beef",
  NA, "spinach",
  NA, "broccoli",
  NA, "mango"
)
target_veg <- c("cabbage", "lettuce", "spinach", "broccoli")

library(dplyr, warn.conflicts = FALSE)
library(purrr)

current %>%
  mutate(
    prev_veg = accumulate(
      head(new_item, -1),
      ~ if_else(.y %in% target_veg, paste(.x, .y, sep = ", "), .x),
      .init = prev_veg[1]
    )
  )
#> # A tibble: 6 × 2
#>   prev_veg                            new_item
#>                                     
#> 1 cabbage                             lettuce 
#> 2 cabbage, lettuce                    apple   
#> 3 cabbage, lettuce                    beef    
#> 4 cabbage, lettuce                    spinach 
#> 5 cabbage, lettuce, spinach           broccoli
#> 6 cabbage, lettuce, spinach, broccoli mango

Source https://stackoverflow.com/questions/71257290

QUESTION

Use VBA to copy unique rows to another spreadsheet if condition is met

Asked 2022-Feb-16 at 14:14

I'm new to VBA and any help would be greatly appreciated!!

My office is coordinating applications for positions across the US. When people apply, they pick which two states they would be willing to work in. All application information is manually entered into Worksheet A, which has a lot of columns, but 5 important ones: Unique ID, First Name, Last Name, Preferred State1, Preferred State2. This worksheet gets updated daily.

I have 50 worksheets (one for each state in the US). I wrote VBA code to copy each row from Spreadsheet A into the 50 state worksheets when the state worksheet is created.

I need to copy the new information that is added to Spreadsheet A every day into the appropriate state spreadsheets. All applicants who picked a state need to go into the state worksheet (the state order of preference doesn't matter).

For example, today, Spreadsheet A could be:

ID First Name Last Name State1 State2 111 Bob Belcher New Jersey Alaska 222 Rose Nylund Minnesota Florida 333 Beef Tobin Alaska California

So the Alaska spreadsheet would have:

ID First Name Last Name 111 Bob Belcher 333 Beef Tobin

Tomorrow, Worksheet A could have new people added (IDs 444 and 555) and I would only want to add the new people who picked Alaska to the Alaska worksheet (ID 555 Colin Robinson).

ID First Name Last Name State1 State2 111 Bob Belcher New Jersey Alaska 222 Rose Nylund Minnesota Florida 333 Beef Tobin Alaska California 444 Charlie Bucket New York Florida 555 Colin Robinson New York Alaska

I was using this code based on unique IDs in Column A, but it doesn't account for the different states.

...

ANSWER

Answered 2022-Feb-16 at 02:09

Here is how I would do it if the only macro I wanted was to be in Spreadsheet A and you just wanted to use copy-paste to transfer data versus sql.

Note: The items below with a *, you can record a macro to generate the code for you and paste it in your function to cobble together the code pretty quickly.

First set ScreenUpdating=false to eliminate the screen from flashing.
Create an array of the state names to loop through.
In the loop, apply a filter to the spreadsheet to reduce the rows to just one's that match the current "state"*
Open the other file - be sure to name the file with the state name so you can reference the filename with the array. (see Workbooks.Open)
Paste by inserting rows at A1* of the state spreadsheet.
Select All and do a menu option Data-->Remove Duplicates*

If you have data that makes #6 a problem, then there will be some more code required to check for existing.

See ya, Sean

Source https://stackoverflow.com/questions/71135429

QUESTION

How to inherit from an abstract class properly in C++?

Asked 2022-Feb-16 at 12:08

I couldn't find a proper topic for this question as I haven't got a proper error message.

I'm trying to create a management system for a restaurant which mainly provides pizza as well as other foods(pasta, wings, etc). I want this system to be used by the staff. I have created an abstract class named Foods that can be used to inherit by other foods. So far I have created a class that inherits from Foods named Pizza. Below are my code.

PS: I have used namespaces for organize foods and staff members separately. As far as I know some people doesn't recommend namespace and my apologies if you're one of them.

interfaces.h

...

ANSWER

Answered 2022-Feb-16 at 10:51

You need to implement the static member variables sauces and drinks in functions.cpp and not in interfaces.h.

functions.cpp

Source https://stackoverflow.com/questions/71140123

QUESTION

Check if any word from a string is in an array (Case insensitive)

Asked 2022-Feb-01 at 10:49

I hope this is not a duplicate, but I couldn't find something matching.

I'm getting the following response from an api:

...

ANSWER

Answered 2022-Feb-01 at 10:49

You can use array_uintersect, which takes a comparison function in which you can do case-insensitive comparison with strcasecmp:

Source https://stackoverflow.com/questions/70938998

QUESTION

Save dictionary to file Python Tkinter

Asked 2022-Jan-27 at 06:42

first-time poster/ new to coding, working with Python3, Tkinter, and Pickle.

For a project I'm working on I have designed a random meal generator that uses user input ingredients and determines what meals are available to be cooked. Everything is functional with the exception of being able to save and open the ingredient dictionary.

Basically what I want is for a user to be able to save their ingredients and open that file using filedialog.

Here is a sample code of what I have written for saving the recipe list:

...

ANSWER

Answered 2022-Jan-27 at 06:21

Easiest way to save a dict is to use json

Source https://stackoverflow.com/questions/70873681

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install beef

The install script installs the required operating system packages and all the prerequisite Ruby gems:. For full installation details, please refer to [INSTALL.txt](https://github.com/beefproject/beef/blob/master/INSTALL.txt) or the [Installation](https://github.com/beefproject/beef/wiki/Installation) page on the wiki. Upon successful installation, be sure to read the [Configuration](https://github.com/beefproject/beef/wiki/Configuration) page on the wiki for important details on configuring and securing BeEF.
[User Guide](https://github.com/beefproject/beef/wiki#user-guide)
[Frequently Asked Questions](https://github.com/beefproject/beef/wiki/FAQ)
[JSdocs](https://beefproject.github.io/beef/index.html)

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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