placeholder | Offline placeholder image generator | Server Side Rendering library
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Offline placeholder image generator
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QUESTION
I built an app using Django 3.2.3., but when I try to settup my javascript code for the HTML, it doesn't work. I have read this post Django Static Files Development and follow the instructions, but it doesn't resolve my issue.
Also I couldn't find TEMPLATE_CONTEXT_PROCESSORS
, according to this post no TEMPLATE_CONTEXT_PROCESSORS in django, from 1.7 Django and later, TEMPLATE_CONTEXT_PROCESSORS
is the same as TEMPLATE
to config django.core.context_processors.static
but when I paste that code, turns in error saying django.core.context_processors.static
doesn't exist.
I don't have idea why my javascript' script isn't working.
The configurations are the followings
Settings.py
...ANSWER
Answered 2021-Jun-15 at 18:56Run ‘python manage.py collectstatic’ and try again.
The way you handle static wrong, remove the static dirs in your INSTALLED_APPS out of STATIC_DIRS and set a STATIC_ROOT then collectstatic again.
Add the following as django documentation to your urls.py
QUESTION
Hi am trying to do a CRUD application am able to do the add user but i got stock with the edit user Actually for my edit user page i just copied the add user page there and then modified it
This is what my app has to do: normally when i enter the edit user page it has to show me the user's existing information then on my part i can now modify it if i wish and then it is stored in my mysql database but it doesn't return anything i actually console logged it to see if it returns anything but it doesn't
...ANSWER
Answered 2021-Jun-15 at 16:54Get data based on its id (Server Side)
QUESTION
We just got Telerik controls today and I am trying to "switch out" the old controls for the new Kendo UI MVC Controls.
I have a select2 multi-selection dropdownlist and I am trying to send the "selected to paramters through the Kendo UI dataSource to the controller method to return the specific records.
Here is my .cshtml Razor code:
...ANSWER
Answered 2021-Jun-15 at 15:19In my loadAssessmentTable()
which was assigned to onclick
of my submit button, all that was needed was the following:
QUESTION
I have a custom slide toggle component created using Angular Material. I followed this guide: https://material.angular.io/guide/creating-a-custom-form-field-control
Everything seems to be working fine except when I dynamically disable the custom component like this:
...ANSWER
Answered 2021-Jun-11 at 19:49You need to add a formGroup binding to your custom component,
QUESTION
I'm trying for a long time to get my labels on the left side on my input fields. I'm banging my head against the wall. I use a font-awesome icon in the label.
I tried a lot of searches on Google and Stack Overflow and tried stuff like inline-block which I see should work but it didn't work for me. My code so far. I guess it's an easy fix for all the great people that are here.
...ANSWER
Answered 2021-Apr-13 at 19:11The easiest method, in my opinion, is to turn .wrapperSnippet
into a CSS Grid layout.
Grid is supported by all modern browsers but IE supports an older version of the spec.
We can define the grid with two columns: one of width auto
, and the other with 1fr
. auto
means that it will take up as much space as needed to fit the element, then the 1fr
will fill the remaining space.
QUESTION
My problem is that, I have a List of Icons(CustomWidgets) what are provide by an API. I need put this icons in my App but when the are 7 or more its looks like these:
I want to put the icons in separate rows. I've tried out a method which split the list in 2 and add it dynamically but didn't print anything because I'm using a FutureBuilder to print the Icons.
Here is the code:
...ANSWER
Answered 2021-Apr-16 at 01:34What I suggest is to use Wrap instead of Row in your case, widget will place in the 2nd row is not enough space
THERE IS THE WAY TO DO IT:
QUESTION
Hello my favorite people!
I am trying to send an email after submitting a form, with the AUTO INCREMENT number attached to the email because the AUTO INCREMENT number is the clients Job Card Reference Number. So far i have successfully created the insert script which inserts the data into the database perfectly, and also sends the email too. But does not attach the AUTO INCREMENT number into the email. The INT(11) AUTO INCREMENT primary key is "job_number" in my MySQL database.
Here is my insert page:
...ANSWER
Answered 2021-Jun-15 at 09:58 $insertId = false;
if($insert_stmt->execute())
{
$insertId = $insert_stmt->insert_id;
$insertMsg="Created Successfully........sending email now";
}
if($insertId){
// do stuff with the insert id
}
QUESTION
I'm trying to put a text before and after the Var content. Unfortunately I was able to put the text only after. I'm a fan, so I don't know Js very well.
I hope to find a solution here, further info below.
My content currently looks like this: 0.000 Kcal (this is an html placeholder)
When the function is executed, the content looks like this: x.xxx Kcal (this is the result of the function + text after var)
What I'm trying to do should be like this: BMR x.xxx Kcal (so add some text before the numbers, but it is not html)
Below is the code.
...ANSWER
Answered 2021-Jun-15 at 12:17This way you can change the characters in the HTML.
QUESTION
i am trying to make login function but the function always make my input was wrong even i using the correct data from database
here's my login section
...ANSWER
Answered 2021-Jun-15 at 11:46From your image, it shows that the password (firsttt) is in the database in plaintext. However, when you are querying it, you are using md5 to hash it before you check the database. The MD5 hash of firsttt is 568745cb18115e238907fbf360beb37a and since that doesn't match the field in the database it does not return a result. If you want to see the result return positive, you can remove the md5() function for now just to see it but you should secure the database in some other way.
MD5 alone would not be secure as common passwords are easily detected. The passwords need to be hashed and salted, which makes them more unique and unindentifiable.
For example, php provides a password_hash function that will hash and salt the password: https://www.php.net/manual/en/function.password-hash.php
which you should use when adding a user to the database.
They also provide a password_verify function that will be able to tell you if the submitted password is correct: https://www.php.net/manual/en/function.password-verify.php
Read here for more information: https://www.php.net/manual/en/faq.passwords.php
QUESTION
so I have a button to create/ append step div and each step has an add action button element.
Question: how do I append action in a specific step for example if I add new action in step 2 then it will only create a new action in step 2
Here is the link to what i did https://jsfiddle.net/noobnoob121212/306boevh/7/
so what i did to create new step is :
...ANSWER
Answered 2021-Jun-15 at 12:14Whenever actionmodal
is open you can save the index()
of div which has open that modal inside data-attribute . Then , when appendaction
button is clicked get the data-attribute and then use $(".steplist .input-group:eq(" + row_no + ")")..
to add new data inside your input-group div.
Demo Code :
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