grandma | fully programmable stress testing framework | Testing library
kandi X-RAY | grandma Summary
kandi X-RAY | grandma Summary
This is a load testing library and CLI tool. It is inspired by the good parts of Vegeta and JMeter, but hopefully leaves out the bad parts of both.
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QUESTION
import os
import random
import time
import math
def stringmanipulator(xy, y=40):
xy= xy.lower()
x = []
x = list(xy)
length = len(x)
y = int(math.floor(length * (y/100)))
while(y):
r =int(random.random()*(length-1))
if(x[r] != '_' and x[r] != ' '):
x[r] = '_'
y = y-1
return x
def printcomplement():
x = int(random.random()*11)
if(x == 0):
print("well done!!")
elif(x == 1):
print("keep going!!")
elif(x == 2):
print("YOU can save him!!")
elif(x == 3):
print("You are the hero no one wanted but everyone deserves.")
elif(x == 4):
print("Genius kid.")
elif(x == 5):
print("You are Smart, not kidding.")
elif(x == 6):
print("You are one who will destroy my carrer using your intellect.")
elif(x == 7):
print("The most kind hearted person I have ever seen till now. Yes I am talking about you")
elif(x == 8):
print("You nailed it.")
elif(x == 9):
print("AND I thought the game was hard.")
elif(x == 10):
print("I will find more difficult words to challenge you with.")
elif(x == 11):
print("How about you put another life on risk after this round.")
def printdis():
x = int(random.random()*11)
if(x == 0):
print("Fool")
elif(x == 1):
print("You will end up killing the fool and then I will hang you next.")
elif(x == 2):
print("What a piece of shit you are.")
elif(x == 3):
print("Hey disgrace to humanity.")
elif(x == 4):
print("Don't cry after the man is dead. You killed him, I gave you a chance to save him.")
elif(x == 5):
print("Dumbass!!")
elif(x == 6):
print("You know what it was my mistake to let such an idiot play.")
elif(x == 7):
print("This is your last game. I don't want fools playing this game.")
elif(x == 8):
print("I see you are already crying.")
elif(x == 9):
print("Even the guy who's life is line is laughing at your stupidity.")
elif(x == 10):
print("My 120 years old grandma has a sharper brain than yours.")
elif(x == 11):
print("Get lost, YOU useless, moronic, unworthy pile of garbage.")
def hangman(i = 0):
if(i == 0):
print("___________")
print("| |")
print("| |")
print("| ")
print("| ")
print("| ")
print("| ")
print("| ")
print("|")
elif(i == 1):
print("___________")
print("| |")
print("| |")
print("| ( ) ")
print("| ")
print("| ")
print("| ")
print("| ")
print("|")
elif(i == 2):
print("___________")
print("| |")
print("| |")
print("| ( ) ")
print("| | ")
print("| | ")
print("| ")
print("| ")
print("|")
elif(i == 3):
print("___________")
print("| |")
print("| |")
print("| ( ) ")
print("| \\ | / ")
print("| | ")
print("| ")
print("| ")
print("|")
elif(i == 4):
print("___________")
print("| |")
print("| |")
print("| \\ ( ) /")
print("| \\ | / ")
print("| ")
print("| ")
print("| ")
print("|")
elif(i == 5):
print("___________")
print("| |")
print("| |")
print("| \\ ( ) /")
print("| \\ | / ")
print("| | ")
print("| / \\")
print("| ")
print("|")
elif(i == 6):
print("___________")
print("| |")
print("| |")
print("| \\ ( ) /")
print("| \\ | / ")
print("| | ")
print("| / \\")
print("| / \\")
print("|")
print("\n\nGAME OVER. You have succesfully killed a person. Better luck next time")
def game(xy, y):
x=[]
i = 0
letter = ''
x = stringmanipulator(xy, y)
xy = xy.lower()
# os.system('cls')
for index in range(len(x)):
if(x[index] == '_'):
while(letter != x[index]):
_= os.system('cls')
hangman(i)
for char in range(len(x)):
print(x[char], end=' ')
print("\n")
letter = input("Enter the letter in the first blank: ")
print(letter+str(i))
if(letter == xy[index]):
print("complement")
x[index] = letter
else:
printdis()
i+=1
dictionary ={}
dictionary["films"] = ["A Space OdysseY", "The GodFather", "Citizen Kane", "Raiders of the lost Ark", "Seven Samurai", "There will be Blood", "Casablanca", "Vertigo", "Notorious", "City Lights"]
dictionary["cities"] = ["Tokyo", "Mecca", "Beijing", "London", "Kolkata", "Washington DC", "Mumbai", "Mexico City", "Delhi", "Shanghai"]
dictionary["fruits"] = ["Damson Plum", "Pomelo", "Blood Orange", "Kumquat", "Blackcurrant", "Acerola", "Avocado", "Pomegrenate", "Apple", "Mango"]
dictionary["country"] = ["Djibouti", "Azerbaijan Azerbaijan,", "Venzuela", "Armenia", "Khazakhstan", "Bangladesh", "Saudi Arabia", "United Kingdom", "United States of America", "India"]
dictionary["flowers"] = ["Monkey Face Orchid", "Naked Man Orchid", "Dancing Girls", "Chamber Maids", "Hibiscus", "Marigold", "Tulip", "Lilies", "Daisy", "Hydrangea"]
print("WELCOME TO THE GAME HANGMAN.\n TAKE THE GAME SERIOUSLY SINCE THE LIFE OF A MAN IS DEPENDING ON YOUR KNOWLEDGE. \n\nI DON'T KNOW HOW MANY CHANCE YOU WILL GET, NOT MANY THAT I CAN CONFIRM.\n SO TRY TO SAVE YOUR FELLOW HUMAN OR LET IT BE MY FOOD. HAHAHAHAHAHAHAHAHAH!!!!!!!")
# x = input("Press 1 for films, 2 for cities, 3 for fruits, 4 for country and 5 for flowers (The most beautiful are usually the hardest): ")
# x = int(x)
x = int(input("Enter a number between 1 and 5: "))
if((x < 1) or(x > 5)):
print("What a moron you are. You couldn't even choose one of the option properly game over good bye, tata, cya")
x = random.randint(1,5)
time.sleep(10)
print("Just kidding you still get to play the game but now I will decide what kind of object you have to guess.")
y = int(input("Enter 40 for easy, 60 for medium and 80 for hard: "))
i = 0
xy = ""
r = random.randint(0,9)
if(x == 1):
xy = dictionary["films"][r]
print("FILMS:")
elif(x == 2):
xy = dictionary["cities"][r]
print("CITIES:")
elif(x == 3):
xy = dictionary["fruits"][r]
print("FRUITS:")
elif(x == 4):
xy = dictionary["country"][r]
print("COUNTRY:")
elif(x == 5):
xy = dictionary["flowers"][r]
print("FLOWERS:")
# hangman(0)
game(xy, y)
...ANSWER
Answered 2021-May-31 at 14:43Running your code os.system('cls') is clearing the screen before the input is read in the loop. This makes it seem that there is no output is being displayed when it's really being overwritten.
A quick test can be done to confirm that this is the problem. To do this we add another input read in the game function. like so:
QUESTION
I am trying to make a Bill of Material list from my CAD software(Creo), this is exported out as a text file and its almost working perferct. The problem is that the text file spits out all parts in model, and I would like to count up duplicates instead of list them out after each other i.e quanties larger then 1.
My code does this nicely if the duplicate is listed in the row above, however if its nested(sub assy) this does not work. In picture below 00151564.asm(level 2) should be listed as quantity=3 but the parts on level 3 should be listed as quantity=1
Below is the original textfile creo spitts out, groups and patterns makes extra unwanteded indents, and material is just sometimes given..
Here is my code:
...ANSWER
Answered 2021-Apr-29 at 15:24This scans the Output sheet and creates a new sheet called "No Duplicates". However, with the bugs in your data I suspect this won't work for more complex cases e.g. where an assembly appears in other assemblies at different levels.
Update 1 - dictionary at each level
QUESTION
I have a large table with a comments column (contains large strings of text) and a date column on which the comment was posted. I created a separate vector of keywords (we'll call this key) and I want to count how many matches there are for each day. This gets me close, however it counts matches across the entire dataset, where I need it broken down by each day. The code:
...ANSWER
Answered 2021-Apr-21 at 18:50As pointed out in the comments, you can use group_by
from dplyr
to accomplish this.
First, you can extract keywords for each comment/sentence. Then unnest
so each keyword is in a separate row with a date.
Then, use group_by
with both date and comment included (to get frequency for combination of date and keyword together). The use of summarise
with n()
will give number of mentions.
Here's a complete example:
QUESTION
The problem I'm having is that this set of code NEEDS to happen in order. It is all packaged inside a component that is updating every second.
Here is what I want to happen when the component mounts:
Step 1: On load, retrieve the last known timestamp stored in local storage and subtract it by new Date() /1000
then console log the answer.
Step 2: retrieve all data from local storage and update state (this includes the timestamp), continuing this process every second.
As it stands in my code, step 2 is happening first.
Here's a video of the app I'm working with and the component that's updating every second to provide context to my issue. I highlight my console log being 0. This is the issue I want to fix. I need the console log to not give me 0, but the current timestamp - the previous timestamp. This is so if a user using my app goes offline and comes back, it counts the time they were gone.: https://www.youtube.com/watch?v=N0tOZhHfio4
Here's my current code:
...ANSWER
Answered 2021-Apr-03 at 00:42A few things. I don't know exactly what you are doing, but you have to know that Javascript is an asynchronous programming language. That means that stuff doesn't happen in order. If a function takes time, Javascript will go onto the next function. It won't wait for the first function to finish to then go to the second function. This makes Javascript very efficient but adds a little more difficulties to the user. There are a few ways to go around this. I have linked articles to three methods.
Callbacks: https://www.w3schools.com/js/js_callback.asp
Promises: https://www.w3schools.com/js/js_promise.asp
Async/Await: https://www.w3schools.com/js/js_async.asp
You can choose whichever you like depending on your circumstances. Also there is something wrong with your code on the last line.
Lockr.set('timeStamp', timeStamp());
You are passing in the timestamp function. When you do this remove the ()
from the timestamp
. Anyways, I hope this helped.
QUESTION
I have a collection "people" in the form:
...ANSWER
Answered 2021-Feb-17 at 16:02- Just need to change startWith frmo
parentID
to_id
, this will returnancestors
with current document $project
to show required fields
QUESTION
In MS SQL Server, I need to convert a table's one column(column name is Question in my case) data to different column headers and another column(Column name is Answer in my case) data to data of the newly formatted column names ( I searched for answered related to similar questions but there are no answers for my issue hence asked a new question).
SQL Fiddler - http://sqlfiddle.com/#!18/b24f0/3
Table has data as http://sqlfiddle.com/#!18/bac182/1/0
This is my Query:
...ANSWER
Answered 2021-Feb-06 at 12:04Your combination of (EmployeeName
, Date
, QuestionID
, Question
) is not unique for EmployeeName = John
. You need a new column to distinquish between the first set of questions for John and his second set. Then you can group on that new column as well and the max()
function should work fine.
I added a column RowNum
to split John's question sets. Your current sample data set contains not enough data to guarantee that this new RowNum
column will always produce the correct results.
If you have a QuestionSetId
column somewhere, then this field should replace the new RowNum
column in the CTE.
QUESTION
Using the w3schools.com SQL tutorial Northwind database, I'm trying to display the category that has the most products shipped. Additionally, I want to display the net income from all sales in that category. I can't figure out how to take the category with the most products shipped, and use the amount of products shipped to calculate the net income of that category. This is because there are many different products that have the same CategoryID but different prices.
...ANSWER
Answered 2021-Jan-25 at 07:24So first of all you get the income for each product and category and then based on that you find total income for that category and you do this with the help of subquery, then you join this resultant table with the category table and with the help of group by you find the product count and total income for each category, below is the sql query for more indepth understanding
QUESTION
I am trying to create a simple Rock, Paper, Scissors game to practice some basic Python skills. I created the code below to take user input and create a simple point-based game. However, when I ran the code, the loop ran infinitely, printing the output message until I force stopped it. How can I alter my code so the while-loop only runs once per user input?
code:
...ANSWER
Answered 2021-Jan-11 at 01:49You need to set your while loop before the user input, otherwise it is just looping over and over the same inputs values:
QUESTION
there is some error with the grandma , cousin, brother, uncle rules i tried so many rules but still could not find the correct one it returns false , please helpppppppppp
...ANSWER
Answered 2020-Oct-19 at 16:12Found: female(elizabith). elizabeth is wrongly spelled !
With this correction, your code should work as normal. Did I reply to your quest for help ?
QUESTION
I couldn't figure out how to paginate a request with Node using https
module.
This is the problem:
Given a string substr
, I have to retrieve information from a movie database. There are multiple pages to retrieve.
The query should read https://jsonmock.hackerrank.com/api/movies/search/?Title=substr&page=pageNumber
, replacing substr
and pageNumber
.
The query response from the website is a JSON response with the following five fields:
page
: current pageper_page
: the maximun number of results per pagetotal
: the total number of records in the search resulttotal_pages
: the total number of pages which must be queried to get all the resultsdata
: An array of JSON objects containing movie information
The response for the query https://jsonmock.hackerrank.com/api/movies/search/?Title=spiderman&page=1
is:
ANSWER
Answered 2020-Jul-05 at 18:10After page is pulled getMovieTitles()
should chcek if there are any more pages - if so, cycle with next page until all is downloaded.
I added new internal function loadNextPage()
to do the actual work to your code, and accumulation of the result in dataUntilNow
:
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