didgeridoo | Your custom IDE on the browser

by fmvilas JavaScript Version: Current License: GPL-2.0

X-Ray Key Features Code Snippets Community Discussions(2)Vulnerabilities Install Support

kandi X-RAY | didgeridoo Summary

didgeridoo is a JavaScript library typically used in Editor applications. didgeridoo has no bugs, it has no vulnerabilities, it has a Strong Copyleft License and it has low support. You can download it from GitHub.

Your custom IDE on the browser

Support

Quality

Security

License

Reuse

Support

didgeridoo has a low active ecosystem.

It has 12 star(s) with 3 fork(s). There are 5 watchers for this library.

It had no major release in the last 6 months.

There are 6 open issues and 2 have been closed. On average issues are closed in 129 days. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of didgeridoo is current.

Quality

didgeridoo has no bugs reported.

Security

didgeridoo has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

didgeridoo is licensed under the GPL-2.0 License. This license is Strong Copyleft.

Strong Copyleft licenses enforce sharing, and you can use them when creating open source projects.

Reuse

didgeridoo releases are not available. You will need to build from source code and install.

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didgeridoo Key Features

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didgeridoo Examples and Code Snippets

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Community Discussions

Trending Discussions on didgeridoo

How do I display each element or alphabet as dash after it matches the input for Hangman?

Is there a way to add characters based on a variable?

QUESTION

How do I display each element or alphabet as dash after it matches the input for Hangman?

Asked 2021-May-09 at 14:30

I have been on and off programming but recently I have been more active and done some basic projects. However I have been stuck on this particular problem for the past 3 weeks and still cannot seems to solve it. Looked through some codes and tried and only could improve some parts. The bottom is my full code.

The problems that I faced is the one that I have stated in my title, I need to display the mystery word as dashes and when I guess the unknown word, it was suppose to appear as the only word. One issue is when I guess the word correctly, it only display the single alphabet and reset immediately.

...

ANSWER

Answered 2021-May-09 at 14:30

Keep a list of all the player's guesses. When you start a new game, set all_guesses to [] and then, reading the letter from the console set:

Source https://stackoverflow.com/questions/67458676

QUESTION

Is there a way to add characters based on a variable?

Asked 2019-May-31 at 01:36

I'm making a text-based game about Hangman and so far I have 10 words with different amounts of characters in each word. The lowest character count is three, so I'm planning to put in three underscores at the start for me to be able to add underscores after the string.

I have a variable set up, called wordPlayingLength which counts up an integer based on the amount of characters in the word that has been selected through a random statement. My question is if there's a way to add underscores that matches up with the word's length in characters?

...

ANSWER

Answered 2019-May-31 at 01:36

In Python, you can multiply a string by an integer to make repetition:

Source https://stackoverflow.com/questions/56387124

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