canopy | A parser compiler for Java , JavaScript , Python , Ruby | Parser library
kandi X-RAY | canopy Summary
kandi X-RAY | canopy Summary
Canopy is a parser compiler targeting Java, JavaScript, Python and Ruby. It takes a file describing a parsing expression grammar and compiles it into a parser module in the target language. The generated parsers have no runtime dependency on Canopy itself. For usage documentation see canopy.jcoglan.com. See CONTRIBUTING.md for instructions for building the project.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of canopy
canopy Key Features
canopy Examples and Code Snippets
def CCCI(self):
"""
Canopy Chlorophyll Content Index
https://www.indexdatabase.de/db/i-single.php?id=224
:return: index
"""
return ((self.nir - self.redEdge) / (self.nir + self.redEdge)) / (
Community Discussions
Trending Discussions on canopy
QUESTION
I'm astonished by the recurrent problem of size vector cannot be allocated
in geom_raster
function. This problem happens with small data set and in my case 1559 observations. I try to do:
ANSWER
Answered 2021-May-27 at 15:29The warning that came with the error was informative
In addition: Warning messages:
1: Raster pixels are placed at uneven horizontal intervals and will be shifted. Consider using geom_tile() instead.
2: Raster pixels are placed at uneven vertical intervals and will be shifted. Consider using geom_tile() instead.
This happen when the data have spurious precision, so geom_raster
tries to make a very fine grid which uses insane amounts of memory.
The solution is simply to round the data to an appropriate amount of precision.
QUESTION
Can someone help me figure out why the same simple calculation gets different answers in python 2 and 3? The expression is (0.2**(-2)-1)**(1/2)
.
When I use python 2 in a Canopy IDE, I get 1
.
When I use python 3 in google colab, I get 4.98
.
In both cases I am literally running exactly the above expression. Any ideas?
...ANSWER
Answered 2021-May-13 at 14:30Integer division works differently in Python 2 and 3.
For example (1/2) will return
0
in Python 2, and
0.5
(a float) in Python 3.
QUESTION
Let's say I have the following simple Canopy test program:
...ANSWER
Answered 2021-Apr-13 at 14:51I don't think there's any built-in way to do this, but it seems pretty easy to manage manually:
QUESTION
I am using MySQL query to show me the files that have been uploaded and are of type V.
The files's information is stored in the vector_data table.
Currently it contains only 1 row.
Nevertheless, it is showing 3 files as a result.
Please see the query and tables below.
The data does not need to be ordered.
It should show all the files uploaded by the user specified in the query.
query
...ANSWER
Answered 2021-Mar-23 at 22:35You are getting 3 rows, 1 for each of the rows of the table project
because in your query you did not add the link between vector_data
and project
, which (I guess) is the column crop
:
QUESTION
I have a data frame like so:
...ANSWER
Answered 2021-Mar-03 at 15:34Try:
QUESTION
I want to do two adjustments into the following graphic:
- I want to remove the
shape
in the legend related to thelinetype
(Model) - I want to remove the
linetype
in the legend related to theshape
(Standard Error (SE))
Code:
...ANSWER
Answered 2021-Feb-17 at 17:24This could be achieved via guide_legend
which allows you to remove the shape
and linetype
via override.aes
like so:
QUESTION
My tibble
is inserted in the end.
I have a data frame with different types of columns (they are different repetitions). The first four columns should be left as they are; the ones that start_with()
(I wrote it like that because maybe the function ca be useful) "canopy" should be summarised into a mean
, as well as "understory" (it's written as "under") and "tree diameter-at-breast-height" (tdbh) – including na.rm = TRUE
. How can I do this? How can I summarise the columns like this?
Data (head):
...ANSWER
Answered 2020-Dec-18 at 13:12Can't you just do:
QUESTION
I am using below codes
...ANSWER
Answered 2020-Dec-18 at 01:06For this you need to understand that even you have the second Y-Axis, it is just a markup and everything draw on the graph is still base on the main Y-Axis(left one).
So you need to do two things:
- Convert anything that should reference to the second Y-Axis to same scale of the one on the left, in this case is the bar scale (LA variables) whose maximum is 15. So you need to divide the value of TT by 20.
- Second Axis needs to label correctly so it will be the main Y-Axis multiply by 20.
QUESTION
1) First I am aware that sets and dictionaries don't have an order, the question confuses me and I am trying to figure this out, you can tell from below my efforts to figure out how to solve the problem. 2) I know that the look of the question is poor so sorry in advance, not sure how to make it more tidy here, have spent over half an hour trying to make it in the proper format etc :-) and it is still not as I would like it to be.
Summary: My difficulty is that the question is requiring me to produce a dictionary with values in a certain order so while I can get the answer of specific values. I can do it without the order it asks unless I have misunderstood.
This is the course question I am referring to, I have tried some of the stuff which is not successful according to the required answer:
(if you don't want to check the link the answer I get from the code is here:
...ANSWER
Answered 2020-Jun-19 at 21:58I think the easiest way to do this would be to just use the Counter function then sort after the fact like this:
QUESTION
ANSWER
Answered 2020-Oct-16 at 15:43The best approach here is not try to hide or cover up the problem, but to fix it properly so you don't have to. Solutions that involve hiding the issue are necessarily going to adversely affect your security.
Note the wording of the error code: ERR_CERT_AUTHORITY_INVALID
. That tells us that the certificate for the site is signed by a non-standard or unknown certificate authority.
You mentioned localhost
in your comment; you're not going to be able to get a certificate for that, but you could create a self-signed one, however, if you've enabled the localhost exemption and you're still getting the error, it suggests that you may not be using localhost after all.
So, if you have a certificate signed by a real CA and you're seeing this error, it's likely that your local OS or browser has an outdated CA root certificate bundle. you can usually get the latest one by making sure your OS packages are up to date.
If your certificate is self-signed, then the 'advanced' button will allow you to add an exemption. I you have set up your own CA and signed the certificate with that, you need to add that CA's public key that signed it to your OS.
If you've got a "regular" commercial certificate from verisign, letsencrypt, comodo or whoever, then a run through a testing tool like testssl.sh or Qualys SSL labs will tell you more about what's going wrong. Without knowing the actual domain we can't test anything for you.
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