scriptular | A rubular.com clone for javascript regular expressions | Regex library
kandi X-RAY | scriptular Summary
kandi X-RAY | scriptular Summary
A regular expression editor for javascript.
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Top functions reviewed by kandi - BETA
- Initialize the controller
- Represents the application .
- Create a new Model
- Represents a result object .
- Try wrapper function .
- Create a new Module .
- Creates a new Result
- Create an instance of Instances
- Creates an Expression
- Creates a new list of TestString strings .
scriptular Key Features
scriptular Examples and Code Snippets
Community Discussions
Trending Discussions on scriptular
QUESTION
Given the string below
[NeMo (PROD)] 10.10.100.100 (EFA-B-3) [Brocade FC-Switch ] Sensor: Power Supply #1 (SNMP Custom Table) Down (No Such Name (SNMP error # 2))
I try to get multiple matches to extract the following values:
...ANSWER
Answered 2019-Aug-09 at 12:21Since there is no way to define separators, the only way is to match the parts and capture them separately.
QUESTION
I'm building regular expression patterns for class in Javascript.
...ANSWER
Answered 2017-Mar-26 at 17:56QUESTION
I have a regex here at scriptular.com
...ANSWER
Answered 2017-Feb-12 at 22:371.) The dot matches any character besides newline. It won't skip over newlines if the desired words would match in lines after the first one. In many regex flavors there is the dotall or single line s
-flag available for making the dot also match newlines but unfortunately not in JS Regex.
Workarounds are to use a character class that contains any character. Such as [\s\S]
any whitespace character \s
together with any non whitespace \S
or [\w\W]
for any word character together with any non word character or even [^]
for not nothing instead of the dot.
2.) Anchor the lookaheads to ^
start of string as it's not wanted to repeat the lookaheads at any position in the string. This will drastically improve performance.
3.) Use lazy matching for being satisfied with first match of each word.
QUESTION
I'm trying to replace a bootstrap column on a div. I'm using the following regex for it.
string.replace("\bcol-\w+-\d+","col-sm-3")
I tried confirming the regex match here. It looks fine. But the string is not getting replaces. Here is a sample snippet. What am i doing wrong?
...ANSWER
Answered 2017-Jan-28 at 10:03You've passed it a string, not a regular expression, as the first argument. Make it a regular expression instead:
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