regexr | JS based tool | Regex library
kandi X-RAY | regexr Summary
kandi X-RAY | regexr Summary
RegExr is a HTML/JS based tool for creating, testing, and learning about Regular Expressions.
Top functions reviewed by kandi - BETA
- Add editor methods for editor instances
- Defines an options object .
- Handles mouse click events .
- Registers event handlers for mouse events .
- Represents the CodeMirror editor .
- Handle mouse wheel events .
- Draw a Selection range
- If we need to update the display area that we need to update the current layout
- Make a change event from the history .
- Constructs a CodeMirror instance .
regexr Key Features
regexr Examples and Code Snippets
Trending Discussions on regexr
ANSWERAnswered 2022-Mar-15 at 02:08
You were correctly checking if the second character isn't the same as the first (group), but you forgot to allow a match on the second character otherwise.
If you want to also want the matches to be 3 characters only,
I am a RegEx beginner and trying to identify the endings of different statements in sms. See screenshot below.
How can I avoid selecting the next letter following by a full-stop that indicates ending of a statement.
Note that some statements have
<.> while some have
Sample SMS: - I want to select just the full-stop and space if any....
ANSWERAnswered 2021-Dec-25 at 05:17
What you're looking for is a look-ahead group. Whether you make that a positive look-ahead and use the negated character set
\D or a negative look-ahead with the character set
\d doesn't really matter- I'll outline both below:
I want to match
After if there isn't an
-ing word after it (and before a comma). So there shouldn't be an
-ing word between
After and the comma.
Desired match (bold):
After sitting down, he began to talk.
After finally sitting down, he began to talk.
After he sat down, he began to talk.
I thought this regex would do it:...
ANSWERAnswered 2021-Oct-23 at 06:12
Try this regex
Matches only sentence from
After and a comma, where there's no word with
-ing after the wo
Just a lazy quantifier to the
.+ (which instead of
\w+in your regex) does the trick
(And also a lazy quantifier after the second
.*, just in case if there's 2 commas in the same sentence)
Tell me if its not working for you...
My sample data is:...
ANSWERAnswered 2021-Oct-20 at 20:29
You can use
sub in the following way:
I thought this regex would match lines with a
[, but not if it has a
ANSWERAnswered 2021-Oct-19 at 15:24
[ and the directly following
.* will match the rest of the line.
Then at the end of the line it will assert not
] directly to the right, which is true because it already is at the end of the line. Then the
.* is optional and it can assert the end of the string.
So it will match any whole line that has at least a single
If you want to match pairs of opening till closing square brackets
[...] and not allow any brackets inside it, or single brackets outside of it and matching at least a single pair, you can repeat 1 or more times matching pairs surrounded by optional chars other than square brackets.
For example I would like my regex expression to capture both "1 dollar" if there are no cents, or "2 dollars and 71 cents" in my text. I currently have...
ANSWERAnswered 2021-Oct-19 at 17:20
Try this regex:
I have a text file that line by line details a timestamp at the very start, and may contain other timestamps in between. The first timestamp is always enclosed in
, and the ones in the middle of the line are always enclosed in
<>. The goal is to create a regex pattern that can create groups for the timestamp and the text that follows it. I'm pretty new to regex, and I'm having a hard time with it. The text would look like this:
ANSWERAnswered 2021-Oct-15 at 06:29
Going with pure regexp splitting I'd use the following. The regexp matches
[ followed by your number pattern, then
] for the timestamp. For the content it takes everything until the first
ANSWERAnswered 2021-Oct-01 at 18:46
Use a negative lookahead at the beginning, and negative lookbehind at the end.
I'm trying to capture an entire LDAP entry from
dn:.+ to the entry's last line, but stopping at last line before next entry, e.g., \n#entry-id: 8266. My trial and error using
egrep is getting absolutely nowhere. NOTE: I'm using exported ldif files where the data resides, fwiw.
Closest I've come is with
egrep "dn: cn=name,ou=People,dc=example,dc=com.+.|\n*.+\n" but no output on terminal. I've tested the actual regex on regexr.com. I understand that is a completey different env.
Thanks in advance!
ANSWERAnswered 2021-Sep-29 at 06:27
egrep uses extended regexp (equivalent to
grep -E). Prefer
grep -P (perl regexp) instead.
-z flag makes your regex multiline:
I want to match a company name once from a string that looks like this
What I want:
Distribution Services Management only once
What I get
CATE-N LUNA SI-N STELE SRL
What I'm trying
ANSWERAnswered 2021-Sep-08 at 20:02
This might help you:
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