combi | ️ A tiny keyboard shortcut | Keyboard library
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kandi X-RAY | combi Summary
️ A tiny keyboard shortcut handling library.
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QUESTION
using the "Replace..." [Find menu] function a slide-in at the bottom appears with an option field/entry for "Find:" and below that one, one for "Replace:"
having completed a replace [eg "Find: abc", "Replace: xyz"] for instance by employing "Replace All" the very slide-in disappears
now for another, new, search, for instance within a document having selected a different, let's say word like "oha", that selection 'oha' is auto-copied over as new entry in "Find:" when using "Replace..." again. this is to say that now in "Find:" the entry does read "oha" tho didn't paste it manually in -- the "abc" entry fromthe previous search got replaced
however, the last entry in the "Replace:"-entry-field remains unchanged
it's the "Find:" entry that get's auto filled in w/out the option [as far as i could figure out]
and that exactly is my question about : any option to modify Sublime's settings such that nothing gets changed/auto-copied/filled-in at "Find:" ?
pretty annoying behaviour, as i experience it, for instance when having to replace just a single character combi within similar text and each time the copy-selected text get's auto-copied/filled-in at "Find:" rather than leave it be till the usr opts to modify that entry from previous replace-calls
...ANSWER
Answered 2021-May-29 at 21:19The Find
and Find and Replace
widgets automatically populate the Find box with either the current selection if there is one, or the previous value used in that box. This box is a dropdown, which contains the previous values used, so you can easily go back through your history in that window and not have to re-type a complicated regular expression, for example.
When the Find box opens pre-populated with a value, it is automatically selected, so to get rid of it all you have to do is hit Backspace or Delete. Alternatively, you can just begin typing your new search query, and it will erase the old one.
There is a setting in Sublime Text 4 that modifies this behavior:
QUESTION
I was working on a binomial expansion in R, I came across some issues and I feel the values do not make sense. Here is my code, I used factorial and combination from "scratch" to compute. I tried x=6, y=2 and n=4 I got 2784 as an answer. If I try 1 it gives 0. If n=i I get infinity because the denominator would equal zero
...ANSWER
Answered 2021-May-23 at 12:15You should be aware of that, 0!
is 1
. In this case, f
should be defined like below
QUESTION
I'm facing a problem with vectorizing a function so that it applies efficiently on a numpy array.
My program entries :
- A pos_part 2D Array of Nb_particles lines, 3 columns (basicaly x,y,z coordinates, only z is relevant for the part that bothers me) Nb_particles can up to several hundreds of thousands.
- An prop_part 1D array with Nb_particles values. This part I got covered, creation is made with some nice numpy functions ; I just put here a basic distribution that ressembles real values.
- A z_distances 1D Array, a simple np.arange betwwen z=0 and z=z_max.
Then come the calculation that takes time, because where I can't find a way to do things properply with only numpy operation of arrays. What i want to do is :
- For all distances z_i in z_distances, sum all values from prop_part if corresponding particle coordinate z_particle < z_i. This would return a 1D array the same length as z_distances.
My ideas so far :
- Version 0, for loop, enumerate and np.where do retrieve the index of values that I need to sum. Obviously quite long.
- Version 1, using a mask on a new array (combination of z coordinates and particle properties), and sum on the masked array. Seems better than v0
- Version 2, another mask and a np.vectorize, but i understand it's not efficient as vectorize is basicaly a for loop. Still seems better than v0
- Version 3, I'm trying to use mask on a function that can I directly apply to z_distances, but it's not working so far.
So, here I am. There is maybe something to do with a sort and a cumulative sum, but I don't know how to do this, so any help would be greatly appreciated. Please find below the code to make things clearer
Thanks in advance.
...ANSWER
Answered 2021-May-08 at 12:48You can get a lot more performance by writing your first version completely in numpy. Replace pythons sum
with np.sum
. Instead of the for i in positions
list comprehension, simply pass the positions
mask you are creating anyways.
Indeed, the np.where
is not necessary and my best version looks like:
QUESTION
I have an array that has first rows as header:
...ANSWER
Answered 2021-Apr-07 at 08:45Destructure the array, and take the keys (1st item), and the values (the rest). Map the values array, and then map each sub-array of values, take the respective key by the value, and return a pair of [key, value]
. Convert the array pairs to an object with Object.fromEntries()
:
QUESTION
I made a code to generate combinations based on first, second, third, fourth, fifth and sixth input. However, it is taking a long time: it usually takes 86-88 seconds.
Is there a faster and better way to do this?
...ANSWER
Answered 2021-Apr-01 at 07:54First of all, generating a large number of combinations will always be slow. The first combination call will generate 13K results, which is a lot.
However, your second loop can be made more efficient. It seems like you are checking every combination to see if it is the combination you want. This is inefficient since you are spending a lot of computing power on many combinations that you can eliminate immediately.
Try something like this for the second loop:
QUESTION
I have a list of lists populated with integers. These integers represent nodes in a graph and the lists in the main list represent cycles in the graph. I want to extract a unique set of nodes - one node from each cycle - in the order of the list of lists.
Example:
I know, it's not possible to have a cycle with only two nodes, but it is the easiest non trivial example i came up with and it should make clear what I am looking for.
...ANSWER
Answered 2021-Mar-03 at 15:23cycles = [[11, 22], [22, 44], [11, 33], [22, 33]]
from itertools import product
a=list(product(*cycles))
[list(i) for i in a if len(i) == len(set(i))]
QUESTION
I have built a function which pulls in values provided by an end user and produces a graph as a result.
The user has the option to provide a site
, which can be either a single value or multiple:
ANSWER
Answered 2021-Feb-23 at 01:15Use paste
with collapse should provide you what you want.
QUESTION
I need to exclude any instance of six values from a dataset that I have and wonder if there is an "all-in-one" solution to achieve this.
Aside from the usual
...ANSWER
Answered 2021-Feb-22 at 22:06We can use %in%
with !
i.e. create a logical vector on a vector of elements on the rhs
of %in%
, and negate (!
)
QUESTION
I have some trouble using C++17 parallel execution algorithm with Boost iterators on MSVC. Here is my code:
...ANSWER
Answered 2021-Feb-22 at 20:10zip iterators can only be input in the C++17 iterator hierarchy because their reference types are not real references.
It is undefined behavior to passing an input iterator to a parallel algorithm. MSVC's implementation happens to check the precondition more aggressively than GCC's.
QUESTION
Hej, I´m an absolute beginner in Python (a linguist by training) and don´t know how to put the twitter-data, which I scraped with Twint (stored in a csv-file
), into a DataFrame
in Pandas to be able to encode nltk frequency-distributions
.
Actually I´m even not sure if it is important to create a test-file and a train-file, as I did (see code below). I know it´s a very basic question. However, to get some help would be great! Thank you.
This is what I have so far:
...ANSWER
Answered 2021-Feb-18 at 09:23You do not need to split your csv in a train and a test set. That's only needed if you are going to train a model, which is not the case. So simply load the original unsplit csv file:
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