objectron | generic model to test equality | Regex library

 by   mena-devs JavaScript Version: 0.1.14 License: Apache-2.0

kandi X-RAY | objectron Summary

objectron is a JavaScript library typically used in Utilities, Regex applications. objectron has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can install using 'npm i @menadevs/objectron' or download it from GitHub, npm.
Compare an object to a generic model to test equality and extract matches. This module provides you with the means to define a tester object containing a set of match rules that will be used against a payload object. The match() method within the module will return whether the payload object has satisfied all the rules and will return the set of matches.
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                        objectron has a low active ecosystem.
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                        It has 18 star(s) with 1 fork(s). There are 5 watchers for this library.
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                        It had no major release in the last 12 months.
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                        There are 3 open issues and 3 have been closed. On average issues are closed in 2 days. There are 1 open pull requests and 0 closed requests.
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                        It has a neutral sentiment in the developer community.
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                        The latest version of objectron is 0.1.14
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                                                objectron has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
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                                                            objectron is licensed under the Apache-2.0 License. This license is Permissive.
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                                                                                  objectron Key Features

                                                                                  Compare an object to a generic model to test equality and extract matches

                                                                                  objectron Examples and Code Snippets

                                                                                  No Code Snippets are available at this moment for objectron.
                                                                                  Community Discussions

                                                                                  Trending Discussions on Regex

                                                                                  How would I match `.scss`, `.sass`, `.css` but not `.ass`? (RegExp)
                                                                                  chevron right
                                                                                  REGEX for matching number with two and three numbered patterns together
                                                                                  chevron right
                                                                                  Is there a better way to clean a string?
                                                                                  chevron right
                                                                                  Complex string manipulation by JavaScript regexp
                                                                                  chevron right
                                                                                  Difference between Pattern.asMatchPredicate and Pattern.asPredicate
                                                                                  chevron right
                                                                                  Regex to replace single occurrence of character in C++ with another character
                                                                                  chevron right
                                                                                  Negating bracketed character classes in Perl regular expressions and grep
                                                                                  chevron right
                                                                                  Regular expression that matches all specified characters in any order at the start of the line
                                                                                  chevron right
                                                                                  Using PowerShell how to replace and save a value in a json file having comments
                                                                                  chevron right
                                                                                  How to get customed tags in a text, and put in another text?
                                                                                  chevron right

                                                                                  QUESTION

                                                                                  How would I match `.scss`, `.sass`, `.css` but not `.ass`? (RegExp)
                                                                                  Asked 2022-Mar-02 at 15:18

                                                                                  I have the following regex: /\.([s]?[ac]ss)$/. The problem is, it matches .scss, .sass, .css, .ass. How would I make it not match .ass?

                                                                                  ANSWER

                                                                                  Answered 2022-Mar-02 at 08:35

                                                                                  You can use

                                                                                  \.(?!a)(s?[ac]ss)$
                                                                                  

                                                                                  See the regex demo. Details:

                                                                                  • \. - a dot
                                                                                  • (?!a) - the next char cannot be a
                                                                                  • (s?[ac]ss) - Group 1: an optional s, a or c and then ss
                                                                                  • $ - end of string.

                                                                                  Another regex that can work is

                                                                                  \.(s(?:css|ass)|css)$
                                                                                  

                                                                                  See this regex demo. Details:

                                                                                  • \. - a dot
                                                                                  • (s(?:css|ass)|css) - s and then css or ass or css
                                                                                  • $ - end of string.

                                                                                  NOTE: if you have a dynamic, user-defined list of such fixed strings to match after a . at the end of string, you can build these regexes automatically using the code at the bottom of my answer.

                                                                                  Source https://stackoverflow.com/questions/71319480

                                                                                  QUESTION

                                                                                  REGEX for matching number with two and three numbered patterns together
                                                                                  Asked 2022-Jan-17 at 10:25

                                                                                  I have an array of 5 numbers, I'd like to match as long as there are three of the same number and two of the same different number in the array, placement does not matter. Number sequences can be any random string of 5 numbers between 1 - 5. Examples of matches would be: 33322 24422 52225 44111 54545 *basically any grouping of 2 and 3 of the same numbers needs to match.

                                                                                  Best I've come up with so far: ^([0-9])\1{2}|([0-9])\1{1}$

                                                                                  I am not so good with regex, any help would be greatly appreciated.

                                                                                  ANSWER

                                                                                  Answered 2022-Jan-16 at 23:38

                                                                                  You can use

                                                                                  ^(?=[1-5]{5}$)(?=.*(\d)(?:.*\1){2})(?=.*(?!\1)(\d).*\2)\d+$
                                                                                  ^(?=.*(\d)(?:.*\1){2})(?=.*(?!\1)(\d).*\2)[1-5]{5}$
                                                                                  

                                                                                  See the regex demo.

                                                                                  If you want to allow any digits, replace [1-5] with \d.

                                                                                  Details:

                                                                                  • ^ - start of string
                                                                                  • (?=[1-5]{5}$) - there must be five digits from 1 to 5 till end of string (this lookahead makes non-matching strings fail quicker)
                                                                                  • (?=.*(\d)(?:.*\1){2}) - a positive lookahead that requires any zero or more chars as many as possible, followed with a digit (captured into Group 1) and then two sequences of any zero or more chars as many as possible and the same digit as captured into Group 1 immediately to the right of the current location
                                                                                  • (?=.*(?!\1)(\d).*\2) - a positive lookahead that requires any zero or more chars as many as possible, followed with a digit (captured into Group 2) that is not equal to the digit in Group 1, and then any zero or more chars as many as possible and the same digit as captured into Group 2 immediately to the right of the current location
                                                                                  • \d+ - one or more digits
                                                                                  • $ - end of string.

                                                                                  Source https://stackoverflow.com/questions/70735094

                                                                                  QUESTION

                                                                                  Is there a better way to clean a string?
                                                                                  Asked 2022-Jan-06 at 09:49

                                                                                  Currently, this is my code.

                                                                                  function clean_string(raw_string) {
                                                                                      A =
                                                                                          "ABCDEFGHIJKLMNOPQRSTUVWXYZ abcdefghijklmnopqrstuvwxyz 1234567890".split(
                                                                                              ""
                                                                                          );
                                                                                      var cleaned_string = raw_string.toLowerCase();
                                                                                      for (i = 0; i < cleaned_string.length; i++) {
                                                                                          if (!A.includes(cleaned_string[i])) {
                                                                                              cleaned_string = setCharAt(cleaned_string, i, " ");
                                                                                          }
                                                                                      }
                                                                                      cleaned_string = cleaned_string.replace(/\s\s+/g, " ");
                                                                                  
                                                                                      return cleaned_string;
                                                                                  }
                                                                                  
                                                                                  function setCharAt(str, index, chr) {
                                                                                      if (index > str.length - 1) return str;
                                                                                      return str.substring(0, index) + chr + str.substring(index + 1);
                                                                                  }
                                                                                  

                                                                                  I don't know regex and it'll probably be easier with regex. Here's what I want to do:

                                                                                  Input: Hello, David World 123!

                                                                                  Output: hello david world 123

                                                                                  .

                                                                                  Input: hELlo., <>;dAVId world .;- 123

                                                                                  Output: hello david world 123

                                                                                  .

                                                                                  Input: He.llo David, w!orld 123#

                                                                                  Output: he llo david w orld 123

                                                                                  .

                                                                                  Basically what I want to do is replace anything but a-z0-9 with a space and then remove double spaces. In other words, I only want a-z0-9 in my results. How can I do that?

                                                                                  P.S. The code works but I think it looks bad and pretty inefficient.

                                                                                  EDIT: Sorry, I meant I only want lowercase letters in my output. I'm dumb.

                                                                                  ANSWER

                                                                                  Answered 2022-Jan-06 at 04:57

                                                                                  A simple solution would be to convert all characters to lowercase, replace any character that isn't a-z, 0-9, or a space with a space character, and then replace multiple space characters with a single space character.

                                                                                  function sanitize(input) {
                                                                                      return input
                                                                                        .toLowerCase()
                                                                                        .replace(/([^a-z\d\s]+)/g, ' ')
                                                                                        .replace(/(\s+)/g, ' ');
                                                                                  }
                                                                                  
                                                                                  console.log(sanitize('Hello, David World 123!'));
                                                                                  console.log(sanitize('hELlo.,     <>;dAVId  world  .;- 123'));
                                                                                  console.log(sanitize('He.llo     David,   w!orld 123#'));

                                                                                  Source https://stackoverflow.com/questions/70602532

                                                                                  QUESTION

                                                                                  Complex string manipulation by JavaScript regexp
                                                                                  Asked 2021-Dec-17 at 14:24

                                                                                  I am generating some meaningful name with the following rule in a JavaScript/Node JS program:

                                                                                  Input: "tenancy_account__accountPublicId__workspace__workspacePublicId__remove-user__userPublicId"

                                                                                  Expected output: "TenancyAccountAccountPublicIdWorkspaceWorkspacePublicIdRemove-userUserPublicId"

                                                                                  Rules:

                                                                                  1. replace any character with zero or more underscore to the non-underscored uppercase Example:x | __*x => X
                                                                                  2. If exists remove last _

                                                                                  This is what is tried so far, looking for better alternatives, if any:

                                                                                  const convertBetterString = (input) => {
                                                                                      const finalString = [];
                                                                                      if (input && input.includes('_')) {
                                                                                          const inputStringSeparation = input.split('_');
                                                                                          if (inputStringSeparation.length > 1) {
                                                                                              if (inputStringSeparation[inputStringSeparation.length - 1] === '') {
                                                                                                  inputStringSeparation.splice(inputStringSeparation.length - 1, 1);
                                                                                              }
                                                                                              inputStringSeparation.forEach((val, index) => {
                                                                                                  if (val === '' && inputStringSeparation[index + 1]) {
                                                                                                      const actualString = inputStringSeparation[index + 1];
                                                                                                      const formattedString = actualString.charAt(0).toUpperCase() + actualString.slice(1);
                                                                                                      finalString.push(formattedString);
                                                                                                  }
                                                                                              });
                                                                                              return finalString.length > 0 ? finalString.join('') : inputStringSeparation.join('');
                                                                                          } else {
                                                                                              return input.charAt(0).toUpperCase() + input.slice(1);
                                                                                          }
                                                                                      } else {
                                                                                          return input;
                                                                                      }
                                                                                  }
                                                                                  

                                                                                  ANSWER

                                                                                  Answered 2021-Dec-17 at 14:21

                                                                                  Split and slice

                                                                                  const capitalise = str => str.slice(0,1).toUpperCase() + str.slice(1); // you can add more tests
                                                                                  
                                                                                  const str = "tenancy_account__accountPublicId__workspace__workspacePublicId__remove-user__userPublicId"
                                                                                  const newStr = str.split(/_+/)
                                                                                    .map(word => capitalise(word))
                                                                                    .join("")
                                                                                  console.log(newStr)

                                                                                  Regexp with optional chaining

                                                                                  const str = "tenancy_account__accountPublicId__workspace__workspacePublicId__remove-user__userPublicId_"
                                                                                  
                                                                                  const newStr = str.replace(/(?:_+|^)(\w)?/g, (_,letter) => letter?.toUpperCase() ?? "")
                                                                                  
                                                                                  console.log(newStr)

                                                                                  Explanation

                                                                                  (?:_+|^) non-capturing the underscore OR start
                                                                                  (\w)? followed by 0 or 1 letter to be captured
                                                                                  (_,letter) => letter?.toUpperCase() ?? "") ignore the match and uppercase the letter if found, that ignores trailing underscores too

                                                                                  Source https://stackoverflow.com/questions/70394177

                                                                                  QUESTION

                                                                                  Difference between Pattern.asMatchPredicate and Pattern.asPredicate
                                                                                  Asked 2021-Nov-16 at 14:57

                                                                                  Java 11 added some new methods to the Pattern class (a compiled version of a regular expression), including:

                                                                                  I am trying to understand the difference between the two and when I would want to use one over the other?

                                                                                  ANSWER

                                                                                  Answered 2021-Nov-16 at 14:57
                                                                                  • Pattern.asPredicate will return true if any part of the input string matches the Regular expression. You should use this method if you're testing some larger body of text for a certain pattern. For example, to test whether a comment from a user contains a hyperlink.
                                                                                  • Pattern.asMatchPredicate will return true if the entire input string matches the Regular expression. You should use this method if you're testing the entire input for a certain pattern. For example, to validate the phone number of a user in their profile.

                                                                                  Pattern.asPredicate internally uses Matcher.find(), while Pattern.asMatchPrediate internally uses Matcher.matches(). So the difference between the two boils down to the difference between these two methods from the Matcher class.

                                                                                  Below are some examples to showcase the difference. You can copy & paste below code in an online Java sandbox like https://www.compilejava.net/ to play around with it yourself.

                                                                                  import java.util.regex.Pattern;
                                                                                  import java.util.function.Predicate;
                                                                                  
                                                                                  public class main
                                                                                  {
                                                                                      public static void main(String[] args) {
                                                                                          Pattern pattern = Pattern.compile("abc");
                                                                                  
                                                                                          // asPredicate will match any part of the input string
                                                                                          Predicate asPredicate = pattern.asPredicate();
                                                                                          
                                                                                          // True, because abc is part of abc
                                                                                          System.out.printf("asPredicate: abc: %s\n", asPredicate.test("abc"));
                                                                                  
                                                                                          // True, because abc is part of abcabc
                                                                                          System.out.printf("asPredicate: abcabc: %s\n", asPredicate.test("abcabc"));
                                                                                  
                                                                                          // True, because abc is part of 123abc123
                                                                                          System.out.printf("asPredicate: 123abc123: %s\n", asPredicate.test("123abc123"));
                                                                                  
                                                                                          // False, because abc is NOT part of 123
                                                                                          System.out.printf("asPredicate: 123: %s\n", asPredicate.test("123")); // -> false
                                                                                  
                                                                                          // asMatchPredicate will only match the entire input string
                                                                                          Predicate asMatchPredicate = pattern.asMatchPredicate();
                                                                                  
                                                                                          // True, because abc exactly matches abc
                                                                                          System.out.printf("asMatchPredicate: abc: %s\n", asMatchPredicate.test("abc"));
                                                                                  
                                                                                          // False, because abc does not exactly match abcabc
                                                                                          System.out.printf("asMatchPredicate: abcabc: %s\n", asMatchPredicate.test("abcabc"));
                                                                                  
                                                                                          // False, because abc does not exactly match 123abc123
                                                                                          System.out.printf("asMatchPredicate: 123abc123: %s\n", asMatchPredicate.test("123abc123"));
                                                                                  
                                                                                          // False, because abc does not exactly match 123
                                                                                          System.out.printf("asMatchPredicate: 123: %s\n", asMatchPredicate.test("123"));
                                                                                      }
                                                                                  }
                                                                                  

                                                                                  Source https://stackoverflow.com/questions/69981170

                                                                                  QUESTION

                                                                                  Regex to replace single occurrence of character in C++ with another character
                                                                                  Asked 2021-Nov-13 at 13:13

                                                                                  I am trying to replace a single occurrence of a character '1' in a String with a different character.

                                                                                  This same character can occur multiple times in the String which I am not interested in.

                                                                                  For example, in the below string I want to replace the single occurrence of 1 with 2.

                                                                                   input:-0001011101
                                                                                  
                                                                                   output:-0002011102
                                                                                  

                                                                                  I tried the below regex but it is giving be wrong results

                                                                                    regex b1("(1){1}"); 
                                                                                    S1=regex_replace( S,
                                                                                                b1,  "2");
                                                                                  

                                                                                  Any help would be greatly appreciated.

                                                                                  ANSWER

                                                                                  Answered 2021-Nov-13 at 09:22

                                                                                  Use a negative lookahead in the regexp to match a 1 that isn't followed by another 1:

                                                                                  regex b1("1(?!1)");
                                                                                  

                                                                                  Source https://stackoverflow.com/questions/69952780

                                                                                  QUESTION

                                                                                  Negating bracketed character classes in Perl regular expressions and grep
                                                                                  Asked 2021-Nov-02 at 23:48

                                                                                  I'm attempting to solve a very simple problem - find strings in an array which only contain certain letters. However, I've run up against something in the behavior of regular expressions and/or grep that I don't get.

                                                                                  #!/usr/bin/perl
                                                                                  
                                                                                  use warnings;
                                                                                  use strict;
                                                                                  
                                                                                  my @test_data = qw(ant bee cat dodo elephant frog giraffe horse);
                                                                                  
                                                                                  # Words wanted include these letters only. Hardcoded for demonstration purposes
                                                                                  my @wanted_letters = qw/a c d i n o t/;
                                                                                  
                                                                                  # Subtract those letters from the alphabet to find the letters to eliminate.
                                                                                  # Interpolate array into a negated bracketed character class, positive grep
                                                                                  # against a list of the lowercase alphabet: fine, gets befghjklmpqrsuvwxyz.
                                                                                  my @unwanted_letters = grep(/[^@wanted_letters]/, ('a' .. 'z'));
                                                                                  
                                                                                  # The desired result can be simulated by hardcoding the unwanted letters into a
                                                                                  # bracketed character class then doing a negative grep: matches ant, cat, and dodo.
                                                                                  my @works = grep(!/[befghjklmpqrsuvwxyz]/, @test_data);
                                                                                  
                                                                                  # Doing something similar but moving the negation into the bracketed character
                                                                                  # class fails and matches everything.
                                                                                  my @fails1 = grep(/[^befghjklmpqrsuvwxyz]/, @test_data);
                                                                                  
                                                                                  # Doing the same thing that produced the array of unwanted letters also fails.
                                                                                  my @fails2 = grep(/[^@unwanted_letters]/, @test_data);
                                                                                  
                                                                                  print join ' ', @works; print "\n";
                                                                                  print join ' ', @fails1; print "\n";
                                                                                  print join ' ', @fails2; print "\n";
                                                                                  

                                                                                  Questions:

                                                                                  • Why does @works get the correct result but not @fails1? The grep docs suggest the former, and the negation section of perlrecharclass suggests the latter, although it uses =~ in its example. Is this something specifically to do with using grep?
                                                                                  • Why does @fails2 not work? Is it something to do with array vs list context? It otherwise looks the same as the subtraction step.
                                                                                  • Besides that, is there a pure regex way to achieve this that avoids the subtraction step?

                                                                                  ANSWER

                                                                                  Answered 2021-Nov-02 at 13:15

                                                                                  Both fails are fixed with the addition of anchors ^ and $ and quantifier +

                                                                                  These both work:

                                                                                  my @fails1 = grep(/^[^befghjklmpqrsuvwxyz]+$/, @test_data);
                                                                                  my @fails2 = grep(/^[^@unwanted_letters]+$/, @test_data);
                                                                                  

                                                                                  Keep in mind that /[^befghjklmpqrsuvwxyz]/ or /[^@unwanted_letters]/ only matches ONE character. Adding + means as many as possible. Adding ^ and $ means all characters from the start to the end of the string.

                                                                                  With /[@wanted_letters]/ you will return a match if there is a single wanted character (even with unwanted characters in the string) -- the logical equivalent to any. Compare to /^[@wanted_letters]+$/ where all the letters need to be in the set of @wanted_letters and is the equivalent of all.

                                                                                  Demo1 only ONE character so grep fails.

                                                                                  Demo2 quantifier means more than one but no anchor - grep fails

                                                                                  Demo3 Anchors and quantifier - expected result.

                                                                                  Once you understand character classes only match ONE character and anchors for the WHOLE string and quantifiers for everything extending the match to the anchors, you can directly grep just with wanted letters:

                                                                                  my @wanted = grep(/^[@wanted_letters]+$/, @test_data);
                                                                                  

                                                                                  Source https://stackoverflow.com/questions/69801030

                                                                                  QUESTION

                                                                                  Regular expression that matches all specified characters in any order at the start of the line
                                                                                  Asked 2021-Oct-31 at 11:30

                                                                                  I'm looking for a regexp that matches any line that contains 'B', 'R', 'A' and 'S' (in any order) at the start. It would match all the following lines, except the last two.

                                                                                  BRASIL
                                                                                  BSRAIL
                                                                                  BARSILERO
                                                                                  BRASILERA
                                                                                  BRASILEÑA
                                                                                  BRASILEÑO
                                                                                  BARBADOS
                                                                                  BOSNIA AND HERZEGOVINA
                                                                                  

                                                                                  I tried the following:

                                                                                  ^(B|R|A|S){4}.*$
                                                                                  ^(?=.*B)(?=.*R)(?=.*A)(?=.*S).*$
                                                                                  ^(?=.{4})(?=.*B)(?=.*R)(?=.*A)(?=.*S).*$
                                                                                  ^(?=.*B)(?=.*R)(?=.*A)(?=.*S){4}.*$
                                                                                  ^(?=.*B){1}(?=.*R){1}(?=.*A){1}(?=.*S){1}.*$
                                                                                  

                                                                                  ANSWER

                                                                                  Answered 2021-Oct-30 at 21:05

                                                                                  There are only 24 permutations :)

                                                                                  ^(ABRS|BARS|RABS|ARBS|BRAS|RBAS|RBSA|BRSA|SRBA|RSBA|BSRA|SBRA|SARB|ASRB|RSAB|SRAB|ARSB|RASB|BASR|ABSR|SBAR|BSAR|ASBR|SABR)
                                                                                  

                                                                                  You can shorten it a bit by grouping pairs of two:

                                                                                  ^((AB|BA)(RS|SR)|(AR|RA)(BS|SB)|(AS|SA)(BR|RB)|(BR|RB)(AS|SA)|(BS|SB)(AR|RA)|(RS|SR)(AB|BA))
                                                                                  

                                                                                  Each double pair matches 4 inputs, e.g., (AB|BA)(RS|SR) can match:

                                                                                  ABRS
                                                                                  ABSR
                                                                                  BARS
                                                                                  BASR
                                                                                  

                                                                                  Source https://stackoverflow.com/questions/69781982

                                                                                  QUESTION

                                                                                  Using PowerShell how to replace and save a value in a json file having comments
                                                                                  Asked 2021-Oct-22 at 22:32

                                                                                  I have a Json file having multiple comments and I want to replace a value in it.

                                                                                  I tried the below and it gives me a json file without comments. But I don't understand how to change the value and save it back with comments. Is this even possible because we are replacing all the comments with empty lines?

                                                                                  $json = Get-Content $jsonfile -Raw | ConvertFrom-Json
                                                                                  $configfile = $json -replace '(?m)(?<=^([^"]|"[^"]*")*)//.*' -replace '(?ms)/\*.*?\*/'
                                                                                  

                                                                                  My config.json is as below and I want to change the value of "version" to 10 through a powershell script and then save it back with the comments intact.

                                                                                      {
                                                                                          "FramewokSettings": {
                                                                                              "Name": "VX",
                                                                                              "Version": "8",  // The value here is not constant. It can be something like v1.4.56.456 also
                                                                                              "GitVersion": "v5",
                                                                                              "DatabaseVersion": "7",
                                                                                              // Doing xyz 
                                                                                              "CounterVersion": "2"
                                                                                              // Doing ABC. 
                                                                                              // Start
                                                                                           }
                                                                                  }
                                                                                  

                                                                                  ANSWER

                                                                                  Answered 2021-Oct-22 at 22:32

                                                                                  Use

                                                                                  (Get-Content test.txt) -replace '^(\s*"Version"\s*:\s*")[^"]*', '${1}10' | Set-Content test.txt
                                                                                  

                                                                                  See proof.

                                                                                  EXPLANATION

                                                                                  --------------------------------------------------------------------------------
                                                                                    ^                        the beginning of the string
                                                                                  --------------------------------------------------------------------------------
                                                                                    (                        group and capture to $1:
                                                                                  --------------------------------------------------------------------------------
                                                                                      \s*                      whitespace (0 or more times (matching the most
                                                                                                               amount possible))
                                                                                  --------------------------------------------------------------------------------
                                                                                      "Version"                '"Version"'
                                                                                  --------------------------------------------------------------------------------
                                                                                      \s*                      whitespace (0 or more times (matching the most
                                                                                                               amount possible))
                                                                                  --------------------------------------------------------------------------------
                                                                                      :                        ':'
                                                                                  --------------------------------------------------------------------------------
                                                                                      \s*                      whitespace (0 or more times (matching the most
                                                                                                               amount possible))
                                                                                  --------------------------------------------------------------------------------
                                                                                      "                        '"'
                                                                                  --------------------------------------------------------------------------------
                                                                                    )                        end of $1
                                                                                  --------------------------------------------------------------------------------
                                                                                    [^"]*                    any character except: '"' (0 or more times
                                                                                                             (matching the most amount possible))
                                                                                  

                                                                                  Source https://stackoverflow.com/questions/69683137

                                                                                  QUESTION

                                                                                  How to get customed tags in a text, and put in another text?
                                                                                  Asked 2021-Oct-04 at 15:01

                                                                                  The header question may not be easy to understand. Hope you can understand my detailed info below.

                                                                                  I have sentence data below, that has some tags, represented by [tn]tag[/tn]:

                                                                                  const sentence = `[t1]Sometimes[/t1] that's [t2]just the way[/t2] it has to be. Sure, there
                                                                                   were [t3]probably[/t3] other options, but he didn't let them [t4]enter his mind[/t4]. It 
                                                                                  was done and that was that. It was just the way [t5]it[/t5] had to be.`
                                                                                  

                                                                                  And i have parts of the sentence.

                                                                                  const parts = [
                                                                                      "Sometimes that's just the way",
                                                                                      "it has to be",
                                                                                      "Sure,",
                                                                                      "there were probably other options,",
                                                                                      "but he didn't let them enter his mind.",
                                                                                      "It was done and that was that.",
                                                                                      "It was just the way it had to be."
                                                                                  ];
                                                                                  

                                                                                  Goal is to add tags on each parts using the sentence above.

                                                                                  const expectedOutput = [
                                                                                      "[t1]Sometimes[/t1] that's [t2]just the way[/t2]",
                                                                                      "it has to be",
                                                                                      "Sure,",
                                                                                      "there were [t3]probably[/t3] other options,",
                                                                                      "but he didn't let them [t4]enter his mind[/t4].",
                                                                                      "It was done and that was that.",
                                                                                      "It was just the way [t5]it[/t5] had to be."
                                                                                  ];
                                                                                  

                                                                                  What I've tried so far are the following, but seemingly does not make sense, and I endup nothing.

                                                                                  1. make a clone sentence, and remove all tags. (code below)
                                                                                  2. find all parts in the sentence.
                                                                                  3. [problem is I don't know how to put again the tags]

                                                                                  I wanna ask is there any chance to achieve it? and how. thanks

                                                                                  export const removeTags = (content) => {
                                                                                    content = content.replace(/([t]|[\/t])/g, '');
                                                                                    return content.replace(/([t\d+]|[\/t\d+])/g, '');
                                                                                  };
                                                                                  

                                                                                  ANSWER

                                                                                  Answered 2021-Oct-04 at 08:47

                                                                                  Here is a solution that assumes that there are no nested tags, that all tags open and close in the part. Also, this assumes that all characters from the sentence are in parts. For this last assumption, I had to add the . after it has to be in the second expected part. I also had to remove newline characters from the sentence but I think it was because of the copy/paste. This solution will loop through all characters and store two parallel buffers : one with the tags, one without. We will use the second one to compare with the parts, and use the first one to generate the output.

                                                                                  const sentence = `[t1]Sometimes[/t1] that's [t2]just the way[/t2] it has to be. Sure, there were [t3]probably[/t3] other options, but he didn't let them [t4]enter his mind[/t4]. It was done and that was that. It was just the way [t5]it[/t5] had to be.`
                                                                                  
                                                                                  
                                                                                  const parts = [
                                                                                    "Sometimes that's just the way",
                                                                                    "it has to be.",
                                                                                    "Sure,",
                                                                                    "there were probably other options,",
                                                                                    "but he didn't let them enter his mind.",
                                                                                    "It was done and that was that.",
                                                                                    "It was just the way it had to be."
                                                                                  ];
                                                                                  
                                                                                  let bufferWithoutTags = ""
                                                                                  let bufferWithTags = ""
                                                                                  const output = []
                                                                                  const buffers = []
                                                                                  let tagOpened = false
                                                                                  
                                                                                  for (let i = 0; i < sentence.length; ++i) {
                                                                                    let c = sentence[i]
                                                                                    bufferWithTags += c
                                                                                    if ( c === '[') {
                                                                                      if (tagOpened && sentence[i+1] === "/") {
                                                                                        tagOpened = false
                                                                                      } else {
                                                                                        tagOpened = true
                                                                                      }
                                                                                      while (c != ']') {
                                                                                        c = sentence[++i]
                                                                                        bufferWithTags += c
                                                                                      }
                                                                                    } else {
                                                                                      bufferWithoutTags += c;
                                                                                    }
                                                                                    if (!tagOpened) {
                                                                                      for (const part of parts) {
                                                                                        if (part === bufferWithoutTags.trim()) {
                                                                                          output.push(bufferWithTags.trim())
                                                                                          bufferWithTags = bufferWithoutTags = ""
                                                                                        }
                                                                                      }
                                                                                    }
                                                                                  }
                                                                                  console.log(output)
                                                                                  

                                                                                  Source https://stackoverflow.com/questions/69432894

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