FireWork | JQuery library to let off online fireworks | Frontend Framework library

 by   noootown JavaScript Version: Current License: MIT

kandi X-RAY | FireWork Summary

kandi X-RAY | FireWork Summary

FireWork is a JavaScript library typically used in User Interface, Frontend Framework, jQuery applications. FireWork has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

A JQuery library to let off online fireworks, as you see in the gif. Move your mouse, type your keyboard and you'll get fireworks! Though the demo website isn't finished, you can still have a try with my fireworks. The website also supports youtube music, replay and captions, which is not packaged in this library. By the way, the upload feature is not done.
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            kandi-support Support

              FireWork has a low active ecosystem.
              It has 7 star(s) with 5 fork(s). There are 1 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              FireWork has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of FireWork is current.

            kandi-Quality Quality

              FireWork has 0 bugs and 0 code smells.

            kandi-Security Security

              FireWork has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              FireWork code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              FireWork is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              FireWork releases are not available. You will need to build from source code and install.
              Installation instructions are not available. Examples and code snippets are available.

            Top functions reviewed by kandi - BETA

            kandi has reviewed FireWork and discovered the below as its top functions. This is intended to give you an instant insight into FireWork implemented functionality, and help decide if they suit your requirements.
            • function to get a firestart point
            • Manages a fireworkworker .
            • Generate random number
            • Adds a new box to the fire point
            • Define a point
            • Converts HSL to HSL
            • Construct a new Firework
            • Construct a fireworkpoint
            • Drawing .
            • Constructs a new Vector instance .
            Get all kandi verified functions for this library.

            FireWork Key Features

            No Key Features are available at this moment for FireWork.

            FireWork Examples and Code Snippets

            No Code Snippets are available at this moment for FireWork.

            Community Discussions

            QUESTION

            Why does the canvas have a black background?
            Asked 2022-Mar-31 at 05:35

            Why does the below canvas have a black background!! I have tried everything but it doesn't go!! Bcs of it the text below it is also not visible! I need it to be transparent to show the elements behind it and the background image of the body. Pls, help fast!! There is a similar question on StackOverflow but the solution given for that question doesn't work correctly for me.

            ...

            ANSWER

            Answered 2022-Mar-28 at 10:21

            As I understand you wanted to have a white background for your canvas? Check this out!

            Source https://stackoverflow.com/questions/71645601

            QUESTION

            Form validation return issues
            Asked 2022-Mar-16 at 10:35

            Im trying to learn form validation and I cannot figure out what is going on here. I am following a W3Schools tutorial and the validate form function is giving an error but it is not doing that on their example.

            I tried copy and pasting the example into my project and just changing the property name and it still gives an error.

            ...

            ANSWER

            Answered 2022-Mar-12 at 09:52

            I don't know if this will solve your problem (what was the error?) but the following line:

            Source https://stackoverflow.com/questions/71448573

            QUESTION

            Testing for an [n]th element when using split('/') on a URL, without it giving a "list index out of range" error
            Asked 2022-Mar-01 at 11:20

            Python 3.10.2

            I have a URL that generally appears as follows, with some slight variation (http/https, www. prefix sometimes, #params at the end to indicate things like referrer or device being displayed on, etc).

            https://madeupdomain.net/u/Hypothetical_Username/Some-Random-Page-Name

            The forms of the URL I'm generally encountering are either:

            https://madeupdomain.net/u/Hypothetical_Username/

            or

            https://madeupdomain.net/u/Hypothetical_Username/Some-Random-Page-Name

            What I'm interested in doing with the URL:

            1. Get the Hypothetical_Username part
            2. Find out if the URL stops at the username or if there is another /path after it

            I've been using user = url.split('/')[4] to get the username portion of the URL. Since the URL always includes the username and the URL is usually consistent (for now), I can rely on this split getting the element I want. If the URL changes a little bit in the future, I know this'll bone me.

            However, the rest of the path is optional.

            If I just use url.split('/')[5], python throws an error as soon as it encounters a URL where split doesn't have a [5]th element.

            So I tired to "test" for it with an if statement and it still complains and throws the error IndexError: list index out of range.

            ...

            ANSWER

            Answered 2022-Mar-01 at 10:49

            You can split the url at '/u/' and then split the last part with '/' to get the username and the path after that.

            Source https://stackoverflow.com/questions/71306521

            QUESTION

            Fandom-py: Unable to get image by using page.images[0]
            Asked 2022-Feb-01 at 09:46

            I'm using fandom module in python for my discord bot. I get this error when I request data by using page.images[0]. It should be an image url. This is the page I want to get.

            ...

            ANSWER

            Answered 2022-Feb-01 at 09:46

            I fixed it by using pymediawiki module.

            This code that use mediawiki can replace fandom module by changing the api of wiki.

            Source https://stackoverflow.com/questions/70863772

            QUESTION

            Print function produces output only within main function
            Asked 2022-Jan-11 at 20:59

            I know my post count looks suspicious but in my six years of coding I always found an answer by doing some research, this issue though has got me stumped so here goes my first post.

            The problem I am facing is simple, I am using python to code a genetic algorithm for Hanabi game, while in other projects I used to print out some info normally so I can debug or ensure results are what expect them to be, in this project and for some very odd reason, whenever I use print() it does not produce an output in most cases, it does produce an output only if it is called from the main function, I will paste my code and result below:

            ...

            ANSWER

            Answered 2022-Jan-11 at 20:59
                with open(os.devnull, 'w') as devnull:
                    with contextlib.redirect_stdout(devnull):
                        result=run(25,num_players,chromosome)
                print("chromosome",chromosome,"fitness",result)
            

            Source https://stackoverflow.com/questions/70673317

            QUESTION

            Showing a point in p5.js using parameters
            Asked 2021-Nov-29 at 01:02

            In my 'show' function I have this command: point(this.position.x, this.position.y);

            This does not cause a point to appear, note I have tried printing these values out directly before this point(..) call and they exist and are within the frame. I have also tried parsing them to an int and passing but no luck.

            However:

            • Passing e.g. 100, 100 to this function makes the point show up
            • Setting this.position.x and this.position.y to e.g. 100 before point(..) call makes the point show up
            • Passing e.g. 100, 100 to new Particle(random(width), height); instead of using width and height also works
            • Assigning new variables to values of this.position.x and this.position.y respectively then passing those to point also does not show the point

            Please find below my code, I have no idea what the issue is

            ...

            ANSWER

            Answered 2021-Nov-29 at 01:02

            The point is actually being drawn on the canvas, it just doesn't seem obvious. This is because you're setting its y value to height which will simply place it at the very bottom of the canvas. The colors also make it hard to see where the point is drawn. The image below shows the point being drawn at (310,399).

            To resolve this, change the y value to be between 0 and height. One way of achieving this is to randomize the y value as you did with random(width) for x. In my solution below, I also changed the background to be drawn with color value 151 instead of 51 for better contrast.

            Source https://stackoverflow.com/questions/69944842

            QUESTION

            How to extract data from nested objects array in React?
            Asked 2021-Oct-26 at 16:02

            I have kind of a special problem. I am currently learning react and have fetched data from my own demo API (a Java Spring project).

            However, I receive the data correctly in React. Now I am creating Components with it (Music Track Metadata). The response of the API returns an Array of Objects and one item within the object is a nested object. Now i don't know how i can extract this information to my React component.

            Here is an example JSON of my response:

            ...

            ANSWER

            Answered 2021-Oct-26 at 16:02

            So, your response.data is an array of 'tracks'. Each 'track' is an Object. You are currently destructuring your 'track' like so, in your .map() method:

            Source https://stackoverflow.com/questions/69726296

            QUESTION

            Find the most frequent value per group in a table column
            Asked 2021-Oct-24 at 09:42

            I need to find most frequent value of object_of_search for each ethnicity. How can I achieve this? Subqueries in the SELECT clause and correlated subqueries are not allowed. Something similar to this:

            ...

            ANSWER

            Answered 2021-Oct-23 at 14:53

            Updated: Fiddle

            This should address the specific "which object per ethnicity" question.

            Note, this doesn't address ties in the count. That wasn't part of the question / request.

            Adjust your SQL to include this logic, to provide that detail:

            Source https://stackoverflow.com/questions/69689118

            QUESTION

            Extracting one url each from similar types
            Asked 2021-Oct-16 at 03:33

            I have one csv file containing thousands of urls. How is it possible to select randomly one url from each base type url. The order of getting url can be anyway. It has to be random.

            ...

            ANSWER

            Answered 2021-Oct-16 at 03:33

            The first thing you would need to do would be to extract the base url, which can do done using urllib.

            You can then use groupby with sample to extract a random url for each base_url.

            Source https://stackoverflow.com/questions/69592304

            QUESTION

            PlayerJoinEvent - Create a welcome message Spigot 1.12.2 (Java)
            Asked 2021-Sep-08 at 11:27

            I don't understand why he always returns to me "You never played" then the first time ok, but the second I don't understand

            I'm trying to make a condition: If the player has already played I do nothing: no message the player receives nothing! If the player has never played : Welcome message + He receives an item + and I get his position to explode fireworks And I would have liked to add a counter of players who join in the second condition

            ...

            ANSWER

            Answered 2021-Sep-08 at 11:27

            if (hasPlayed != true) should be if (hasPlayed == true) as you have it doing the opposite of what you want.

            Your code would look like:

            Source https://stackoverflow.com/questions/69096786

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install FireWork

            You can download it from GitHub.

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