buba | Build your ES2015 projects with Buba heart | Frontend Framework library
kandi X-RAY | buba Summary
kandi X-RAY | buba Summary
Build your ES2015+ projects with Buba :heart:. Transpile your ES2015+ code into ES5 with Buba. For ease of setup, your .js files must be located inside of a directory named src at the root of your packages.
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- Creates a parent directory if it exists
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QUESTION
So I have the following code:
...ANSWER
Answered 2022-Feb-14 at 13:34The static variable i
declared in the function is initialized only once before the program startup. So its value is preserved between function calls.
In this for loop
QUESTION
I need to replace whatever expressions in between 2 patterns of JSON file, those patterns are multi occurrences and I would like to replace them only once by my choice (let's say in the 4th occurrence out of 6).
I've created a sed expression that works when I have only one occurrence in the file, but when adding more than one it is for some reason doesn't work when trying to replace the second occurrence.
This is my sed:
...ANSWER
Answered 2021-Jun-07 at 18:40That's close to 5 KiB of JSON on a single line — it's a pain to try reading it.
There are two sequences of [CDATA[…]]
— the first is about 140 characters long, the second about 45 characters long. Your primary problem is that the .*
notation in your sed
script is 'greedy'; it will start matching after the first CDATA
and read until the end of the second. You need to restrict it so it doesn't skip the ]]
end marker. That's not trivial. A moderate approximation is:
QUESTION
String1: \txd\tbuba:pub|rub|spo-os|ix|beach|app|one|op|sono\tadT\tad\t
String2: \txd\tbuba:pub\tadT\tad\t
I have two sample strings and need common regex to extract pub|rub|spo|ix|beach|app|one|op|sono
and pub
I tried buba:(\w(.)*(-os)?)\\t
but not working.
Please assist.
...ANSWER
Answered 2021-Feb-01 at 09:29You could use
QUESTION
I am trying to total figures in the 'Amount' column by date and where the class is the same.
E.g. of desired df is below where i am trying to calculate 'Total Amount' column:
- To Date Name Class Amount Total Amount
- 1/31/2020 Smith A 1 5
- 1/31/2020 Byrne A 1 5
- 1/31/2020 McDaid A 1 5
- 1/31/2020 Buba A 1 5
- 1/31/2020 Holland A 1 5
- 1/31/2020 Capital B 1 2
- 1/31/2020 Padmir B 1 2
I have tried the below but its giving me an output of NA
...ANSWER
Answered 2020-Aug-21 at 20:02You have to provide grouped columns as a list:
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