birds | Bird Sound Synthesis based on AMFM | Audio Utils library
kandi X-RAY | birds Summary
kandi X-RAY | birds Summary
Bird Sound Synthesis based on AM+FM
Support
Quality
Security
License
Reuse
Top functions reviewed by kandi - BETA
Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of birds
birds Key Features
birds Examples and Code Snippets
Community Discussions
Trending Discussions on birds
QUESTION
The Question
How do I best execute memory-intensive pipelines in Apache Beam?
Background
I've written a pipeline that takes the Naemura Bird dataset and converts the images and annotations to TF Records with TF Examples of the required format for the TF object detection API.
I tested the pipeline using DirectRunner with a small subset of images (4 or 5) and it worked fine.
The Problem
When running the pipeline with a bigger data set (day 1 of 3, ~21GB) it crashes after a while with a non-descriptive SIGKILL.
I do see a memory peak before the crash and assume that the process is killed because of a too high memory load.
I ran the pipeline through strace. These are the last lines in the trace:
ANSWER
Answered 2021-Jun-15 at 13:51Multiple things could cause this behaviour, because the pipeline runs fine with less Data, analysing what has changed could lead us to a resolution.
Option 1 : clean your input dataThe third line of the logs you provide might indicate that you're processing unclean data in your bigger pipeline mmap(NULL, could mean that | "Get Content" >> beam.Map(lambda x: x.read_utf8()) is trying to read a null value.
Is there an empty file somewhere ? Are your files utf8 encoded ?
Option 2 : use smaller files as inputI'm guessing using the fileio.ReadMatches() will try to load into memory the whole file, if your file is bigger than your memory, this could lead to errors. Can you split your data into smaller files ?
If files are too big for your current machine with a DirectRunner you could try to use an on-demand infrastructure using another runner on the Cloud such as DataflowRunner
QUESTION
Let's say I have a collection called "pets"
The collection contains three different types of pets: cat, dog, and bird
Now let's say there are 10 cats, 10 dogs, and 10 birds in the collection (30 documents in total).
Is there a way to make a single query to pets that gets me 3 cats, 2 dogs, and 1 bird?
Basically I want to specify each type of pet I want, and limit each type of pet to a specific number, all in one query. The reason for this is because I want to be efficient and not make many queries.
This is what I have currently:
...ANSWER
Answered 2021-Jun-12 at 01:33Thanks to prasad_, here is the solution that solves my case:
QUESTION
I have a pandas DataFrame which looks like this
...ANSWER
Answered 2021-Jun-10 at 13:44You can use get_level_values to filter.
QUESTION
I'm working on an October CMS project which use a blog where I need to seperate blog posts in two major categories. When listing blog posts using the RainLab.Blog plugin's Post List component, I need to list categories that are sub-categories under a specific top-level category and exclude other categories.
In the TWIG template, I want to iterate through and list out the categories that belong to "Birds" and not "Sealife".
In the default Post List component, categories are listed like this:
...ANSWER
Answered 2021-Jun-07 at 16:04If it's totally fine to hardcode category then you can simply compare categories parent's slug or id to hardcoded value.
Here I am using the
slugto compare parent, you can also useidit's totally up to you.
QUESTION
How i can access below object type value which is coming as request body from data factory output of another function app in http trigger function. Now i need to perform some operation with these ouput in http trigger function. { "functionName": "GoogleAuth", "method": "POST", "headers": {}, "body": { "Response": "[{"id":"hjk","name":"abc","description":"hki","brand":"Birds Eye","ean":"125","mediaStorageKey":"124","maxQuantity":6,"price":1.75,"size":224.0,"sizeUnits":"Grams"}]", "effectiveIntegrationRuntime": "DefaultIntegrationRuntime (West Europe)", "executionDuration": 0, "durationInQueue": { "integrationRuntimeQueue": 0 }, "billingReference": { "activityType": "ExternalActivity", "billableDuration": [ { "meterType": "AzureIR", "duration": 0.016666666666666666, "unit": "Hours" } ] } } }
I am trying to access it like this but is showing error.
...ANSWER
Answered 2021-Jun-04 at 07:03QUESTION
I have done the Einstein's Riddle exercise with linear programming. I implemented this solutions in Gusek. How can i tell if there is more than one solution?
Einsten's riddle:
There are 5 houses in five different colors. In each house lives a person with a different nationality. These five owners drink a certain type of beverage, smoke a certain brand of cigar and keep a certain pet. No owners have the same pet, smoke the same brand of cigar or drink the same beverage.
Constaints:
the Brit lives in the red house
the Swede keeps dogs as pets
the Dane drinks tea
the green house is on the left of the white house
the green house's owner drinks coffee
the person who smokes Pall Mall rears birds
the owner of the yellow house smokes Dunhill
the man living in the center house drinks milk
the Norwegian lives in the first house
the man who smokes blends lives next to the one who keeps cats
the man who keeps horses lives next to the man who smokes Dunhill
the owner who smokes BlueMaster drinks beer
the German smokes Prince
the Norwegian lives next to the blue house
the man who smokes blend has a neighbor who drinks water
Can I tell which constraints are redundant?
Thank you for your help
...ANSWER
Answered 2021-Jun-04 at 08:53Your decisions/solution will be in the form of binary or integer varibles.
If they are binary, add in a new constraint like the one below: (Y are all the binaries which were 1 and `Y are binaries which were 0.)
sum(Y) + sum(i-Y) != |Y|+|Y|
Keep repeating this till you get an infeasible model. This can be extended to the integer case too.
As for redundancy, you have to manually try removing them and see if the solution changes. However, in terms of reduncancy, you might have cases where constraint A and B are redundant OR constraint C is redundant. You could have multiple sets of potential redundant constraints depending on which you eliminate.
QUESTION
So I have an assignment and a little stumped on the last part (very new so bear with me).
I have two files "birds.txt" and "birds2.txt". essentially I have the first part done where it will read "birds.txt" and sort them in a list by frequency of how many times a specific bird is seen which works fine (how many times the name of any given bird appears in the "birds"txt").
The part I can't seem to wrap my head around is how I would take my existing list and compare it to my second file "birds2.txt" and then have it remove any duplicate entries. So the first and second file will have some of the same birds and if when reading the second file it finds a bird already in the list it removes it then prints this "new" list again.
I apologize if I'm not clear enough or missing any info...below is my code up to where I'm at.
...ANSWER
Answered 2021-Jun-01 at 16:52I think deletion while comparing with strings loaded from file is somewhat similar to first part of your problem where you were adding items to the list. You can create a method in your class which will scan the file line by line, search for a match for that line in linked list and remove if it's a match.
I was able to do that with three helper methods:
QUESTION
#include
struct BirdHome{
char area[500];
char heightcm[100];
char feederquantity[10];
char hasNest[5];
};
struct Bird{
char isRinged[5];
char nameSpecies[50];
char birdAgeMonths[500];
struct BirdHome hom;
char gender[6];
};
struct Bird birds;
int main(void){
FILE *oput;
int max=100;
int count = 0;
char filename[100];
printf("file name? : ");
scanf("%s", &filename);
count = load(filename, &birds, max);
if (count == 0)
printf("No structures loaded\n");
else (
printf("Data loaded\n")
);
save(&birds, oput);
return 0;
}
int load(char *filename, struct Bird *birds, int max){
int count = 0;
FILE *fp = fopen(filename, "r");
char line[100 * 4];
if (fp == NULL)
return 1;
while (count < max && fgets(line, sizeof(line), fp) != NULL){
sscanf(line, "%s %s %s %s %s %s %s %s", birds[count].isRinged, birds[count].nameSpecies,
birds[count].birdAgeMonths, birds[count].hom.area,
birds[count].hom.heightcm, birds[count].hom.feederquantity,
birds[count].hom.hasNest,birds[count].gender);
count++;
}
fclose(fp);
return count;
}
int save (struct Bird *birds, FILE *oput){
int i;
oput=fopen("birdssave.txt","w");
for (i=0;i<3;i++){
fprintf(oput,"%s %s %s %s %s %s %s %s\n",birds[i].isRinged, birds[i].nameSpecies,
birds[i].birdAgeMonths, birds[i].hom.area,
birds[i].hom.heightcm, birds[i].hom.feederquantity,
birds[i].hom.hasNest,birds[i].gender);
}
fclose(oput);
}
ANSWER
Answered 2021-May-30 at 10:50The load function is made unproperly so it doesn't work. The normal functions does a lot more things to do. Here is the text of it with the needed commentaries
QUESTION
Here is the code for file "lib.h"
...ANSWER
Answered 2021-May-30 at 10:44The problem here is that original Array that must've contained a dynamic array of class "Bird" doesn't have any of it. because it was like this
QUESTION
The xml format is a good way to store any hierarchical data. As an example we are using the classification of animals
...ANSWER
Answered 2021-May-28 at 10:32What we can see in the html table, is that the first row holds a cell for every hierarchy level which is represented as a column. This means it has to be generated a row with all elements from the highest till the deepest hierarchy level. The element on the deepest hierarchy level is the one without further descendants. To get these we can use this xpath expression
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install birds
Support
Reuse Trending Solutions
Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items
Find more librariesStay Updated
Subscribe to our newsletter for trending solutions and developer bootcamps
Share this Page
